parse currency name to integer values in PHP - php

Question

I have a currency value as follows say,
$6.041 billion USD (2006) or US$6.041 billion (2009)[1] or €6.041 billion (2010)[1].
I want to parse the currency value in such a way that I want to store it in three different variables i.e. $number, $currency, $year (i.e) $number = 6,041,000,000 and$currency = "euro" and $year = 2010.
The problem is that the string might have € or $ or USD. But I need to parse them accordingly.
Also I might end up having million also. According to that succeeding zeros should vary. Also I might or might not have decimal points in the currency. i.e 6.041 billion or 6 billion.
How to handle all the cases and store the result in the three variables I need?
similarly how to handle £(67.1) million (2011)[1] HK $ 648 million (2006) 22,440,000, 1,325.26 crore (US$241.2 million) [4].?
I am thinking of a brute force solution to handle each case one by one.
But that is not a apt one.
Is there any simplest way to do this?
Any help would be appreciated?

Answer 1

You could try running regular expressions something like this (untested):
if(preg_match('/([$€])([\d\.]+)\s?([\w]+)[^\(]*\((\d+)\)/',$value,$matches)){
switch($matches[1]){
case '$':
$currency = 'dollar';
break;
case '€':
$currency = 'euro';
break;
// and more for more currencies
}
$number = $matches[2];
switch($matches[3]){
case 'billion':
$number = intval($number*1000000000);
break;
case 'million':
$number = intval($number*1000000);
break;
// and more for more multipliers
}
$year = $matches[4];
}
Remember to add all the possible currency symbols you need to support in the first pair of square brackets in the regular expression [$€].

Answer 2

Untested and I am sure there are more elegant ways to do things, but this should work:
<?php
echo parseCurrency('$6.041 billion USD (2006)');
function parseCurrency($input){
if(strpos($input, 'USD') || strpos($input, '$')){
$currency = 'USD';
$floatVal = (float) get_string($input, '$', ' ');
}
elseif(strpos($input, '€')){
$currency = 'EUR';
$floatVal = (float) get_string($input, '€', ' ');
}
else{
$currency = 'undefined';
die();
}
if(strpos($input, 'billion'){
$number = $floatVal * 1000000000;
}
elseif(strpos($input, 'million'){
$number = $floatVal * 1000000;
}
else{
$number = 'undefined';
die();
}
if (preg_match('/\\([12][0-9]{3}\\)/', $input, $years)){
$year = $years[0];
}
else{
$year = 'undefined';
die();
}
return $number . ', ' . $currency . ', ' . $year;
}
//used to find million or billion
function get_string($string, $start, $end){
$string = " ".$string;
$pos = strpos($string,$start);
if ($pos == 0) return "";
$pos += strlen($start);
$len = strpos($string,$end,$pos) - $pos;
return substr($string,$pos,$len);
}