How to avoid repeating the same code in this case - php

Question

In the code below there's a chunck of code that repeats itself. Can this be done in another way so that the code does not repeat. No matter what I try, I keep ending with the same thing. The code is below, but it's a lot more in the production version. This thing does country location.
if ($GL)
{
echo 'Managed to find your location';
}else{
echo "Could not identify GL. Please select from the list below.";
}
This is the entire thing (stripped down).
$GL = false; //GL is detected using ip to location, and returns boolean
$location = 'UK';//Read from a cookie.
if(isset($location))
{
echo 'We found a cookie with your location<br />';
if(array_key_exists($location,$countries))
{
echo 'We found a country in the array. Carrying on<br />';
}else
{
echo 'Did not find a country in the array. Looking for GL';
if ($GL)
{
echo 'Managed to find your location. Carrying on';
}else{
echo "Could not identify GL. Please select from the list below.";
}
}
}
else
{
echo 'Did not find a location cookie<br />';
if ($GL)
{
echo 'Managed to find your location.Carrying on.';
}else{
echo "Could not identify GL. Please select from the list below.";
}
}

Answer 1

There are a couple simple solutions you could do. Such as:
1) Put it in a function:
function validGL($GL)
{
if ($GL)
{
echo 'Managed to find your location.Carrying on.';
}
else
{
echo "Could not identify GL. Please select from the list below.";
}
}
2) Store a boolean to determine if a valid location was found:
$GL = false; //GL is detected using ip to location, and returns boolean
$location = 'UK';//Read from a cookie.
$locationFound = false;
if(isset($location))
{
echo 'We found a cookie with your location<br />';
if(array_key_exists($location,$countries))
{
echo 'We found a country in the array. Carrying on<br />';
$locationFound = true;
}
else
{
echo 'Did not find a country in the array. Looking for GL';
}
}
else
{
echo 'Did not find a location cookie<br />';
}
if (!$locationFound)
{
if ($GL)
{
$GL_msg = 'Managed to find your location. Carrying on';
}
else
{
$GL_msg = "Could not identify GL. Please select from the list below.";
}
}

Answer 2

You can rephrase it like this:
If location is passed and found within valid list of countries, use that.
If not, if GL is found, use that.
Show the list if all else fails.
In code:
if (isset($location) && array_key_exists($location,$countries)) {
echo 'We found a country in the array. Carrying on<br />';
} elseif ($GL) {
echo 'Managed to find your location. Carrying on';
} else {
echo "Could not identify GL. Please select from the list below.";
}

Answer 3

You can make it a function and just call that function with the GL variable. This way you dont have to repeat the same if over and over.