How to make php output a link? - php

Question

The following code nicely outputs the column of users i have in a mysql database table in the browser.
<?php
$len = count($name);
for($i=0;$i<$len;$i++){
echo $name[$i];
echo "<p/>";
}
?>
However i would like each name to serve as a link to an external website. The website corresponding to each $name[] in the array is on the same row in the same table. So let us say that $name[0] has website w[0].
How on earth would i go about outputting the php in the browser so that each name linked to the corresponding website? Many thanks in advance. I hope i have been clear enough. Cheers
Sorry, i should probably add the above that appears in my php script:
$name = array();
$w = array();
$i=0;
while($result = mysql_fetch_array($hof)){
$name[$i] = $result['username'];
$w[$i] = $result['website'];
$i++;
}

Answer 1

while($result = mysql_fetch_array($hof)){
echo ''.$result['username'].'<br>';
}

Answer 2

<?php
$len = count($name);
echo '<p>'
for($i=0;$i<$len;$i++){
echo '' . $name[$i] . '';
}
echo "<p/>";
?>
However, you should start learning some HTML basics before asking questions here.

Answer 3

Let's go!
Step #1.
Mysql Users table exmaple:
ID | Username | Website
1 | user_1 | user-1.com
2 | user_2 | user-2.com
3 | user-3 | user-3.com
Step #2
PHP
$mysqli = new mysqli("mhost", "muser", "mpassword", "databse");
if (! mysqli_connect_errno()) {
$query = "SELECT Username,Website FROM Users ORDER by ID DESC LIMIT 50,5";
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_row()) {
echo '' . $row[1] . '';
}
$result->close();
}

Answer 4

Easy just use ' instead of " in echo or string variable. Just like
<?php
echo ' Power Point Website';
?>