php - variable iteration in function - php

Question

I wanted to have a result like this
50+2+2+2+2 = 58
But I'm getting these kind of result
50
2
2
2
2
these are my codes.
<?php
$height = 50;
echo $height;
function hey($x)
{
return $height += $x;
}
$i = 4;
while($i != 0)
{
echo "<br>".hey(2);
$i--;
}
?>
Please take note that the location of my variable and loop must be and really meant at that position.
what do i need to change on my code. I am new in using php functions.
thanks for the help.

Answer 1

You can use a global variable like this try:
function hey($x)
{
global $height;
return $height += $x;
}
And print the variable height only after the called function.
If you don't put global before the variable inside the function it the seems that you create a new variable inside your function. With global you tell to the server to take the variable that you have created outside the function

Answer 2

In this function:
function hey($x)
{
return $height += $x;
}
$height is not in scope, so it is undefined. You should pass it in:
function hey($x, $height)
{
return $height += $x;
}
Then call it like this:
hey(2, $height);

Answer 3

this is scope problem :
function hey($x)
{
global $height;
return $height += $x;
}

Answer 4

Change to:
global $height;
then
while($i != 0)
{
echo "+".hey(2);
$i--;
}
echo "=" . $height;

Answer 5

I don't understand that you want, but if you need output like that, please try this code..
br mean go to bottom, so I delete it.
<?php
$height = 50;
echo $height;
function hey($x)
{
echo " + $x";
return $x;
}
$i = 4;
while($i != 0)
{
$height += hey(2);
$i--;
}
echo " = $height";
?>

Answer 6

This is online demo: http://phpfiddle.org/main/code/6h1-x5z
<?php
function getResult($height = 50, $increment = 2, $times = 4){
echo $height."+";
$total = 0;
for ($i = 0; $i < $times; $i++){
$total += $increment;
if ($i != ($times-1)){
echo $increment."+";
}
else{
echo $increment." = ".($height+$total);
}
}
}
//usage
getResult(50,2,4);
//The print out: 50+2+2+2+2 = 58
?>