php mysql drop down list - php

Question

I have a PHP form that shows data from a MySQL table. Each row obviously has different data, what I want to do is have a drop down list that displays data relevant to the data entry in each row.
for example, lets say I have two tables. Fruit and Fruit_Colors, as below:
so if my PHP Form was displayed as below, the MySQL data named fruits would display the data in the Fruit column. The color would then be fetched from the Fruit_Colors table depending on the PHP form output value in field 'Fruit'. so the drop down list for each row will be different.
my PHP form table syntax is:
<table id="hor-minimalist-a">
<tr>
<th>ID</th>
<th>Fruit</th>
<th>Color</th>
</tr>
<? while($row = $fruits->fetch(PDO::FETCH_ASSOC)) { ?>
<tr>
<td><? echo $row['id']; ?></td>
<td><? echo $row['fruit']; ?></td>
<td><SELECT NAME="fruitcolor" id="fruitcolor">
<OPTION VALUE=0 >
*// what goes here???*
</option>
</SELECT>
</td>
</tr>
<? } ?>
</table>
Any advice how I can complete this would be appreciated. remember this table could be up to 50 rows so need a dynamic way of passing the 'fruit' value to the drop down list.
Syntax I know for the drop down list populations is:
function fruitcolor_dropdown($db)
{
$result = $db->query("select color from Fruit_Color where Fruit=*'outputted value'*");
return $result;
}
$colors= fruitcolor_dropdown($db);
while($row = $colors->fetch(PDO::FETCH_ASSOC)) {
$color=$row["color"];
$optionsfruitcolors.="<OPTION VALUE=\"$color\">".$color;
}
Advice appreciated as always. Thanks and Regards.

Answer 1

It will be bad idea to connect and fire query two time when you can do it in single query-
you can see demo
$query = "select f.*,group_concat(color SEPARATOR '|') as fcolor from fruit F Left join fruit_color fc using (fruit) group by fc.fruit";
Above will be your query and you will loop it like below:
<? while($row = $fruits->fetch(PDO::FETCH_ASSOC)) { ?>
<tr>
<td><? echo $row['id']; ?></td>
<td><? echo $row['fruit']; ?></td>
<td><SELECT NAME="fruitcolor" id="fruitcolor">
<OPTION VALUE=0 >
<?php
$array = explode("|", $fcolor);
$count = count($array);
for($loop=0;$loop<$count;$loop) {
echo "<option>".$array[$loop]."</option>";
}
?>
</option>
</SELECT>
</td>
</tr>
<? } ?>

Answer 2

Check this out. We create a function to generate the dropdown options. It accepts the DB and the fruit as parameters --> loops through and makes the DOM --> outputs it to the browser.
PHP Function
function getColors($db, $fruit)
{
$result = $db->query(
sprintf("select color from Fruit_Color where Fruit = '%s'",
$fruit
)
);
$output = '';
while($row = $result->fetch(PDO::FETCH_ASSOC))
{
$output .= sprintf(
'<option value="%s">%s</option>',
$row['color'],
$row['color']
);
}
return $output;
}
Template
<? while($row = $fruits->fetch(PDO::FETCH_ASSOC)) { ?>
<tr>
<td><? echo $row['id']; ?></td>
<td><? echo $row['fruit']; ?></td>
<td><SELECT NAME="fruitcolor" id="fruitcolor">
<?php echo getColors($db, $row['fruit']); ?>
</SELECT>
</td>
</tr>
<? } ?>

Answer 3

use this in selectbox
function fruitcolor_dropdown($db)
{
$result = $db->query("select color from Fruit_Color where Fruit=*'outputted value'*");
return $result;
while($row = $colors->fetch(PDO::FETCH_ASSOC)) {
$color=$row["color"];
$optionsfruitcolors.="<OPTION VALUE=\"$color\">".$color;
}
}
<select name="fruitcolor" id="fruitcolor">
<?php $colors= fruitcolor_dropdown($db); ?>
</select>