Leaving website disclaimer through PHP? - php

Due to legal reasons, I want every external hyper link posted on my forum to first link to a You're leaving this website and are being redirected to a website that is not our property... -disclaimer page. Something like http://www.mydomain.com/?leave=FINALURLHERE would do fine, but how do I set up this system?
I can easily make a script that does it for all URLs, but I only want this to happen to external URLs. Can anybody push me towards the right direction?

Presumably you're using some form of BBCode on your forums. You can just edit that to add your leaving page first.
If you're not, then you'll have to resort to some rather messy JavaScript. Something like:
var links = document.getElementsByTagName('a'), l = links.length, i,
domain = location.protocol+"//"+location.hostname+"/";
for( i=0; i<l; i++) {
if( links[i].href.substr(0,domain.length) != domain) {
links[i].href = "/exit.php?target="+encodeURIComponent(links[i].href);
}
}

Related

WordPress: append query string to all URL's

A user will be directed from a website to a landing page that will have a query string in the URL i.e. www.sitename.com?foo=bar&bar=foo. What I want to do, is then append that query string to all links on the page, preferably whether they were generated by WordPress or not (i.e. hard coded or not) and done server-side.
The reason for this is because their goal destination has to have the query string in the URL. I could use cookies, but i'd rather not since it has many other problems that it will bring with it for my specific use case.
I have explored the possibility of using .htaccess in conjunction with $_SERVER['QUERY_STRING'] to no avail. My understanding of .htaccess isn't great, but in my mind I assumed it would be possible to rewrite the current URL to be current URL + the variable that stores $_SERVER['QUERY_STRING'].
I've also explored add_rewrite_rule but couldn't find a logical way to achieve what I want.
Here's the Javascript solution I have, but as I said, I'd like a server-side solution:
const links = document.querySelectorAll('a');
links.forEach(link => {
if (!link.host.includes(location.host)) {
return;
}
const url = new URL(link.href);
const combined = Array.from(url.searchParams.entries()).reduce((agg, [key, val]) => {
agg.set(key, val);
return agg;
}, (new URL(location.href)).searchParams);
const nextUrl = [link.protocol, '//', link.host, link.pathname].join('');
link.href = (new URL(`${nextUrl}?${combined.toString()}`)).toString();
});

pass a value from one page to another outside querystring and without javascript?

One solution to automatically building navigation for a site is by scanning a folder for documents like this:
foreach(glob('pages/*.pg.php') as $_SITE_NAV_filePath):
$_SITE_NAV_filePath = explode('.pg',pathinfo($_SITE_NAV_filePath,PATHINFO_FILENAME));
$_SITE_NAV_fileName = $_SITE_NAV_filePath[0];
$_SITE_NAV_qv = preg_replace('/([A-Z])/','-$1',$_SITE_NAV_fileName); $_SITE_NAV_qv = trim($_SITE_NAV_qv,'-');
$_SITE_NAV_name = preg_replace('/([A-Z])/',' $1',$_SITE_NAV_fileName);
?>
<li><?=$_SITE_NAV_name?></li>
<?php
endforeach;
This code will turn "AnAwesomePage.pg.php" into a menu item like this :
<li>An Awesome Page</li>
This might be bad practice (?).
Anyway; I don't use this method very often since most of the time the sites have a database, and with that comes better solutions...
But my question is this:
Is there a way to prefix the filename with a integer followed by and underscore (3_AnAwesomePage.pg.php), for sorting order purposes, and pass it somehow to the destination page outside of the querystring and without any async javascript?
I could just explode the filename once again on "_" to get the sort order and store it somewhere, somehow?
This is the code for handeling the page query request:
$_SITE_PAGE['qv'] = $_GET['page'];
if (empty($_SITE_PAGE['qv'])){ $_SITE_PAGE['qv'] = explode('-','Home'); }
else { $_SITE_PAGE['qv'] = explode('-',$_GET['page']); }
$_SITE_PAGE['file'] = 'pages/'.implode($_SITE_PAGE['qv']).'.pg.php';
This code turns "An-Awesome-Page" back into "AnAwesomePage.pg.php" so it's possible to include it with php.
But with a prefix, it's not so easy.
The probliem is; Now there's no way to know what prefix number there was before since it has been stripped away from the query string. So I need to send it somehow along in the "background".
One very bad solution I came up with was to transform the navigation link into a form button and just _POST the prefix interger along with the form. At fist it sounded like a nice solution, but then I realized that once a user refreshes their page, it didn't look very good. And after all, that's not what forms are for either...
Any good solutions out there?
Or some other and better way for dealing with this?
There are two ways to keep that number saved, you can use cookies or php session variables.
But in this case, if user first enter the url in the browser or in a new browser, then he should be taken to default number.
Like you have:
1_first-page.php
2_first-page.php
3_first-page.php
If user enter the url like: domain.com/?page=first-page, you have to take him to 1_first-page.php to any number which you want to be default.

Change all domains in links on a website

need some advice on how to fix an ugly situation. our forum has resided on a couple of different domains over the years. we lost one domain that was in use 5-6 yrs ago and apparently some posts on our forum still have links in the threads that point to the old domain. what would be the most efficient way to change all links that point to
http://www.olddomain.com/stuff
point to
http://www.newdomain.com/stuff
the only part that has changed is the domain name, all thread variables in the url remain the same. is this something that is best done client side with javascript/jquery or should it be handled on a server level with a PHP function (dont know where to begin here..)? some pseudocode that doesn't seem to do what I need it to on the client side...
$('a').each(function() {
var domanin = 'newdomain';
if(href.search('olddomain.com') != -1) {
$(this).attr('href', newdomain);
}
});
thank you
I think it will make more sense if you handle this in the back end. Search engines will not notice the change you make through JavaScript.
So I advise you search for those domains in your database and replace them there.
Well you should probably do this on the server side, as it was said before, but if you can't for whatever reason, here is what you could do on the javascript side of things.
$('a').each(function() {
this.host = 'www.newdomain.com';
});
Note that this example uses jQuery, but you could do the same in plain javascript with getElementsByTagName.
To do this in JavaScript (w/ jQuery):
$('a').each(function() {
var link = this.href;
if(link.search('olddomain.com') != -1) {
this.href = link.replace('olddomain.com', 'newdomain.com');
}
});
Here is a jsfiddle: http://jsfiddle.net/tHXxK/
However I would suggest changing the links in the database, just get rid of all the old references. To do this create a script that searches for the old URLs and replaces them, something like:
$query = mysql_query("SELECT [id], [link] FROM [table] WHERE [link] LIKE '%//olddomain.com/%' OR [link] LIKE '%//www.olddomain.com/%'", $db) or trigger_erroR(mysql_error());
while ($row = mysql_query($query)) {
$iQuery = mysql_query("UPDATE [table] SET [link]='" . mysql_real_escape_string(str_replace(array('//olddomain.com/', '//www.olddomain.com/'), array('//newdomain.com/', '//www.newdomain.com/'), $row['link']) . "' WHERE [id]=" . $row['id']), $db) or trigger_error(mysql_error());
}
If it'd be me, I would have used a server side script to replace all instances of the old domain with the new one and be done with it once and for all.
I assume your forum DB is rather a large one. For the sake of system resources you can write a multi-step script and do the job in multiple steps.
This is a better approach as it can improve the data consistency for search engines as well.

How to get the users who like your page? [duplicate]

I was wondering if it was possible to query the following:
List of (all) users who like my facebook page, and
Additional information those users have made publicly available (beyond first and last name)
Basically looking to generate detailed marketing stats of users who like my facebook page, if possible. Any suggestions or alternatives welcome.
Thank you.
I am afraid this is NOT possible, follow this bug for more information.
Another proof is the page_fan table you will notice that only the uid field is indexable so you need to know the user id to search it and not the page_id, as you know if a user "likes" a page this would mean he is a "fan" of that page.
After being actively working with the Facebook API for a while now, and following the announcements and API releases (and deprecations) along with the introduction and changes of policies, I can understand that Facebook will only share info about their users by letting them explicitly do so (a.k.a interact/authorize your Apps).
And hence the best thing to do in the absence of such feature is:
Understand your audience through Page Insights
Collect fans interests & info by creating custom apps through Page Tabs and using other Facebook features like Questions
Alright, nobody wants to break Facebook's TOS but they have tied our hands on our own basic data. So, scraping is illegal, but not saving a page. What I have done (and note that I needed this for offline purpose anyway):
Go to https://www.facebook.com/browse/?type=page_fans&page_id={FAN PAGE ID}
Scroll down until you have all of your fans. Save this page on your local machine, let's say, Facebook.html.
Now, using ruby and nokogiri:
require 'nokogiri'
>true
f = File.open('/your_path/Facebook.html')
doc = Nokogiri::HTML.parse(f.read)
doc.xpath('//div[#class="fsl fwb fcb"]/a').each {|link| puts link.content}
Do a graph search likes this: "People who like [your fanpage's name]". You will all the result.
Then create shortcut on your browser with this javascripts code, it will click on the View more link and scrolling until all result are shown in the page:
javascript: i = 0;minutes = 30;counter = minutes * 60;function repeatScroll() {
if (i < counter) {window.scrollTo(0, document.body.scrollHeight);i++;}
setTimeout(repeatScroll, 1000);}repeatScroll();
After that, create other shortcut and run this js code to retrieve all UID from the search result:
javascript:var txt="";e=document.getElementsByClassName("FriendRequestOutgoing");
for(var i=0; i<e.length; i++) {v=e[i].getAttribute("data-profileid");
if(v) txt+=v+"\n"}document.body.innerHTML="<textarea>"+txt+"</textarea>";
A textarea box will appear in the screen with all uid inside. Just copy it to your notepad and import into your Custom Audience in Facebook Ad Manager.
I created and use this code everyday to get all UID with criterial I need.
You can launch any graph search you want.
This is homemade code, so using it without your own responsibility :)
Enjoy them.
It's possible, just not with FQL anymore.
Do a GET of https://www.facebook.com/browse/?type=page_fans&page_id={FAN PAGE ID} and scrape out the users.
Viola.
Now you can get people on your page with this link, or click on Settings button, than on People on the left sidebar. https://www.facebook.com/[PAGENAME]/settings/?tab=people_and_other_pages
If you want to get all the user's photo, press F12 and add these codes to the Console:
javascript:i=0;minutes=30;counter=minutes*60;function repeatScroll(){if(i<counter){window.scrollTo(0, document.body.scrollHeight);i++;}setTimeout(repeatScroll,1000);}repeatScroll();
than, when you reached the bottom of the page:
javascript:var txt="";e=document.getElementsByClassName("img"); for(var i=0; i<e.length; i++) {v=e[i].getAttribute("src"); if(v) txt+="<img src='"+v+"'>\n"}document.body.innerHTML="<textarea>"+txt+"</textarea>";
To display photos: create a HTML page and first insert these lines into that file:
<meta charset="utf-8">
<style>img { width:21px; margin:-1px; }</style>
<div style="width:851px; height:315px;background-color:white;">
<!-- PASTE HERE PHOTOS' CODE YOU GET -->
<span style="color:#3B5998;font-weight:bold;font-size:20px;margin-bottom:4px;">600 like, thank you!</span>
<!-- PASTE HERE PHOTOS' CODE YOU GET -->
</div>
Then create shortcut on your browser with this javascript code, it will click on the View more link and scrolling until all result are shown in the page:
i = 0;
minutes = 30;
counter = minutes * 60;
function repeatScroll() {
if (i < counter) {
window.scrollTo(0, document.body.scrollHeight);
i++;
}
setTimeout(repeatScroll, 1000);
}
repeatScroll();
After that, create other shortcut and run this js code to retrieve all UID from the search result:
var e=document.getElementsByClassName("fsl fwb fcb");
var ids = [];
for(var i = 0 ; i < e.length; i++){
ids.push(JSON.parse(e[i].childNodes[0].getAttribute("data-gt")).engagement.eng_tid);
}
console.log(ids);
load all list
i = 0;
minutes = 30;
counter = minutes * 60;
function repeatScroll() {
if (i < counter) {
window.scrollTo(0, document.body.scrollHeight);
i++;
}
setTimeout(repeatScroll, 1000);
}
repeatScroll();
get id
var e=document.getElementsByClassName("_3cb8");
var ids = [];
for(var i = 0 ; i < e.length; i++){
ids.push(e[i].getAttribute("href"));
}
console.log(ids);
You can get it using facebook open graph.
https://graph.facebook.com/<your-page-name-or-page-id>/likes
For example :
https://graph.facebook.com/chickfila/likes
You need to send graph api call using "id" for more detail about user who like you page.
However, this call will retrieve the other Facebook objects that the page (Chickfila) has liked, NOT the users who have liked the Chickfila page.

Downloading Youtube videos with PHP [closed]

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I am searching for a way to download Youtube videos using PHP. I have searched how to do this for hours but unfortunately all the Google results I find are years old and do not work anymore.
I would appreciate it if someone could explain how to do this, or give a link to an up-to-date article that explains it in detail.
Thanks very much.
The first thing you should do is get a tool like Fiddler and visit a YouTube video page. In Fiddler, you will see all of the files that make up that page, including the FLV itself. Now, you know that the video isn't one of the CSS files, nor is it the image files. You can ignore those. Look for a big file. If you look at the URL, it begins with /videoplayback.
Now, once you've found it, figure out how the browser knew to get that file. Do a search through the sessions (Ctrl+F) and look for "videoplayback". You will see a hit on the first page you went to, like http://www.youtube.com/watch?v=123asdf. If you dig through that file, you'll see a DIV tag with the ID of "watch-player". Within that there is a script tag to setup the flash player, and within that are all of the flash parameters. Within those is the URL to the video.
So now you know how to use your tools to figure out how the browser got to it. How do you duplicate this behavior in PHP?
Do a file_get_contents() on the page that references the video. Ignore everything not in that watch-player div. Parse through the code until you find that variable that contains the URL. From there you will probably have to unescape that URL. Once you have it, you can do a file_get_contents() (or some other download method, depending on what you are trying to do) to get the URL. it is that simple. Your HTML parsing code will be the most complex.
Finally, keep in mind what you are about to do may be illegal. Check the EULA.
Nobody writes manuals/howtos that become outdated every four weeks. The closest you can get is inspecting the actual extraction methods in a contemporary implementation. Quite readable:
http://bitbucket.org/rg3/youtube-dl/raw/2010.08.04/youtube-dl
If you don't want to read through/reimplement it, it's obviously not simple, you could just run it as-is from PHP:
system("youtube-dl '$url'");
last time i was working on fixing one of the brocken chrome extension to download youtube video. I fixed it by altering the script part. (Javascript)
var links = new String();
var downlink = new String();
var has22 = new Boolean();
has22 = false;
var Marked=false;
var FMT_DATA = fmt_url_map;//This is html text that you have to grab. In case of extension it was readily available through:document.getElementsByTagName('script');
var StrSplitter1='%2C', StrSplitter2='%26', StrSplitter3='%3D';
if (FMT_DATA.indexOf(',')>-1) { //Found ,
StrSplitter1=',';
StrSplitter2=(FMT_DATA.indexOf('&')>-1)?'&':'\\u0026';
StrSplitter3='=';
}
var videoURL=new Array();
var FMT_DATA_PACKET=new Array();
var FMT_DATA_PACKET=FMT_DATA.split(StrSplitter1);
for (var i=0;i<FMT_DATA_PACKET.length;i++){
var FMT_DATA_FRAME=FMT_DATA_PACKET[i].split(StrSplitter2);
var FMT_DATA_DUEO=new Array();
for (var j=0;j<FMT_DATA_FRAME.length;j++){
var pair=FMT_DATA_FRAME[j].split(StrSplitter3);
if (pair.length==2) {
FMT_DATA_DUEO[pair[0]]=pair[1];
}
}
var url=(FMT_DATA_DUEO['url'])?FMT_DATA_DUEO['url']:null;
if (url==null) continue;
url=unescape(unescape(url)).replace(/\\\//g,'/').replace(/\\u0026/g,'&');
var itag=(FMT_DATA_DUEO['itag'])?FMT_DATA_DUEO['itag']:null;
var itag=(FMT_DATA_DUEO['itag'])?FMT_DATA_DUEO['itag']:null;
if (itag==null) continue;
var signature=(FMT_DATA_DUEO['sig'])?FMT_DATA_DUEO['sig']:null;
if (signature!=null) {
url=url+"&signature="+signature;
}
if (url.toLowerCase().indexOf('http')==0) { // validate URL
if (itag == '5') {
links += '<span class="yt-uix-button-menu-item" id="v240p">FLV (240p)</span>';
}
if (itag == '18') {
links += '<span class="yt-uix-button-menu-item" id="v360p">MP4 (360p)</span>';
}
if (itag == '35') {
links += '<span class="yt-uix-button-menu-item" id="v480p">FLV (480p)</span>';
}
if (itag == '22') {
links += '<span class="yt-uix-button-menu-item" id="v720p">MP4 HD (720p)</span>';
}
if (itag == '37') {
links += ' <span class="yt-uix-button-menu-item" id="v1080p">MP4 HD (1080p)</span>';
}
if (itag == '38') {
links += '<span class="yt-uix-button-menu-item" id="v4k">MP4 HD (4K)</span>';
}
FavVideo();
videoURL[itag]=url;
console.log(itag);
}
}
You can get separate video link from videoURL[itag] array.
Above logic can be converted to PHP easily
The extension can be downloaded from location http://www.figmentsol.com/chrome/ytdw/
I hope this would help someone. This is working solution (date:06-04-2013)

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