jquery show button when checkbox is checked - php

Question

I want to show the delete button below the table if any of the row checkboxes are checked. Otherwise, the button should stay hidden.
Table I want it to be implemented.
screenshot of table:
This is the html table code behind.
<table id="datatable_example" class="responsive table table-striped table-bordered" style="width:100%;margin-bottom:0; ">
<thead>
<tr>
<th style="width:0px; padding-right:0px;" class="jv no_sort"> <label class="checkbox ">
<input type="checkbox">
</label>
</th>
<th style="width:200px;" class=""> Skill </th>
<th style="width:300px;" class="to_hide_phone no_sort"> Description </th>
<th class=""> Rating </th>
<th style="width:200px;" class="ue no_sort"> Date </th>
<th class="ms no_sort "> Actions </th>
</tr>
</thead>
<tbody>
<?php echo $skills; ?>
</tbody>
</table>
This is the skills variable:
$skills="";
while($row=mysql_fetch_array($skills_list))
{
$showskillid=$row['skill_id'];
$showskillname=$row['skill_name'];
$showskilldescription=$row['skill_desc'];
$showskillrating=$row['skill_rating'];
$showskill_lastupdated=$row['last_updated'];
$skills .="<tr>
<td><label class=\"checkbox\">
<input type=\"checkbox\" class=\"chkboxes\" name=\"ids[]\">
</label></td>
<td class=\"to_hide_phone\"> $showskillname </td>
<td class=\"to_hide_phone\">$showskilldescription</td>
<td> $showskillrating </td>
<td> $showskill_lastupdated </td>
<td class=\"ms\"><div class=\"btn-group1\"> <i class=\"gicon-edit\"></i> <a class=\"btn btn-small\" rel=\"tooltip\" data-placement=\"top\" data-original-title=\"View\"><i class=\"gicon-eye-open\"></i></a> <a class=\"btn btn-small\" rel=\"tooltip\" data-placement=\"bottom\" data-original-title=\"Remove\"><i class=\"gicon-remove \"></i></a> </div></td>
</tr>";
}
The Jquery which I tried but I know I am newbie in jquery so need help to fix it.
<script type="text/javascript">
$(document).ready(function() {
$('.delbtn').hide();
});
$('.chkboxes').click(function(){
$('.delbtn').toggle();
});
</script>
Jquery I tried it somehow works like when I click one checkbox the button shows up and when I go and click the other checkbox the button disappears?
I know toggle should not be used here..
What instead should I use here to fix this issue, or if there is more better option to fix it I am open to it..

Answer 1

This will show the Delete button when at least one checkbox is checked.
$('.chkboxes').change(function(){
$('.delbtn').toggle($('.chkboxes:checked').length > 0);
});
But instead of hiding it, the more common approach is to enable and disable the button:
$('.delbtn').prop('disabled', true);
$('.chkboxes').change(function(){
$('.delbtn').prop('disabled', $('.chkboxes:checked').length == 0);
});