Remove an entire word if it containins a word [duplicate] - php

Question

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Closed 10 years ago.
Possible Duplicate:
Remove entire word if the word contains specific string
How I can remove an entire word that contains a word?
For example, 'releas' should delete released, releases releasing etc.
/* Read in from the file here, not in the function - you only need to read the file once */
$wordlist = array('release','announce');
/* Sample data */
$words = 'adobe releases releases Acrobat X';
foreach ($wordlist as $v)
$words = clean($v,$words);
function clean($wordlist,$value)
{
return preg_replace("/\b$wordlist\b/i", '***',trim($value));
}
echo 'Words: '.$words.PHP_EOL;

Answer 1

You can loop through your $wordlist
function clean($wordlist,$value)
{
foreach ($wordlist as $word) {
$value = preg_replace("/\b\w*$word\w*\b/i", '***', trim($value));
}
return $value;
}
and doing it in one replace
function clean($wordlist,$value)
{
$all_words = implode('|', $wordlist);
return preg_replace("/\b\w*(?:$all_words)\w*\b/i", '***', trim($value));
}
Update:
Looking through other answers and comments, it seems I haven't looked properly at the question. If $wordlist is not an array, you can just use #fthiella's answer.

Answer 2

I would use this REGEXP;
return preg_replace("/\w*$wordlist\w*/i", '***', trim($value));
Applyed to your code, it would be:
foreach ($wordlist as $v)
$words = clean($v, $words);
function clean($word, $value) {
return preg_replace("/\w*$word\w*/i", '***',trim($value));
}
(notice that I renamed $wordlist to $word to make things clearer, since $wordlist is also the name of the array)

Answer 3

try it this way
$_words = implode( '|', $wordlist );
return preg_replace( "/\b\w*{$_words}\w*\b/i", "***", trim( $value ) );
or better
$_words = array();
foreach ( $wordlist as $word ) {
$_words[] = '/\b\w*' . preg_quote( $word ) . '\w*\b/i';
}
return preg_replace( $_words, '***', trim( $value ) );
the second way avoids problems with regex, if some reserved chars appear inside the words.