How to copy a file without overwriting the destination file? - php

Question

The script I made is.
<?php
$source_file = 'http://www.domain.tld/directory/img.png';
$dest_file = '/home/user/public_html/directory/directory/img.png';
copy($source_file, $dest_file);
?>
I need that image to not be delete and reuploaded every time the script is running. I would either want it to be img1.png, img2.png, img3.png, etc. Or img(Date,Time).png, img(Date,Time).png, etc. Is this possible and if so, how do I do this?

Answer 1

If you're concerned with overwriting a file, you could just drop in a timestamp to ensure uniqueness:
$dest_file = '/home/user/public_html/directory/directory/img.png';
// /home/user/public_html/directory/directory/img1354386279.png
$dest_file = preg_replace("/\.[^\.]{3,4}$/i", time() . "$0", $dest_file);
Of if you wanted simpler numbers, you could take a slightly more tasking route and change the destination file name as long as a file with that name already exists:
$file = "http://i.imgur.com/Z92wU.png";
$dest = "nine-guy.png";
while (file_exists($dest)) {
$dest = preg_replace_callback("/(\d+)?(\.[^\.]+)$/", function ($m) {
return ($m[1] + 1) . $m[2];
}, $dest);
}
copy($file, $dest);
You may need to be using a later version of PHP for the anonymous function callback; I tested with 5.3.10 and everything worked just fine.

Answer 2

<?php
$source_file = 'http://www.domain.tld/directory/img.png';
$dest_file = '/home/user/public_html/directory/directory/img.png';
if(!is_file($dest_file)){
copy($source_file, $dest_file);
}
else{
$fname = end(explode('/',$dest_file));
$fname = time().'-'.$fname;
$dest_file = dirname($dest_file).'/'.$fname;
copy($source_file,$dest_file);
}
?>
use this code
This will add time before filename

Answer 3

$source_file = 'http://www.domain.tld/directory/img.png';
$dest_file = '/home/user/public_html/directory/directory/img'.uniqid().'.png';
copy($source_file, $dest_file);
uniquid gives you a unique Id which is rarely possible to overwrite...
also i would make folders for each month or related to the id of the image
like
mkdir(ceil($imgId / 1000), 0777);

Answer 4

You can use rename().
For Example:
rename ("/var/www/files/file.txt", "/var/www/sites/file1.txt");
Or
You can also use copy
$source_file = 'http://www.domain.tld/directory/img.png';
$dest_file = '/home/user/public_html/directory/directory/img.png';
if(!is_file($dest_file)){
copy($source_file, $dest_file);
}
Or if you want to add time it ,you can try like this.
$source="http://www.domain.tld/directory/";
$destn ="/home/user/public_html/directory/directory/";
$filename="image.png";
$ex_name = explode('.',$filename));
$newname = $ex_name[0].'-'.time().$ex_name[1]; //where $ex_name[0] is filename and $ex_name[1] is extension.
copy($source.filename,$destn.$newname );