how to remove a table row by a button? - php

I have created a form in which we can add multiple rows by click on a button. but I dont't know how to delete that rows.
The Code:
<form>
<table>
<?php
for ($i=0; $i<100; $i++) {
$inst_no = $i+1;
// Display only the first line
if ($nbr_ligne == 0) $nbr_ligne = 1;
if ($i >= $nbr_ligne) $display = 'style="display:none"';
echo '
<tr id="cell'.$i.'" '.$display.'>
<td align="center"><b>'.$inst_no.'</b><br> </td>
<td><input type="text" name="total_balance[]" id="total_balance'.$i.'" class="payment_text_box" /><br>
<input type="button" value="Add Installment" class="installment_button" onclick="javascript:document.getElementById(\'cell'.($i+1).'\').style.display=\'table-row\'; this.style.display=\'none\'" />
</td>
<td><input type="text" name="installment_amount[]" id="installment_amount'.$i.'" class="payment_text_box"/><br> </td>
<td><input type="text" name="remaining_balance[]" id="remaining_balance'.$i.'" class="payment_text_box" /><br>
<input name="submit" type="button" value="Remove Installment" class="installment_button" onclick="remove();" />
</td>
<td><input type="text" name="installment_date[]" id="installment_date'.$i.'" class="payment_text_box"/><br> </td>
</tr>';
}
?>
</table>
</form>
Please tell me what is the way to remove that rows?

ithink this is use for how to add and remove table row by button.
http://www.mredkj.com/tutorials/tableaddrow.html

In your JavaScript remove() function add the something like the following (untested):
thisItem.parentNode.parentNode.parentNode.removeChild(thisItem.parentNode.parentNode);

Related

Jquery empty field add message beside the field

Jquery:
$(document).ready(function(){
$("#login_form").submit(function(event){
var username = $.trim($("#username").val());
var password = $.trim($("#password").val());
if(username.length < 1){
if(!$("#user_error").length){
$("#username_error").append("<p id='user_error'>Required</p>");
}
}
if(username.length < 1|| password.length < 1){
$("#username_error").append("<p id='user_error'>Required</p>");
$("#password_error").append("<p id='pass_error'>Required</p>");
event.preventDefault();
}
});
});
View:
<? $attr = array( "id" => "login_form"); echo form_open("KGLogin/verify_login",$attr); ?>
<table id="loginform">
<tr>
<th>Log-in</th>
</tr>
<tr>
<td>
<input type="text" name="username" id='username' placeholder="Username" />
</td>
<td id="username_error"></td>
</tr>
<tr>
<td>
<input type="password" name="password" id='password' placeholder="Password" />
</td>
<td id="password_error"></td>
</tr>
<tr>
<td>
<input type="submit" name="login" value="Login" />
</td>
</tr>
</table>
<? echo form_close(); ?>
Is there a simpler way to do this? IF i submit it twice without inputting anything, it will continue to append. Im a newbie to jquery, Cant seem to find a simple way to do things, all search results in google directs me to complicated jqueries.
How do i keep the function from stacking the error message.
Ill just put this as an answer, so no one would suggest.
<?if(form_error('username'))echo "required";;?>
Put the following code in autoload file.
$autoload['helper'] = array('url','array','html','form');
Then try this in view file
<?php if (form_error('your field name'))
{
echo "required";
}
;?>

PHP How to Insert Data Input from a Dynamically-Generated Form

I need assistance in taking the next step in inserting data entered into a dynamically-generated form. I have looked for a number of days at other similar questions and am still missing a piece.
Here is my HTML form (minus error trapping/validations):
<form id="form" name="form" method="post" action="recipeaddsubmit.php">
<table id="myTable">
<tr>
<td width="10%">Amount</td>
<td width="10%">Measure</td>
<td width="35%">Ingredient</td>
</tr>
<tr>
<td valign="top">
<input type="text" name="Amt1" id="Amt1" size="1" />
<input type="text" name="Amt2" id="Amt2" size="1" />
</td>
<td valign="top">
<select name="Measure" id="Measure">
<option>Cup</option>
<option>Ounce</option>
</select>
</td>
<td valign="top">
<input type="text" name="Ing" id="Ing" size="40" />
</td>
</tr>
</table>
<button type="button" onclick="displayResult()">Insert new row</button>
<input type="submit" name="button" id="button" value="Submit" />
</form>
Here is the javascript in my header:
<script>
function displayResult()
{
var table=document.getElementById("myTable");
var row=table.insertRow(-1);
var cell1=row.insertCell(0);
var cell2=row.insertCell(1);
var cell3=row.insertCell(2);
cell1.innerHTML="<input type='text' name='Amt1' id='Amt1' size='1' />
<input type='text' name='Amt2' id='Amt2' size='1' />";
cell2.innerHTML="<select name='Measure' id='Measure'> <option>Cup</option>
<option>Ounce</option></select>";
cell3.innerHTML="<input type='text' name='Ing' id='Ing' size='40' />";
}
</script>
And here is my attempted/partial mysqli insert statement (checkInput is a self-created validation function I have used before without issue):
$amt1 = checkInput($_POST['Amt1']);
$amt2 = checkInput($_POST['Amt2']);
$measure = checkInput($_POST['Measure']);
$ing = checkInput($_POST['Ing']);
$ingAddQuery ="INSERT INTO Ingredient (Amt1, Amt2, Measure, Ing)
VALUES ({$amt1}, {$amt2}, {$measure}, {$ing})";
mysqli_query($mysqli,$ingAddQuery);
if (!mysqli_query($mysqli,$ingAddQuery))
{
die('Error: ' . mysqli_error());
}
What I don't understand is how to incorporate a foreach loop in terms of how to increment for a certain number of rows; I understand the concept but not the application in this case.
Thank you for your assistance!
change the name from amt1 to amt1[] and etcetera...
so
<input type="text" name="Amt1[]" id="Amt1[]" size="1" />
When you submit the form,
$_POST['Amt1']; //is an array
will be an array, so you could do
$Amt1Array = $_POST['Amt1'];
foreach($Amt1Array => $Amt1){
//do stuff here
}
Better yet you can index the array using the js to create names like...
<input type="text" name="Amt1[0]" id="Amt1[0]" size="1" />
<input type="text" name="Amt2[0]" id="Amt2[0]" size="1" />
<input type="text" name="Amt1[1]" id="Amt1[1]" size="1" />
<input type="text" name="Amt2[1]" id="Amt2[1]" size="1" />
Then in the PHP you could
$Amt1Array = $_POST['Amt1'];
$Amt2Array = $_POST['Amt2'];
foreach($Amt1Array as $key => $Amt1Value){
$Amt2Value = $Amt2Array[$key];
//do stuff with rows
}
I have a suggestion.
Why don't u create a hidden input type.
<input type="hidden" name="cellCount" value="0" />
Each time u insert a new row, change value of this hidden field. This will not show on browser. This hidden element will also get submit when u submit form. this can be retrieved on server by $_POST["cellCount"].
Hope this will help u.

PHP POST value from a looped table

Please help me out of this.....
I am designing a table which is inside a form.
the table is generated based on while loop.
In each row there is a download button.
when i click download the POST value should get the same row information.
But my POST variable is giving me the last row information only.
I tried using input-type as hidden... But it did not work
Here is the code for your reference
enter code here
<form name="simpleform" method="post" action="insert.php">
<?php
$data = "environment";
$user_name = $_SESSION['username'];
$serch = mysql_query("SELECT * FROM data WHERE (data_category = '" . $data . "') ");
while ($record=mysql_fetch_assoc($serch))
{?>
<tr class="warning">
<td >
<input type="text" value=<?php echo $record['data_ID'];?> readonly="readonly" >
<input type="hidden" value=<?php echo $record['data_ID'];?> name="dataid" />
</td>
<td >
<input type="text" value=<?php echo $record['data_name'];?> readonly="readonly" >
<input type="hidden" value=<?php echo $record['data_name'];?> name="dataname" />
</td>
<td >
<input type="text" value=<?php echo $record['data_downloads'];?> readonly="readonly">
<input type="hidden" value=<?php echo $record['data_downloads'];?> name="datadown" />
</td>
<td >
<input type="text" value="" >
<input type="hidden" value="" name="datause" />
</td>
<td>
<input type="submit" name="simplesubmit" value="Go to download" />
</td>
</tr>
<?php }
exit;
?>
</tbody>
</form>
The problem is that you are using the same name attribute for all your controls. Thus, when PHP receives the form, they get overwritten, and you only see the last value of the form.
The simplest way to avoid that is just appending [] to the end of your names -- eg name=dataid[]. This will make PHP take all arguments as an array, so you don't lose data.
The second problem, is that your submit button also has the same name - you should diversify it by using some row-specific data in its name, such as 'name="submit-'.$record['data_name'].'"'
For more info, more code from you is needed, such as what are the data you are printing like.
Every post button can have its name and value, so if you change your code to produce a traceable post button name you can just do whatever you want with that.
<table>
<tr>
<td>...</td>
<td>...</td>
<td><input type="submit" name="submit[1]" value="OK" />
</tr>
<tr>
<td>...</td>
<td>...</td>
<td><input type="submit" name="submit[2]" value="OK" />
</tr>
</table>
When the form is posted its very easy to capture which button is clicked;
if ($_POST["submit"]) {
$id = key($_POST["submit"]);
}
Thanks for info... and good response. As you said , i replaced the same and saw the post value is giving me all arguments as array. My purpose is to let the client download file that he clicks. so if the client click the first row button in the table, the post value should get only that Data_name. So that i can run a query to get the URL of that data_name and download

PHP post two values in one field, one of which is hidden

Is there a way that I can post two values at the same time from a single field in a table but hide one from the user?
I would like the following form to post the values ID and reason_name when it is submitted but have the user only be able to see (and edit in the text box) the reason_name.
<form name="add_positioning" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<table border="1" class="autoTable_pos">
<tr>
<td>Positioning</td><td> </td></tr>
<?
$sql= "SELECT * FROM gradeReason WHERE reason_userID = $user_id AND category = 'positioning' AND current = 1";
$result = mysqli_query($mysqli,$sql) or die(mysqli_error($mysqli));
while($row = mysqli_fetch_array($result)){?>
<tr>
<td>
<input type="text" name="reason[]" size="25" value="<? echo $row['reason_name']; ?>"/>
</td>
<td>
<input type="button" value="Delete" class="delRow_pos"/>
</td>
</tr>
<?
}
?>
<tr>
<td>
<input type="text" name="reason[]" size="25"/>
</td>
<td>
<input type="button" value="Delete" class="delRow_pos"/>
</td>
</tr>
<tr>
<td colspan="2" align="right">
<input type="submit" value="Save" name="save_reasons"/>
</td>
</tr>
</table>
</form>
The form POST action so far (basic echo at the moment for my own sanity to check that it posts the values correctly, which it does...)
if(isset($_POST['save_reasons'])) {
foreach($_POST['reason'] as $item) {
echo $item.'<br/>';
}
}
This table displays the values that are held in a database but enables the user to add more values by dynamically adding a new row (using JQUERY I haven't included) to the table when they type in an empty one at the bottom and also allows them to edit or delete existing values.
For each value posted I intend to check if the ID value is empty, if it is it means that it is a new value and enter a new record into the database, if it isn't update the existing record in the database with the corresponding ID. I don't have a problem writing that bit, I just can't think how to get the ID value posted as well as the reason_name while keeping ID hidden from the user.
Add the ID to the name attribute of the Text boxes of the reasons loaded from the DB. Leave the other Text boxes added using JQ without the ID.
E.g.
Text box which shows the existing reason loaded from the DB
<input type="text" name="reason[][ID]" size="25"/>
Text box added with JQ
<input type="text" name="reason[]" size="25"/>
Then once you submit the form you get you will get the following array.
array
'reason' =>
array
0 =>
array
14 => string 'VAL1' (length=4)
1 => string 'VAL2' (length=5)
By checking for an array in the each element in the "reason" array, you can differentiate two type of Text Boxes.
Here is the complete code I have tested.
<?PHP
//var_dump($_POST);
foreach($_POST['reason'] as $item=>$value)
{
if(is_array($value)){
foreach($value as $ID=>$reason)
{
echo "Existing Reason : ".$ID." - ".$reason."<br>";
}
}
else{
echo "New Reason : ".$item." - ".$value.'<br/>';
}
}
?>
<form action="" method="POST">
<input type="text" name="reason[][14]" size="25" value="aaaa"/>
<input type="text" name="reason[]" size="25" value="bbbbb"/>
<input name="" type="submit">
</form>
Assuming the id is at $row['reason_id'] I think you want:
$i = 0;
while($row = mysqli_fetch_array($result)){?>
<tr>
<td>
<input type="hidden" name="reason_id[<? echo $i; ?>]" size="25" value="<? echo $row['reason_id']; ?>"/>
<input type="text" name="reason[<? echo $i; ?>]" size="25" value="<? echo $row['reason_name']; ?>"/>
</td>
<td>
<input type="button" value="Delete" class="delRow_pos"/></td></tr>
<? $i++ } ?>
This way you can later
if(isset($_POST['save_reasons'])) {
foreach($_POST['reason'] as $key => $item) {
$id = $_POST['reason_id'][$key];
echo $id . " " . $item.'<br/>';
}
}

Trouble with dynamic form values with PHP

I have a loop in a form for dynamically adding/removing items, however, only the last item is removed every time. I can add items just fine though.
I can't figure out why no matter which items I try to remove from both add_friends and register_tasks, ONLY the last item is removed. When I echo $_POST['task_name'] it's always the last item on the list, never the one I selected(unless of course I select the last item).
Here is the form
<center><h2>Create Event</h2></center>
<form method="post">
<?
$form = new common_functions();
if($form->check_saved_forms($my_username, "event") == TRUE){
$this->existing_forms(); //allow the user to select existing forms that they have created
}
?>
<tr><td>Title:</td><td><input type="text" width="20%" name="event_title" value="<? echo $form_data[0]; ?>" /></td></tr>
<tr><td>Details:</td><td><input type="text" width="20%" name="event_details" value="<?echo $form_data[1]; ?>" /></td></tr>
<tr><td>Date:</td><td><input type="text" width="20%" name="event_date" id="event_date" value="<? echo $form_data[2]; ?>" /></td></tr>
<tr><td> <input type="submit" name = "submit_event" id = "lOBut" value="Create Event" /></td></tr>
</table>
<?
//this is the section giving me trouble
$form->add_friends($added_friends);
$form->register_tasks($tasks,$nums);
?>
</form>
Both add_friends and register_tasks dynamically add and remove friends/tasks by a textbox, and a list of the added items are shown. users can remove items, however, right now only the last item is removable and I can't figure out why.
Here is register (add_friend is the same, but labeled differently)
function register_tasks($tasks,$nums){
<table>
<td><input type="textbox" size="50" name="register_description"/> </td></tr>
<td><input type ="textBox" name="register_num" /> </td>
<td><input type="submit" name="add_register_tasks" value="Add"/></td></tr>
</table>
<?
if(count($tasks) > 0){
?>
<table>
<tr><td><b>Registration Item Description</b></td><td><b># Of Available Spots</b></td></tr><br>
<?
foreach (array_combine($tasks, $nums) as $task => $task_num){
?>
<tr><td><? echo $task; ?></td><td><? echo $task_num; ?></td>
<td><input type="submit" name="remove_task" value="Remove"/></td>
<td><input type="hidden" name="task_name" value="<? echo $task; ?>"/>
<td><input type="hidden" name="task_num" value="<? echo $task_num; ?>"/></td></tr>
<?
}
?></table><?
}
You need to place the form tag inside the loop. Right now what happens is all the records are displayed in a single form and no matter what item you choose, it takes only the last value. Another alternate solution would be to use GET method and pass the number/name as query string.

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