Numerologic(Pitagoric) calculations in Python - php

Question

everybody!
I'm new on Python and I'm using version 3.
I already program in PHP and I have done a script where I enter a string (a name like 'John') and the script returns the number associated to this name, based on a calculation from ASCii table.
The formula is => (ASCii code - 65)%9+1.
Here's my script in PHP:
<?php
$entry=strtoupper("Jack");
$value = 0;
for ($i = 0; $i < strlen($entry); $i++) {
if ($entry[$i] >= "A" && $entry[$i] <= "Z") {
$temp = (ord($entry[$i]) - 65)%9 + 1;
$value += $temp;
}
}
$result = $value%9;
if ($result == 0) $result = 9;
echo $result;
?>
The above result should be 7.
Here's my script in Python:
entry = input("Type your name: ")
name = entry.upper()
value = 0
for letter in range(len(name)):
while letter:
temp = int(ord(name[letter])-65)%9+1
value += temp
result = value%9
if result == 0:
result = 9
print(result)
Well, it's not working, because it seems that Python doesn't run through letters the same way I did in PHP on the first IF statement I used.
Does anybody know how can I solve this?
Thanks in advance!!!
God bless you all!

Answer 1

There are a few problems with your python code.
The biggest one is the if from php somehow becoming a while(and an infinite one) in python.
The direct translation to python would be(and it should make the code work):
if 'A' <= name[letter] <= 'Z':
But, you should never loop through indices in python.
Instead, loop directly over the values you want to work with.
Instead of:
for i in range(len(some_list)):
# do stuff with some_list[i]
You should do:
for item in some_list:
# do stuf with item
Edit:
This is how the loop would look written in a more pythonic way:
for letter in name:
if 'A' <= letter <= 'Z':
value += (ord(letter) - 65) % 9 + 1
Also, you can see here that the int() call and the temp variable are not really needed.