This question already has an answer here:
Should we ever check for mysqli_connect() errors manually?
(1 answer)
Closed 2 years ago.
How do you prevent a connection error if, for example, the database name is invalid, for the given code below?
$mysql = new mysqli('localhost', 'user', 'pass', 'wrongdatabase');
if($mysql->connect_errno)
die($mysql->connect_error);
The if statement will output the right error message, but there will still be a warning sent from the first line, which says
Warning: mysqli::mysqli() [<a href='mysqli.mysqli'>mysqli.mysqli</a>]: (42000/1049): Unknown database 'wrongdatabase' in C:\wamp\www\example.php on line 14
I know with PDO you would simply wrap it in a try/catch block, but how to do it with MySQLi?
The answer here was incorrect and outdated. A more recent answer to this question can be found here
Related
This question already has an answer here:
Should we ever check for mysqli_connect() errors manually?
(1 answer)
Closed 2 years ago.
I keep getting this error"
Warning: mysqli_error() expects parameter 1 to be mysqli, boolean given in C:\xampp\htdocs\php-contact-form\index.php on line 8
this is the connection i used:
$conn = mysqli_connect("localhost","root","Guyle4u2021","newDolce") or die("Connection Error: " . mysqli_error($conn));
By the looks of it, you need to remove the "or die("Connection Error: " . mysqli_error($conn))" and see what happens.
Also, id recommend switching to PDO because it's more consistent and is more widely used by the community, therefore additional support.
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
What to do with mysqli problems? Errors like mysqli_fetch_array(): Argument #1 must be of type mysqli_result and such
(1 answer)
Closed 2 years ago.
I have been trying to do a DELETE statement and i even tried running the query in MySQL workbench and everything was ok but in my service it does't seem to accept it.
$statement_delete = $this->conn->prepare("DELETE FROM crm_suite_tcl.aos_products_quotes where parent_id = ?");
$statement_delete->bind_param("s", $id_pedido);
$statement_delete->execute();
$resultado_borrar_lineas = $statement_delete->get_result();
It throws that the statement is false, so it doesn't let me execute it
Fatal error: Call to a member function bind_param() on boolean in
Fatal error: Call to a member function bind_param() on boolean in C:\xampp2\htdocs\crm\service\sync\include\db_handler.php on line 210
The error you are getting basically means that your statement cannot be prepared most likely due to a syntax error (a column or table that doesn't exist).
Try adding in your code:
if(!$statement_delete){
error_log($this->conn->error);
}
This should write the error to the console and you will be able to correct it.
This question already has an answer here:
PHP connection error with the database [closed]
(1 answer)
Closed 8 years ago.
I keep getting this error each time I run my .php page
It is supposed to show images taken from the server.
This page does show all the images but also error which is:
"Warning: mysqli_select_db() expects parameter 1 to be mysqli, string
given in F:\users\1203158\httpdocs\Adventure_Sports\gallery.php on
line 79 "
I do not understand how to eliminate this error
You presumably have:
$link = mysqli_connect( ... );
And my guess is you're doing:
mysqli_select_db("database_name");
That's how it was done with mysql_select_db, but with mysqli_, you have to pass the connection handler.
mysqli_select_db($link, "database_name");
The error is telling you that it's expecting a mysqli object (the connection handler) but is getting a string (the database name).
This question already has answers here:
Warning: mysql_query(): 3 is not a valid MySQL-Link resource
(4 answers)
Closed 9 years ago.
I am new to programming and following online tutorial.
I got an error please help.
Connected successfully
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/www/divitiae.net.co/make_my_tables.php on line 22
below is line 22
include_once("php_includes/db_connect.php");
$query = mysql_query($db_connect, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
The error you are getting means that the $db_connect variable you are passing to the mysql_query function is not a MySQL connection object, as would be returned by the mysql_connect function.
Your php_includes/db_connect.php should contain something like:
$db_connect = mysql_connect('hostname', 'username', 'password');
mysql_select_db('databasename');
This will connect to the database on server hostname using the username and password provided. It then selects the database databasename as the database to perform operations on.
Warning!
You really, really, REALLY should not use the mysql_* set of functions because they are deprecated and you should use either the mysqli_* functions or implement PDO, as those are more flexible, safer, supported, and have better features.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Warning: mysql_query(): 3 is not a valid MySQL-Link resource
I don't know why the $GUconnection resource isn't working on queries since I set it up as a global variable. The db connection is
$GUconnection = mysql_connect(serverip, username, password);
#mysql_select_db(dbname, $GUconnection) or die('Cannot connect to the database.');
The following query is located in an include file that is included in the file containing the mysql connection above:
global $GUconnection;
$GUresult = mysql_query("SELECT field FROM `tablename` WHERE field = 'hey' LIMIT 1", $GUconnection);
if(mysql_num_rows($GUresult)) {
$GUfile = mysql_fetch_assoc($GUresult);
}
The errors I got where
Warning: mysql_query(): 3 is not a valid MySQL-Link resource in /home/ on line 49
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/ on line 50
If I don't have the include and just paste the query directly underneath the connection then it works. What seems to be the problem?
Feel the power of google.
While writing your question on SO brings you no help, exact error message pasted into google's search box finds you complete solution. In much less time.
The connection may fail, so you should check for connection errors.