I've created a PHP file which shows the results from a MySQL database as we all create like in
echo "<table><tr><td>";
...
echo "</td></tr></table>";
But now I want to make a button at the bottom of the table, something like 'save report', which saves the created table into HTML format.
So how could it be done?
You can use the following scripts:
index.php
In index.php, you have the HTML table.
<?php
$contents = "<table><tr><td>A</td><td>B</td></tr><tr><td>One</td><td>Two</td></tr><tr><td>Three</td><td>Four</td></tr></table>"; // Put here the source code of your table.
?>
<html>
<head>
<title>Save the file!</title>
</head>
<body>
<?php echo $contents; ?>
<form action="savefile.php" method="post">
<input type="hidden" name="contents" value="<?php echo htmlspecialchars($contents); ?>">
<input type="submit" value="Save file" />
</form>
</body>
</html>
savefile.php
And then use the file savefile.php to popup your browser's download dialog to save the file.
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
header('Content-type: text/html');
header('Content-Disposition: attachment; filename="table.html"');
echo $_POST['contents'];
}
?>
I think you want to save reports generated by PHP/MySQL as HTML file?
<?php
// Open file for writing
$fileHandle = fopen("/DestinationPath/DestinationFile.html", "w");
// Dump File
$head = "<html><head><title>my reports</title></head><body>\n";
fwrite($fileHandle, $head);
$sql = mysql_query("Your sql query here");
while ($result = mysql_fetch_assoc($sql)) {
$line = $result['yourmysqlfield']."\n";
fwrite($fileHandle, $line);
}
$foot = "</body></html>\n";
fwrite($fileHandle, $foot);
// Close File
close($fileHandle);
?>
Related
I am having trouble writing back to a text file selected from a html form with a dropdown menu, the script is able to read but is unable to write back, returns "Unable to Open File".using PHP fopen and fwrite
This is the index.html code:
<html>
<head></head>
<title>Edit Server Side Text Files</title>
<body>
<form action="function.php" method="post">
<select name="list">
<option value="./files/banned-kdf.txt">banned-kdf.txt</option>
<option value="./files/blackList.txt">blackList.txt</option>
</select>
<input type="submit" name="edit" value="Edit" />
</form>
</body>
</html>
And this is the function.php code:
<?php
if(isset($_POST["edit"])) {
$filename = $_POST["list"];
global $filename;
// var_dump($filename);
$myfile = fopen("$filename", "r") or die("Unable to open file!");
$filecontent = fread($myfile,filesize("$filename"));
fclose($myfile);
}
?>
<html>
<form action="<?php echo $PHP_SELF;?>" method="post">
<textarea name="textareaContent" rows="50" cols="100">
<?
if(isset($filecontent)) { echo $filecontent; }
?>
</textarea>
<br>
<br>
<input type="submit" name="update" value="Update" />
</textarea>
<?
//write to text file
if(isset($_POST["update"])) {
// The following two lines are just for troubleshooting and have been commented out.
// echo $_POST["update"];
// var_dump($filename);
$myfile = fopen("$filename", "w") or die("Unable to open file!");
fwrite($myfile, $_POST["textareaContent"]);
fclose($myfile);
}
?>
</form>
<br>
<br>
Return to List Selection
</html>
You're not sending file name in the second form, just code, so, $filename is undefined. Add it in an input hidden:
global $variable; is not useful here, because the variable will not be present on next script execution, when processing the form.
<?php
// Default value for contents:
$filecontent = '';
// Ok, read the file here
if(isset($_POST["edit"])) {
$filename = $_POST["list"];
global $filename; // This will not be useful
$myfile = fopen("$filename", "r") or die("Unable to open file!");
$filecontent = fread($myfile,filesize("$filename"));
fclose($myfile);
}
// If request comes from second form, process it
if(isset($_POST['update'])) {
// Get file name from input hidden
$filename = $_POST["filename"];
$myfile = fopen("$filename", "w") or die("Unable to open file!");
fwrite($myfile, $_POST["textareaContent"]);
fclose($myfile);
// End the script, no need to show the form again
die('File updated successfully.');
}
?>
<html>
<form action="<?php echo $PHP_SELF;?>" method="post">
<input type="hidden" name="filename" value ="<?php
// Send filename within form
echo $filename;
?>">
<textarea name="textareaContent" rows="50" cols="100">
<?
// No if needed here, we already have a value
echo $filecontent;
?>
</textarea>
<br>
<br>
<input type="submit" name="update" value="Update" />
</form>
<br>
<br>
Return to List Selection
</html>
Please check the permission of target file and the folder in this the file is supposed to be.
I've been at this for a while and been through other options on stack but can't get this to work. (I'm pretty nooby, sorry!)
I have a form which i want to send data to my txt file but it's just not writing.
ANY help greatly appreciated, thank you!!
My HTML Form:
<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>php test</title>
</head>
<title></title>
</head>
<body>
<form action="myprocessingscript.php" method="POST">
<input name="field1" type="text" />
<input name="field2" type="text" />
<input type="submit" name="submit" value="Save Data">
</form>
<a href='/tmp/mydata.txt'>Text file</a>
</body>
And my PHP
<?php
if(isset($_POST['field1']) && isset($_POST['field2'])) {
$data = $_POST['field1'] . '-' . $_POST['field2'] . "\n";
$ret = fwrite('/tmp/mydata.txt', $data, FILE_APPEND | LOCK_EX);
if($ret === false) {
die('There was an error writing this file');
}
else {
echo "$ret bytes written to file";
}
}
else {
die('no post data to process');
}
You need to open a file before you can write to it with fwrite().
$fp = fopen('/tmp/mydata.txt', 'w');
$ret = fwrite($fp, $data);
//and don't forget to close it
fclose($fp);
if($ret === false) {
...
Based on the flags you use in the question I think the function you might be thinking of is file_put_contents (See Docs HERE) and not fwrite.
Try to add this line of code:
$myfile = fopen("/tmp/mydata.txt", "w") or die("Unable to open file!");
before the fwrite(), then you can now insert data/text in your file:
fwrite($myfile, $data);
My program uses PHP to open a list of configuration settings from a txt file called "configurationSettings.txt" and puts the data from it onto a form.
What I'm trying to figure out is how to enable my program to update the data on the original txt file if the user changes anything through the form.
Here is an example of the txt file data:
Channel 7
4.0000
6.0000
Here is my code that reads the data and fills my form:
<?php
$configFile = fopen("configurationSettings.txt", "r");
$title1 = fgets($configFile);
$gain1 = fgets($configFile);
$offset1 = fgets($configFile);
fclose($configFile);
?>
<form action="program.php" method="post">
Channel 8 Title:<br>
<input type="text" name="channel0Title" value="<?php echo $title1 ?>">
<br>
Gain:<br>
<input type="text" name="channel0Gain" value="<?php echo $gain1 ?>">
<br>
Offset:<br>
<input type="text" name="Channel0Offset" value= "<?php echo $offset1 ?>">
<br>
<input type="submit" id ="submitButton" value="Submit">
</div>
</form>
And heres a picture of what it looks like:
What do I do to update the original txt file by pressing the submit button?
Tested, works 100%. You don't have to create .txt. Gets created automatically if not present.
index.html
<form action="program.php" method="post">
Channel 8 Title:<br><input type="text" name="channel0Title" value="Channel 7"><br>
Gain:<br><input type="text" name="channel0Gain" value="4.000"><br>
Offset:<br><input type="text" name="channel0Offset" value= "6.000"><br>
<input type="submit" id ="submitButton" value="Submit">
</form>
program.php
<?php
$title = $_POST["channel0Title"]; //You have to get the form data
$gain = $_POST["channel0Gain"];
$offset = $_POST["channel0Offset"];
$file = fopen('configurationSettings.txt', 'w+'); //Open your .txt file
ftruncate($file, 0); //Clear the file to 0bit
$content = $title. PHP_EOL .$gain. PHP_EOL .$offset;
fwrite($file , $content); //Now lets write it in there
fclose($file ); //Finally close our .txt
die(header("Location: ".$_SERVER["HTTP_REFERER"]));
?>
if(isset($_POST['field1']) && isset($_POST['field2'])) {
$data = $_POST['field1'] . '-' . $_POST['field2'] . "\n";
$ret = file_put_contents('/tmp/mydata.txt', $data, FILE_APPEND | LOCK_EX);
if($ret === false) {
die("There was an error writing this file");
}
else {
echo "$ret bytes written to file";
}}
Why when i try to export MySql table to CSV with header('Content-Disposition:attachment; filename="'.$filename.'"'); It doesn't get done properly:
it does create the CSV file
however it does it on the beginning of the file, where the page code is
and after the code the is table content
This is the code witch exports it:
$this->view->table = $model->info('name');
$is_csv = $this->_getParam('csv');
if ($this->_request->isPost() && $is_csv) {
$fichier = 'file.csv';
header('Content-type: text/plain');
header('Content-Disposition: attachment; filename="'.$fichier.'"');
$fp = fopen('php://output', 'w+');
$data = $model->fetchAll();
foreach ($data as $fields) {
fputcsv($fp, $fields->toArray());
}
fclose($fp);
}
And here i'm calling this with button:
<form method="post">
<input type="hidden" name="table" value="<?php echo $this->table ?>" />
<button type="submit" class="btn" name="csv" value="csv">
<?php echo Core_Locale::translate('CSV')?>
</button>
</form>
put this code up in your application then application create view.
I had same issue but i solved it this way..
i put peace of code to function/block and place it over echo or render html
put exit; on the end of function/block
if(isset($_POST['submit'])) {
$csv = new Csv();
$filename = $csv->generateFileDate();
if($filename !== false) {
$data = file_get_contents($csv->folder .'reports/'. $filename);
header('Content-Type: application/csv; charset=utf-8');
header('Content-Disposition: attachement;filename="'.$filename.'";');
echo $data;
exit;
}
}
?>
<!doctype html>
<html lang="us">
<head> .........
hope this help to you
Ok here is what I have going on.
I am listing the contest of a directory so I can edit and delete files.
The code I am using to do that is below (Other then editing as it does not work).
<?php
$directory = ("enctlfiles/");
$dir = opendir($directory);
$files = array();
while (($file = readdir($dir)) != false) {
$files[] = $file;
}
closedir($dir);
sort($files);
print("<TABLE border=1 cellpadding=5 cellspacing=0 class=whitelinks>\n");
print("<TR><TH>File Name</TH><th>Modified Date</th><th>Entries In File</th><th>Delete | Edit</th></TR>\n");
foreach ($files as $file)
{
if (strpos($file, '.jpg',1)||strpos($file, '.ctl',1) ){
echo "<TR><TD><a href=$directory$file>$file</a></td>";
echo "<td>";
echo date("F d Y H:i:s",filemtime($directory. $file));
echo "<td>";
echo count(file($directory. $file));
echo "<td>";
echo "<a href=enctlfiles/dodelete.php?file=$file>Delete</a> | <a href=enctlfiles/editfile.php?file=$file>Edit</a>";
}
}
?>
That lists all of the files in order in a nice pretty table. The delete function works. The edit one not so much . It is due to me not knowing what I am doing I am sure of it.
Here is the contents of the editfile.php
<form action="edit.php" method="post">
<TEXTAREA NAME="save" COLS=150 ROWS=50 wrap="off">
<?php
$dir = ".";
include($dir. '/' .$_GET['file']);
?>
</textarea>
<P><INPUT TYPE="SUBMIT" VALUE="Update File"><INPUT TYPE="RESET">
</FORM>
That populates the textarea with the file contents when you click on the "Edit" link. I don't know if that is the right way to get the data in there to be able to edit the file.
Here is the contents of the edit.php file:
<?php
//I have tried this but it give me that Unable to open file.
//$org = ($_GET['file']) or exit("Unable to open file!");
//This returns me to the prodsh.php page but does not edit the file.
$org = $_POST['save'] or exit("Unable to open file!");
$copy = $org . date("-m-d-Y-His");
copy($org,$copy);
$f = fopen($org, 'w');
fwrite($f, $_POST['save']);
fclose($f);
header('Location: http://somesite.com/GroveTuckey/itemsetup/prodsh.php');
?>
I think the editfile.php and the edit.php file are jacked up but don't know where.
I am trying to learn this and this site has been very helpful when I get stumped on something so I thank you in advance for the help given.
Also I know the danger of editing files via a webpage. This is not public or on a server that is accessible by the world. Right now I don't want to deal with a database.
I have edited files using the below code:
<form action="doedit.php" method="post">
<TEXTAREA NAME="save" COLS=150 ROWS=50 wrap="off">
<?php
include('somefile.ctl');
?>
</textarea>
<P><INPUT TYPE="SUBMIT" VALUE="Update File"><INPUT TYPE="RESET">
</FORM>
With the contents of doedit.php being:
<?php
$org = 'Somefile.ctl';// This is the name of the file in the form above
$copy = $org . date("-m-d-Y-His");
copy($org,$copy);
$f = fopen('somefile.ctl', 'w');//This is the name of said file also.
fwrite($f, $_POST['save']);
fclose($f);
header('Location: http://somesite.com/GroveTickey/editfile.php');
?>
But since the names of the files can be anything I can't put specific names in the script.
This works great other then having to hardcode file names.
You aren't passing the name of the file back to edit.php. Set the form's action to edit.php?file=<?php echo $_GET['file']; ?>.
El codigo para editar lo hice asi:
---Inicio
<? php
$filename = isset($_GET['file']) ? $_GET['file'] : '';
$directory = ("C:\\Linux\\www\\contenido\\"); // Restrict to this directory...
$fn = $directory . $filename;
if (isset($_POST['content']))
{
$content = stripslashes($_POST['content']);
$fp = fopen($fn,"w") or die ("Error opening file in write mode!");
fputs($fp,$content);
fclose($fp) or die ("Error closing file!");
}
?>
<form action="<?php echo $_SERVER["PHP_SELF"] ?>" method="post">
<textarea rows="25" cols="100" name="content"><?php readfile($fn); ?></textarea>
<hr />
<input type="submit" value="Guardar">
</form>
back to list
And work great