"bookName": "I've been discovered",
"bookGenre": {
"0": "Classics",
"1": "Fantasy",
"2": "Romance"
}
"bookName": "Doctor Who",
"bookGenre": {
"0": "Classics",
"1": "Biography"
}
"bookName": "I don't want to tread carefully",
"bookGenre": {
"0": "Classics",
"1": "Fantasy",
"2": "History"
}
I want to get all the books in the genre Classics, but excluding the genre Fantasy and History.
$genre = array("Classics");
$genreNot = array("Fantasy", "History");
$q = find(array("bookGenre" => array('$in' => $genre), "bookGenre" => array('$nin' => $genreNot)));
In this query, I get all my books, and the exception is not bringing the genre Fantasy and History does not work.
How to make a request to the excluded genre work?
Hmm you have got a fundamental problem with your arrays here:
$q = find(array("bookGenre" => array('$in' => $genre),
"bookGenre" => array('$nin' => $genreNot)));
You have duplicate keys for the same object so actually the only clause in this query that goes through is "bookGenre" => array('$nin' => $genreNot). I believe instead you can combine the $in and $nin:
$q = find(array(
"bookGenre" => array('$in' => $genre, '$nin' => $genreNot)
));
Like so.
Related
i done search tutorial for send post json with curl ..
but for this value i cant find in here..
and my question how to convert to array post json in value if like
this, and this my value post json
{
"payment_type": "bca_klikpay",
"transaction_details": {
"order_id": "orderid-01",
"gross_amount": 11000
},
"item_details": [
{
"id": "1",
"price": 11000,
"quantity": 1,
"name": "Mobil "
}
],
"customer_details":{
"first_name": "John",
"last_name": "Baker",
"email": "john.baker#email.com",
"phone": "08123456789"
},
"bca_klikpay": {
"description": "Pembelian Barang"
}
}
i done try to php array like this but still error
$item = array('id' => 'id1', 'price' => 11000, 'quantity' => 1 , 'name' => 'Mobil');
$data2 =array('payment_type' => 'bca_klikpay',
'transaction_details' => array('order_id' => 'orderid-01', 'gross_amount' => 11000),
'item_details' => array([$item]),
'customer_details'=> array('first_name' => 'john',
'last_name' => 'baker', 'email' => 'john.baker#email.com', 'phone' => 08123456789),
'bca_klikpay' => array('description' => 'Pembelian Barang'));
maybe someone can help me.. and sory for my bad english
thanks
There is the following error - the phone number has to be string, not number, so it would look like this 'phone' => '08123456789', because numbers cannot begin with 0.
Beside this, there is the following issue - You should not set item_details like this, but rather 'item_details' => [$item]. You do not need 2 nested arrays, just one. (array() is equal to []. They are practically the same in your use case. So you are doing something like array(array($item)), which is wrong)
What else, you have to do a $json = json_encode($data2); at the end and it will return what you want it to.
I am android developer and new in PHP. I don't know PHP very well. I create
<?php
header('Content-Type: application/json; charset=utf-8');
$mysqli = new mysqli ('localhost', 'mabhi', '9993', 'general');
//PROBLEM LANGUAGE ?????
if (function_exists('mysql_set_charset')) {
mysqli_set_charset($mysqli, 'utf8');
} else {
mysqli_query($mysqli, "SET NAMES 'utf8'");
}
// Check if album id is posted as GET parameter
$myq = $mysqli->query('SELECT * FROM Ages');
while ($myr = $myq->fetch_assoc()) {
$array["Questions"][] = (array(
'Question' => $myr['Question'],
'Answer' => $myr['option1'],
'Answer' => $myr['option2'],
'Answer' => $myr['option3'],
'Answer' => $myr['option4'],
'CorrectAnswer' => $myr['CorrectAnswer'],
));
}
echo json_encode($array, JSON_UNESCAPED_UNICODE);
?>
output:
{
"Questions": [
{
"Question": "sfsa sfd s sdf",
"Answer": "vvv",
"CorrectAnswer": null
},
{
"Question": "dsfgdsfgv dsf dfs",
"Answer": "vvvv vv",
"CorrectAnswer": null
}
]
}
But I would like json output in below format: Answer are displayed multiple times for each question. Please suggest me what changes in my code.
{
"Questions": [
{
"Question": "dfsfdsfgv dfsfsd dfs sf",
"CorrectAnswer": 3,
"Answers": [
{
"Answer": "vvvvvvv"
},
{
"Answer": "vvv"
},
{
"Answer": "vv"
},
{
"Answer": "v"
}
]
},
{
"Question": "dgdsgdsgdsgszdfvgfvds",
"CorrectAnswer": 0,
"Answers": [
{
"Answer": "Lee"
},
{
"Answer": "Wrangler"
},
{
"Answer": "Levi's"
},
{
"Answer": "Diesel"
}
]
}
]
}
As pointed by jereon, you are overwriting the value of Answer key. You need to create a separate array for the all the Answers together.
Change
$array["Questions"][] = (array(
'Question' => $myr['Question'],
'Answer' => $myr['option1'],
'Answer' => $myr['option2'],
'Answer' => $myr['option3'],
'Answer' => $myr['option4'],
'CorrectAnswer' => $myr['CorrectAnswer'],
));
to
$array["Questions"][] = (array(
'Question' => $myr['Question'],
'Answers' => array((object)array('Answer' => $myr['option1']),
(object)array('Answer' => $myr['option2']),
(object)array('Answer' => $myr['option3']),
(object)array('Answer' => $myr['option4'])),
'CorrectAnswer' => $myr['CorrectAnswer'],
));
You should not assign multiple array elements with the same identifier ("Answer") as they would just overwrite each other. I would suggest you to use a non-associative array for the Answers so that your target JSON would look like this:
{
"Questions": [
{
"Question": "dfsfdsfgv dfsfsd dfs sf",
"CorrectAnswer": 3,
"Answers": [
"vvvvvvv",
"vvv",
"vv",
"v"
]
},
{
"Question": "dgdsgdsgdsgszdfvgfvds",
"CorrectAnswer": 0,
"Answers": [
"Lee",
"Wrangler",
"Levi's",
"Diesel"
]
}
]
}
Therefore you would use the following PHP code for the loop:
$array = array();
while ($myr = $myq->fetch_assoc()) {
$array["Questions"][] = array(
'Question' => $myr['Question'],
'CorrectAnswer' => $myr['CorrectAnswer'],
'Answers' => array(
$myr['option1'],
$myr['option2'],
$myr['option3'],
$myr['option4'],
),
);
}
First thing you are doing wrong is you are overwriting the value of answer options so what will happen is when your 1st option will be overwritten by 2nd option, 2nd option with 3rd and 3rd option with 4th option. So you will have to create an array for answers and push every answer in that array and in the end assign this answer option array to answer. So your code should look like below
while ( $myr = $myq->fetch_assoc () ) {
$answers_array=new array();
$answer_option=new stdClass(); // Create a object to format in required format and use this object to store every option of answer
$answer_option->answer=$myr['option1'];
array_push($answers_array,$answer_option);
$answer_option->answer=$myr['option2'];
array_push($answers_array, $answer_option);
$answer_option->answer=$myr['option3'];
array_push($answers_array, $answer_option);
$answer_option->answer=$myr['option4'];
array_push($answers_array,$answer_option);
$array["Questions"][] = array(
'Question' => $myr['Question'],
'CorrectAnswer' => $myr['CorrectAnswer'],
'answers' => $answers_array;
);
}
i have googled for solution to my problem but nun helped me.
here i have three tables items, feeds and images. each item has one feed and one or more images.
i have 3 functions. one is to return records from items table the second one receives feeds_id (foreign key in items table) then return records from feeds table. the third function is to return all images related to items_id.
those functions are :
* To get all items in database:
function get_items(){
return $query = Database::getInstance('db')
->table('items')
->columns(
'id',
'items.rowid',
'items.feed_id as feed_id',
'title' )
->findAll();
}
* To get feed data from feeds table :
function get_feeds($id){
return $query = Database::getInstance('db')
->table('feeds')
->eq('id',$id)
->findAll();
}
* To get image data from images table :
function get_images($id){
return $query = Database::getInstance('db')
->table('images')
->columns('items_id','src as image_url',
'title as image_title',
'alt')
->eq('items_id',$id)
->findAll();
}
Then i have the following code to call those function and display the result in jsonformat:
$response['items'] = array();
$response['feeds'] = array();
$response['images'] = array();
foreach ($items = get_items() as $item) {
$response['items'][] = array(
'id' => (int)$item['rowid'],
'feed_id' => (int)$item['feed_id'],
'title' => $item['title'],
);
foreach ($feeds = get_feeds((int)$item['feed_id']) as $feed) {
$response['feeds'][] = array(
'title' => $feed['title'],
'logo_url' => $feed['logo_url'],
'site_url' => $feed['site_url'],
);
}
foreach ($images = get_images($item['id']) as $image) {
$response['images'][] = array(
'id' => $image['items_id'],
'url' => $image['image_url'],
'thumb' => $_SERVER['SERVER_NAME'] . /myServer/images/thumbs/'. 'thumb_'.basename($image['image_url']),
'title' => $image['image_title'],
'alt' => $image['alt']
);
}
}
echo json_encode($response, JSON_PRETTY_PRINT);
so, my expectation is to get json output like:
"items": [
{
"id": ,
"feed_id":
"title":
"feeds": [
{
"title": ,
"logo_url": ,
"site_url": "
}
]
"images": [
{
"id": ,
"url": ",
"thumb":
"title": "",
"alt": ""
},
{
....
}
]
}]
i mean each item array should include nested arrays of its related data coming from get_feeds and get_images functions.
instead of that, i get response like :
//here i select two items from my db
"items": [
{ //first_item
"id": ,
"feed_id":
"title":
},
{ //second_item
"id": ,
"feed_id":
"title":
}
],
"feeds": [
{ // feed data for first item
"title": ,
"logo_url": ,
"site_url": "
},
{ // feed data for second item
"title": ,
"logo_url": ,
"site_url": "
}
],
"images": [
{ // image data for first item
"id": ,
"url": ",
"thumb":
"title": "",
"alt": ""
},
{ // other images data
....
}
]
}]
as you see i am getting output without keeping relation between items, feeds and images, all of them are shown independently.
my queries are fine but i am suspecting error in my foreach statements.
i could fix this issue by joining those tree tables in one query, but i don't want to do that because i need to do validation and other operations to output comes from each table.
i appreciate your help
i found the solution. it is very easy :)
it is just like:
$response['items'][] = array(
'id' => (int)$item['rowid'],
'feed_id' => (int)$item['feed_id'],
'title' => $item['title'],
'feeds' => array(
)
'images' => array(
)
);
I'm currently taking the results of a table and using wp_send_json to using it as a JSON response. The data is encoded as expected, however I'd like to tweak the output a bit by changing the keys, formating, and order. I'm not sure how to rebuild the array and encode as json after so I'm looking for a little bit of help.
$stuff= $wpdb->get_results( $wpdb->prepare("SELECT * FROM wp_table"), ARRAY_A);
wp_send_json($stuff);
As of now the results I get via print_r look as follows.
Array(
[0] => Array(
[id] => 1[gender] => Male[email] => test#loas . com[lat] => 38[long] => - 97[country_srt] => USA[country_long] => UnitedStates
) [1] => Array(
[id] => 2[gender] => Female[email] => femal#test . com[lat] => 38[long] => - 97[country_srt] => USA[country_long] => UnitedStates
)
)
When encoded I get:
[{
"id": "1",
"gender": "Male",
"email": "test#loas.com",
"lat": "45",
"long": "-76",
"country_srt": "USA",
"country_long": "United States"
}, {
"id": "2",
"gender": "Female",
"email": "femal#test.com",
"lat": "98",
"long": "-34",
"country_srt": "USA",
"country_long": "United States"
}]
Thing is, I don't really need some of these values and also need to format some things to output for easy map plotting. For instance the country longform and gender go into an html formatted string. What I'm looking to do is transform this array to result in:
[ idhere: {
"value": "1",
"latitude": "45",
"longitude": "-76",
"tooltip": {"content":"HTML Showing gender variable and country variable"}
}, idhere: {
"value": "2",
"latitude": "98",
"longitude": "-34",
"tooltip": {"content":"HTML Showing gender variable and country variable"}
}]
I think what you need to do is break down the process down into steps (so you can change the data around) instead of sending your sql data to json directly.
build your own array
iterate over your sql result set while adding your own markup
send the output to json
something like:
$preJSON = array();
// select only columns you need
$sql = "SELECT id, gender, country_srt, lat, long
FROM wp_table"
$count = 0; // this is for $preJSON[] index
foreach( $wpdb->get_results( $sql ) as $key => $row ) {
// each column in your row will now be accessible like this:
// $my_column = $row->column_name;
// now we can do:
$value = $row->id;
$latitude = $row->lat;
$longitude = $row->long;
$gender = $row->gender;
$country = $row->country_srt;
$tooltip = array(
"content" => "HTML and stuff" . $gender . "more HTML and stuff" . $country
);
// now we can build a row of this information in our master array
$preJSON[$count] = array(
"value" => $value,
"latitude" => $latitude,
"longitude" => $longitude,
"tooltip" => $tooltip
);
// increment the index
++$count;
}
// after foreach
// send the whole array to json
$json = json_encode( $preJSON );
I believe this should be the basic gist of what you need
CakePHP API returns result like this:
{
"status": "OK",
"themes": [
{
"Theme": {
"id": "20",
"user_id": "50",
"name": "dwdwdw",
"language_code_from": "cz",
"language_code_to": "en",
"type": "CUSTOM",
"created": "2014-10-19 15:36:05",
"count_of_cards": 0
}
}
]
}
I would like to ask, how can in remove nested Theme object to get result like this?:
{
"status": "OK",
"themes": [
{
"id": "20",
"user_id": "50",
"name": "dwdwdw",
"language_code_from": "cz",
"language_code_to": "en",
"type": "CUSTOM",
"created": "2014-10-19 15:36:05",
"count_of_cards": 0
}
]
}
Here is my CakePHP code:
$this->Theme->recursive = -1;
// GET USER ID
$themeData['user_id'] = $isSessionValid;
// GET ALL THEMES RELATED TO USER
$foundThemes = $this->Theme->find('all', array(
'conditions' => array(
'Theme.user_id' => $themeData['user_id'])
)
);
$themes = array();
// FOREACH THEMES AND GET COUNT FOR CARDS FOR EACH THEME
foreach($foundThemes as $foundTheme) {
// GET COUNT OF QUESTIONS FOR ACTUAL THEME
$countOfCards = $this->Theme->Card->find('count', array(
'conditions' => array(
'Card.theme_id' => $foundTheme['Theme']['id'])
)
);
// APPEND TO ACTUAL ARRAY
$foundTheme['Theme']['count_of_cards'] = $countOfCards;
array_push($themes,$foundTheme);
}
// SET SUCCESS RESPOSNSE
$this->set(array(
'status' => 'OK',
'themes' => $themes,
'_serialize' => array(
'status',
'themes',
)
));
Many thanks for any advice.
You can manipulate CakePHP's array formats using its built in Hash utility: http://book.cakephp.org/2.0/en/core-utility-libraries/hash.html#Hash
What I would do would be to flatten the results:
$results = Hash::flatten($results);
Your data array will end up as a single dimensional array looking like this:
$results = array(
'status' => 'OK'
'themes.0.Theme.id' => 20,
...
'themes.1.Theme.id' => 21,
...
);
You can then use string replace to remove "Theme" from your keys:
$keys = array_keys($results);
$keys = str_replace('Theme.', '', $keys);
Then you can use Hash::expand to get your original array, now formatted how you want:
$results = Hash::expand(array_combine($keys, array_values($results)));
I dont think CakePHP supports this. if you want to do this with an easy way check the Set Utility.
http://book.cakephp.org/2.0/en/core-utility-libraries/set.html