How to use $_Get to store its values in a database? - php
I want to display all users that a "super" user is responsible for. Then the "super" user can send a comment to any of the users by clicking on their user id.
The first part of showing all the users is working fine! My problem is in sending a comment by the super user. I want to store the user id (ie suid) in the database. So I think to use the $_Get function. But when I tried it, nothing stores in the database. I think I made a mistake in it. So can anyone help me on that?
This is the code that will show all users to the super user:
<?php
session_start();?>
<?php
require("noCache.php");
$uid=$_SESSION['uid'];
?>
<html>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Send a comment</title>
<meta charset="utf-8">
<link rel="stylesheet" href="css/reset.css" type="text/css" media="all">
<link rel="stylesheet" href="css/layout.css" type="text/css" media="all">
<link rel="stylesheet" href="css/style.css" type="text/css" media="all">
<script type="text/javascript" src="js/jquery-1.4.2.js" ></script>
<script type="text/javascript" src="js/cufon-yui.js"></script>
<script type="text/javascript" src="js/cufon-replace.js"></script>
<script type="text/javascript" src="js/Myriad_Pro_400.font.js"></script>
<script type="text/javascript" src="js/Myriad_Pro_700.font.js"></script>
<script type="text/javascript" src="js/Myriad_Pro_600.font.js"></script>
</head>
<body>
<div class="main">
<header>
<div class="wrapper">
<h1> Biz</h1>
</div>
<nav>
<ul id="menu">
<li class="alpha"><span><span>Home</span></span></li>
<li><span><span>About</span></span> </li>
<li><span><span>Projects</span></span></li>
<li><span><span>Contacts</span></span></li>
<li class="omega"><span><span>Services</span></span></li>
</ul>
</nav>
</br></br>
</header>
<head>
<!-- CSS Stylesheet -->
<style type="text/css">
html{
}
body{
text-align:center;
}
</style>
</head>
<?php
$dbh=mysql_connect("localhost", "root", "hahaha1") or die (mysql_error());
mysql_select_db ("senior");
$result = mysql_query("SELECT * FROM sensorusers where uid=$uid");
echo "<html><body>";
echo "<table cellspacing=10 cellpadding=5 ><tr> <th>ID</th><th>Name</th><th>Username</th><th>Password</th><th>Date of Registeration</th><th>Phone</th></tr>";
while ($row = mysql_fetch_array($result))
{ echo "<form method='post' action='sendcomment.php'>";
echo "<tr><td><input type='submit' name='suid' value='".$row['suid']."' /></td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['dusername'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['phone'] . "</td></tr></form>";
$_GET['suid'] = $row['suid'];
}
echo "</table></body></html>";
mysql_close($dbh);
?>
<html>
<body>
<!-- CSS Stylesheet -->
<style type="text/css">
body {
font-family:"Andalus"
font: 16px ;
color:black;
padding: 30px 5px;
text-align: center;
}
</style></body></html>
Here is the part that I want to ask about:
echo "<table cellspacing=10 cellpadding=5 ><tr> <th>ID</th><th>Name</th><th>Username</th><th>Password</th><th>Date of Registeration</th><th>Phone</th></tr>";
while ($row = mysql_fetch_array($result))
{ echo "<form method='post' action='sendcomment.php'>";
echo "<tr><td><input type='submit' name='suid' value='".$row['suid']."' /></td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['dusername'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['phone'] . "</td></tr></form>";
$_GET['suid'] = $row['suid'];
}
Solution:
Thank you all for helping. I fixed the code. I used method post to save the value of suid the first time. Then I print it as a hidden input. Finally I save the value of the hidden input in the sql and it works!
you have POST I DONT SEE GETin your code , and its depend on your html inputs (u didnt post them)if u make method GET or POST.
if your method is GET then you use GET
but try use this
if(isset($_POST['submit'])){
instead of
if($submit){
EDIT .
you are using method='post'
then you must use POST not GET
EDIT2:
you have an error in your sql , you used VALUE and it should be VALUES
instead of this
$place="INSERT INTO comments VALUE
replace it by
$place="INSERT INTO comments (columns here ,..., ,..) VALUES
How to use $_GET:
Put the data in the URL like so:
sendcomment.php?suid=blahblahblah
Then you can use $_GET, like so:
$suid = $_GET['suid']
Currently your code uses POST to send suid
Or change your form method.
echo "<form method='post' action='sendcomment.php?suid=".$row['suid']."'>";
There are multiple issues in your code. I will try to list the biggest ones, but may still miss some.
Code 1 -
Issue 1-
You have multiple <html></html>,<head></head>, and <body></body> blocks.
<html>
...
<head>
...
</head>
<body>
...
<head>
...
</head>
...
echo "<html><body>";
...
echo "...</body></html>";
...
<html>
<body>
...
</body>
</html>
Issue 2-
Your <form> is around a <td> block, which is invalid, so it will not POST properly. It either needs to be around the table <form><table></table></form>, or inside a cell <td><form></form></td>.
echo "<table cellspacing=10 cellpadding=5 ><tr> <th>ID</th><th>Name</th><th>Username</th><th>Password</th><th>Date of Registeration</th><th>Phone</th></tr>";
while ($row = mysql_fetch_array($result))
{ echo "<form method='post' action='sendcomment.php'>";
echo "<tr><td><input type='submit' name='suid' value='".$row['suid']."' /></td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['dusername'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['phone'] . "</td></tr></form>";
$_GET['suid'] = $row['suid'];
}
echo "</table></body></html>";
Issue 3-
You are misusing $_GET and it is outside your <form></form> tags. $_GET is used to get value from the url.
$_GET['suid'] = $row['suid'];
Code 2-
Issue 1-
You are setting $id1=$_GET["suid"];, but in your form in Code #1, you are using method="post".
$id1=$_GET["suid"];
Issue 2-
When you are posting from Code #1 to Code #2 (<form><input type='submit' name='suid' value='".$row['suid']."' /></form>), you are only sending name='suid', so all your $_GET & $_POST vars will not be set to be used in the INSERT-
$id1=$_GET["suid"];
...
$name=$_POST['sent_by'];
$id=$_POST['hidden_id'];
$id2=$_POST['hidden_id2'];
$message=$_POST['message'];
$submit= $_POST['submit'];
...
Issue 3-
You have errors in you query. It should be VALUES, not VALUE, you should include the columns before `INSERT INTO comments (id,name,message,receiver,sender,date,time) VALUES ('','$name','$message','$id','$id1','$date','$time')
$place="INSERT INTO comments VALUE('','$name','$message','$id','$id1','$date','$time')";
$run = mysql_query("$place");
Issue 4-
All your value= in your form is missing the quotes '' around the values.
<form action="sendcomment.php" method="post">
<input type ='hidden' name='hidden_id' value = <?php print $uid; ?> >
<input type ='hidden' name='hidden_id2' value = <?php print $id1; ?> >
Name : <input type ='name' name='sent_by' value = <?php print $username; ?>></br>
Message: <textarea name='message'></textarea></br>
<input type='submit' value='submit' name="submit" /></br>
</form>
I know that you have accepted an answer, but you have a lot of code issues to still address. Each of these will cause you issues with your form and inserting into your database. Plus they will cause you more issues.
Just simply this
$id1=$_GET["suid"];
replace with
$id1=$_POST["suid"];
When using $_GET varible shuld be in the url.
When using $_POST variable isn't shown in url
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echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['fire'] . "</td>";
echo "<td>" . $row['level'] . "</td>";
echo "<td>" . $row['desc'] . "</td>";
echo "<td>" . $row['addy'] . "</td>";
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<head>
<style type="css/text">
body{overflow-y:hidden;
white-space-collapse:collapse;}
body{background-color:black}
body{font-family:'trebuchet ms' }
.body{font-family:'trebuchet ms' }
.hide{visibility:collapse; }
#hide{visibility:collapse; }
.nopad{padding-bottom:0px; margin-bottom:0px; }
.borders{ }
</style>
</head>
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<form action="detailentry.php" method="POST" style="white-space-collapse:collapse;">
<font color="white">
<table border="0" class="borders">
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<td><font color="white"><input type="text" maxlength="11" value="<?php echo $id2;?>" required name="inci_num">  RM911 ID:</font></td>
<td><center><font color="white"><? echo strtoupper($_COOKIE['username']);?></font></center></td>
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<td colspan="2"><textarea placeholder="Enter Incident Notes here" required rows="4" cols="36" name="notes"></textarea></td>
</tr><input id="hide" style="visibility:collapse;" class="hide" hidden type="checkbox" name="auto" value="auto" checked>
<tr class="nopad">
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**Note: I know I should be using the new syntax, one thing at a time please. Also, I realize that the code be made nicer and easier to read. Again, that's secondary to fixing this problem.
This is what I am trying to accomplish:
I need to take the $id2 variable from the incidents.php page and simultaneously transfer it to both details.php and detailentry.php when the user clicks on the incident number on incidents.php. On detailentry.php, $id2 needs to be in the Inc #: text input box.
Thank you for your help in advance!!!
hmm. An 8 year old question nobody answered. and 2 "answers" that were just dismissive comments. Here's a real answer: You can pass the data between frames by making a session variable. Session variables are accessible between frames. https://www.php.net/manual/en/reserved.variables.session.php has full info. I see you have session_start() in two of your 3 php files. Add it to the top of the third one. Then assign a session variable with whatever value you want to pass to another frame: $_SESSION['vartopass']=$varyouwanttopass; now $_SESSION['vartopass'] is available in your other frames that start with session_start(). $variwantedinthisframe=$_SESSION['vartopass']; So, yeah, 8 years late. You probably figured this out by now, but someone else hasn't, and I hate dismissive statements that don't help anyone.