I have a string which i want to check with a regex. It is not allowed for it to start with a 0. So please see the following examples:
012344 = invalid
3435545645 = valid
021 = invalid
344545 = valid
etc.
How does this regex look in PHP?
PS. This must be a regex solution!
The REGEX should looks like that :
^[1-9][0-9]*$
PHP Code :
<?php
$regex = "#^[1-9][0-9]*$#";
function test($value, $regex)
{
$text = "invalid";
if(preg_match($regex, $value)) $text = "valid";
return $value+" = "+$text+"\n\r";
}
echo test('012345', $regex);
echo test('12345', $regex);
?>
Well it would be a simple /[1-9][0-9]*/.
Please research your question better next time.
This could have also helped you: Regular expression tester
Edit:
Yeah, the answer got downvoted, because it's missing the anchors and seems to be wrong. For completess' sake, I posted the php code I would use with this regex. And no it's not wrong. It may not be the most elegant way, but I like checking whether the regex matched the whole string afterwards more. One reason is that to debug a regex and see what it actually matched I just have to comment out === $value after return $matches[0]
<?php
function matches($value) {
preg_match("/[1-9][0-9]*/", $value, $matches);
return $matches[0] === $value;
}
//Usage:
if (matches("1234")) {
//...
}
?>
Related
I have some words with | between each one and I have tried to use preg_match to detect if it's containing target word or not.
I have used this:
<?php
$c_words = 'od|lom|pod|dyk';
$my_word = 'od'; // only od not pod or other word
if (preg_match('/$my_word/', $c_words))
{
echo 'ok';
}
?>
But it doesn't work correctly.
Please help.
No need for regular expressions. The functions explode($delimiter, $str); and in_array($needle, $haystack); will do everything for you.
// splits words into an array
$array = explode('|', $c_words);
// check if "$my_word" exists in the array.
if(in_array($my_word, $array)) {
// YEP
} else {
// NOPE
}
Apart from that, your regular expression would match other words containing the same sequence too.
preg_match('/my/', 'myword|anotherword'); // true
preg_match('/another/', 'myword|anotherword'); // true
That's exactly why you shouldn't use regular expressions in this case.
You can't pass a variable into a string with single quotes, you need to use either
preg_match("/$my_word/", $c_words);
Or – and I find that cleaner :
preg_match('/' .$my_word. '/', $c_words);
But for something as simple as that I don't even know if I'd use a Regex, a simple if (strpos($c_words, $my_word) !== 0) should be enough.
You are using preg_match() the wrong way. Since you're using | as a delimiter you can try this:
if (preg_match('/'.$all_words.'/', $my_word, $c_words))
{
echo 'ok';
}
Read the documentation for preg_match().
So, I know there are a ton of related questions on SO, but none of them are quite what I'm looking for. I'm trying to implement a PHP function that will convert text URLs from a user-generated post into links. I'm using the 'improved' Regex from Daring Fireball towards the bottom of the page: http://daringfireball.net/2010/07/improved_regex_for_matching_urls
The function does not return anything, and I'm not sure why.
<?php
if ( false === function_exists('linkify') ):
function linkify($str) {
$pattern = '(?xi)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:\'".,<>?«»“”‘’]))';
return preg_replace($pattern, "\\0", $str);
}
endif;
?>
Can someone please help me get this to work?
Thanks!
Try this:
$pattern = '(?xi)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`\!()\[\]{};:\'".,<>?«»“”‘’]))';
return preg_replace("!$pattern!i", "\\0", $str);
PHP's preg function do need delimiters. The i at the end makes it case-insensitive
Update
If you use # as the delimiter, you wan't need to escape the ! in the pattern as such use the original pattern string (the pattern does not have a #): "#$pattern#i"
Update 2
To ensure that the links are correct, do this:
$pattern = '(?xi)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:\'".,<>?«»“”‘’]))';
return preg_replace_callback("#$pattern#i", function($matches) {
$input = $matches[0];
$url = preg_match('!^https?://!i', $input) ? $input : "http://$input";
return '' . "$input";
}, $str);
This will now append http:// to the urls so that browser doesn't think it is a relative link.
I was looking to just get the urls from a string using the same regex from the answer above by d_inevitable and wasn't looking to turn them into links or care about the rest of the string, I only wanted the urls with in the string so this is what I did. Hope it helps.
/**
* Returns the urls in an array from a string.
* This dos NOT return the string, only the urls with-in.
*/
function get_urls($str){
$regex = '(?xi)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:\'".,<>?«»“”‘’]))';
preg_match_all("#$regex#i", $str, $matches);
$urls = $matches[0];
return $urls;
}
Friends,
I'm rushing towards deadline and I think that makes me do childish mistakes.
Here I have validation that requires regex and each time I input valid expression preg_match returns false. It is long now I'm trying to spot error but I cannot! I have googled and AFAICS, things seems alright please help me spot the error.
Thanks,
Stefano
<?php
$string = "37961/T.08";//valid ID, it is supposed to match
$regex = '/^[0-9]{5,}/[a-zA-Z]\.[0-9]{2,}/';
if (preg_match($regex, $string)) {
echo 'matched expression!';
} else {
echo 'unmatched expression pattern';//comes here instead of valid regex!
}
?>
Looks like you need to escape your /
$regex = '/^[0-9]{5,}\/[a-zA-Z]\.[0-9]{2,}/';
i have the following pattern that i am trying to solve with preg_match
http://www.1.com/images/001/001/001/1.jpg
http://www.2.com/images/002/002/002/2.jpg
http://www.3.com/images/003/003/003/3.jpg
http://www.4.com/images/004/004/004/4.jpg
http://www.5.com/images/005/005/005/5.jpg
etc.
i need to get only everything that goes after IMAGES and ends before last slash, for example 002/002/002
Hope i could explain well.
Thank you.
You have to use preg_match_all in this case.
<?php
$in = 'http://www.1.com/images/001/001/001/1.jpg
http://www.2.com/images/002/002/002/2.jpg
http://www.3.com/images/003/003/003/3.jpg
http://www.4.com/images/004/004/004/4.jpg
http://www.5.com/images/005/005/005/5.jpg';
if (preg_match_all('~images/(.*?)\.jpg~i', $in, $matches)) {
print_r ($matches[1]);
} else {
echo 'NOT FOUND';
}
$var="UseCountry=1
UseCountryDefault=1
UseState=1
UseStateDefault=1
UseLocality=1
UseLocalityDefault=1
cantidad_productos=5
expireDays=5
apikey=ABQIAAAAFHktBEXrHnX108wOdzd3aBTupK1kJuoJNBHuh0laPBvYXhjzZxR0qkeXcGC_0Dxf4UMhkR7ZNb04dQ
distancia=15
AutoCoord=1
user_add_locality=0
SaveContactForm=0
ShowVoteRating=0
Listlayout=0
WidthThumbs=100
HeightThumbs=75
WidthImage=640
HeightImage=480
ShowImagesSystem=1
ShowOrderBy=0
ShowOrderByDefault=0
ShowOrderDefault=DESC
SimbolPrice=$
PositionPrice=0
FormatPrice=0
ShowLogoAgent=1
ShowReferenceInList=1
ShowCategoryInList=1
ShowTypeInList=1
ShowAddressInList=1
ShowContactLink=1
ShowMapLink=1
ShowAddShortListLink=1
ShowViewPropertiesAgentLink=1
ThumbsInAccordion=5
WidthThumbsAccordion=100
HeightThumbsAccordion=75
ShowFeaturesInList=1
ShowAllParentCategory=0
AmountPanel=
AmountForRegistered=5
RegisteredAutoPublish=1
AmountForAuthor=5
AmountForEditor=5
AmountForPublisher=5
AmountForManager=5
AmountForAdministrator=5
AutoPublish=1
MailAdminPublish=1
DetailLayout=0
ActivarTabs=0
ActivarDescripcion=1
ActivarDetails=1
ActivarVideo=1
ActivarPanoramica=1
ActivarContactar=1
ContactMailFormat=1
ActivarReservas=1
ActivarMapa=1
ShowImagesSystemDetail=1
WidthThumbsDetail=120
HeightThumbsDetail=90
idCountryDefault=1
idStateDefault=1
ms_country=1
ms_state=1
ms_locality=1
ms_category=1
ms_Subcategory=1
ms_type=1
ms_price=1
ms_bedrooms=1
ms_bathrooms=1
ms_parking=1
ShowTextSearch=1
minprice=
maxprice=
ms_catradius=1
idcatradius1=
idcatradius2=
ShowTotalResult=1
md_country=1
md_state=1
md_locality=1
md_category=1
md_type=1
showComments=0
useComment2=0
useComment3=0
useComment4=0
useComment5=0
AmountMonthsCalendar=3
StartYearCalendar=2009
StartMonthCalendar=1
PeriodOnlyWeeks=0
PeriodAmount=3
PeriodStartDay=1
apikey=ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
";
in that string only i want "api==ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ";
plz guide me correctly;
EDIT
As shamittomar pointed out, the parse_str will not work for this situation, posted the proper regex below.
Given this seems to be a QUERY STRING, use the parse_str() function PHP provides.
UPDATE
If you want to do it with regex using preg_match() as powertieke pointed out:
preg_match('/apikey=(.*)/', $var, $matches);
echo $matches[1];
Should do the trick.
preg_match(); should be right up your alley
people are so fast to jump to preg match when this can be done with regular string functions thats faster.
$string = '
expireDays=5
apikey=ABQIAAAAFHktBEXrHnX108wOdzd3aBTupK1kJuoJNBHuh0laPBvYXhjzZxR0qkeXcGC_0Dxf4UMhkR7ZNb04dQ
distancia=15
AutoCoord=1';
//test to see what type of line break it is and explode by that.
$parts = (strstr($string,"\r\n") ? explode("\r\n",$string) : explode("\n",$string));
$data = array();
foreach($parts as $part)
{
$sub = explode("=",trim($part));
if(!empty($sub[0]) || !empty($sub[1]))
{
$data[$sub[0]] = $sub[1];
}
}
and use $data['apikey'] for your api key, i would also advise you to wrpa in function.
I can bet this is a better way to parse the string and much faster.
function ParsemyString($string)
{
$parts = (strstr($string,"\r\n") ? explode("\r\n",$string) : explode("\n",$string));
$data = array();
foreach($parts as $part)
{
$sub = explode("=",trim($part));
if(!empty($sub[0]) || !empty($sub[1]))
{
$data[$sub[0]] = $sub[1];
}
}
return $data;
}
$data = ParsemyString($string);
First of all, you are not looking for
api==ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
but you are looking for
apikey=ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
It is important to know if the api-key property always occurs at the end and if the length of the api-key value is always the same. I this is the case you could use the PHP substr() function which would be easiest.
If not you would most probably need a regular expression which you can feed to PHPs preg_match() function. Something along the lines of apikey==[a-zA-Z0-9\-] Which matches an api-key containing a-z in both lowercase and uppercase and also allows for dashes in the key. If you are using the preg_match() function you can retrieve the matches (and thus your api-key value).