I want to allow alphanumeric characters and periods; however, the phrase cannot contain more two or more periods in a row, it cannot start or end with a period, and spaces are not allowed.
I am using both PHP and Javascript.
So far, I have /^(?!.*\.{2})[a-zA-Z0-9.]+$/
This works for allowing alphanumeric characters and periods, while denying spaces and consecutive periods, but I still am not sure how to check for starting and/or ending periods. How might I do this? and, is there an even better way to do what I already have?
It nearly always helps to draw a finite state machine to conceptualize what your regular expression should look like.
^(?:\w\.?)*\w$
here's a possible way
/^(?!\.)((?:[a-z\d]|(?<!\.)\.)+)(?<!\.)$/i
for more explanations and tests see here: http://www.regex101.com/r/rZ6yH4
edit: according to tyler's solution, here's him way, shortened and reduced to letters and digits
/^(?:[a-z\d]+(?:\.(?!$))?)+$/i
( http://www.regex101.com/r/dL5aG0 )
A start would be:
/^[^. ](?!.*\.{2})[a-zA-Z0-9.]+[^. ]$/
but it should be tested carefully.
Related
I have a regex that will be used to match #users tags.
I use lokarround assertions, letting punctuation and white space characters surround the tags.
There is an added complication, there are a type of bbcodes that represent html.
I have two types of bbcodes, inline (^B bold ^b) and blocks (^C center ^c).
The inline ones have to be passed thru to reach for the previous or next character.
And the blocks are allowed to surround a tag, just like punctuation.
I made a regex that does work. What I want to do now is to lower the number of steps that it does in every character that’s not going to be a match.
At first I thought I could do a regex that would just look for #, and when found, it would start looking at the lookarrounds, that worked without the inline bbcodes, but since lookbehind cannot be quantifiable, it’s more difficult since I cannot add ((\^[BIUbiu])++)* inside, producing much more steps.
How could I do my regex more efficient with fewer steps?
Here is a simplified version of it, in the Regex101 link there is the full regex.
(?<=[,\.:=\^ ]|\^[CJLcjl])((\^[BIUbiu])++)*#([A-Za-z0-9\-_]{2,25})((\^[BIUbiu])++)*(?=[,\.:=\^ ]|\^[CJLcjl])
https://regex101.com/r/lTPUOf/4/
A rule of thumb:
Do not let engine make an attempt on matching each single one character if
there are some boundaries.
The quote originally comes from this answer. Following regular expression reduces steps in a significant manner because of the left side of the outermost alternation, from ~20000 to ~900:
(?:[^#^]++|[#^]{2,}+)(*SKIP)(*F)
|
(?<=([HUGE-CHARACTER-CLASS])|\^[cjleqrd])
(\^[34biu78])*+#([a-z\d][\w-.]{0,25}[a-z\d])(\^[34biu78])*+(?=(?1))
Actually I don't care much about the number of steps being reported by regex101 because that wouldn't be true within your own environment and it is not obvious if some steps are real or not or what steps are missed. But in this case since the logic of regex is clear and the difference is a lot it makes sense.
What is the logic?
We first try to match what probably is not desired at all, throw it away and look for parts that may match our pattern. [^#^]++ matches up to a # or ^ symbols (desired characters) and [#^]{2,}+ prevents engine to take extra steps before finding out it's going nowhere. So we make it to fail as soon as possible.
You can use i flag instead of defining uppercase forms of letters (this may have a little impact however).
See live demo here
I'm getting insane over this, it's so simple, yet I can't figure out the right regex. I need a regex that will match blacklisted words, ie "ass".
For example, in this string:
<span class="bob">Blacklisted word was here</span>bass
I tried that regex:
((?!class)ass)
That matches the "ass" in the word "bass" bot NOT "class".
This regex flags "ass" in both occurences. I checked multiple negative lookaheads on google and none works.
NOTE: This is for a CMS, for moderators to easily find potentially bad words, I know you cannot rely on a computer to do the filtering.
If you have lookbehind available (which, IIRC, JavaScript does not and that seems likely what you're using this for) (just noticed the PHP tag; you probably have lookbehind available), this is very trivial:
(?<!cl)(ass)
Without lookbehind, you probably need to do something like this:
(?:(?!cl)..|^.?)(ass)
That's ass, with any two characters before as long as they are not cl, or ass that's zero or one characters after the beginning of the line.
Note that this is probably not the best way to implement a blacklist, though. You probably want this:
\bass\b
Which will match the word ass but not any word that includes ass in it (like association or bass or whatever else).
It seems to me that you're actually trying to use two lists here: one for words that should be excluded (even if one is a part of some other word), and another for words that should not be changed at all - even though they have the words from the first list as substrings.
The trick here is to know where to use the lookbehind:
/ass(?<!class)/
In other words, the good word negative lookbehind should follow the bad word pattern, not precede it. Then it would work correctly.
You can even get some of them in a row:
/ass(?<!class)(?<!pass)(?<!bass)/
This, though, will match both passhole and pass. ) To make it even more bullet-proof, we can add checking the word boundaries:
/ass(?<!\bclass\b)(?<!\bpass\b)(?<!\bbass\b)/
UPDATE: of course, it's more efficient to check for parts of the string, with (?<!cl)(?<!b) etc. But my point was that you can still use the whole words from whitelist in the regex.
Then again, perhaps it'd be wise to prepare the whitelists accordingly (so shorter patterns will have to be checked).
Is this one is what you want ? (?<!class)(\w+ass)
I have a regex that was written for me for passwords:
~^[a-z0-9!##\$%\^&\*\(\)]{8,16}$~i
It's supposed to match strings of alphanumerics and symbols of 8-16 characters. Now I need to remove the min and max length requirement as I need to split the error messages for user friendliness - I tried to just take out the {8,16} portion but then it breaks it. How would I do this? Thanks ahead of time.
I take it you're doing separate checks for too-long or too-short strings, and this regex is only making sure there are no invalid characters. This should do it:
~^[a-z0-9!##$%^&*()]+$~i
+ means one or more, * means zero or more; it probably doesn't matter which one you use.
I got rid of some unnecessary backslashes, too; none of those characters has any special meaning in a character class (inside the square brackets, that is).
First, a brief example, let's say I have this /[0-9]{2}°/ RegEx and this text "24º". The text won't match, obviously ... (?) really, it depends on the font.
Here is my problem, I do not have control on which chars the user uses, so, I need to cover all possibilities in the regex /[0-9]{2}[°º]/, or even better, assure that the text has only the chars I'm expecting °. But I can't just remove the unknown chars otherwise the regex won't work, I need to change it to the chars that looks like it and I'm expecting. I have done this through a little function that maps the "look like" to "what I expect" and change it, the problem is, I have not covered all possibilities, for example, today I found a new -, now we got three of them, just like latex =D - -- --- ,cool , but the regex didn't work.
Does anyone knows how I might solve this?
There is no way to include characters with a "similar appearance" in a regular expression, so basically you can't.
For a specific character, you may have luck with the Unicode specification, which may list some of the most common mistakes, but you have no guarantee. In case of the degree sign, the Unicode code chart lists four similar characters (\u02da, \u030a, \u2070 and \u2218), but not your problematic character, the masculine ordinal indicator.
Unfortunately not in PHP. ASP.NET has unicode character classes that cover things like this, but as you can see here, :So covers too much. Also as it's not PHP doesn't help anyway. :)
In PHP you are going to be limited to selecting the most common character sets and using them.
This should help:
http://unicode.org/charts/charindex.html
There is only one degree symbol. Using something that looks similar is not correct. There are also symbols for degree Fahrenheit and celsius. There are tons of minus signs unfortunately.
Your regular expression will indeed need to list all the characters that you want to accept. If you can't know the string's encoding in advance, you can specify your regular expression to be UTF-8 using the /u modifier in PHP: "/[0-9]{2}[°º]/u" Then you can include all Unicode characters that you want to accept in your character class. You will need to convert the subject string to UTF-8 also before using the regex on it.
I just stumbled into good references for this question:
http://www.unicode.org/Public/6.3.0/ucd/NameAliases.txt
https://docs.python.org/3.4/library/unicodedata.html#unicodedata.normalize
https://www.rfc-editor.org/rfc/rfc3454.html
Ok, if you're looking to pull temp you'll probably need to start with changing a few things first.
temperatures can come in 1 to 3 digits so [0-9]{1,3} (and if someone is actually still alive to put in a four digit temperature then we are all doomed!) may be more accurate for you.
Now the degree signs are the tricky part as you've found out. If you can't control the user (more's the pity), can you just pull whatever comes next?
[0-9]{1,3}.
You might have to beef up the first part though with a little position handling like beginning of the string or end.
You may also exclude all the regular characters you don't want.
[0-9]{1,3}[^a-zA-Z]
That will pick up all the punctuation marks (only one though).
I am looking to implement a system to strip out url's from text posted by a user.
I know there is no perfect solution and users will still attempt things like:
www dot google dot com
so I know that ultimately any solution will be flawed in some way... all I am looking to do really is reduce the number of people doing it.
Any suggestions, source or approaches appriciated,
Thanks
There are number of regular expression pattern matchers here. Some of them are quite complex.
I would suggest that running multiple ones may be a good idea.
You need to define exactly what you want to strip out. The stricter the definition, the more false positives you will get. The following example will remove any string with 3 characters, followed by a period, more letters, another period and 2-4 more letters:
$text = preg_replace('/[a-z]{3}\.[a-z]+\.[a-z]{2,4}/i', '', $text);
The other end of strictness might be anything that ends on a period and 2-4 letters (like .com):
$text = preg_replace('/[a-z]+\.[a-z]{2,4}/i', '', $text);
Note that the latter will strip out the last word of a sentence, the full stop and the first word of the next sentence if someone forgets to add a space inbetween the sentences.