Two While Loops, Second Returns Empty Array? - php

I'm experimenting with MySQLi and using the following code to check differences for how I should approach my array formatting/usage for fetch_array(MYSQLI_ASSOC);
here is my code:
include "Database.php";
$ArrayQuery = $mysqli->query("SELECT * FROM accountinformation");
while ($ArrayResults = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
echo count($ArrayResults);
echo "<br>";
}
echo "<br><br><bR><br>";
$Empty = array();
while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
foreach ($ArrayResult AS $ArrayRes)
{
$Empty[] = $ArrayRes;
}
}
print_r($Empty);
The problem is, that i'm using the same Variable for my while loop, the first one returns 3 then 3 Which is expected.
But the problem is, with my second query; it returns a blank array
array( ) when print_r();
and when I do:
while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
print_r($ArrayResult);
}
For my Second while loop, it returns nothing for output.
I have checked my variables $ArrayResults and $ArrayResult are not duplicates, they are in fact unique.
Why is my second while loop returning nothing when my first one is working?
Update
When I produce a second query into the mixture with a different starting variable:
$ArrayQuer = $mysqli->query("SELECT * FROM accountinformation");
and modify my second while loop:
while ($ArrayResult = $ArrayQuer->fetch_array(MYSQLI_ASSOC))
{
print_r($ArrayResult);
}
I get the expected output? So is it a case of MySQLi not allowing the same parameters to be used twice throughout the script?

mysqli_data_seek
Adjusts the result pointer to an arbitrary row in the
result
while ($ArrayResults = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
echo count($ArrayResults);
echo "<br>";
}
echo "<br><br><bR><br>";
mysqli_data_seek($ArrayQuery,0); // Addition Made Here
$Empty = array();
while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
foreach ($ArrayResult AS $ArrayRes)
{
$Empty[] = $ArrayRes;
}
}
print_r($Empty);
To re-use an already fetched array; you should use mysqli_data_seek(); (Notice I have added it above your `$Empty Variable) This should be the problem.
See the manual here:
http://us.php.net/manual/en/mysqli-result.data-seek.php
Think of this scenario; Why would you re-buy something you already own?
Fits perfectly in your case

Related

php mysql_fetch_array() not working as expected

$result = mysql_query($strSql);
foreach($bestmatch_array as $restaurant)
{
while($row = mysql_fetch_array($result))
{
if($restaurant == $row[0])
{
$value = $row[1];
}
}
}
What I am trying to do is sort the result of array formed by query according to the values stored in $bestmatch array.
I don't know what I am doing wrong but the 4th line just seems to run once. Please help guys. Thanx in advance.
php mysql_fetch_array() not working as expected
Your expectation is not right.
foreach($bestmatch_array as $restaurant)
{
// This loop will only run for first iteration of your foreach.
while($row = mysql_fetch_array($result))
{
}
// everything has been fetched by now.
}
That is a logically incorrect sequence.
You expect your inner loop to be called over and over again as many times as you have the outer loop run but record fetch does not work like that. For outer loop's first run all the rows in $result will be fetched and since you do not reset the counter after your while loop that means after the first run there will be no more rows for the next run.
Solution? Fetch the row from mysql first then use a simple in_array call to check whether that restaurant is there in your array.
$result = mysql_query($strSql);
while($row = mysql_fetch_array($result))
{
$name=$row[0];
if(in_array($name,$bestmatch_array))
$value=$name;
}
Store the results of the query in the array first:
$result = mysql_query($strSql);
$results_row = array();
while($row = mysql_fetch_array($result))
{
$results_row[] = array($row[0],$row[1]);
}
foreach($bestmatch_array as $restaurant)
{
foreach ($results_row as $key => $value)
{
if($restaurant == $results_row[$key][0])
{
$value = $results_row[$key][1];
}
}
}

PHP - Execute select query and loop through results

I am developing a web service using PHP. I am having some trouble while executing the select query. This is the code I'm using.
DB_Functions.php
public function getCompanies() {
$result = mysql_query("SELECT * FROM company");
// check for successful store
if ($result) {
return mysql_fetch_array($result,true);
} else {
return false;
}
}
GetCompanies.php
<?php
require_once 'include/DB_Functions.php';
$db = new DB_Functions();
$companies = array();
//$rows = $db->getCompanies();
while ($row = $db->getCompanies()) {
echo $row['companyName'];
$rowArr = array();
$rowArr['CompanyName'] = $row['companyName'];
$rowArr['CompanyID'] = $row['companyId'];
//array_push($companies, $rowArr);
$companies[] = $rowArr;
}
header('Content-Type: application/json');
$response=array("Companies"=>$companies);
$json = json_encode($response);
echo $json
?>
But the problem is in GetCompanies.php file the while loop is runs endless. The code appears to be ok. Any help would be appreciated.
When you do while ($row = $db->getCompanies()) { you are running the entire query over again and returning the 1st row each time. mysql_fetch_array returns one row.
What you need to do is have getCompanies() loop over all the rows and return an array.
public function getCompanies() {
$result = mysql_query("SELECT * FROM company");
// check for successful store
if ($result) {
$ret = array();
while($row = mysql_fetch_assoc($result)){
$ret[] = $row;
}
return $ret;
} else {
return false;
}
}
Now, getCompanies() will return you an array that you can just foreach over:
$rows = $db->getCompanies();
foreach($rows as $row){
// ...
}
Change your while loop declaration to something like
foreach($rows as $row) {}
And as Pavlin said, move the function call to getCompanies() outside the loop.
Also, how about modifying the query to select a particular set of fields from the database and directly sending them as the response without doing any additional processing?
Since you are implementing Select query without any condition(where clause). And since the company table has data it would always return true in the while loop this makes the while loop an infinite loop. For while to work properly the condition should become false to exit the loop.
Its not a programming flaw its a logical one.
The php docs have all the information you need. You're using the wrong function:
mysqli_fetch_array — Fetch a result row as an associative, a numeric
array, or both
vs
mysqli_fetch_all — Fetches all result rows as an associative array, a
numeric array, or both
Just change your return statement to
return mysqli_fetch_all($result);
or
return mysqli_fetch_all($result, MYSQLI_ASSOC);
to get an associative array.
And of course, you need to move your getCompanies call outside of the loop.
NOTE
php mysql_* functions have been depricated since version 5.5.* and are going to be removed from the language soon. You should look into mysqli_* or PDO.

PHP: why can't I loop twice on mysqli_fetch_array() results? [duplicate]

This question already has answers here:
Mysqli query doesn't work twice
(2 answers)
Closed 5 years ago.
I'm retrieving some data from a mysql database. There are two loops which uses the same result set.
while ($row = mysqli_fetch_array($newsQuery)) {
echo "<a href='news-article.php?articleId=" .$row["news_id"]."' class='list-group-item active'>".$row["news_title"]."</a>";
}
This loop ends with success. then in the same page I have the following loop.
while ($row = mysqli_fetch_array($newsQuery)) {
echo $row["news_content"];
}
This loop doesn't return anything even if there are content in the table. When I try it in the first loop. the content is displayed correctly. Any idea on what I'm doing wrong.
From PHP's mysqli_fetch_array DOCS:
Returns an array that corresponds to the fetched row or NULL if there are no more rows for the resultset represented by the result parameter.
You are using a 'while' loop on $row = mysqli_fetch_array($newsQuery)
This means the loop will keep going untill mysqli_fetch_array($newsQuery) returns NULL.
This is the reason why you cant use that loop again, since mysqli has finished fetching the results and the mysqli_fetch_array($newsQuery) now returns NULL untill you make a new query.
Try populating a variable with the results first, then loop on that variable:
$results = array();
while ($row = mysqli_fetch_array($newsQuery)) {
$results[] = $row;
}
foreach ($results as $key => $row) {
echo "<a href='news-article.php?articleId=" .$row["news_id"]."' class='list-group-item active'>".$row["news_title"]."</a>";
}
foreach ($results as $key => $row) {
echo $row["news_content"];
}
While it is best to avoid logic that results in looping through a result set twice, if necessary you need to reset the result set back to the start:-
mysqli_data_seek($newsQuery, 0);
Because you already fetch the value of $newsQuery Try this code
//temporary save the news content into array
$content = array();
$x=0;
while ($row = mysqli_fetch_array($newsQuery)) {
echo "<a href='news-article.php?articleId=" .$row["news_id"]."' class='list-group-item active'>".$row["news_title"]."</a>";
$content[$x]= $row["news_content"];
$x++;
}
and if you want to retrieve it
//now retrieve it
for($y=0; $y<count($content); $y++)
{
echo $content[$y]+"<br/>";
}

PHP/SQL can't use data from query after while loop

$sql = mysql_query("SELECT * FROM table WHERE user='$user'" );
while($data=mysql_fetch_array($sql)){
echo $data['user']; //this is fine
}
echo $data['user'];
$data=mysql_fetch_array($sql);
echo $data['user'];
The last two echos are empty?
I need to have an array outside of the loop that is equivalent to the 'last' loop cycle.
The while loop keeps fetching data, until there is no more data and therefore false is returned by mysql_fetch_array. This last value, false, is still in $data after the loop has ended, but simply printing it using echo, won't print anything you can see. The same goes for the next call of mysql_fetch_array and echo. You can check this by doing a var_dump of the $data variable. This will show you that it contains the boolean false.
If you want to be able to use the data after the loop has ended, you can save all the data you fetch into one big array. That might be a bad option though if you're fetching a lot of data, but from there you should be able to change it yourself so you can save and use the useful data. To store all the data in an array, change the loop into this:
$alldata = array();
while($data=mysql_fetch_array($sql))
{
echo $data['user'];
$alldata[] = $data;
}
You can then for example iterate over $alldata to go over the results again.
Update: In your last comment you said you want to access the last record that was fetched. You can do that like this:
$lastdata = array();
while($data=mysql_fetch_array($sql))
{
echo $data['user'];
$lastdata = $data;
}
$lastdata will then contain the last record in your result.
Because of the following:
while($data = mysql_fetch_array($sql)) {
// mysql_fetch_array returned something 'not false' and this value
// is assigned to $daat
}
// mysql_fetch_array() returned false, because there are no more rows
// false is assigned to $data, and because the statement within while(...)
// isn't true anymore the loop is stopped.
Use
$data = mysql_fetch_array($sql);
if (!$data) {
echo "User don't exists";
}
for example to handle this situation

Search PHP Array from results of SQL

I currently have an array in php that stores product names, normally 5 - 10. I would like to create something where the results of a SQL query is matched against the array to make sure they are all correct, and if not to show an error.
So far I have put the results into an array, then ran the query to get the results. I believe I need to put some sort of while loop with the results of the query and check the array in that while loop?
You have the array with the product name($products) and the results of the query($row).
While you loop trough the results you can check if the element is present,otherwise echo error and break the loop:
While(...) {
if(!in_array($row['retrivedprod'],$products)) {
echo 'error';
break;
}
}
You can cycle while receiving results from db with a while loop and checking results with the in_array function http://php.net/manual/en/function.in-array.php
$availability = 0;
$cart_products = array("book", "album");
$available_products = array();
while($row = mysql_fetch_array($result)) {
$available_products[] = $row['product'];
}
foreach($cart_products as $key => $value){
if (in_array($value, $available_products)){
$availability = 1;
}
}

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