How to send lead via API to Getresponse - php

Question

I have a html form where name and email address are getting collected. I try to submit these informations to a GetResponse list using this script:
<?php
function mytheme_save_to_getresponse($form)
{
require_once 'jsonRPCClient.php';
$api_key = 'myAPIkey';
$api_url = 'http://api2.getresponse.com';
$client = new jsonRPCClient($api_url);
$result = NULL;
try {
$result = $client->get_campaigns(
$api_key,
array (
# find by name literally
'name' => array ( 'EQUALS' => 'testlist' )
)
);
}
catch (Exception $e) {
# check for communication and response errors
# implement handling if needed
die($e->getMessage());
}
$campaigns = array_keys($result);
$CAMPAIGN_ID = array_pop($campaigns);
$subscriberEmail = $_GET['email'];
try {
$result = $client->add_contact(
$api_key,
array (
'campaign' => $CAMPAIGN_ID,
'name' => $subscriberName,
'email' => $subscriberEmail,
'cycle_day' => '0'
)
);
}
catch (Exception $e) {
# check for communication and response errors
# implement handling if needed
die($e->getMessage());
}
}
?>
The script doesn't show any errors but GetResponse is not saving the lead to my list. Am I doing something wrong?
Thanks
James

Answer 1

If u are getting a response as [queued]=>1 then your script is working fine..
It will be added to your contact only after a validation/confirmation of entered email
$subscriberEmail will recieve a confirmation email...after the user click on the link contact will get added

Answer 2

This line is wrong:
'name' => $subscriberName,
because you have undefined variable and post it to then GetResponse API 'name' params without value so GetResponse API return Invalid params.
Change to:
$subscriberName => "Some_test_name", // for test only
In this line:
$subscriberEmail = $_GET['email'];
you should set some email in GET table maybe for test just change to:
$subscriberEmail = "test#domain.com"; // or sth like this.
Last idea is var_dump $result variable then you see response from GetResponse API
$result = null; // before try {
var_dump($result); // before end of function } ?>

Answer 3

Your code is looks good and You have to set the call back url for error handling