How do I select MySQL Data that are from next year - php

I am working on a file management project, where I have expiry dates for every file. I need to list all the files that are going to expire the next year. What will be the SQL query?
should it be something like:
$date = date ('Y-m-j');
$newdate = strtotime ( '+1 year' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
$sql = "SELECT * FROM `files` WHERE `expDate` = year ($newdate)" ;

Try:
$sql = "SELECT * FROM `files` WHERE YEAR(`expDate`) = YEAR(NOW()) + 1" ;

If the expDate is in mysql timestamp(yyyy-mm-dd hh:mm:ss) , you can use this
DATE_ADD(`expDate`, INTERVAL 1 YEAR)

Try this
$newdate = date ( 'Y-m-j' , strtotime('+1 year') );
$sql = "SELECT * FROM `files` WHERE `expDate` = year ($newdate)" ;
or
$sql = "SELECT * FROM `files` WHERE `expDate` = YEAR(NOW())+1;

you can use mysql DATE_ADD to add years
$sql = "SELECT * FROM `files` WHERE `expDate` = YEAR(DATE_ADD($date, INTERVAL 1 YEAR))";

Related

Search data between two dates in dd/mm/yyyy hh:mm:ss in sql

I want to fetch all records between two dates from database in php. Date format is dd/mm/yyyy hh:mm:ss. example 06/Dec/2016 05:56:15
I'm using following code
$Sdate=date_create($_GET['sdate']);
$start=date_format($Sdate,"d/M/Y H:i:s");
$Edate=date_create($_GET['edate']);
$end=date_format($Edate,"d/M/Y H:i:s");
$sql = "SELECT * FROM `payments` WHERE `customerid` = '".$_SESSION['id']."' AND dateandtime BETWEEN ('".$start."', '".$end."') ORDER BY id DESC";
But this is not working
Thank You in advance for helping me
Try this:
$Sdate = date('Y-m-d H:i:s', strtotime($_GET['sdate']);
$Edate = date('Y-m-d H:i:s', strtotime($_GET['edate']);
$sql = "SELECT * FROM `payments`
WHERE `customerid` = '".$_SESSION['id']."'
AND dateandtime BETWEEN '$Sdate' AND '$Edate'
ORDER BY id DESC";
The correct syntax is:
dateField BETWEEN dateFieldLow AND dateFieldHigh

filter date from timestamp field in mysql

I have saved rows in my table with custom timezone.Now I want to retrieve data from those table for just today.
So here is what I tried
date_default_timezone_set('America/Los_Angeles');
$dt = new DateTime();
$today = $dt->format('Y-m-d'); //outputs 2015-12-07
$ok = mysqli_query($sqli,"SELECT * FROM `table` WHERE `date` = '$today'" );
And my row contains date in timestamp format like 2015-12-07 22:42:02
But I get empty result.
Try this:
$ok = mysqli_query($sqli,"SELECT * FROM `table` WHERE DATE(date) = CURDATE()" );
to convert time according to timezone: ConvertTimeZone
if $today='2015-12-07 22:42:02'; your query will give the result.
$today='2015-12-07 22:42:02';
$ok = mysqli_query($sqli,"SELECT * FROM `table` WHERE `date` = '$today'" );
else do pass the today date and next date and retrieve the value as given
$today='2015-12-07';
$next='2015-12-08';
$ok = mysqli_query($sqli,"SELECT * FROM `table` WHERE `date` >= '$today' and `date` <= '$next' " );
for more details refer this Oracle SQL : timestamps in where clause How to compare Timestamp in where clause
You should convert date to timestamp before passing it to mysql:
date_default_timezone_set('America/Los_Angeles');
$dt = new DateTime();
$today = $dt->format('Y-m-d'); //outputs 2015-12-07
$ok = outputs("SELECT * FROM `table` WHERE DATE_FORMAT(date,'%Y-%m-%d')= $today" );

select date that is less or equal to current date

I am trying to select the date in the field end_date that is less or equal to current date but did not work and my field end_date as the same date format(08-09-2014) data as current date below is my code thanks
$currentdate = date("d-m-Y");
$query1 = "SELECT * FROM location WHERE end_date <= '$currentdate'";
$result1 = mysql_query ($query1) or die('query error');
while( $line1 = mysql_fetch_assoc($result1)){
echo $line1['end_date'];
}
try this
SELECT * FROM location WHERE end_date <= DATE_FORMAT(CURDATE(), '%Y-%m-%d')
try with -
SELECT * FROM location WHERE end_date <= DATE_FORMAT(CURDATE(), '%d-%m-%Y')
$currentdate = date("Y-m-d");
$query1 = "SELECT * FROM location WHERE `end_date` <= '$currentdate'";
$result1 = mysql_query ($query1) or die('query error');
while( $line1 = mysql_fetch_assoc($result1)){
echo $line1['end_date'];
}
try this... must have in database date format;;
If your currentdate is independent of the system date (e.g. if you are operating over different timezones), and if, for some reason, your end_date is not a date type, then try this:
SELECT * FROM location
WHERE str_to_date(end_date, '%d-%m-%Y') <= str_to_date('$currentdate', '%d-%m-%Y')
where the format can be changed to match your inputs.
If you want to compare dates, then make sure you are comparing dates and not strings.

mysql check if uid record exist for today based on timestamp else do an insert

Im trying to do a mysql check if a record from $uid exist from today based on $timestamp and if it doesnt then do an INSERT.
//EXAMPLE RECORD FROM TABLE VOTE
--- #vote_fb_uid# --- #vote_time#
665414807 1369219044
tjt
//STEP 1 - do a look up on $uid and check with timestamp $today
$timestamp = $this->time;
$date = date('Y-m-d', $timestamp);
$today = date('Y-m-d');
$sql = "
SELECT * FROM vote WHERE
vote_fb_uid = '$this->fb_uid',
WHERE vote_time = '$CHECK_IF_THERE_IS_AN_ENTRY_FROM_TODAY'";
$res = mysql_query($sql) or die( mysql_error());
//STEP 2 - If no records are found for today - then we do an INSERT
if($no_record_for_today) {
$sql = sprintf("
INSERT INTO vote(
vote_fb_uid,
vote_time)
VALUES ('%s','%s')",
mysql_real_escape_string($this->fb_uid),
mysql_real_escape_string($this->time));
$res = mysql_query($sql) or die( mysql_error());
}
Obviously im strugling with the SQL part for the look up - im wondering if there isnt some in-built SQL function to do this or similar?
to check if you had a vote in the last 24 hours :
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid'
AND FROM_UNIXTIME(vote_time) >= DATE_SUB(NOW(), INTERVAL 1 DAY)
if you want to limit to the same day (mean you are allowed to post at 2013.05.21 23:55 and 2013.05.22 00:05)
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid'
AND DATE(FROM_UNIXTIME(vote_time)) = DATE(NOW())
CURDATE()
Returns the current date as a value in 'YYYY-MM-DD' or YYYYMMDD format, depending on whether the function is used in a string or numeric context.
mysql> SELECT CURDATE();
-> '2008-06-13'
mysql> SELECT CURDATE() + 0;
-> 20080613
Try this:
$today = date('Y-m-d'); //change it to timestamp if you want in timestamp
$sql = "
SELECT count(*) as total FROM vote WHERE
vote_fb_uid = '$this->fb_uid' and
vote_time = '$today'";
$res = mysql_query($sql) or die( mysql_error());
if($res[0]['total'] < 1){
$sql = sprintf("
INSERT INTO vote(
vote_fb_uid,
vote_time)
VALUES ('%s','%s')",
mysql_real_escape_string($this->fb_uid),
mysql_real_escape_string($this->time));
$res = mysql_query($sql) or die( mysql_error());
} else{
//return error("custom","","Already Inserted.");
echo "already inserted";
}
Your $sql query have a syntax error, you have used two times clause WHERE the correct syntax to use two or more clauses in where is using AND to join them, to get only record wich don't have an entry for today you can use DATE_SUB with 1 day interval
SELECT *
FROM vote
WHERE vote_fb_uid = '$this->fb_uid',
AND vote_time <= DATE_SUB(vote_time, INTERVAL 1 DAY)

Selecting new records by datetime

I'm trying to select records which have a recdate within the past year
$goodate = date('Y-m-d h:i:s', mktime(0, 0, 0, date("m"), date("d"), date("Y")-1));
$sqlstmt = "SELECT * FROM #__mytable WHERE id=".$uid." AND recdate > ".$goodate.'"' ;
but I'm getting no records.
What am I doing wrong?
$sqlstmt = "SELECT * FROM #__mytable
WHERE id=".$uid."
AND recdate > ADDDATE(CURDATE(), INTERVAL -1 YEAR)";
If you want to do this programmatically, the DateTime object is a great tool.
$date = new DateTime();
$gooddate = $date->sub(DateInterval::createFromDateString('1 year'));
$sql = "SELECT * FROM #__mytable WHERE id=".$uid." AND recdate > ".$goodate->format('Y-m-d').'"';
This is assuming your date field is mysql type DATE. If not, there are similar DateTime methods for outputting unix timestamps, and the format() method accepts any formatting string that date() does.
$sql = "
select *
from #__mytable
where
id = $uid
and
date_format(recdate, '%Y') = date_format(adddate(curdate(), interval -1 year), '%Y')
"

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