Array with empty values need to be discarded - php

Question

Given, In a input form user can separate some specific names by new line and i am saving those names in an array. Then I print those names and at last say something like "thank you for the names".
$var = "name1
name2
";
$your_array = explode("\n", $var);
for($i=0; $i<(sizeof($your_array));$i++) {
echo ($your_array[$i]);
}
echo "Thank you for the names"
But the problem is if someone enter more than one newline before or after a name then the next name show after some distance like below
name1
name2
Thank you for the names
How can escape this and output as below
name1
name2
Thank you for the names
I tried to use array_filter() but it don't work here.
Update:
If someone input
$var = "name1\nname2\n\n\n
name3
name4";
output should be like
name1
name2
name3
name4
But all the answers show like
name1
name2
name3
name4

Answer 1

Let's use a foreach loop for the sake of simplicity...
1) We need to iterate through the new array and trim the names so we lose all whitespace.
2) We echo out the name, if and only if the length of the name is 1 or more.
3) We add on a <br> tag to make each name appear on a new line.
<?php
$var = "name1\nname2\n\n\n";
$your_array = explode("\n", $var);
foreach($your_array as $name)
{
if(preg_match("/[a-zA-Z0-9]{1,}/i", $name)) {
$name = trim($name);
echo (strlen($name) > 1) ? sprintf('%s<br>', $name) : '';
}
}
echo "Thank you for the names";
?>

Answer 2

$your_array = explode(PHP_EOL, $var);
$names = array();
for ($i = 0; $i < count($your_array); $i ++ )
{
// trim clean spaces and newlines surrounding each line
// resulting value is assigned to $test
// if this value is not empty the conditional is a true proposition
// so is assigned to $names
if ($test = trim($your_array[$i]))
$names[] = $test;
}
echo implode(PHP_EOL, $names) . PHP_EOL;
echo 'Thank you for the names.';
EDIT: using foreach
$your_array = explode(PHP_EOL, $var);
foreach ($your_array as $name)
{
if ($test = trim($name))
$names[] = $test;
}
if ($names)
{
// echo implode(PHP_EOL, $names) . PHP_EOL;
echo implode('<br />', $names) . '<br />';
echo 'Thank you for the names.';
}
else
echo 'Names missing.';
EDIT 2
trim accept a charlist to explicit removes, so if you want maintain spaces, make a list with newlines and carriage return only.
trim($name, "\r\n");
NOTE: PHP_EOL is the correct new line char depending of server (unix or windows).

Answer 3

Be a better PHP developer and use native PHP array functions:
$raw_arr = array(' trim ', 'fine', ' ');
array_walk($raw_arr, function(&$value) {
$value = trim($value);
});
$reduced_arr = array_filter($raw_arr);
print_r($reduced_arr);
Note: I have used a closure. If you are running PHP < 5.3, you'll need to move this to a UDF.
UPDATE
Seems like you don't wish to trim the user input. As such, you can drop array_walk and its closure.
$raw_arr = array('    trim  ', 'fine', '');
$reduced_arr = array_filter($raw_arr);
print_r($reduced_arr);

Answer 4

for($i=0; $i<(sizeof($your_array));$i++) {
if (empty($your_array[$i])) continue;
echo ($your_array[$i]);
}
echo "Thank you for the names"

Answer 5

You can use array_filter + array_map + trim to discard empty space
$var = "name1
name2
";
$array = array_filter(array_map("trim",explode("\n", $var)));
echo implode(PHP_EOL, $array) , PHP_EOL;
echo "Thank you for the names";
Or just use preg_match_all
preg_match_all("/\S?([a-z0-9]+)\S?/", $var,$array);
echo implode(PHP_EOL, $array[0]),PHP_EOL;
echo "Thank you for the names";
Both Would Output
name1
name2
Thank you for the names