I am currently generating a list of links (to files in a single directory) using this PHP script:
### BEGIN Directory Listing
PHP script to list files in a dir, currently lists dummy files as well, but it works.
<?php
$dir="./content"; // Directory where files are stored
if ($dir_list = opendir($dir)) {
while(($filename = readdir($dir_list)) !== false) {
//this kills the annoying .. and . directory listing
if($filename == ".." || $filename == ".") continue; ?>
<p><?php echo $filename; ?></p>
<?php
}
closedir($dir_list);
}
?>
### END Directory Listing
I now wish to only list files with a filename length of 8 characters (the ./content folder contains multiple length filenames but only one filetype). It should also be noted, the files do NOT show/have file extensions.
As always, your help and knowledge is greatly appreciated!
Check the length with strlen()
if (strlen($filename) !== 8) continue;
if ($dir_list = opendir($dir)) {
while(($filename = readdir($dir_list)) !== false) {
if(strlen($filename) !== 8) continue;
//this kills the annoying .. and . directory listing
if($filename == ".." || $filename == ".") continue; ?>
Check it with strlen() function
if(strlen($filename) ==8)){
//do something }
Related
I want to delete files in a specific directory in PHP. How can I achieve this?
I have the following code but it does not delete the files.
$files = array();
$dir = dir('files');
while ($file = $dir->read()) {
if ($file != '.' && $file != '..') {
$files[] = $file;
}
unlink($file);
}
I think your question isn't specific, this code must clear all files in the directory 'files'.
But there are some errors in that code I think, and here is the right code:
$files= array();
$dir = dir('files');
while (($file = $dir->read()) !== false) { // You must supply a condition to avoid infinite looping
if ($file != '.' && $file != '..') {
$files[] = $file; // In this array you push the valid files in the provided directory, which are not (. , ..)
}
unlink('files/'.$file); // This must remove the file in the queue
}
And finally make sure that you provided the right path to dir().
You can get all directory contents with glob and check if the value is a file with is_file() before unlinking it.
$files = glob('files/*'); // get directory contents
foreach ($files as $file) { // iterate files
// Check if file
if (is_file($file)) {
unlink($file); // delete file
}
}
If you want to remove files matching a pattern like .png or .jpg, you have to use
$files = glob('/tmp/*.{png,jpg}', GLOB_BRACE);
See manual for glob.
I am making a simple php script which just read a text file from server and delete it after showing on web.Script works well but it reads another file and delete another. It should delete the same file it reads. Any help please. Here is my code:
<?php
$mystr = '';
if ($handle = opendir('.')) {
while (false !== ($entry = readdir($handle))) {
if ($entry != "." && $entry != "..") {
$info = pathinfo($entry);
if ($info["extension"] == "txt") {
$mystr = $entry;
}
}
}
closedir($handle);
}
if (empty($mystr)) {
}else{
$contents = file_get_contents($mystr);
echo $contents;
unlink($mystr);
}
?>
Update
I dont know the file name, So in a loop I get the file name. I want to read any .txt file in the folder. This I read file one by one and at the same time delete it.
Your script is just this :
foreach(glob('/path/to/dir/*.txt') as $file)
{
readfile($file);
unlink($file);
}
See readfile() and glob() manual pages.
I need to get the contents of several files within a directory but which is the best way of doing this?
I am using
$data = file_get_contents('./files/myfile.txt');
but I want every file without having to specify the file individually as above.
You can use glob to get particular file extention and file_get_contents to get the content
$content = implode(array_map(function ($v) {
return file_get_contents($v);
}, glob(__DIR__ . "/files/*.txt")));
/**
* Change the path to your folder.
* This must be the full path from the root of your
* web space. If you're not sure what it is, ask your host.
*
* Name this file index.php and place in the directory.
*/
// Define the full path to your folder from root
$path = "/home/content/s/h/a/shaileshr21/html/download";
// Open the folder
$dir_handle = #opendir($path) or die("Unable to open $path");
// Loop through the files
while ($file = readdir($dir_handle)) {
$data = file_get_contents('$filet');
}
// Close
closedir($dir_handle);
You can dir the directory and loop through it to get the contents of all files.
<?php
$path = './files';
$d = dir($path);
$contents = '';
while (false !== ($entry = $d->read())) {
if (!($entry == '..' || $entry == '.')) {
$contents .= file_get_contents($path.'/'.$entry);
}
}
$d->close();
?>
If you only want .txt files you can change the if statement of the code above from:
if (!($entry == '..' || $entry == '.')) {
to:
if (substr($entry, -4) == '.txt') {
This will result to a variable $contents that is type string and has all the contents of all the files (or only txt files if you select the 2nd solution) that are in the ./files dir.
I am trying to read a file name current.conf and then use the name of a folder saved in it to opendir(); when I open:
$file = fopen("current.conf","r");
$lines = fread($file,"10");
fclose($file);
$lines = "/".$lines."/";
echo $lines;
$dir=opendir($lines);
$files=array();
while (($file=readdir($dir)) !== false)
{
if ($file != "." and $file != ".." and $file != "index.php")
{
array_push($files, $file);
}
}
closedir($dir);
The current.conf has only one line in it:
2.1-2328
I am not able to open the folder that is named in the conf files. I have a feeling it has to do with the formatting of the conf file but not sure.
I suspect the directory doesn't exist (or you don't have the rights to read it), but without a specific error (opendir is most likely throwing an E_WARNING - check your logs, etc.)
Incidentally, you could re-write your code to reduce its complexity as follows:
<?php
// Grab the contents of the "current.conf" file, removing any linebreaks.
$dirPath = '/'.trim(file_get_contents('current.conf')).'/';
$fileList = scandir($dirPath);
if(is_array($fileList)) {
foreach($fileList as $file) {
// Skip the '.' and '..' in here as required.
echo $file."\n";
}
}
else echo $dirPath.' cound not be scanned.';
?>
In this instance the call to scandir will throw an E_WARNING.
I have this PHP script which i'm grabbing images from a directory and displaying them. The directory only has 4 image files in it and yet there are 6 li's. In firebug the images just have the paths 'Images/uploaded/.' and 'Images/uploaded/..'
Are there hidden files that this script is grabbing but not displaying correctly?
<?php
$dir = 'Images/uploaded/';
if($handle = opendir($dir)) {
while(false !== ($file = readdir($handle))) {
echo "<li><img class=\"thumb\" src=\"".$dir.$file."\" /></li>";
}
}
closedir($handle);
?>
Your test for . or .. fails... example: You load '.' and your test says:
if('." is not "." OR its not "..")
change this conditional to && (and).
Those are the entries for "current directory" and "parent directory, respectively. Just filter them out.