I have this array :
$GivenString = array("world", "earth", "extraordinary world");
how to get 'unmatch' string of variables like this :
$string = 'hello, world'; // output = 'hello, '
$string = 'down to earth'; // output = 'down to '
$string = 'earthquake'; // output = ''
$string = 'perfect world'; // output = 'perfect '
$string = 'I love this extraordinary world'; // output = 'I love this '
thanks!
I think simple str_replace will help you
$GivenString = array("world", "earth", "extraordinary");
echo str_replace($GivenString, "", $string);
array_diff http://php.net/manual/en/function.array-diff.php
$tokens = explode(' ', $string);
$difference = array_diff($tokens, $GivenString);
str_replace will not help, as there are $string = 'earthquake'; // output = '' in example. Here's piece of code that will do your job done.
$GivenString = array("world", "earth", "extraordinary world");
foreach ($GivenString as &$string) {
$string = sprintf('%s%s%s', '[^\s]*', preg_quote($string, '/'), '[^\s]*(\s|)');
}
// case sensitive
$regexp = '/(' . implode('|', $GivenString) . ')/';
// case insensitive
// $regexp = '/(' . implode('|', $GivenString) . ')/i';
$string = 'earthquake';
echo preg_replace($regexp, '', $string);
Related
My code below is working
<?php
//load synonyms of words
$json_file = fopen("dict.json", "r") or die("Unable to open file!");
$js = fread($json_file, filesize("dict.json"));
$json = json_decode($js, true);
$text = "Hello my friend, today i am feeling good.";
$ar_text = explode(" ", $text);
foreach ($ar_text as $val)
{
$rand = rand(1, 3);
$randx = rand(1, 3);
if ($rand == $randx)
{
if (array_key_exists($val, $json))
{
$null = "{" . $val . "|";
$inc = $json[$val]['sinonim'];
$i = 1;
foreach ($inc as $siap)
{
$null .= $siap . "|";
if ($i == 4) break;
$i++;
}
$null .= "}";
$text = str_replace(" $val ", " $null ", $text);
//echo $null."<br>";
}
else
{
//echo "not found ".$val."<br>";
}
}
//echo $val;
}
$text = str_replace("|}", "}", $text);
echo $text;
//echo $json['mengaras']['tag'];
?>
i use explode to get word by word and then replace with word synonyms, how to get a phrase like "really good" and find it on dict.json.
Example: Hello, i am really good right now.
Output: Hello, i am {so fine|super fine|superb} now.
Use str_replace() - Replace all occurrences of the search string with the replacement string
$text = "Hello, i am really good right now.";
$find = "really good";
$replace = "so fine|super fine|superb";
$newtext= str_replace($find, $replace, $text);
OUTPUT:
Hello, i am so fine|super fine|superb right now.
You can do it this way too:
$text = 'Hello, i am really good right now.';
$match = 'really good';
$match_len = strlen($match);
$replace = array("so fine","super fine", "superb");
$pos = strpos($text, $match);
if($pos !== false){
echo "Word Found!";
$replace = implode("|", $replace);
$embed = '{' . $replace . '}';
echo $text_before . ' ' . $embed . ' ' . $text_after;
} else{
echo "Word Not Found!";
}
Output
Hello, i am {so fine|super fine|superb} right now.
So there's my problem :
$var = "93 Avenue d'Aubière";
I used this $var with this function:
function stripAccents($str) {
$str = preg_replace('/[\x{00C0}\x{00C1}\x{00C2}\x{00C3}\x{00C4}\x{00C5}]/u','A', $str);
$str = preg_replace('/[\x{0105}\x{0104}\x{00E0}\x{00E1}\x{00E2}\x{00E3}\x{00E4}\x{00E5}]/u','a', $str);
$str = preg_replace('/[\x{00C7}\x{0106}\x{0108}\x{010A}\x{010C}]/u','C', $str);
$str = preg_replace('/[\x{00E7}\x{0107}\x{0109}\x{010B}\x{010D}}]/u','c', $str);
$str = preg_replace('/[\x{010E}\x{0110}]/u','D', $str);
$str = preg_replace('/[\x{010F}\x{0111}]/u','d', $str);
$str = preg_replace('/[\x{00C8}\x{00C9}\x{00CA}\x{00CB}\x{0112}\x{0114}\x{0116}\x{0118}\x{011A}]/u','E', $str);
$str = preg_replace('/[\x{00E8}\x{00E9}\x{00EA}\x{00EB}\x{0113}\x{0115}\x{0117}\x{0119}\x{011B}]/u','e', $str);
$str = preg_replace('/[\x{00CC}\x{00CD}\x{00CE}\x{00CF}\x{0128}\x{012A}\x{012C}\x{012E}\x{0130}]/u','I', $str);
$str = preg_replace('/[\x{00EC}\x{00ED}\x{00EE}\x{00EF}\x{0129}\x{012B}\x{012D}\x{012F}\x{0131}]/u','i', $str);
$str = preg_replace('/[\x{0142}\x{0141}\x{013E}\x{013A}]/u','l', $str);
$str = preg_replace('/[\x{00F1}\x{0148}]/u','n', $str);
$str = preg_replace('/[\x{00D2}\x{00D3}\x{00D4}\x{00D5}\x{00D6}\x{00D8}]/u','O', $str);
$str = preg_replace('/[\x{00F2}\x{00F3}\x{00F4}\x{00F5}\x{00F6}\x{00F8}]/u','o', $str);
$str = preg_replace('/[\x{0159}\x{0155}]/u','r', $str);
$str = preg_replace('/[\x{015B}\x{015A}\x{0161}]/u','s', $str);
$str = preg_replace('/[\x{00DF}]/u','ss', $str);
$str = preg_replace('/[\x{0165}]/u','t', $str);
$str = preg_replace('/[\x{00D9}\x{00DA}\x{00DB}\x{00DC}\x{016E}\x{0170}\x{0172}]/u','U', $str);
$str = preg_replace('/[\x{00F9}\x{00FA}\x{00FB}\x{00FC}\x{016F}\x{0171}\x{0173}]/u','u', $str);
$str = preg_replace('/[\x{00FD}\x{00FF}]/u','y', $str);
$str = preg_replace('/[\x{017C}\x{017A}\x{017B}\x{0179}\x{017E}]/u','z', $str);
$str = preg_replace('/[\x{00C6}]/u','AE', $str);
$str = preg_replace('/[\x{00E6}]/u','ae', $str);
$str = preg_replace('/[\x{0152}]/u','OE', $str);
$str = preg_replace('/[\x{0153}]/u','oe', $str);
$str = preg_replace('/[\x{0022}\x{0025}\x{0026}\x{0027}\x{00A1}\x{00A2}\x{00A3}\x{00A4}\x{00A5}\x{00A6}\x{00A7}\x{00A8}\x{00AA}\x{00AB}\x{00AC}\x{00AD}\x{00AE}\x{00AF}\x{00B0}\x{00B1}\x{00B2}\x{00B3}\x{00B4}\x{00B5}\x{00B6}\x{00B7}\x{00B8}\x{00BA}\x{00BB}\x{00BC}\x{00BD}\x{00BE}\x{00BF}]/u',' ', $str);
return $str;
}
This return an empty string if I use $var but it return the correct string if I use "93 Avenue d'Aubière" as a parameter.
I tried to use preg_last_error to check if there was any error but it return 0 that means no error.
I'm connectin my DB like this:
$db = new PDO('mysql:host=localhost;dbname=somedb;charset=utf8', 'username', 'password');
Getting data like this :
$sqlSelectCommandeExapaq = "SELECT * FROM commande_exapaq WHERE statut = 'en cours'";
$res = $db->query($sqlSelectCommande);
$arrayResCmd = $res->fetchAll();
Then I passed $arrayResCmd into this function :
public static function generateInterfaceFile($orders_array)
{
// Init file
$record = new DPDStation();
// Loop through each order
foreach ($orders_array as $order_data)
{
// Add data to file
$record->add($order_data['customer_adress'], 0, 35);
}
return $record;
}
And there is the DPDStation Constructor :
function __construct() {
$this->line = str_pad("", 1634);
$this->contenu_fichier = '';
}
And the add function :
function add($txt, $position, $length) {
$txt = $this->stripAccents($txt);
$this->line = substr_replace($this->line, str_pad($txt, $length), $position, $length);
}
And adding content into the file with :
$dpd = new DPDStation();
$record = $dpd->generateInterfaceFile($arrayResCmd);
file_put_contents($filename, '$VERSION=110'."\r\n", FILE_APPEND);
file_put_contents($filename, $record->contenu_fichier."\r\n", FILE_APPEND);
Because nothing was add to the file, I look into the stripAccents and the problem seems to come from it.
Thanks for your help :)
I have a csv file that contains company names. I would want to match it against my database. In order to have a cleaner and nearer matches, I am thinking of eliminating some company suffixes like 'inc', ' inc', ', inc.' or ', inc'. Here's my sample code:
$string = 'Inc Incorporated inc.';
$wordlist = array("Inc","inc."," Inc.",", Inc.",", Inc"," Inc");
foreach ($wordlist as &$word) {
$word = '/\b' . preg_quote($word, '/') . '\b/';
}
$string = preg_replace($wordlist, '', $string);
$foo = preg_replace('/\s+/', ' ', $string);
echo $foo;
My problem here is that the 'inc.' doesn't get removed. I'm guessing it has something to do with the preq_quote. But I just can't figure out how to solve this.
Try this :
$string = 'Inc incorporated inc.';
$wordlist = array("Inc","inc.");
foreach ($wordlist as $word) {
$string =str_replace($word, '', $string);
}
echo $string;
OR
$string = 'Inc Incorporated inc.';
$wordlist = array("Inc","inc.");
$string = str_replace($wordlist, '', $string);
echo $string;
This will output as 'corporated'...
If you want "Incorporated" as result, make the "I" is small.. and than run my above code (first one)...
Try this. It may involve type juggling at some point, but will have your desired result
$string = 'Inc Incorporated inc.';
$wordlist = array('Inc', 'inc.');
$string_array = explode(' ', $string);
foreach($string_array as $k => $a) {
foreach($wordlist as $b) {
if($b == $a){
unset($string_array[$k]);
}
}
$string_array = implode('', $string_array);
You can use this
$string = 'Inc Incorporated inc.';
$wordlist = array("Inc "," inc.");
$foo = str_replace($wordlist, '', $string);
echo $foo;
Run this code here
This will work for any number of elements in array...
$string = 'Inc Incorporated inc.';
$wordlist = array("Inc");
foreach($wordlist as $stripped)
$string = preg_replace("/\b". preg_quote($stripped,'/') ."(\.|\b)/i", " ", $string) ;
$foo = preg_replace('/\s+/', ' ', $string);
echo $foo;
I want to remove words from sentence if word contains #, I am using php.
Input: Hi I am #RaghavSoni
Output: Hi I am
Thank You.
You could do:
$str = preg_replace('/#\w+/', '', $str);
This is not a good way, but it works :
<?php
$input="Hi I am #RaghavSoni";
$inputWords = explode(' ', $input);
foreach($inputWords as $el)
{
if($el[0]=="#" )
{
$input = str_replace($el, "", $input);
}
}
echo $input;
?>
while(strpos($string, '#') !== false) {
$location1 = strpos($string, "#");
$location2 = strpos($string, " ", $location1);
if($location2 !== false) {
$length = $location2 - $location1;
$string1 = substr($string, 0, $location1);
$string2 = substr($string, $location2);
$string = $string1 . $string2;
}
}
echo $string;
echo str_replace("#RaghavSoni", "", "Hi I am #RaghavSoni.");
# Output: Hi I am.
I have a string like this one text more text "empty space".
How can I replace the space in "empty space" and only this space with ###?
$string = 'text more text "empty space"';
$search = 'empty space';
str_replace($search, 'empty###space', $string);
How about this, with no regular expressions:
$text = 'foo bar "baz quux"';
$parts = explode('"', $text);
$inQuote = false;
foreach ($parts as &$part) {
if ($inQuote) { $part = str_replace(' ', '###', $part); }
$inQuote = !$inQuote;
}
$parsed = implode('"', $parts);
echo $parsed;
$somevar = "empty space";
$pattern = "/\s/";
$replacement = "###";
$somevar2 = preg_replace($pattern, $replacement, $somevar);
echo $somevar2;
$string = "My String is great";
$replace = " ";
$replace_with = "###";
$new_string = str_replace($replace, $replace_with, $string);
This should do it for you. http://www.php.net/manual/en/function.str-replace.php
Edited after you comments
Maybe it's not the best solution, but you can do it like this:
$string = 'text more text "empty space"';
preg_match('/(.*)(".*?")$/', $string, $matches);
$finaltext = $matches[1] . str_replace(' ', '###', $matches[2]);