Search a number in string formatted array in PHP? - php

Question

My array looks like this:
array( '0|500|0.50', '501|1000|0.75' );
I am trying to run a search to get the KEY which has the searched value.
I made this function to search:
function cu_array_search($str,$array){
foreach($array as $key => $value) {
if(strstr($str,$value)) {
return true;
} else {
return false;
}
}
}
and using it like this when checking:
if (cu_array_search(500,$array) {
but it never return true, despite that 500 exists in first key in array .
How to resolve this?
Thanks

Answer 1

strpos will make you function return true even that's 0.5001 but not 500.
You should explode the value by |, then check whether the number in the array.
function cu_array_search($num, $array){
return count(array_filter($array, function ($var) use ($num) {
return in_array($num, explode('|', $var));
})) > 0;
}

Answer 2

The haystack is the first argument, not the second:
if(strstr($value,$str)) {
Additionally, strpos is faster at this, so you should use:
function cu_array_search($str,$array){
foreach($array as $key => $value) {
if(strpos($value,$str) !== false) {
return $key;
} else {
return false;
}
}
}

Answer 3

First, strstr parameters are wrong
Second, return false should be at the end of the loop.
Third, If you need KEY then You need to use return $key instead of return true
function cu_array_search($str,$array){
foreach($array as $key => $value) {
if(strstr($value, $str)) {
return $key;
}
}
return false;
}

Answer 4

This works fine
<?php
function cu_array_search($str, $array) {
foreach($array as $key => $value) {
$temp_array=explode('|', $value);
if (in_array($str, $temp_array))
return true;
}
return false;
}
$array = array( '0|500|0.50', '501|1000|0.75' );
if (cu_array_search(500, $array))
echo "success";
else
echo "failed" ;
?>