PHP Function To Get Character Number - php

How can I write a function that gives me number of the character that is passed to it
For example, if the funciton name is GetCharacterNumber and I pass B to it then it should give me 2
GetCharacterNumber("A") // should print 1
GetCharacterNumber("C") // should print 3
GetCharacterNumber("Z") // should print 26
GetCharacterNumber("AA") // should print 27
GetCharacterNumber("AA") // should print 27
GetCharacterNumber("AC") // should print 29
Is it even possible to achieve this ?

There is a function called ord which gives you the ASCII number of the character.
ord($chr) - ord('A') + 1
gives you the correct result for one character. For longer strings, you can use a loop.
<?php
function GetCharacterNumber($str) {
$num = 0;
for ($i = 0; $i < strlen($str); $i++) {
$num = 26 * $num + ord($str[$i]) - 64;
}
return $num;
}
GetCharacterNumber("A"); //1
GetCharacterNumber("C"); //3
GetCharacterNumber("Z"); //26
GetCharacterNumber("AA"); //27
GetCharacterNumber("AC"); //29
GetCharacterNumber("BA"); //53
?>

Not very efficient but gets the job done:
function get_character_number($end)
{
$count = 1;
$char = 'A';
$end = strtoupper($end);
while ($char !== $end) {
$count++;
$char++;
}
return $count;
}
echo get_character_number('AA'); // 27
demo
This works because when you got something like $char = 'A' and do $char++, it will change to 'B', then 'C', 'D', … 'Z', 'AA', 'AB' and so on.
Note that this will become the slower the longer $end is. I would not recommend this for anything beyond 'ZZZZ' (475254 iterations) or if you need many lookups like that.
An better performing alternative would be
function get_character_number($string) {
$number = 0;
$string = strtoupper($string);
$dictionary = array_combine(range('A', 'Z'), range(1, 26));
for ($pos = 0; isset($string[$pos]); $pos++) {
$number += $dictionary[$string[$pos]] + $pos * 26 - $pos;
}
return $number;
}
echo get_character_number(''), PHP_EOL; // 0
echo get_character_number('Z'), PHP_EOL; // 26
echo get_character_number('AA'), PHP_EOL; // 27
demo

Use range and strpos:
$letter = 'z';
$alphabet = range('a', 'z');
$position = strpos($alphabet, $letter);
For double letters (eg zz) you'd probably need to create your own alphabet using a custom function:
$alphabet = range('a', 'z');
$dictionary = range('a','z');
foreach($alphabet AS $a1){
foreach($alphabet AS $a2) {
$dictionary[] = $a1 . $a2;
}
}
Then use $dictionary in place of $alphabet.

Here is the full code that does what you want.
Tested it and works perfectly for the examples you gave.
define('BASE', 26);
function singleOrd($chr) {
if (strlen($chr) == 1) {
return (ord($chr)-64);
} else{
return 0;
}
}
function multiOrd($string) {
if (strlen($string) == 0) {
return 0;
} elseif (strlen($string) == 1) {
return singleOrd($string);
} else{
$sum = 0;
for($i = strlen($string) - 1; $i >= 0; $i--) {
$sum += singleOrd($string[$i]) * pow(BASE, $i);
}
}
return $sum;
}

I think ord should be a more efficient way to have your number :
$string = strtolower($string);
$result = 0;
$length = strlen($string);
foreach($string as $key=>$value){
$result = ($length -$key - 1)*(ord($value)-ord(a)+1);
}
and result would contain what you want.

Related

How to replace multiple random characters in string with underscore(_) in PHP

I am using codes like "gjhyYhK", "HJjhkeuJ" etc. But want user to show these codes like:
gj_y__K
HJj__e_J
means code will be edited with "_" at random positions in code.
This will do what you want:
$str = "gjhyYhK";
$len = strlen($str);
$num_to_remove = ceil($len * .4); // 40% removal
for($i = 0; $i < $num_to_remove; $i++)
{
$k = 0;
do
{
$k = rand(1, $len);
} while($str[$k-1] == "_");
$str[$k-1] = "_";
}
print $str . "\n";
If you want more underscores, change the value of $underscores. This will guarantee you get how many underscores you want, so long as you want fewer than the length of the string
Try this:
$string=array(
'gjhyYhK',
'HJjhkeuJ'
);
$arr=array();
foreach ($string as $key=>$value) {
$arr[$key]='';
for ($i=1; $i <=strlen($value); $i++) {
if(rand(0,1)){
$arr[$key].=substr($string[$key],$i,1);
}else{
$arr[$key].='_';
}
}
}
var_dump($arr);
you can try below code to get the functionality what you are looking for
<?php
$string = "gjhyYhK";
$percentage = 40;
$total_length = strlen($string);
$number_of_underscore = floor(($percentage / 100) * $total_length); // I have use floor value, you can use ceil() as well
for ($i = 1; $i <= $number_of_underscore; $i++)
{
$random_position = rand(0, strlen($string) - 1); // get the random position of character to be replaced
if (substr($string, $random_position, 1) !== '_') // check if its already replaced underscore (_)
{
$string = preg_replace("/" . (substr($string, $random_position, 1)) . "/", '_', $string, 1); // here preg_replaced use to replace the character only once, (i.e str_replace() will replace all matching characters)
}
else
{
$i--; // else decrement $i for the loop to run one more time
}
}
echo $string;
?>
let me know if any other help needed
$str = "ADFJ";
$strlen = strlen($str);
$newStr = '';
for ($i = 0; $i < $strlen; $i++) {
if ($i == rand(0, $strlen)) {
$newStr .= '_';
} else {
$newStr .= $str[$i];
}
}
echo $newStr;

Replacing char with number

There is this code that I am doing
Example a string of this value
z12z
I want to generate it
0120
0121
0122
... until 0129
then
1120
1121
1122
... until 1129
until 9129 , its sort of like two four loop, but I got no idea how to implement this.
and the issue is z can be anywhere and it can be zzzz
where it will be
0000 until 9999
or it could also be z0z0, z could be anywhere. What kind of method should I use for such.
Thanks!
I am doing it with php
for every occurance of letter 'z' , i will need do a for loop to generate the possible number, from 0 to 9, you can say z is a for loop for 0 to 9, e.g z555 will yield 0555,1555,2555,3555,4555,5555,6555,7555,8555,9555 , issue is z can occur with a possibility of 0 to 4, like z555 , zz55,zzz5, zzzz, and z position is random , I need generate the possible z number output
z position could be 55z5 , 5z55 , 5zz5 . its does not have a fix position.
<?php
$numbers = array();
for ($i = 0; $i <= 9; $i++){
for ($j = 120; $j <= 129; $j++){
$numbers[] = $i . $j;
}
}
print_r('<pre>');
print_r($numbers);
A better answer that take the z char is:
<?php
function strReplaceNth($search, $replace, $subject, $nth)
{
$found = preg_match_all('/' . preg_quote($search) . '/', $subject, $matches, PREG_OFFSET_CAPTURE);
if (false !== $found && $found > $nth) {
return substr_replace($subject, $replace, $matches[0][$nth][1], strlen($search));
}
return $subject;
}
function cleanup($numbers, $char)
{
$tmp = array();
for ($i = 0; $i < count($numbers); $i++){
if (strpos($numbers[$i], $char) === false){
$tmp[] = $numbers[$i];
}
}
return $tmp;
}
function generateNumber($numbers, $char)
{
if (!is_array($numbers)){
if (strpos($numbers, $char) === false){
return array($numbers);
} else {
$tmp = $numbers;
$numbers = array();
for ($j = 0; $j <= 9; $j++){
$numbers[] = strReplaceNth($char, $j, $tmp, 0);
}
return generateNumber($numbers, $char);
}
} else {
for ($i = 0; $i < count($numbers); $i++){
if (strpos($numbers[$i], $char) === false){
return cleanup($numbers, $char);
} else {
$numbers = array_merge($numbers, generateNumber($numbers[$i], $char));
}
}
return generateNumber($numbers, $char);
}
}
function getCharPos($string, $char)
{
$pos = array();
for ($i = 0; $i < strlen($string); $i++){
if (substr($string, $i, 1) == $char){
$pos[] = $i;
}
}
return $pos;
}
$string = 'z12z';
$char = 'z';
$occurences = getCharPos($string, $char);
$numbers = array();
if (count($occurences) > 0){
$numbers = generateNumber($string, $char);
} else {
$numbers[] = $string;
}
print_r('<pre>');
print_r($numbers);die();

prevent Random PHP generator from including zeros

I have a php script that creates a random 10 digit order number:
// Assign order number length
$digits = 10;
// Create random order number to be stored with this order
$order_number = rand(pow(10, $digits-1), pow(10, $digits)-1);
How do I prevent this from ever including the digit zero 0 in the random 10 digit number? Thanks in advance!
You can do fancy base conversions, but in the end, the most straightforward way is to just get a string:
function random_string($count, $available) {
$result = '';
$max = strlen($available) - 1;
for($i = 0; $i < $count; $i++) {
$result .= $available[rand(0, $max)];
}
return $result;
}
…
$order_number = random_string($digits, '123456789');
You can treat it as a number of base 9
base_convert(rand(0, pow(9, $digits) - 1), 10, 9)
This will give you numbers with digits from 0 to 8.
Now just add 1 to every digit to make it 1 to 9
(pow(10, $digits) - 1) / 9
will give you a number filled with ones. Now just add it to your previous number and there you go:
$digits = 10;
$order_number = (pow(10, $digits) - 1) / 9 + base_convert(rand(0, pow(9, $digits) - 1), 10, 9);
Try this :D
function getRandom($from, $to){
$num = rand($from, $to);
$have_zero = true;
$strNum = strval($num);
while ($have_zero){
$have_zero = false;
for ($i = 0; $i < sizeof($strNum); $i++){
if ($strNum[$i] == '0'){
$have_zero = true;
$num = rand($from, $to);
$strNum = strval($num);
break;
}
}
}
return $num;
}
getRandom(1111111111, 9999999999);
You could use a simple function like this:
function getRandom($length) {
$numbers = '';
for($i = 0; $i < $length; $i++) {
$numbers .= rand(1, 9);
}
return $numbers;
}
echo getRandom(10);
I would make a function.
<?php
function myRandomNumberWithoutZeros($digits)
{
$result = str_replace("0", "",rand(pow(10,$digits-1), pow(10, $digits)-1)."");
$resultLength = strlen($result);
if($resultLength < $digits)
{
return intval($result.myRandomNumberWithoutZeros($digits-$resultLength));
}
return intval($result);
}
echo myRandomNumberWithoutZeros(10);
?>

Auto incrementing unique url

I am looking to create an auto incrementing unique string using PHP, containing [a-Z 0-9] starting at 2 chars long and growing when needed.
This is for a url shrinker so each string (or alias) will be saved in the database attached to a url.
Any insight would be greatly appreciated!
Note this solution won't produce uppercase letters.
Use base_convert() to convert to base 36, which will use [a-z0-9].
<?php
// outputs a, b, c, ..., 2o, 2p, 2q
for ($i = 10; $i < 99; ++$i)
echo base_convert($i, 10, 36), "\n";
Given the last used number, you can convert it back to an integer with intval() increment it and convert the result back to base 36 with base_convert().
<?php
$value = 'bc9z';
$value = intval($value, 36);
++$value;
$value = base_convert($value, 10, 36);
echo $value; // bca0
// or
echo $value = base_convert(intval($value, 36) + 1, 10, 36);
Here's an implementation of an incr function which takes a string containing characters [0-9a-zA-Z] and increments it, pushing a 0 onto the front if required using the 'carry-the-one' method.
<?php
function incr($num) {
$chars = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
$parts = str_split((string)$num);
$carry = 1;
for ($i = count($parts) - 1; $i >= 0 && $carry; --$i) {
$value = strpos($chars, $parts[$i]) + 1;
if ($value >= strlen($chars)) {
$value = 0;
$carry = 1;
} else {
$carry = 0;
}
$parts[$i] = $chars[$value];
}
if ($carry)
array_unshift($parts, $chars[0]);
return implode($parts);
}
$num = '0';
for ($i = 0; $i < 1000; ++$i) {
echo $num = incr($num), "\n";
}
If your string was single case rather than mixed, and didn't contain numerics, then you could literally just increment it:
$testString="AA";
for($x = 0; $x < 65536; $x++) {
echo $testString++.'<br />';
}
$testString="aa";
for($x = 0; $x < 65536; $x++) {
echo $testString++.'<br />';
}
But you could possibly make some use of this feature even with a mixed alphanumeric string
To expand on meagar's answer, here is how you can do it with uppercase letters as well and for number arbitrarily big (requires the bcmath extension, but you could as well use gmp or the bigintegers pear package):
function base10ToBase62($number) {
static $chars = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
$result = "";
$n = $number;
do {
$remainder = bcmod($n, 62);
$n = bcdiv($n, 62);
$result = $chars[$remainder] . $result;
} while ($n > 0);
return $result;
}
for ($i = 10; $i < 99; ++$i) {
echo base10ToBase62((string) $i), "\n";
}

How to calculate the hamming distance of two binary sequences in PHP?

hamming('10101010','01010101')
The result of the above should be 8.
How to implement it?
without installed GMP here is easy solution for any same-length binary strings
function HammingDistance($bin1, $bin2) {
$a1 = str_split($bin1);
$a2 = str_split($bin2);
$dh = 0;
for ($i = 0; $i < count($a1); $i++)
if($a1[$i] != $a2[$i]) $dh++;
return $dh;
}
echo HammingDistance('10101010','01010101'); //returns 8
You don't need to implement it because it already exists:
http://php.net/manual/en/function.gmp-hamdist.php
(If you have GMP support)
The following function works with hex strings (equal length), longer than 32 bits.
function hamming($hash1, $hash2) {
$dh = 0;
$len1 = strlen($hash1);
$len2 = strlen($hash2);
$len = 0;
do {
$h1 = hexdec(substr($hash1, $len, 8));
$h2 = hexdec(substr($hash2, $len, 8));
$len += 8;
for ($i = 0; $i < 32; $i++) {
$k = (1 << $i);
if (($h1 & $k) !== ($h2 & $k)) {
$dh++;
}
}
} while ($len < $len1);
return $dh;
}
If you don't have GMP support there is always something like this. Downside it only works on binary strings up to 32 bits in length.
function hamdist($x, $y){
for($dist = 0, $val = $x ^ $y; $val; ++$dist){
$val &= $val - 1;
}
return $dist;
}
function hamdist_str($x, $y){
return hamdist(bindec($x), bindec($y));
}
echo hamdist_str('10101010','01010101'); //8
Try this function:
function hamming($b1, $b2) {
$b1 = ltrim($b1, '0');
$b2 = ltrim($b2, '0');
$l1 = strlen($b1);
$l2 = strlen($b2);
$n = min($l1, $l2);
$d = max($l1, $l2) - $n;
for ($i=0; $i<$n; ++$i) {
if ($b1[$l1-$i] != $b2[$l2-$i]) {
++$d;
}
}
return $d;
}
You can easily code your hamming function with the help of substr_count() and the code provided in this comment on the PHP manual.
/* hamdist is equivilent to: */
echo gmp_popcount(gmp_xor($ham1, $ham2)) . "\n";
Try:
echo gmp_hamdist('10101010','01010101')

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