PHP form are not uploading images - php

Question

I'm having a problem to upload images using a form. This is my form code :
<?php
echo '<table width="70%">';
echo '<tr>';
echo '<td>Add Promotion</td>';
echo '</tr>';
echo "<form action='addpromotion_post.php' method='post' enctype='multipart/form-data' name='form1' id='form1'>";
echo '<tr>';
echo "<td> </td>";
echo '</tr>';
echo '<tr>';
echo "<td>Promotion :</td>";
echo "<td><textarea name='promotion1' rows='2'></textarea></td>";
echo '</tr>';
echo '<tr>';
echo "<td>Valid From :</td>";
echo "<td><input type='text' size='40' name='validfrom1' value='promotion' /></td>";
echo '</tr>';
echo '<tr>';
echo "<td>Add Picture :</td>";
echo "<td><input type='file' name='pic1' id='pic1' /></td>";
echo '</tr>';
echo '<tr>';
echo "<td>Add Picture :</td>";
echo "<td><input type='file' name='pic2' id='pic2' /></td>";
echo '</tr>';
echo '<tr>';
echo "<td>Add Picture :</td>";
echo "<td><input type='file' name='pic3' id='pic3' /></td>";
echo '</tr>';
echo '<tr>';
echo "<td> </td>";
echo '</tr>';
echo'<tr>
<td colspan="3" align="center"><input type="submit" name="button" id="button" value="Submit" /></td>
</tr>
</table>
</form>';
This is my post code :
<?php
//session_start();
include_once("connection.php");
$promotion= $_POST["promotion1"];
$validfrom= $_POST["validfrom1"];
$promotion= mysql_real_escape_string($promotion);
$validfrom= mysql_real_escape_string($validfrom);
$sql = "insert into promotion(proid, promotion, validfrom) values ('', '$promotion', '$validfrom')";
mysql_query($sql) or die ("Error in query: $sql");
$lastid=mysql_insert_id();
$file = "slider_imagesClient/".$lastid."/";
mkdir($file);
$pic1 = $_FILES['pic1']['name'];
$pic2 = $_FILES['pic2']['name'];
$pic3 = $_FILES['pic3']['name'];
print_r($pic1);
$ext1 = pathinfo($pic1,PATHINFO_EXTENSION);
$ext2 = pathinfo($pic2,PATHINFO_EXTENSION);
$ext3 = pathinfo($pic3,PATHINFO_EXTENSION);
//$fileEnote = $_FILES['eNote']['name'];
$path1 = $file.$pic1.'.'.$ext1;
$path2 = $file.$pic2.'.'.$ext2;
$path3 = $file.$pic3.'.'.$ext3;
print_r($path1);
$ory1 = $sfish.$pic1.'.'.$ext1;
$ory2 = $sfish.$pic2.'.'.$ext2;
$ory3 = $sfish.$pic3.'.'.$ext3;
if (!file_exists($path1))
{
move_uploaded_file ($_FILES['pic1']['tmp_name'], $path1) or die ("Error");
}
if (!file_exists($path2))
{
move_uploaded_file ($_FILES['pic2']['tmp_name'], $path2) or die ("Error");
}
if (!file_exists($path3))
{
move_uploaded_file ($_FILES['pic3']['tmp_name'], $path3) or die ("Error");
}
if(!empty($pic1)) {
$sql5= "INSERT INTO pimage (id, proid, image)
VALUES ('', $lastid, '$ory1')";
mysql_query($sql5) or die ("Error in query: $sql5");
}
else
{
$not = "not good";
print_r($not);
}
if(!empty($pic2)) {
$sql5= "INSERT INTO image (resID, image)
VALUES ($lastid, '$ory2')";
mysql_query($sql5) or die ("Error in query: $sql5");
}
else
{
$not = "not good";
print_r($not);
}
if(!empty($pic3)) {
$sql5= "INSERT INTO image (resID, image)
VALUES ($lastid, '$ory3')";
mysql_query($sql5) or die ("Error in query: $sql5");
}
else
{
$not = "not good";
print_r($not);
}
?>
print_r($pic1) are not outputting anything. print_r($path1) just outputting slider_imagesClient/50/.
How can I solve this? I'm suspecting error in the form but I couldn't find any. Thank you very much :D. Really appreciate your help.

Answer 1

echo '<table width="70%">';
echo '<tr>';
echo '<td>Add Promotion</td>';
echo '</tr>';
echo "<form action='addpromotion_post.php' method='post'
enctype='multipart/form-data' name='form1' id='form1'>";
change like this
echo "<form action='addpromotion_post.php' method='post' enctype='multipart/form-data' name='form1' id='form1'>";
echo '<table width="70%">';
echo '<tr>';
echo '<td>Add Promotion</td>';
echo '</tr>';