I made some researchs but couldnt find yet the exact concept needed to achieve this:
::: EDIT ::: my initial request wasnt clear so here I try again
I have two tables,
table_01 with four columns: id / name / address / id_cat
AND
table_02 with two columns: id_cat / category
id_cat in table_01 and table_02 is just an INT(10), while category is a VARCHAR supposed to contain the exact name of the category (which is quite long). What I am trying to do is, when a query is made on table_01, the echo shows rows of table_01 as result, but instead of showing id_cat as a number, it shows the text from table_02 category.
The result shows as I am expecting it, but, if for example in table_02, I have a rowid_cat = 1 , category = AAAAA, I would like to echo the id_cat from table_01 as the category from table_02, so still for example, 002 | standon | 125 market street | AAAAA instead of what I get now, which is 002 | standon | 125 market street | 1.
I didnt create relation between both tables yet.
If I understand what you are after, your query for the data would just need to be something like:
select t1.id as id, t2.category as category from tab_01 as t1
left join tab_02 as t2 on t1.id_cat = t2.id_cat where t1.id = '5';
The 5 is obviously the id you are looking for in tab_01.
I am not fully clear about your question. But I think this will help you.
Right now you have created one-to-many relationship between this two tables. This means one category (tab_02) can have multiple tab_01 data.
You can try this query:
SELECT t1.id_cat AS id_cat_number, t2.*
FROM tab_02 t2
INNER JOIN tab_01 t1 ON t1.id_cat = t2.id_cat
WHERE t2.category = XXXXXXXX
Related
I have the following tables
ea_users
id
first_name
last_name
email
password
id_roles
ea_user_cfields
id
c_id = custom field ID
u_id = user ID
data
ea_customfields
id
name = name of custom field
description
I want to get all users which have a certain role, but I also want to retrieve all the custom fields per user. This is for the backend of my software where all the ea_users and custom fields should be shown.
I tried the following, but for each custom field, it duplicates the same user
$this->db->join('(SELECT GROUP_CONCAT(data) AS custom_data, id AS dataid, u_id, c_id
FROM ea_user_cfields userc
GROUP BY id) AS tt', 'tt.u_id = ea.id','left');
$this->db->join('(SELECT GROUP_CONCAT(name) AS custom_name, id AS customid
FROM ea_customfields AS cf
GROUP BY id) AS te', 'tt.c_id = te.customid','left');
$this->db->where('id_roles', $customers_role_id);
return $this->db->get('ea_users ea')->result_array();
the problem that u did not understand properly how join works.
its ok, that u have duplicates in select when u have relation one to many.
in few words your case: engine tries to fetch data from table "A" (ea_users) then JOIN according to the conditions another table "B" (ea_customfields). If u have one to many relation between tables (it means that one record from table "A" (lets say that we have in this table A1 record) can contain few related rows in table "B", lets call them as B1.1, B1.2 and B1.3 and B1.4), in this case it will join this records and put join result in memory. So in memory u would see something like
| FromTable A | FromTableB |
| A1 | B1.1 |
| A1 | B1.2 |
| A1 | B1.3 |
| A1 | B1.4 |
if u have 10 records in table "B", which related to the table "A" it would put 10 times in memory copy of data from table "A" during fetching. And then will render it to u.
depending on join type rows, with missing related records, can be skipped at all (INNER JOIN), or can be filled up with NULLs (LEFT JOIN or RIGHT JOIN), etc.
When u think about JOINs, try to imagine yourself, when u try to join on the paper few big tables. U would always need to mark somehow which data come from which table in order to be able to operate with it later, so its quite logically to write row "A1" from table "A" as many times as u need to fill up empty spaces when u find appropriate record in table "B". Otherwise u would have on your paper something like:
| FromTable A | FromTableB |
| A1 | B1.1 |
| | B1.2 |
| | B1.3 |
| | B1.4 |
Yes, its looks ok even when column "FromTable A" contains empty data, when u have 5-10 records and u can easily operate with it (for example u can sort it in your head - u just need to imagine what should be instead of empty space, but for it, u need to remember all the time order how did u wrote the data on the paper). But lets assume that u have 100-1000 records. if u still can sort it easily, lets make things more complicated and tell, that values in table "A" can be empty, etc, etc.. Thats why for mysql engine simpler to repeat many times data from table..
Basically, I always stick to examples when u try to imagine how would u join huge tables on paper or will try to select something from this tables and then make sorting there or something, how would u look through the tables, etc.
GROUP_CONCAT, grouping
Then, next mistake, u did not understand how GROUP_CONCAT works:
The thing is that mysqlEngine fetch on the first step structure into memory using all where conditions, evaluating subqueries + appends all joins. When structure is loaded, it tried to perform GROUPing. It means that it will select from temporary table all rows related to the "A1". Then will try to apply aggregation function to selected data. GROUP_CONCAT function means that we want to apply concatenation on selected group, thus we would see something like "B1.1, B1.2, B1.3, B1.4". Its in few words, but I hope it will help a little to understand it.
I googled table structure so u can write some queries there.
http://www.mysqltutorial.org/tryit/query/mysql-left-join/#1
and here is example how GROUP_CONCAT works, try to execute there query:
SELECT
c.customerNumber, c.customerName, GROUP_CONCAT(orderNumber) AS allOrders
FROM customers c
LEFT JOIN orders o ON (c.customerNumber = o.customerNumber)
GROUP BY 1,2
;
can compare with results with previous one.
power of GROUP in aggregation functions which u can use with it. For example, u can use "COUNT()", "MAX()", "GROUP_CONCAT()" or many many others.
or example of fetching of count (try to execute it):
SELECT c.customerName, count(*) AS ordersCount
FROM customers AS c
LEFT JOIN orders AS o ON (c.customerNumber = o.customerNumber)
GROUP BY 1
;
so my opinion:
simpler and better to solve this issue on client side or on backend, after fetching. because in term of mysql engine response with duplication in column is absolutely correct. BUT of course, u can also solve it using grouping with concatenations for example. but I have a feeling that for your task its overcomplicating of logic
PS.
"GROUP BY 1" - means that I want to group using column 1, so after selecting data into memory mySql will try to group all data using first column, better not to use this format of writing on prod. Its the same as "GROUP BY c.customerNumber".
PPS. Also I read comments like "use DISTINCT", etc.
To use DISTINCT or order functions, u need to understand how does it work, because of incorrect usage it can remove some data from your selection, (same as GROUP or INNER JOINS, etc). On the first look, you code might work fine, but it can cause bugs in logic, which is the most complicated to find out later.
Moreover DISTINCT will not help u, when u have one-to-many relation(in your particular case). U can try to execute queries:
SELECT
c.customerName, orderNumber AS nr
FROM customers c
INNER JOIN orders o ON (c.customerNumber = o.customerNumber)
WHERE c.customerName='Alpha Cognac'
;
SELECT
DISTINCT(c.customerName), orderNumber AS nr
FROM customers c
INNER JOIN orders o ON (c.customerNumber = o.customerNumber)
WHERE c.customerName='Alpha Cognac'
;
the result should be the same. Duplication in customer name column and orders numbers.
and example how to loose data with incorrect query ;):
SELECT
c.customerName, orderNumber AS nr
FROM customers c
INNER JOIN orders o ON (c.customerNumber = o.customerNumber)
WHERE c.customerName='Alpha Cognac'
GROUP BY 1
;
Well, best explained with a example:
MYSQL TABLE NAME: CLIENTS
ID NAME CODE
1 Mark 0
2 Joe 1
What I want:
HTML TABLE:
MATCH NAME
Mark Joe
Did you get it? Like, I need to take the NAME from the person who has a ID equal to the CODE of other.
I think that you won't need my code, since I just want to know the function that allows me to echo two distinct "NAMES". Like, if I call two echo $name; how the code knows who is who?
Ps.: I'm not a back-end developer, take it easy =)
Ps².: It is a loop (what I know to do hehehehe), it has to repeat that "search" and list a lot of "MATCHES", you know?
we can find reord in the same table by using self join...
SELECT e.NAME as parent, m.NAME as child FROM CLIENTS e, CLIENTS m WHERE e.ID = m.CODE
Hope this will be your solution
Using Mysql JOIN
SELECT b.name, a.name as match_name
FROM clients a
JOIN clients b
ON a.id = b.code;
Output
+------+------------+
| name | match_name |
+------+------------+
| Joe | Mark |
+------+------------+
I have a series of tables that I want to get rows returned from in the following format:
Student ID | Last Name | First Name | Quiz Scores
-------------------------------------------------
xxxxxxx | Snow | Jon | 0,0,0,0,0,0,0,0
There's 3 relevant tables (changing any existing DB structure is not an option):
person - table of all people in the organization
enrollment - table of student and faculty enrollment data
tilt.quiz - table of quiz scores, with each row storing an individual score
The tricky part of this is the Quiz Scores. A row for the quiz score only exists if the student has taken a the quiz. Each quiz row has a module, 1 - 8. So possible quiz data for a student could be (each of these being a separate row):
person_id | module | score
---------------------------
223355 | 1 | 100
223355 | 2 | 95
223355 | 4 | 80
223355 | 7 | 100
I need the quiz scores returned in proper order with 8 comma separated values, regardless if any or all of the quizzes are missing.
I currently have the following query:
SELECT
person.id,
first_name,
last_name,
GROUP_CONCAT(tilt.quiz.score) AS scores
FROM person
LEFT JOIN enrollment ON person.id = enrollment.person_id
LEFT JOIN tilt.quiz ON person.id = tilt.quiz.person_id
WHERE
enrollment.course_id = '$num' AND enrollment_status_id = 1
GROUP BY person.id
ORDER BY last_name
The problems with this are:
It does not order the quizzes by module
If any of the quizzes are missing it simply returns fewer values
So I need the GROUP_CONCAT scores to at least include commas for missing quiz values, and have them ordered correctly.
The one solution I considered was creating a temporary table of the quiz scores, but I'm not sure this is the most efficient method or exactly how to go about it.
EDIT: Another solution would be to execute a query to check for the existence of each quiz individually but this seems clunky (a total of 9 queries instead of 1); I was hoping there was a more elegant way.
How would this be accomplished?
There are some assumptions here about your data structure, but this should be pretty close to what you're after. Take a look at the documentation for GROUP_CONCAT and COALESCE.
SELECT `person`.`id`, `person`.`first_name`, `person`.`last_name`,
GROUP_CONCAT(
COALESCE(`tilt`.`quiz`.`score`, 'N/A')
ORDER BY `tilt`.`quiz`.`module_id`
) AS `scores`
FROM `person`
CROSS JOIN `modules`
LEFT JOIN `enrollment` USING (`person_id`)
LEFT JOIN `tilt`.`quiz` USING (`person_id`, `module_id`)
WHERE (`enrollment`.`course_id` = '$num')
AND (`enrollment`.`enrollment_status_id` = 1)
GROUP BY `person`.`id`
ORDER BY `person`.`last_name`
First thing to do is use the IFNULL() function on the score
Then, use ORDER BY inside the GROUP_CONCAT
Here is my proposed query
SELECT
person.id,
first_name,
last_name,
GROUP_CONCAT(IFNULL(tilt.quiz.score,0) ORDER BY tilt.quiz.module) AS scores
FROM person
LEFT JOIN enrollment ON person.id = enrollment.person_id
LEFT JOIN tilt.quiz ON person.id = tilt.quiz.person_id
WHERE
enrollment.course_id = '$num' AND enrollment_status_id = 1
GROUP BY person.id
ORDER BY last_name
I am building a news feed from multiple tables status, events and tracks. The data retrieved from these tables should correspond to the user-id of all the users that I follow. On the face of it I thought this seemed simple enough and I could do this with a few joins.
Every row in each of the status, events and tracks table has unique ID and they are also unique from each other, this should make matters easier later. I have done this using a unique_id table with a primary key to retrieve ID's before inserting.
My trouble is upon joining everything together the values duplicate.
Example
If I have this data.
----------
**Status**
user-id = 1
id = 1
status = Hello Universe!
----------
**Events**
user-id = 1
id = 2
event-name = The Big Bang
----------
**Tracks**
user-id = 1
id = 3
track-name = Boom
----------
Assuming I follow user 1 I would want to retrieve this.
user-id ---- id ---- status ---- event-name ---- track-name
1 1 Hello NULL NULL
Universe
1 2 NULL The Big Bang NULL
1 3 NULL NULL Boom
But in reality what I would get is something like this.
user-id ---- status.id ---- events.id ---- tracks.id ---- status ---- event-name ---- track-name
1 1 2 3 Hello The Big Bang Boom
Universe
And that row would be repeated 3 times.
Most of the queries I have tried will get something along those lines.
SELECT * FROM users
INNER JOIN followers ON users.id = followers.`user-id`
LEFT JOIN status ON followers.`follows-id` = status.`user-id`
LEFT JOIN events ON followers.`follows-id` = events.`user-id`
LEFT JOIN tracks ON followers.`follows-id` = tracks.`user-id`
WHERE users.`id` = 2
I am using laravel, so eventually this query will be put into Eloquent format. If there is a simpler and a not performance degrading way of doing this in Eloquent please let me know.
Edit
I cannot use a UNION as there is a different number of values in each table. The example is simplified for ease of reading.
Thanks to Frazz for pointing out I could use UNIONS. I have researched into them and come up with this query.
SELECT stream.*, users.id AS me FROM users
INNER JOIN followers ON users.id = followers.`user-id`
LEFT JOIN (
SELECT `id`,`user-id`,`created_at`, `name`, NULL as status
FROM events
UNION ALL
SELECT `id`,`user-id`, `created_at`,NULL AS name, `status`
FROM status
) AS stream ON stream.`user-id` = `followers`.`follows-id`
WHERE users.id = 2
Now comes the process of converting it to an eloquent model...
I have been trying to understand joins for a while now, I've noticed quite a few examples showing how to retrieve a value based on a two-table query using a left / inner join. I will try to draw out my example for you all, hopefully it will aid in the explanation of my question.
Table 1:
project_id | project_name
1 super-project
Table 2:
project_id | course_id ---> project_id and course_id are foreign keys here.
1 3
Table 3:
course_id | course_name ---> course_id is a primary key here
3 | Writing 101
My Goal:
I would like to be able to return "Writing 101" by using the project_id. So, if I know the project_id is 1, I would query the db to find that the course_id associated with the current project is 3. I would then use the course_id of 3 to query table 3 and find that the related course_name is writing 101.
Is there a way to do this in a single query using join of some sort?
select course_name from Table3
inner join Table2
on Table2.course_id = Table3.course_id
where Table2.project_id = 1
Notice there is only 1 join needed!
Also note that if the project_id = 1 is present in more than one course all of those courses will appear.
Can you explain why only one join is needed as opposed to the answer below which requires two joins?
The other answer does not require two joins. As the project_id is present in the "middle" table there is no need to look for it in Table1. Now, if you require the name of the project (which is not the case because you didn't mention that in the question) then you would have to join the Table1
Here you go:
SELECT c.course_name
FROM Table3 c
INNER JOIN Table2 pc ON pc.course_id = c.course_id
INNER JOIN Table1 p ON p.project_id = pc.project_id
WHERE project_id = 1