I am successfully able to save the input value using ajax post but it is not loading the next page.
Client Side code:
<script type="text/javascript">
function notifyEmail() {
var form_data = {
'email':$('#inviteEmail').val()
};
alert($('#inviteEmail').val());
$.ajax({
url: "<?php echo site_url('main/email_invites'); ?>",
type: 'POST',
data: form_data,
success: function(msg) {
return true;
}
});
}
</script>
<input type='text' id='inviteEmail' placeholder='Enter email'/>
<a href='#' name='email' id='invite-all' onclick='notifyEmail();' class='btn'>Notify Me</a>
Controller Code:
function email_invites()
{
$this->load->model('emailInvites');
if($query = $this->emailInvites->saveEmailInvite())
{
$this->load->view('emailInvites');
}
}
What I do is the following which could help you
<script type="text/javascript">
function notifyEmail() {
var form_data = {
'email':$('#inviteEmail').val()
};
alert($('#inviteEmail').val());
$.ajax({
url: "<?php echo site_url('main/email_invites'); ?>",
type: 'POST',
data: form_data,
dataType:'json',
success: function(msg) {
if(msg.response)
//load the content in the body or wherever you want
jQuery('body').load("<?php echo site_url('main/email_invites/show'); ?>");
else
console.log("Opps, Something wrong happend");
return true;
}
});
}
</script>
<input type='text' id='inviteEmail' placeholder='Enter email'/>
<a href='#' name='email' id='invite-all' onclick='notifyEmail();' class='btn'>Notify Me</a>
In the controller
function email_invites($action = 'process')
{
if($action == 'process')
{
$this->load->model('emailInvites');
$query['response'] = $this->emailInvites->saveEmailInvite();
echo json_encode($query);
}
else
{
$this->load->view('emailInvites');
}
}
You do not need to echo the url, just use it in ajax call like this,
$.ajax({
url: 'main/email_invites',
type: 'POST',
data: form_data,
success: function(msg) {
return true;
}
});
If site_url method returns the required url, then the ajax call needs to be,
$.ajax({
url: "<?php echo site_url('main/email_invites'); ?>",
type: 'POST',
data: form_data,
success: function(msg) {
return true;
}
});
Related
I have done the code like this in view page and controller done in codeigniter
While pressing enter key multiple times data saving to the table. Can anybody help to solve this problem
View Page
<form>
<div class="cmt-box">
<textarea class="form-control" name="txtArea" id="txtArea<?php echo $row->id;?>" onkeypress="onTestChange(1)" rows="1"></textarea>
</div></form>
script
function onTestChange(id) {
$("#txtArea"+id).keypress(function(e) {
if(e.which == 13) {
dataString=document.getElementById("txtArea"+id).value;
$.ajax({
type: "POST",
url: "<?php echo site_url('show/insertcomment'); ?>",
data: { comment :dataString, id:id},
success: function(data){
location.reload();
}
});
}
});
}
$(".class_txtarea").keypress(function(e) {
if(e.which == 13) {
dataString=document.getElementById(this).value;
$.ajax({
type: "POST",
url: "<?php echo site_url('show/insertcomment'); ?>",
data: { comment :dataString, id:id},
success: function(data){
location.reload();
}
});
}
});
HTML:
<div class="cmt-box">
<textarea class="form-control mytext" name="txtArea" id="txtArea<?php echo $row->id;?>" rows="1"></textarea>
</div>
Jquery:
$(document).ready(function(){
$('.mytext').keyup(function (evt) {
evt = evt || window.event;
if (evt.keyCode == 13) { /* pressed enter key */
$.ajax({
type: "POST",
url: "<?php echo site_url('show/insertcomment'); ?>",
data: { comment :dataString, id:id},
success: function(data){
location.reload();
}
});
}
});
});
I want to send the id of a button onclick frome view to controller through ajax but it return the error:
500 Internal Server Error
my view:
<a data-toggle="modal"data-target="#Add_Money_to_campaign" ><button onclick="addId('<?php echo $id;?>');"> Add</button></a>
controller
$id= $this->input->post('dataString');
$this->model->function($id);
script:
function addId(id){
var dataString = id
alert(dataString)
$.ajax({
type: "post",
url: "<?php echo base_url('controller/function');?>",
data: {dataString:dataString},
cache: false,
success: function(html){
alert(html);
}
});
}
I'm updating your code
Your view:
<a data-toggle="modal" data-target="#Add_Money_to_campaign" ><input type="submit" value="Add" onclick="addId(<?php echo $id;?>);" /></a>
Your JS:
function addId(id){
var id = id
alert(id);
$.ajax({
type: "post",
url: "<?php echo base_url('controller/function');?>",
data: {id:id},
cache: false,
async: false,
success: function(result){
console.log(result);
}
});
}
Your function
$id= $this->input->post('id');
echo $id;
$this->model->function($id);// you might have error over here you need to specify your model_name as my_model
i want to populate two fields when some one fill up card no.
<input type="text" id="name" name="name" class="form-control" Value="<?php echo $grow['name']; ?>">
<input type="text" id="address" name="address" class="form-control" Value="<?php echo $grow['address']; ?>">
but this code populate field one by one. can any one suggest be better code for populating two fields from database. Thank you
jquery
<script type="text/javascript">
$(document).ready(function()
{
$("#krishi").keyup(function()
{
var k=$(this).val();
var q="name";
$.ajax
({
type: "POST",
url: "getresult.php",
data: 'k='+k+'&q='+q,
cache: false,
success: function(data)
{
if(data){
$("#name").val(data);
$.ajax
({
type: "POST",
url: "getresult.php",
data: 'k='+k+'&q=address',
cache: false,
success: function(data)
{
if(data){
$("#address").val(data);
}
}
});
}else
$("#name").val("");
$("#address").val("");
}
});
});
});
</script>
getresult.php
<?php
define('INCLUDE_CHECK',true);
include("mysql.php");
$k=$_POST['k'];
$q=$_POST['q'];
$sql=mysql_query("select * from inward where krishi='$k'");
$row=mysql_fetch_array($sql);
echo $row[$q];
?>
Try to extract both name and address from database and json them
$k=$_POST['k'];
$q=$_POST['q'];
$sql=mysql_query("select address,name from inward where krishi='$k'");
$row=mysql_fetch_array($sql);
$result = array(
'name'=>$row['name'],
'address'=>$row['address']);
echo json_encode($result);
After that parse them via jquery
$.ajax
({
type: "POST",
url: "getresult.php",
data: 'k='+k+'&q=address',
cache: false,
success: function(data)
{
if(data){
var parsedData = jQuery.parseJSON(data);
$("#name").val(parsedData.name);
$("#address").val(parsedData.address);
}
}
});
Javascript Code:
<script type="text/javascript">
$(document).ready(function()
{
$("#krishi").keyup(function()
{
var k = $(this).val();
var q = "name";
$.ajax({
type: 'POST',
url: "getresult.php",
data: 'k='+k,
cache: false,
success: function(data)
{
var jsonArr = $.parseJSON(data);
if(typeof response =='object')
{
$("#name").val(jsonArr.name);
$("#address").val(jsonArr.address);
}
else
{
$("#name").val("");
$("#address").val("");
}
}
});
});
});
</script>
PHP Code:
<?php
define('INCLUDE_CHECK',true);
include("mysql.php");
$k = $_POST['k'];
$sql = mysql_query("select * from inward where krishi='$k'");
$row = mysql_fetch_assoc($sql);
echo json_encode(array('name' => $row['name'], 'address' => $row['address']);
?>
<script type="text/javascript">
$(document).ready(function() {
$("a").click(function() {
var content = $('#content').html();
var data = {"content":content};
$.ajax({
type: "POST",
dataType: "json",
url: "ajax.php",
data: {content:content},
success function (data) {
alert('Hello!');
}
});
});
});
</script>
<div id="content"><?php echo $content; ?></div>
ajax.php
echo json_encode($_POST['content']); ?>
Nothing happens... WhatI really want to achieve is to get that alert box and get the return data, but I am lost since I don't get any errors or nothing.
You miss " : " after success
<script type="text/javascript">
$(document).ready(function() {
$("a").click(function() {
var content = $('#content').html();
var data = {"content":content};
$.ajax({
type: "POST",
dataType: "json",
url: "ajax.php",
data: {content:content},
success: function (data) {
alert('Hello!');
}
});
});
});
</script>
<div id="content"><?php echo $content; ?></div>
As #sofl said, if you change it to success:function (data) { it will work!
Just remember that the $("a") from $("a").click(function() { called when click in a link tag like <a href"">.
If you are using an input ou button with a class="a" you should change the code to $(".a").click(function() {
(just add a . before a)
PS: If you're using a link, you should set the href="" to href="#" to work.
I am using an ajax call which is as follows
var ID=$(this).attr('id');
var input=$("#input_"+ID).val();
var dataString = {id: ID, value: input};
$("#span_"+ID).html(input);
if(input.length>0)
{
$.ajax({
type: "POST",
url: "/apps/worker_app.php",
data: dataString,
cache: false,
success: function(html)
{
$("#span_"+ID).html(span);
}
});
}
How can I get the data in my php function edit_ajax() which is inside worker_app
I use post but the array come to be empty
Thanks
Add dataType: 'json',
var ID=$(this).attr('id');
var input=$("#input_"+ID).val();
var dataString = {id: ID, value: input};
$("#span_"+ID).html(input);
if(input.length>0)
{
$.ajax({
type: "POST",
url: "/apps/worker_app.php",
data: dataString,
dataType: 'json',
cache: false,
success: function(msg)
{
$("#span_"+ID).html(span);
}
});
}
and in worker_app.php get id and value by
$id=$_POST['id'];
$value=$_POST['value'];
edit_ajax($id,$value);
function edit_ajax($id,$value){
$sql="update from ..........";
}
Is this what u want?
Have you tried setting the dataType in your ajax call, like this:
$.ajax({
type:"POST",
url: "/apps/worker_app.php",
data: dataString,
cache: false,
success:function(html) {
},
dataType:"json"
});
Also, you could use a tool like firebug to see so the data is passed correctly in your ajax request.
Here is an example:
file1.php:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js" type="text/javscript"></script>
<script type="text/javascript">
$(document).ready(function() {
// catch submit event for your form
$('#form1').submit(function() {
// serialize data from form
var data = $(this).serialize();
$.ajax({
type="POST",
url:"file2.php",
data:data,
success:function(resp) {
// output response
$('#output').html(resp);
}
});
return false;
});
]);
</script>
</head>
<body>
<div id="output"></div>
<form method="POST" id="form1">
<input type="text" name="name" />
<input type="submit" value="send" />
</form>
</body>
</html>
file2.php:
<?php
if(isset($_POST['name'])) {
header('Content-type: text/html');
echo '<p>Response From Server - Your name is: '.$_POST['name'].'</p>';
}
?>
in /apps/worker_app.php get those posted values
$id=$_POST['id'];
$value=$_POST['value'];
and now use the values with your php function
function edit_ajax($id,$value)
{
echo $id;
echo $value;
}
echo $return=edit_ajax($id,$value);
now you can get the values in the current page as
success: function(html)
{
$("#span_"+ID).html(span);
}
> $.ajax({
> type: "POST",
> url: "/apps/worker_app.php",
> data: dataString,
> cache: false,
> success: function(msg)
> {
> $("#span_"+ID).html(msg);
> }
> });
on success, the argument function is receiving should be same used with
$("#span_"+ID).html(msg);