PHP, Get tomorrows date from date - php

Question

I have a PHP date in the form of 2013-01-22 and I want to get tomorrows date in the same format, so for example 2013-01-23.
How is this possible with PHP?

Answer 1

Use DateTime
$datetime = new DateTime('tomorrow');
echo $datetime->format('Y-m-d H:i:s');
Or:
$datetime = new DateTime('2013-01-22');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
Or:
$datetime = new DateTime('2013-01-22');
$datetime->add(new DateInterval("P1D"));
echo $datetime->format('Y-m-d H:i:s');
Or in PHP 5.4+:
echo (new DateTime('2013-01-22'))->add(new DateInterval("P1D"))
->format('Y-m-d H:i:s');

Answer 2

$tomorrow = date("Y-m-d", strtotime('tomorrow'));
or
$tomorrow = date("Y-m-d", strtotime("+1 day"));
Help Link: STRTOTIME()

Answer 3

Since you tagged this with strtotime, you can use it with the +1 day modifier like so:
$tomorrow_timestamp = strtotime('+1 day', strtotime('2013-01-22'));
That said, it's a much better solution to use DateTime.

Answer 4

<? php
//1 Day = 24*60*60 = 86400
echo date("d-m-Y", time()+86400);
?>

Answer 5

echo date ('Y-m-d',strtotime('+1 day', strtotime($your_date)));

Answer 6

Use DateTime:
To get tomorrow from now :
$d = new DateTime('+1day');
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;
Results : 28/06/2017 08.13.20
To get tomorrow from a date :
$d = new DateTime('2017/06/10 08.16.35 +1day')
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;
Results : 11/06/2017 08.16.35
Hope it helps!

Answer 7

/**
* get tomorrow's date in the format requested, default to Y-m-d for MySQL (e.g. 2013-01-04)
*
* #param string
*
* #return string
*/
public static function getTomorrowsDate($format = 'Y-m-d')
{
$date = new DateTime();
$date->add(DateInterval::createFromDateString('tomorrow'));
return $date->format($format);
}

Answer 8

By strange it can seem it works perfectly fine: date_create( '2016-02-01 + 1 day' );
echo date_create( $your_date . ' + 1 day' )->format( 'Y-m-d' );
Should do it

Answer 9

here's working function
function plus_one_day($date){
$date2 = formatDate4db($date);
$date1 = str_replace('-', '/', $date2);
$tomorrow = date('Y-m-d',strtotime($date1 . "+1 days"));
return $tomorrow; }

Answer 10

$date = '2013-01-22';
$time = strtotime($date) + 86400;
echo date('Y-m-d', $time);
Where 86400 is the # of seconds in a day.