how can i get php file contents with php or js file from other server
with allow_url_fopen ON ?
i try this first - ITS WORK but from my server !
<?php
$url = "index.php";
$json = file_get_contents($url);
echo $json;
echo 1;
?>
i its not work
<?php
$url = "http://mysite.com/index.php";
$json = file_get_contents($url);
echo $json;
echo 1;
?>
anyone know how get file content with allow_url_fopen from other server?
or other user from my server?
or get variable from that file?
How a file is opened depends on the stream wrapper, which depends on the full URL.
file_get_contents('index.php') defaults to the local file system wrapper, i.e. it opens the file directly from the hard disk and reads its contents.
file_get_contents('http://example.com/index.php') uses the HTTP stream wrapper. You cannot access the file on the hard disk of another server directly (hopefully you can't). Opening http://example.com/index.php is the same as putting that URL into your browser: it makes an HTTP request to that URL and the result is whatever the other server outputs after processing the PHP file, like with any regular web request.
Related
How to read a .php file using php
Let's say you have two files a.php and b.php on same folder.
Code on the file b.php
<?php
echo "hi";
?>
and code on a.php
<?php
$data = file_get_contents('b.php');
echo $data;
You access a.php on browser.
What do you see? A blank page.
Please check the page source now. It is there.
But not showing in browser as <?php is not a valid html tag. So browser can not render it properly to show as output.
<?php
$data = htmlentities(file_get_contents('b.php'));
echo $data;
Now you can see the output in browser.
If you want to get the content generated by PHP, then
$data = file_get_contents('http://host/path/file.php');
If you want to get the source code of the PHP file, then
$data = file_get_contents('path/file.php');
Remember that file_get_contents() will not work if your server has *allow_url_fopen* turned off.
//get the real path of the file in folder if necessary
$path = realpath("/path/to/myfilename.php");
//read the file
$lines = file($path,FILE_IGNORE_NEW_LINES);
Each line of the 'myfilename.php' will be stored as a string in the array '$lines'.
And then, you may use all string functions in php. More info about available string functions is available here: http://www.php.net/manual/en/ref.strings.php
I am able to put the following url in any browser and the xml appears after a few seconds...
ftp://USER:PASSWORD#aphrodite.WEBSITE.net/exports/xml/products.xml
I tried the following code in a php file so I can run a cron daily at midnight and for it to save the xml file on my server. There is a xml file being saved in my data directory but it is blank. Any ideas?
<?php
$content = file_get_contents('ftp://USER:PASSWORD#aphrodite.WEBSITE.net/exports/xml/products.xml');
file_put_contents('./data/products.xml', $xml);
?>
Try this:
<?php
$xml = file_get_contents('ftp://USER:PASSWORD#aphrodite.WEBSITE.net/exports/xml/products.xml');
file_put_contents('./data/products.xml', $xml);
?>
Your $content is not used in the file_put_contents method call so you are not writing anything to the file. I changed the code so that the data gets written to the file.
Nothing wrong with your code since file_get_contents almost supports all the protocols, But you may need to change $xml to $content because as I see $xml variable does not exists in your code.
I want to store some data retrieved using an API on my server. Specifically, these are .mp3 files of (free) learning tracks. I'm running into a problem though. The mp3 link returned from the request isn't to a straight .mp3 file, but rather makes an ADDITIONAL API call which normally would prompt you to download the mp3 file.
file_put_contents doesn't seem to like that. The mp3 file is empty.
Here's the code:
$id = $_POST['cid'];
$title = $_POST['title'];
if (!file_exists("tags/".$id."_".$title))
{
mkdir("tags/".$id."_".$title);
}
else
echo "Dir already exists";
file_put_contents("tags/{$id}_{$title}/all.mp3", fopen($_POST['all'], 'r'));
And here is an example of the second API I mentioned earlier:
http://www.barbershoptags.com/dbaction.php?action=DownloadFile&dbase=tags&id=31&fldname=AllParts
Is there some way to bypass this intermediate step? If there's no way to access the direct URL of the mp3, is there a way to redirect the file download prompt to my server?
Thank you in advance for your help!
EDIT
Here is the current snippet. I should be echoing something, correct?
$handle = fopen("http://www.barbershoptags.com/dbaction.php?action=DownloadFile&dbase=tags&id=31&fldname=AllParts", 'rb');
$contents = stream_get_contents($handle);
echo $contents;
Because this echos nothing.
SOLUTION
Ok, I guess file_get_contents is supposed to handle redirects just fine, but this wasn't happening. So I found this function: https://stackoverflow.com/a/4102293/2723783 to return the final redirect of the API. I plugged that URL into file_get_contents and volia!
You seem to be just opening the file handler and not getting the contents using fread() or another similar function:
http://www.php.net/manual/en/function.fread.php
$handle = fopen($_POST['all'], 'rb')
file_put_contents("tags/{$id}_{$title}/all.mp3", stream_get_contents($handle));
How to read a .php file using php
Let's say you have two files a.php and b.php on same folder.
Code on the file b.php
<?php
echo "hi";
?>
and code on a.php
<?php
$data = file_get_contents('b.php');
echo $data;
You access a.php on browser.
What do you see? A blank page.
Please check the page source now. It is there.
But not showing in browser as <?php is not a valid html tag. So browser can not render it properly to show as output.
<?php
$data = htmlentities(file_get_contents('b.php'));
echo $data;
Now you can see the output in browser.
If you want to get the content generated by PHP, then
$data = file_get_contents('http://host/path/file.php');
If you want to get the source code of the PHP file, then
$data = file_get_contents('path/file.php');
Remember that file_get_contents() will not work if your server has *allow_url_fopen* turned off.
//get the real path of the file in folder if necessary
$path = realpath("/path/to/myfilename.php");
//read the file
$lines = file($path,FILE_IGNORE_NEW_LINES);
Each line of the 'myfilename.php' will be stored as a string in the array '$lines'.
And then, you may use all string functions in php. More info about available string functions is available here: http://www.php.net/manual/en/ref.strings.php
I have a simple code written (based on some tutorials found around the internet) to parse and display an XML file. However, I only know how to reference an XML file stored on my server and I would like to be able to use an XML file that is being returned to me from a POST.
Right now my code looks like this:
if( ! $xml = simplexml_load_file('test.xml') )
{
echo 'unable to load XML file';
}
else
{
foreach( $xml as $event)
{
echo 'Title: ';
echo "$event->title<br />";
echo 'Description: '.$event->info.'<br />';
echo '<br />';
}
}
Is there some way I can replace the simpleXML_load_file function with one that will allow me to point to the POST URL that returns the XML file?
Use simplexml_load_string instead of loadfile:
simplexml_load_string($_POST['a']);
If you get the url to the file in the POST you can propably use the simplexml_load_file function with the url, but if that doesn't work you can use the file_get_contents in combination with the simplexml_load_string:
//say $_POST['a'] == 'http://example.com/test.xml';
simplexml_load_file($_POST['a']); // <-- propably works
simplexml_load_string(file_get_contents($_POST['a'])); //<-- defenitly works (propaly what happens internally)
also getting contents of external files could be prohibited by running PHP in safe mode.
If you are receiving a file that's been uploaded by the user, you can find it (the file) looking at the content of the $_FILES superglobal variable -- and you can read more about files uploads here (for instance, don't forget to call move_uploaded_file if you don't want the file to be deleted at the end of the request).
Then, you can work with this file the same way you already do with not-uploaded files.
If you are receiving an XML string, you can use simplexml_load_string on it.
And if you are only receiving the URL to a remote XML content, you have to :
download the file to your server
and, then, parse its content.
This can be done using simplexml_load_file, passing the URL as a parameter, if your server is properly configured (i.e. if allow_url_fopen is enabled).
Else, the download will have to be done using curl -- see curl_exec for a very basic example, and curl_setopt for the options you can use (you'll especially want to use CURLOPT_RETURNTRANSFER, to get the XML data as a string you can pass to simplexml_load_string).
From http://www.developershome.com/wap/wapUpload/wap_upload.asp?page=php4:
If you do not want to save the
uploaded file directly but to process
it, the PHP functions
file_get_contents() and fread() can
help you. The file_get_contents()
function returns a string that
contains all data of the uploaded
file:
if (is_uploaded_file($_FILES['myFile']['tmp_name']))
$fileData = file_get_contents($_FILES['myFile']['tmp_name']);
That will give you a handle on the raw text within that file. From there you will need to parse through the XML. Hope that helps!
Check out simplexml_load_string. You can then use cURL to do the post and fetch the result. An example:
<?php
$xml = simplexml_load_string($string_fetched_with_curl);
?>