I am looking for the best way to get the last weekday from a particular date. The example I am using is what was the last workday before Christmas eve (24th Dec).
unfortunately this doesn't work:
echo date('l jS \of F Y h:i:s A', strtotime('last weekday before 24th December 2012'));
Just remove before and your example will work fine (as of PHP 5.2.0). The absolute date part (24th December 2012) is processed first, followed by the relative part (last weekday), as per the relative formats documentation.
Original
last weekday before 24th December 2012
Correct
last weekday 24th December 2012
Per the other answers, previous and last when used as in the question behave in the exact same way; meaning the immediately preceding occurrence of something (in this case, a weekday). last does have another special meaning when used in the style of last dayname of, which is not being used in the question.
Reference:
Relative Formats manual page
And in fact each of the date/time formats pages document the available formats.
Have you tried something like this:
echo date('l jS \of F Y h:i:s A', strtotime('24th December 2012 previous weekday'));
This will output something like Friday 21st of December 2012 12:00:00 AM using PHP 5.3.19
Heres another way you could go about this, its not the prettiest thing but it should work:
$date = '24th December 2012';
$dateN = intval(date('N', strtotime($date)));
if ($dateN === 1) {
$prevWeekday = date('l jS \of F Y h:i:s A', strtotime($date . '-3 days'));
} else if ($dateN === 7) {
$prevWeekday = date('l jS \of F Y h:i:s A', strtotime($date . '-2 day'));
} else {
$prevWeekday = date('l jS \of F Y h:i:s A', strtotime($date . '-1 day'));
}
echo $prevWeekday;
Related
I am saving date and time in a single column i.e 2015-04-15 13:22:58 and I want to show this time and date in this format: 15th April 2015, 1:22 pm.
I have used this code:
$dt = '2015-04-15 13:22:58';
echo date("jS F Y", strtotime($dt));
and it shows only date (15th April 2015). How can I fetch time along with date?? Any help would be highly appreciable.
Try
$dt = '2015-04-15 13:22:58';
echo date("jS F Y h:i a", strtotime($dt));
//Result is 15th April 2015 01:22 pm
echo date("jS F Y g:i a", strtotime($dt));
// Result is 15th April 2015 1:22 pm
change "jS F Y" to "js F Y g:i a". That will output the time in your desired format as well as the date.
$dt = '2015-04-15 13:22:58';
echo date("jS F Y g:i a", strtotime($dt));
Output:
15th April 2015 1:22 pm
if you want to format date time in php, you can use date_format like this.
echo date_format(strtotime($dt), "jS F Y g:i A");
Can anybody tell me why strtotime() seems to be adding 1 day? This seems to only happen in the late afternoon (something like 7 or 8 PM), otherwise it says the correct day.
echo date('m/d/Y h:i:s a', time());
Output:
12/21/2015 08:34:43 pm
echo gmdate('l, F jS, Y', strtotime(date('m/d/Y h:i:s a', time())));
Output:
Tuesday, December 22nd, 2015
I would like the above output, however, I want today's date (the 21st not the 22nd).
Use date instead of gmdate.
You are using gmdate() which gets the date in UTC. The problem only happens late in the afternoon/evening because at those times it really is the next day in UTC time.
You're also doing too much work - you can simplify that line of code to this:
// echo gmdate('l, F jS, Y', strtotime(date('m/d/Y h:i:s a', time())));
echo date('l, F jS, Y');
Otherwise you've created a timestamp from a time string based on the current time stamp. You could just leave the second parameter to date empty and the current time "now" is assumed.
It is also very important to make sure you are calling date_default_timezone_set somewhere or that you have it configured in your php.ini.
This detail in your code...
echo gmdate('l, F jS, Y', strtotime(date('m/d/Y h:i:s a', time())));
(= the "gmdate") will always return Greenwich Mean Time (GMT), which is London/UK.
So change that to date(....
And add date_default_timezone_set('America/New_York'); anyway...
Decided to ultimately use:
$date = new DateTime(date('Y-m-d'), new DateTimeZone('America/New_York'));
$timestamp = $date->format('U');
$date = gmdate('l, F jS, Y', $timestamp);
based on Alexander's comment.
In php I have time like this
$time = '2015-06-29T16:00:00Z';
I want to convert that time like this format Tuesday, December 16, 2015 3:00 PM
For that I tried
echo date( 'jS F Y', strtotime( $time) );
but it is showing time like 1st January 1970
So can someone help me to get the actual time format as I want.
A simple DateTime class usage should suffice, just feed it into the constructor, the just use ->format and provide the desired output format:
$time = '2015-06-29T16:00:00Z';
$date = new DateTime($time);
echo $date->format('jS F Y');
Sample Output
You can use the DateTime class for better handling of dates
$time = '2015-06-29T16:00:00Z';
$dateTime = new DateTime($time);
echo $dateTime->format('l, F d, Y g:i A');
$time = '2015-06-29T16:00:00Z';
echo date( 'l, F j, Y H:i A',strtotime($time));
l, F j, Y H:i A can be re-ordered to change the output.
About date function, http://php.net/manual/en/function.date.php
Just pass proper format parameters to it.
$time = '2015-06-29T16:00:00Z';
echo date( 'l, F j, Y g:i A', strtotime( $time) );
Use preg_split:
$parts = preg_plit("/Z/",$time);
$parts = preg_split("/T/",$parts[0]);
$theDate=$parts[0];
$theTime=$parts[1];
$what_you_want=date(strtotime($theDate." ".$theTime);
Note that you can still change the format of the output.
I would like to display this format of the current date using PHP. I have googled and found a few variances of what I want to do but the company I work for wants it specifically in this format to match what they've mailed out.
Monday, March 16, 2015
Thanks.
If you looked at the PHP documentation for date you'd be able to figure it out very easily:
echo date('l, F j, Y');
which outputs
Monday, March 16, 2015
As mentioned by #alfallouji, you should have a look at the php documentation.
Here is what you need:
$now = new \DateTime();
echo $now->format('l, F j, Y');
The date format string should be "l, F d, Y".
You can display current date in this format as below:
<?php
echo date("l, F d, Y");
?>
Is there anyway to convert the value of idate("z") to a date format that reads the Day, Month, and Year? My code looks like this:
$date_int = idate("z");
$date_text = strtotime($date_int);
$date = date("l, F j, Y", $date_text);
For some reason, it's still echoing Thursday, January 1, 1970.
Any ideas?
idate("z") is incorrect as that will return the day of the year. It seems like you want idate("U"), but in that case just use date() without the second parameter, it will assume time(). Example:
$date = date("l, F j, Y");
That should be all you need.
idate("z") will only return the day of the year. Today being 74. strtotime will not understand 74 as a parsing format. Therefore date() fails all together.
Assuming you want the date of the CURRENT YEAR:
$dayOfYear = 80;
print date("l, F j, Y", strtotime($dayOfYear - idate("z") . " day")); // Wednesday, March 21, 2012
$dayOfYear = 1;
print date("l, F j, Y", strtotime($dayOfYear - idate("z") . " day")) // Monday, January 2, 2012