how to unset post array? - php

every time i am refreshing the page and i am getting the same value stored in the post array.
i want execution of echo statement only after submit and after refreshing no echo results..
<?php
if(isset($_POST['submit']))
{
$name = $_POST['name'];
echo "User name : <b> $name </b>";
}
?>
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input type="text" name="name"><br>
<input type="submit" name="submit" value="Submit Form"><br>
</form>

From just a form, you won't be able to check if it was a refresh, or a first submit, regardless of using GET or POST method.
To ensure a single message, you need to:
a. redirect the user to somewhere else after you processed the request.
if(isset($_POST['submit'])) {
// process data
header("Location: new-url");
}
And display the message on the other URL.
b. set a cookie / session variable, which tells you the form was already processed.
if(isset($_POST['submit']) && !isset($_SESSION['form_processed'])) {
$_SESSION['form_processed'] = true;
}
This second approach will kill your form until the user closes the browser, so you should do something more complex - like storing another hidden field in the form, and storing that in the session.

If you submit a form and then refresh the resulting page, the browser will re-post the form (usually prompts first). That is why the POST data is always present.
An option would be to store a session variable and have it sent in the form, then check if it matches in the form processing code - to determine if it is a re-post or not.
Within the form:
<input type="hidden" name="time" value="<?php echo $time; ?>" />
In the PHP:
session_start();
if(isset($_POST['submit']))
{
if(isset($_SESSION['time']) && $_SESSION['time'] == $_POST['time'])
{
echo "User name : <b> $name </b>";
}
}
$time = $_SESSION['time'] = time();
Another option is to redirect after processing the post data:
if(isset($_POST['submit']))
{
...
...
header('Location: ' . basename($_SERVER['PHP_SELF']));
exit();
}

You need to maintain a state as to whether $name has already been displayed or not. The easiest way is probably to maintain that state in a browser cookie.
<?php
$nonce = $_COOKIE['nonce'];
$new_nonce = mt_rand();
setcookie('nonce', $new_nonce);
if(isset($_POST['submit']) && $_POST['nonce'] == $nonce)
{
$name = $_POST['name'];
echo "User name : <b> $name </b>";
}
?>
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input type="hidden" name="nonce" value="<?php echo $new_nonce ?>">
<input type="text" name="name"><br>
<input type="submit" name="submit" value="Submit Form"><br>
</form>
Problems
you are polluting the user “session” with stale variable.
this will break if your user opens several windows (or tabs) to the same page. To fix this you would have to change the nonce cookie into an array of nonces, and update it accordingly.

if you want refresh page after submit use
<form method="get"
sure if your form hasn't a lot of data and also need to use $_GET instead of $_POST variable:)
correct way for you, but this logic is not good, need to refactor this script:
<?php
if(isset($_POST['submit']))
{
$name = $_POST['name'];
echo "User name : <b> $name </b>";
unset($_POST['submit']);
}
?>
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input type="text" name="name"><br>
<input type="submit" name="submit" value="Submit Form"><br>
</form>

Related

Php POST method to 2 page

I just sent data to a page called diak_o.php with post method but I need to use this data on an another page. How can I send it to two pages or send from the first page to the next?
<form action="diak_o.php" method="post">
<input type="text" name="name"><br>
<input type="submit" value="Bejelentkezés" />
</form>
You could store it in Sessions and access it on multiple pages like this:
Page 1:
<form action="page2.php" method="post">
<input type="text" name="page1text"/>
<input type="submit"/>
</form>
Page 2:
<?php
session_start();
$dataFromPage1 = $_SESSION['page1text'] = $_POST['page1text'];
echo $dataFromPage1;
?>
You can use $_SESSION or just but i think $_POST should still work in the next file too...
when you send that data from this page to second page like diak_o.php in this page you can access it by below code.
in diak_o.php write code like below.
<?PHP
session_start();
echo $_POST['name'];
$_SESSION["name"] = $_POST['name'];
?>
in the other page you can use $_SESSION["name"] by accessing it.
you can also use COOKIE OF PHP.
On this URL there are different methods for passing data from one page to another.
http://www.discussdesk.com/how-to-get-data-from-one-page-to-another-page-in-php.htm
Thanks.
You need to give your button a name attribute, then on diak_o.php you check if the button isset, after that you check if the text input is not empty, else assign a session to the text input
Your Form
<form action="diak_o.php" method="post">
<input type="text" name="name"><br>
<input type="submit" value="Bejelentkezés" name="submit" />
</form>
diak_o.php
<?php
session_start();
if(isset($_POST['submit'])){
if(empty($_POST['name'])){
die("enter name");
}else{
$_SESSION['name']= $_POST['name'];
}
}
?>
anotherpage.php
<?php
session_start();
echo $_SESSION['name']; // will output the value from form.
?>
when ever your wanna use the value on your pages, just use $_SESSION['name'];

How to Automatically POST Form if Variable is passed via URL

I want form to post automatically if zip variable is passed from URL.
URL looks like: www.sitename.com/maps/zipsearch.php?zip=90210
Form looks like:
<form method="post">
Zipcode:
<input name="zip" value="<?php echo (isset($_GET["zip"]))? $_GET["zip"]:"";?>" />
<input type="submit" name="subbut" value="Find instructors" />
</form>
So it fills the input box with zip code but I would like it to post automatically to see results again if zip is passed.
Maybe an IF / THEN?
Any help would be appreciated.
You mean to echo the value passed in GET parameter?
<input type="submit" name="subbut" value="<?php echo isset($_GET['zip'])?$_GET['zip']:'Find'; ?>" />
EDIT
Or, if you are asking about submitting the form, then something like this might work I believe:
<input type="submit" name="subbut" value="<?php echo isset($_GET['zip'])?$_GET['zip']:'Find'; ?>" />
<?php if( isset( $_GET['zip'] ) ) { ?>
<script>
document.forms["name_of_the_form_here"].submit();
</script>
<?php } ?>
like this:
<form id="form" action="form.php" method="post">
Zipcode:
<input name="zip" value="<?php echo (isset($_GET["zip"]))? $_GET["zip"]:"";?>" />
<input type="submit" name="subbut" value="Find instructors" />
</form>
<?php if (isset($_GET["zip"])): ?>
<script>document.getElementById('form').submit()</script>
<?php endif; ?>
since passing data via URL means GET method, so i think you have a little misconception with your question.
if you would like to post automatically you dont need to show form.
just put this code in your zipsearch.php
if ($_GET['zip'] != ""){
// do what you want if zip parameter is not null
}else{
// do what you want if zip parameter is null
}
It looks like your form is submitting to itself. (Eg. zipsearch.php displays HTML form. When user submits form, it is posted back to zipsearch.php which displays the search results).
If this is the case, you don't have to post anything, because you are already inside the file that handles the form submission. You could do something like this:
<?php
if (isset ($_POST['zip'])) {
$zip = $_POST['zip']; /* Form was submitted */
} else if (isset ($_GET['zip'])) {
$zip = $_GET['zip']; /* "?zip=" parameter exists */
}
if (isset ($zip)) {
/* Display search results */
} else {
/* Display form */
}

Saving form values with php and calling cookie using SESSION

I am making a form in html. When a person clicks on submit, it checks if certain fields are filled correctly, so pretty simple form so far.
However, i want to save the text which is typed into the fields, if a person refreshes the page. So if the page is refreshed, the text is still in the fields.
I am trying to achieve this using php and a cookie.
// Cookie
$saved_info = array();
$saved_infos = isset($_COOKIE['offer_saved_info']) ? explode('][',
$_COOKIE['offer_saved_info']) : array();
foreach($saved_infos as $info)
{
$info_ = trim($info, '[]');
$parts = explode('|', $info_);
$saved_info[$parts[0]] = $parts[1];
}
if(isset($_SESSION['webhipster_ask']['headline']))
$saved_info['headline'] = $_SESSION['webhipster_ask']['headline'];
// End Cookie
and now for the form input field:
<div id="headlineinput"><input type="text" id="headline"
value="<?php echo isset($_SESSION['webhipster_ask']['headline']) ?
$_SESSION['webhipster_ask'] ['headline'] : ''; ?>"
tabindex="1" size="20" name="headline" /></div>
I am new at using SESSION within php, so my quesiton is:
Is there a simpler way of achieving this without using a cookie like above?
Or what have i done wrong in the above mentioned code?
First thing is I'm pretty sure you're echo should have round brackets around it like:
echo (isset($_SESSION['webhipster_ask']['headline']) ? value : value)
That's not really the only question your asking though I think.
If you're submitting the data via a form, why not validate using the form values, and use the form values in your html input value. I would only store them to my session once I had validated the data and moved on.
For example:
<?php
session_start();
$errors=array();
if($_POST['doSubmit']=='yes')
{
//validate all $_POST values
if(!empty($_POST['headline']))
{
$errors[]="Your headline is empty";
}
if(!empty($_POST['something_else']))
{
$errors[]="Your other field is empty";
}
if(empty($errors))
{
//everything is validated
$_SESSION['form_values']=$_POST; //put your entire validated post array into a session, you could do this another way, just for simplicity sake here
header("Location: wherever.php");
}
}
if(!empty($errors))
{
foreach($errors as $val)
{
echo "<div style='color: red;'>".$val."</div>";
}
}
?>
<!-- This form submits to its own page //-->
<form name="whatever" id="whatever" method="post">
<input type="hidden" name="doSubmit" id="doSubmit" value="yes" />
<div id="headlineinput">
<input type="text" id="headline" value="<?php echo $_POST['headline'];?>" tabindex="1" size="20" name="headline" />
<!-- the line above does not need an isset, because if it is not set, it will simply not have anything in it //-->
</div>
<input type="submit" value="submit" />
</form>

Add data to sql on button click

my page receives data which i retrieve with $_post. I display some data and at the bottom of page my button has to save data to mysql. I could submit form to next page, but how do i access the data that I have retrieved with post then? Lets say i have following code (in reality alot more variables ..):
<?php
$v= $_POST["something"];
echo $v;
echo "Is the following information correct? //this would be at the bottom of the page with the buttons
?>
<input type="button" value="submit data" name="addtosql">
You can do it in two methods:
1) You can save the POST variable in a hidden field.
<input type="hidden" name="somevalue" value="<?php if(isset($_POST["something"])) echo $_POST["something"];?>" >
The hidden value also will get passed to the action page on FORM submission. In that page you can access this value using
echo $_POST['somevalue'];
2) Use SESSION
You can store the value in SESSION and can access in any other page.
$v= $_POST["something"];
session_start();
$_SESSION['somevalue']=$v;
and in next page access SESSION variable using,
session_start();
if(isset($_SESSION['somevalue']))
echo $_SESSION['somevalue'];
Take a look. Below every thing should be on single php page
// first create a function
function getValue($key){
if(isset($_POST[$key]))
return $_POST[$key];
else
return "";
}
// process your form here
if(isset($_POST['first_name']){
// do your sql stuff here.
}
// now in html
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input type="text" name="first_name" value="<?php echo getValue("first_name"); ?>" />
<input type="submit" />
</form>

when working with php sessions form input data not getting save

Hey i have having a problem i just found working with session i am using at the moment firefox 23 but i have check that on some other browsers as well.
I have created a simple code where i have created a form and just opened a session and i have noticed that once i have submit the form and then click on "Go Back" to return to the page the info i have inserted is not saved on the browser.
Normally when you submit a form once you go back the data you have entered is saved and you can just edit the inputs and resent it but when i have used session_start() on the page that function stopped working.
Well i am guessing maybe the browser save the form data in sessions as well and once i use it in php it's somehow effect the normally way the browser work.
I hope someone know how i can fix that i know you are able to save sessions with html5 and javascript now but i would rather do that with php.
Attached below is the code i have been using:
<?php
session_start();
// store session data
$_SESSION['name']= "name";
?>
<form method="post" action="index.php">
<input type="text" name="email" placeholder="Email" /><br />
<input type="text" name="name" placeholder="Name" /><br />
<input type="submit" name="submit" value="Submit" />
</form>
The browser refilling the form is simply that, the browser. This is not something you should rely upon for form re-population.
Your PHP code does not attempt to refill the form by printing anything within the input value="" attributes.
Generally when a form is submitted a programmer will validate the submitted values, store them in some fashion (the session is fine) and if they need them to reappear on the form they will print those values back out like I described.
I think you want to put the CORRECT fields back into the form values and blank out the incorrect ones. You don't have to use sessions:
<?php // formx.php
// accept POST variables
$fld1 = isset($_POST['fld1']) ? $_POST['fld1'] : "";
$fld2 = isset($_POST['fld2']) ? $_POST['fld2'] : "";
// edit variables
$errmsg = "";
if (!$fld1 == "") { if($fld1 <> "1") { $errmsg .= "fld1 is not 1<br />\n"; $fld1 = ""; } }
if (!$fld2 == "") { if($fld2 <> "2") { $errmsg .= "fld2 is not 2<br />\n"; $fld2 = ""; } }
if ($errmsg == "") { $errmsg = "Values accepted"; }
// output form
$body = <<<EOD
<html>
<body>
<div>%s</div><!-- errmsg -->
<form name="formnm" action="formx.php" method="post">
Enter "1" <input type="text" name="fld1" value="%s" /><br />
Enter "2" <input type="text" name="fld2" value="%s" /><br />
<input type="submit" value="Submit" />
</form>
</body>
</html>
EOD;
printf($body, $errmsg, $fld1, $fld2);
?>

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