how to check content of request_uri - php

Question

hello i would like to know how to avoid double postings in a request_uri.
as an example:
http://www.example.com/foo/foo/...
should only be:
http://www.example.com/foo/...
for example i would like to create a check that i need for a header-function that needs to be checked before it headers. it should not header if the url-string contains double postings. so the check would be something like:
$host = $_SERVER['HTTP_HOST'];
$url = $_SERVER['REQUEST_URI'];
$urlArray = explode('/', $url);
$urlArrayUnique = array_unique($urlArray);
$urlUnique = implode('/', $urlArrayUnique);
if (isset($_SESSION['a'])){
$var = $_SESSION['a'];
if($url !== $urlUnique){
header ('Location:'.$host.'/'.$var.'/'.$basename);
exit;
}
}
if there is someone who could help me out i really would appreciate.
thanks alot.

Answer 1

Try the below code, use explode and get unique and implode it into URL....
$url = $_SERVER['REQUEST_URI'];
$urlArray = explode('/', $url);
$urlArrayUnique = array_unique($urlArray);
$urlUnique = implode('/', $urlArrayUnique);
You can get dulicate values in $urlArray too...

Answer 2

You can modify this below code to suit as per your need:
$host = $_SERVER['HTTP_HOST'];
$url = $_SERVER['REQUEST_URI'];
$urlArray = explode('/', $url);
$lai = max(array_keys($urlArray));//here we get the max array index
if($urlArray[$lai-1] != $urlArray[$lai])header('Location:'.$host.'/'.$var.'/'.$basename);