So im gonna try to explain this:
I got datepicker where you select 2 dates (start and end).
For example:
01-01-2012 till 11-12-2012
Now im gonna use these dates to search for jobs in a table:
startdate job: 10-10-2012
enddate job: 20-12-2012
I want to get that job as a result, because the job is running between those 2 dates.
I tried to use BETWEEN but that doesn't seem to work for me. Can somebody help me with the query? Ofcourse i translate the date format to yyyy-mm-dd.
The point is that i want to show the job even if only 1 day is in the range of the datepicker date.
You're looking for the intersection of 2 date ranges. So given dateranges d1 and d2, you know that d2.start must occur before d1.end. You also know that d2.end must occur after d1.start. If both conditions are true, then you have overlap. In SQL:
SELECT d.*
FROM thedates d
WHERE d.jobstart < $myenddate
AND d.jobend > $mystartdate
ETA diagram for clarity:
Simply use the statement as
SELECT * FROM dummydb.tblorders t where t.date_purchased >= '2012-03-24 00:00:00' and t.date_purchased <= '2012-03-24 23:59:59';
Related
I want to filter some items based on two different dates using MySQL. In my database I store data like 2017-03-28 10:55:10. But I need only the date part, not the time so I used the DATE() function:
select sum(cashamount) as sumcashsalesamount,
DATE(transactiondate) as datepart
from master_transaction
where transactiondate BETWEEN '2017-02-22%' AND '2017-03-28%'
order by transactiondate desc
Above this query have two dates 2017-02-22% and 2017-03-28% but this return no result.
But when I change this 2017-03-28% date to 2017-03-29% (tomorrow date) I get results.
Don't use between with "dates". I put that in quotes, because your values are really datetime values.
The best way to write this condition is:
where transactiondate >= '2017-02-22' and
transactiondate < '2017-03-29'
Note the inequality for the second condition. BETWEEN is inclusive, so it would include midnight on 2017-03-28.
Why is this best?
It allows the query optimizer to take advantage of indexes and partitions.
It is exactly the logic that you want.
It works for both date and datetime types.
BETWEEN is inclusive on both sides, and if no time component is given for a date, it defaults to 00:00:00. Since 2017-03-28 10:55:10 > 2017-03-28 00:00:00 it is not included in the result set.
2017-03-28% = 2017-03-28 00:00:00
If something happened during that day, you need 2017-03-28 23:59:59, or date_sub(2017-03-29, INTERVAL 1 second) for ease
You can only use wildcard characters (%) with LIKE.
Use:
where date(transactiondate) BETWEEN '2017-02-22' AND '2017-03-28'
if you use between and you want today, all day, you must put tomorrow date
And i fix my problem
select sum(cashamount) as sumcashsalesamount
from master_transaction
where DATE(transactiondate)BETWEEN '2017-02-22' AND '2017-03-28'
order by transactiondate desc
I just re-place the DATE(transactiondate) in where condition its worked
how to search between two date , when date format in database like :
2015-10-10 02:23:41 am
i just want to search between two date with format :
2015-10-10
without
02:23:41 am
any ideas please ?
Your question isn't completely clear. But, I guess you hope to find all the rows in your table where Date occurs on or after midnight on 2015-08-05 and before midnight on 2015-09-11 (the day after the end of the range you gave in your question.
Those two search criteria will find all the rows with Date values in the range you specified. (I'm ignoring the 02 at the end of 2015-09-10 02 in your question because I can't guess what it means, if anything.)
Try this query:
SELECT *
FROM table
WHERE `Date` >= '2015-08-05'
AND `Date` < '2015-09-10' + INTERVAL 1 DAY
This has the benefit that it can exploit an index on the Date column if you have one, so it can be fast.
You could write
SELECT *
FROM table /* slow! */
WHERE DATE(`Date`) BETWEEN '2015-08-05' AND '2015-09-10'
That's slightly easier to read, but the WHERE condition isn't sargable, so the query will be slower.
Notice that the beginning of the range uses >= -- on or after midnight, and the end of the range uses < -- before midnight.
Pro tip: Avoid the use of reserved words like DATE for column names. If you make mistakes writing your queries, their presence can really confuse MySQL, not to mention you, and slow you down.
May I suggest:
select * from table where cast(date as date) between '2015-08-05' and '2015-09-10'
When your where clause is based on a timestamp, but you're using date as the parameters for your between, it excludes anything that happens on the second date unless it happened precisely at midnight.
When using the end date for the range, include the time of the end of the day:
SELECT *
FROM YourTable
WHERE date BETWEEN '2015-08-05' AND '2015-09-10 23:59:59'
I am trying to abstract querying a month of data on the MySQL level without having to implement a series of conditions that determine the last day of a given month on a given year. LAST_DAY() seemed to be the answer but it appears to only return the date and not the provided time.
SELECT LAST_DAY('2011-02-05 23:59:59');
returns
2011-02-28
When I try to use it in a query, I lose all the entries from the last day of the month because without time the date value is not accepted.
SELECT * FROM subscriptions
WHERE (`modified_at` BETWEEN '2014-12-01 00:00:01' AND LAST_DAY('2014-12-01 23:59:59'));
How can I modify this query so that the LAST_DAY function either generates the last time of the day or preserves the time given?
How about changing the logic to ignore times?
SELECT *
FROM subscriptions
WHERE `modified_at` >= '2014-12-01' AND
`modified_at` < date_add('2014-12-01', interval 1 month)
And this doesn't need last_day().
Use ADDTIME(expr1,expr2);
Like this:
ADDTIME(LAST_DAY('2011-02-05 23:59:59'), '23:59:59')
I want to compare a datetime from sql and the todays date.
The datetime in sql is for example 2015/05/09 12:00:00 and the current date is 2015/05/09. I want to compare these things if they are equal, but for the whole day so the time is a problem. I have the following query.
$q1="SELECT reservations.reservation_id, reservations.room_id, room.room_rate, reservations.arrival_date, reservations.departure_date,
meals.meal_rate, room.room_rate, roomtype.max_persons,
CONCAT(clients.first_name,' ',clients.last_name)as name
FROM reservations, clients, meals, room, roomtype
WHERE reservations.room_id=room.room_id AND reservations.client_id=clients.client_id AND room.roomtype_id=roomtype.roomtype_id
AND reservations.meals=meals.meal_id AND reservations.arrival_date=CURDATE()
GROUP BY reservation_id
";
reservations.arrival_date=CURDATE() this is equal only at 12:00:00 o'clock. i want that to be equal for the whole day.Actually i want to compare if these two dates are equal without time but my database must be datetime with the time...
does anyone has an idea?
thanx in advance
You should learn to use standard join syntax. Simple rule: Never use commas in the from clause.
The answer to your question is either the date() function (or something similar):
where date(reservations.arrival_date) = CURDATE()
Or an inequality:
where (reservations.arrival_date >= CURDATE() and
reservations.arrival_date < date_add(CURDATE(), interval 1 day)
)
The second is actually preferred because it can make use of an index on reservations(arrival_date).
this is my first question so forgive me if I am doing this wrong. I have been trying to think up a query for the above described problem and I can't seem to get anywhere.
SELECT SUM(slots) AS totals,date
FROM
(
SELECT start, end, date, slots
FROM 1000_appointments
WHERE date > NOW() AND HOUR(end) <= 12 AND employeeID='1000001'
) q
GROUP BY date HAVING totals < 6
This gets me the days where the total of slots is less than 6 and that is great but I also need all rows for that date and, if at all possible, dates that have no entries in the table. I could possible do the sorting and listing in php but I figured there might be a more elegant way of doing this within mysql.
I hope this describes the problem well enough. The reasoning behind this is that I need to find dates where "slots" are still available ie dates that aren't booked out.
Thank you, for your help in advance.
Wrapping that will get all the rows for you:
SELECT start, end, a.date, slots, totals
FROM 1000_appointments a
JOIN
(SELECT SUM(slots) AS totals,date
FROM 1000_appointments
WHERE date > NOW() AND HOUR(end) <= 12 AND employeeID='1000001'
GROUP BY date HAVING totals < 6
) t
where a.date = t.date
It's not so easy to get the dates not in the table. It will probably require using cursors. I'd recommend doing this in your php code.