Rekognition Facial Recognition parsing JSON with PHP [duplicate] - php

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Parse Json in php
Im using an API to CURL a submitted user image to a remote server, the response is in JSON and I'm not sure how to parse it.
Here is my php CURL file
<?php
$api_key = 'xxxxxx';
$api_secret = 'xxxxx';
$Dirty_uid = $_GET['uid'];
$uid = htmlentities($Dirty_uid);
$Dirty_img = $_GET['img'];
$img = htmlentities($Dirty_img);
$query2 = 'http://rekognition.com/func/api/?api_key='.$api_key.'&api_secret='.$api_secret.'&jobs=face_recognize&urls='.$img.'&name_space=xxx&user_id=xxx';
$ch2 = curl_init();
curl_setopt($ch2, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch2, CURLOPT_URL, $query2); // get the url contents
$data2 = curl_exec($ch2); // execute curl request
curl_close($ch2);
$json2 = json_decode($data2);
print_r($json2)
?>
and here is a sample of the JSON data that comes back (Generic)
Code:
{
url: "http://farm3.static.flickr.com/2566/3896283279_0209be7a67.jpg",
face_detection: [
{
boundingbox:
{
tl: {
x: 50,
y: 118
},
size:{
width:232;
height:232;
}
}
name: "mona_lisa:0.92,barack_obama:0.02,mark_zuckerberg:0.01,"
}
]
usage: {
status: "success",
quota: 999,
api_id: "xxx"
}
}
Where the json string says "name" I need my script to only print the username if the number (after the : is higher then a threshold (lets say .70 for now).
How do I do this? I've worked with XML api's before and returning the data was simple with a
Code:
$xml = simplexml_load_string($data);
type thing.

You already have most of it. You have json_decodeed the result. Now you just need to access the data like
$name = $json2->face_detection[0]->name

Related

JSON: Update base64 string using url JSON

I'm new to JSON Code. I want to learn about the update function. Currently, I successfully can update data to the database. Below is the code.
<?php
require_once "../config/configPDO.php";
$photo_after = 'kk haha';
$report_id = 1;
$url = "http://172.20.0.45/TGWebService/TGWebService.asmx/ot_maintainReport?taskname=&reportStatus=&photoBefore=&photoAfter=". urlencode($photo_after) . "&reportID=$report_id";
$data = file_get_contents($url);
$json = json_decode($data);
$query = $json->otReportList;
if($query){
echo "Data Save!";
}else{
echo "Error!! Not Saved";
}
?>
the problem is, if the value of $photo_after is base64 string, which is too large string, it will give the error:
1) PHP Warning: file_get_contents.....
2) PHP Notice: Trying to get property 'otReportList' of non-object in C:
BUT
when I change the code to this,
<?php
require_once "../config/configPDO.php";
$photo_after = 'mama kk';
$report_id = 1;
$sql = "UPDATE ot_report SET photo_after ='$photo_after', time_photo_after = GETDATE(), ot_end = '20:30:00' WHERE report_id = '$report_id'";
$query = $conn->prepare($sql);
$query->execute();
if($query){
echo "Data Save!";
}else{
echo "Error!! Not Saved";
}
?>
The data will updated including when the value of $photo_after is in base 64 string.
Can I know what is the problem? Any solution to allow the base64 string update thru json link?
Thanks
// ...
// It's likely that the following line failed
$data = file_get_contents($url);
// ...
If the length of $url is more than 2048 bytes, that could cause file_get_contents($url) to fail. See What is the maximum length of a URL in different browsers?.
Consequent to such failure, you end up with a value of $json which is not an object. Ultimately, the property otReportList would not exist in $json hence the error: ...trying to get property 'otReportList' of non-object in C....
To surmount the URL length limitation, it would be best to embed the value of $photo_after in the request body. As requests made with GET method should not have a body, using POST method would be appropriate.
Below is a conceptual adjustment of your code to send the data with a POST method:
<?php
require_once "../config/configPDO.php";
# You must adapt backend behind this URL to be able to service the
# POST request
$url = "http://172.20.0.45/TGWebService/TGWebService.asmx/ot_maintainReport";
$report_id = 1;
$photo_after = 'very-long-base64-encoding-of-an-image';
$request_content = <<<CONTENT
{
"taskname": $taskname,
"report_id": $report_id,
"photoBefore": $photoBefore,
"photo_after": $photo_after,
"reportStatus": $reportStatus
}
CONTENT;
$request_content_length = strlen($request_content);
# Depending on your server configuration, you may need to set
# $request_headers as an associative array instead of a string.
$request_headers = <<<HEADERS
Content-type: application/json
Content-Length: $request_content_length
HEADERS;
$request_options = array(
'http' => array(
'method' => "POST",
'header' => $request_headers,
'content' => $request_content
)
);
$request_context = stream_context_create($request_options);
$data = file_get_contents($url, false, $request_context);
# The request may fail for whatever reason, you should handle that case.
if (!$data) {
throw new Exception('Request failed, data is invalid');
}
$json = json_decode($data);
$query = $json->otReportList;
if ($query) {
echo "Data Save!";
} else {
echo "Error!! Not Saved";
}
?>
sending a long GET URL is not a good practice. You need to use POST method with cURL. And your webservice should receive the data using post method.
Here's example sending post using PHP:
//
// A very simple PHP example that sends a HTTP POST to a remote site
//
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"http://www.example.com/tester.phtml");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS,
"postvar1=value1&postvar2=value2&postvar3=value3");
// In real life you should use something like:
// curl_setopt($ch, CURLOPT_POSTFIELDS,
// http_build_query(array('postvar1' => 'value1')));
// Receive server response ...
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$server_output = curl_exec($ch);
curl_close ($ch);
// Further processing ...
if ($server_output == "OK") { ... } else { ... }
Sample code from: PHP + curl, HTTP POST sample code?
And all output from the webservice will put in the curl_exec() method and from there you can decode the replied json string.

Getting a specific value from an array

I'm trying to get a specific column from an array for each record returned.
The array is called fields and one of the arrays in the array is locations. I'm looking for a specific column in the array called name.
Here's what I have:
foreach ($new_results as $result):?>
$locations = array_map($result->locations->location,function($obj) { return $obj->location; });
echo implode(",",$locations);
endforeach;
I'm connecting to a web service to pull this data. The above is the code that the company gave me, but they haven't tested it as far as I know. It doesn't work for me.
Here's the call to the API
$results = $connection->call('groups/getAll', $params=array("suspended" => "no","fields" =>"locations"));
$new_results = $results->groups->group;
Here's an example from the API.
{
"id": "xxxx",
"fields": {
"locations": [
"North",
"Central"
]
}
}
Any thoughts on what I'm doing wrong? I'm still very new to PHP so I may be missing something very obvious.
How to get json using curl:
How to get JSON data from Rest API by PHP Curl?
Now with that in mind you can dive a little deeper into the object manipulation in terms of the response here: Accessing JSON object elements in PHP.
//""" code from the first link
$service_url = "http://127.0.0.1:8000/api/thesis/?format=json";
$curl = curl_init($service_url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, 0);
//execute the session
$curl_response = curl_exec($curl);
//finish off the session
curl_close($curl);
$curl_jason = json_decode($curl_response, true);
print_r($curl_jason);
//""" code from the first link
&
//""" code from the second link
/*Variable passed in from the ExtJS interface as JSON object*/
$json = $_POST["newUserInfo"];
//$json = '{"USER":{"ID":"","FULL_USER_NAME":"Some Guy","ENTERPRISE_USER_NAME":"guyso01","USER_EMAIL":"Some.Guy#Email.com","USER_PHONE":"123-456-7890"},"PERMISSIONS":{"ID":"","USER_ID":"","IS_ADMIN":"true"},"SETTINGS":{"ID":"","USERS_ID":"","BACKGROUND":"default"}}';
//Test to view the decoded output
//var_dump(json_decode($json));
//Decode the $json variable
$jsonDecoded = json_decode($json,true);
//Create arrays for each table from the $jsonDecoded object
$user_info = array($jsonDecoded['USER']);
$permissions_info = array($jsonDecoded['PERMISSIONS']);
$settings_info = array($jsonDecoded['SETTINGS']);
// """ code from the first link

Record the result of a curl GET request using php & mysql

I'm trying to understand how to record the result of a curl GET request using php. I'm looking at outputing part or all of the result to mysql.
https://github.com/cloudtrax/docs/blob/master/api/code/php/simple_api_server_test_harness.php
function invoke_curl($method, $endpoint, $headers, $json) {
$api_server = 'https://api.cloudtrax.com';
try {
// get a curl handle then go to town on it
$ch = curl_init($api_server . $endpoint);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($ch);
if ($result == FALSE) {
if (curl_errno($ch) == 0)
echo "#### NOTE ####: nil HTTP return: This API call appears to be broken" . "\n";
else
throw new Exception(curl_error($ch), curl_errno($ch));
}
else
echo "RESULT: \n" . $result . "\n";
}
The $result shows like this:
{
"clients": {
"ssid2": 4,
"ssid1": 10
},
"rows": [
{
"time": "2016-03-23T02:45:00Z",
"ssid2": {
"traffic": {
"unclassified": {
// etc...
How can I associate each part of the result too a variable so I can then input too mysql?
It looks like this result in json format. You can use json_decode to decode it:
$resultObject = json_decode($result);
$clients = $resultObject->clients;
// ... get other data from result
The code below will convert the json into a PHP array. You can then use the indexes of the array to pull out values.
$result = json_decode($result);
$clients = $result->clients;
// Some MySQL queries
If your response is a JSON response then you can simply use php's json_decode to get parsed object.
$result = curl_exec($ch);
//to get associative array passing true
$jsonObj = json_decode($result, true);
$clients = $jsonObj['clients'];
$rows = $jsonObj['rows'];
You can refer to these answers for more detail:
Parsing JSON object in PHP using json_decode and
Parsing JSON file with PHP

Change Output of PHP Script to use POST Method

Bear with my inexperience here, but can anyone point me in the right direction for how I can change the PHP script below to output each variable that is parsed from the XML file (title, link, description, etc) as a POST method instead of just to an HTML page?
<?php
$html = "";
$url = "http://api.brightcove.com/services/library?command=search_videos&any=tag:SMGV&output=mrss&media_delivery=http&sort_by=CREATION_DATE:DESC&token= // this is where the API token goes";
$xml = simplexml_load_file($url);
$namespaces = $xml->getNamespaces(true); // get namespaces
for($i = 0; $i < 80; $i++){
$title = $xml->channel->item[$i]->video;
$link = $xml->channel->item[$i]->link;
$title = $xml->channel->item[$i]->title;
$pubDate = $xml->channel->item[$i]->pubDate;
$description = $xml->channel->item[$i]->description;
$titleid = $xml->channel->item[$i]->children($namespaces['bc'])->titleid;
$html .= "<h3>$title</h3>$description<p>$pubDate<p>$link<p>Video ID: $titleid<p>
<iframe width='480' height='270' src='http://link.brightcove.com/services/player/bcpid3742068445001?bckey=AQ~~,AAAABvaL8JE~,ufBHq_I6FnyLyOQ_A4z2-khuauywyA6P&bctid=$titleid&autoStart=false' frameborder='0'></iframe><hr/>";/* this embed code is from the youtube iframe embed code format but is actually using the embedded Ooyala player embedded on the Campus Insiders page. I replaced any specific guid (aka video ID) numbers with the "$guid" variable while keeping the Campus Insider Ooyala publisher ID, "eb3......fad" */
}
echo $html;
?>
#V.Radev Here's another PHP script using cURL that I think will work with the API I'm trying to send data to:
<?PHP
$url = 'http://api.brightcove.com/services/post';
//open connection
$ch = curl_init($url);
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS, '$title,$descripton,$url' . stripslashes($_POST['$title,$description,$url']));
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);
// Enable for Charles debugging
//curl_setopt($ch,CURLOPT_PROXY, '127.0.0.1:8888');
$result = curl_exec($ch);
curl_close($ch);
print $result;
?>
My question is, how can I pass the variables from my feed parsing script (title, description, URL) to this new script?
I have this code from Brightcove, can I just output the variables from my parser script and send to this PHP script so that the data goes to the API?
<?php
// This code example uses the PHP Media API wrapper
// For the PHP Media API wrapper, visit http://docs.brightcove.com/en/video-cloud/open-source/index.html
// Include the BCMAPI Wrapper
require('bc-mapi.php');
// Instantiate the class, passing it our Brightcove API tokens (read, then write)
$bc = new BCMAPI(
'[[READ_TOKEN]]',
'[[WRITE_TOKEN]]'
);
// Create an array of meta data from our form fields
$metaData = array(
'name' => $_POST['bcVideoName'],
'shortDescription' => $_POST['bcShortDescription']
);
// Move the file out of 'tmp', or rename
rename($_FILES['videoFile']['tmp_name'], '/tmp/' . $_FILES['videoFile']['name']);
$file = '/tmp/' . $_FILES['videoFile']['name'];
// Create a try/catch
try {
// Upload the video and save the video ID
$id = $bc->createMedia('video', $file, $metaData);
echo 'New video id: ';
echo $id;
} catch(Exception $error) {
// Handle our error
echo $error;
die();
}
?>
Post is a request method to access a specific page or resource. With echo you are sending data which means that you are responding. In this page you can only add response headers and access it with a request method such as post, get, put etc.
Edit for API request as mentiond in the comments:
$curl = curl_init('your api url');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $your_data_to_send);
$result_from_api = curl_exec($curl);
curl_close($curl);

Getting JSON Object by calling a URL with parameters in PHP

I'm trying to get json data by calling moodle url:
https://<moodledomain>/login/token.php?username=test1&password=Test1&service=moodle_mobile_app
the response format of moodle system is like this:
{"token":"a2063623aa3244a19101e28644ad3004"}
The result I tried to process with PHP:
if ( isset($_POST['username']) && isset($_POST['password']) ){
// test1 Test1
// request for a 'token' via moodle url
$json_url = "https://<moodledomain>/login/token.php?username=".$_POST['username']."&password=".$_POST['password']."&service=moodle_mobile_app";
$obj = json_decode($json_url);
print $obj->{'token'}; // should print the value of 'token'
} else {
echo "Username or Password was wrong, please try again!";
}
Result is: undefined
Now the question:
How can I process the json response format of moodle system? Any idea would be great.
[UPDATE]:
I have used another approach via curl and changed in php.ini following lines: *extension=php_openssl.dll*, *allow_url_include = On*, but now there is an error: Notice: Trying to get property of non-object. Here is the updated code:
function curl($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$moodle = "https://<moodledomain>/moodle/login/token.php?username=".$_POST['username']."&password=".$_POST['password']."&service=moodle_mobile_app";
$result = curl($moodle);
echo $result->{"token"}; // print the value of 'token'
Can anyone advise me?
json_decode() expects a string, not a URL. You're trying to decode that url (and json_decode() will NOT do an http request to fetch the url's contents for you).
You have to fetch the json data yourself:
$json = file_get_contents('http://...'); // this WILL do an http request for you
$data = json_decode($json);
echo $data->{'token'};

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