mysql query ironing one search result on webpage? - php

Question

My query printed on webpage
SELECT * FROM products WHERE (product_name like '%meat%' OR description like '%meat%' OR ingradients like '%meat%') AND hide!=1 ORDER BY id ASC
If I run the same query query in mysql its showing 2 results with my php loop code its showing only one result,
my php code
<?php
$keyword=mysql_real_escape_string($_GET['Keyword']);
$query2 = "SELECT * FROM products WHERE (product_name like '%$keyword%' OR description like '%$keyword%' OR ingradients like '%$keyword%') AND hide!=1 ORDER BY id ASC ";
echo $query2 ;
$result2 = mysql_query($query2) or die('Error, query failed2');
if (mysql_num_rows($result2)>0){
mysql_data_seek($result2, 0);
$row2 = mysql_fetch_array($result2, MYSQL_ASSOC)
?>
<ul id="product-listing">
<?php
$i=1;
while($row2 = mysql_fetch_array($result2, MYSQL_ASSOC)){ ?>
<li <?php $i; if ($i%3==0) {echo "class=\"last\"";} ?>>
<div class="img">
<?php if ( $row2['new'] ==1 ) { ?>
<div class="new"><img src="images/new.png" width="18" height="41" /></div>
<?php } ?>
<img src="images/products/284X190/<?php echo $row2['image_1']; ?>" width="284" height="190" alt="" title="" /> </div>
<div class="name"><?php echo $row2['product_name']; ?></div>
<form action="" method="post">
<div class="price">Price:
<?php if ( $row2['market_price'] !=0 ) { ?>
<span> $<?php echo $row2['market_price']; ?> </span>
<?php } ?>
$<?php echo $row2['price']; ?></div>
<div class="add-to-cart">
<input type="image" src="images/btn-1.jpg" />
</div>
<div class="clear"></div>
</form>
</li>
<?php $i++; } ?>
</ul>
<?php } else { ?>
No Products,
<?php } ?>

Answer 1

You should use a while loop in your php.
while($item = mysql_fetch_assoc($query))
{
print_r($item); // echo out whatever you need to for each item returned
}