Copy added info from one mysql table to another in PHP - php

I have two tables in different mysql databases.
I would like to copy from table A to table B. Only one way.
I need to read last datetime from table B and then check if there any data added to table A after this readed datetime. If there is some data added, then copy it.
I tried this:
It writes one row if I refresh page, but I need it to write everything in one load!
do
{
#TABLE A
$querylastA = "SELECT * FROM `stock` ORDER BY `jrk` DESC LIMIT 1";
$resultlastA = mysql_query($querylastA) or die(mysql_error());
while($rows=mysql_fetch_array($resultlastA)){
$lastcodeA = $rows['datetime'];
}
#TABLE B
$querylastB = "SELECT * FROM `stockcopy` ORDER BY `jrk` DESC LIMIT 1";
$resultlastB = mysql_query($querylastB) or die(mysql_error());
while($rows=mysql_fetch_array($resultlastB)){
$lastcodeB = $rows['datetime'];
}
#TABLE A - NEXT DATE AFTER LAST DATE IN TABLE B
$querynextA = "SELECT datetime FROM stock WHERE datetime > '$lastcodeB' ORDER BY datetime ASC LIMIT 1";
$resultnextA = mysql_query($querynextA) or die(mysql_error());
while($rows=mysql_fetch_array($resultnextA)){
$nextcodeA = $rows['datetime'];
}
mysql_query("INSERT INTO stockcopy(datetime, data1, data2) SELECT datetime, data1, data2 FROM stock WHERE datetime = '$nextcodeA'");
echo "Date from table A " . $lastcodeA . "<br>";
echo "Date from table B " . $lastcodeB . "<br>";
}
while ('$lastcodeA' == '$lastcodeB');

You can insert data on a table using a SELECT statement, so all you need to do is put the condition in the SELECT.
For instance:
INSERT INTO table_example(foo, bar)
SELECT foo, bar FROM table_example2
WHERE time_condition > {SOME DATE}
This will insert into table_example the rows that the SELECT statement returns, which are the ones that satisfy the time condition. You will need to replace {SOME DATE} with an actual date (without brackets).
Also, please see: INSERT with SELECT
And also: Select columns across different databases

You can do this with little to no knowledge of SQL, but with a bit of creativity :)
Create a temporary table (table_c), and copy the contents of table_a there.
Then manually (this means by running delete queries in phpmyadmim) delete the information that doesn't matter anymore ( DELETE FROM table_c WHERE id < 1000 for example ).
Then, export the info from table_c and import it into table_b (and delete table_c

Problem was in: while ('$lastcodeA' == '$lastcodeB');
Changed it to: while ($lastcodeA != $lastcodeB); now it works! Thank you all :)

Related

select with update in one query

I have a query like:
SELECT id, name, surname, fromId, toId, msg_text, readed FROM messages WHERE toId = 2;
So I want to update all selected rows.readed = 1. And Query must return all selected rows.
These action must do in one query if possibe.
Sorry for my english
Short answer: No, it is not possible in a single query.
A little less short answer: There is something known as a command-query separation which in short suggests that a command should do something and return nothing and a query should do nothing and return something. I recommend following this principle if you intend on building good software.
I wont get into why this is not possible because I myself am not that much of an SQL guru and I could only guess but I would suggest an easy solution to your problem.
When you get your results then you are most likely processing them in PHP. Assuming the results are sorted in ascending order - on the first iteration grab the minimum id and on the last one grab the maximum id, then run an update query:
UPDATE messages SET readed = 1 WHERE toId = ? AND (id >= <minimum id> AND id <= <maximum id>)
On a side note - name and surname are probably not what you want to store in a messages table.
You can update only with an UPDATE query. An UPDATE query can return only one thing: that is number of affected rows. So, you cannot update and select the value you need in a single query.
Have a look here Update a table then return updated rows in mySQL
You can do that with stored procedure.
Create a stored procedure which executes the update and the select as well.
Eg:
DROP PROCEDURE IF EXISTS myproc;
delimiter //
CREATE PROCEDURE myproc()
begin
set #qry='select id, name, surname, fromId, toId, msg_text, readed from messages where toId = 2';
prepare query from #qry;
execute query;
update messages set readed=1 where toId = 2;
end //
Then you can run the query through this procedure.
Eg:
$sql = "call myproc()";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"]. " - Name: " . $row["name"]. "<br>";
}
} else {
echo "0 results";
}

Add MySQL Count Column to PHP/HTML Table

I'm developing a website using HTML, PHP and MySQL to access a database. On one page I present a table with data from that database. This is some of the code I'm using:
$sql1 = "SELECT * FROM MyTable ORDER BY ID ASC";
$rs1 = mysqli_query($link,$sql1);
(...)
while($row1 = mysqli_fetch_assoc($rs1)) {
echo "<tr><td>".$row1['ID']."</td><td>".$row1['Field1']."</td><td></td><td>".$row1['Field2']."</td><td>".$row1['Field3']."</td></tr>\n" ;
}
Notice the empty <td></td>? That's because I want to have there the number of time a given ID appears on two other tables (there are foreign keys involved, obviously). I have sorted out the code I need for that:
$sql2 = "SELECT (SELECT COUNT(*) FROM MyTable2 WHERE ID2=$row1['ID'])+(SELECT COUNT(*) FROM MyTable3 WHERE ID2=$row1['ID']) AS total";
However, I'm struggling with figuring out a way to add this result to the other table. Any help?
try with this.. it inserts the total to an table after selecting the count.
"INSERT INTO total_table (total)
SELECT (SELECT COUNT(*) FROM MyTable2 WHERE ID2=$row1['ID'])+(SELECT COUNT(*) FROM MyTable3 WHERE ID2=$row1['ID']) AS total
WHERE cid = 2"

Update values of database with values that are already in DB

I've a database that stores data read from different sensors. The table looks like this:
[SensorID][timestampMS][value]
[Sensor1][123420][10]
[Sensor1][123424][15]
[Sensor1][123428][6554]
[Sensor1][123429][20]
What I would like to do is the following: There are some reads that are corrupted (numbers that are 6554), and I would like to Update that with the next value that is not corrupted (in the example shown below that would be 20). So, if a number is 6554, I would like to update that with the next value (in timestamp), that is not corrupted.
I was thinking on doing this in PHP, but I wonder if it's possible to do it directly with a SQL script.
Appreciate :)
You can use a correlated sub-query...
UPDATE
myTable
SET
value = (SELECT value FROM myTable AS NextValue WHERE sensorID = myTable.SensorID AND timestampMS > myTable.timestampMS ORDER BY timestampMS ASC LIMIT 1)
WHERE
value = 6554
The sub-query gets all the following results, ordered by timestampMS and takes just the first one; That being the next value for that SensorID.
Note: If no "next" value exists, it will attempt to update with a value of NULL. To get around this, you can add this to the WHERE clause...
AND EXISTS (SELECT value FROM myTable AS NextValue WHERE sensorID = myTable.SensorID AND timestampMS > myTable.timestampMS ORDER BY timestampMS ASC LIMIT 1)
EDIT
Or, to be shorter, just use IFNULL(<sub_query>, value)...
Not sure if this is valid syntax, can't test it ATM. You may need to change this to be JOINs instead of the nested subqueries, but in concept you can do something like (for SQL Server):
UPDATE t1
SET Value = ( SELECT Value
from MyTable t2
WHERE t2.SensorID =t1.SensorID
AND t2.[timestamp] =
( SELECT MIN([TimeStamp])
FROM mytable t3
where t3.sensorid = t2.sensorID
AND t3.[timestamp] > t2.[timestamp]
)
)
FROM Mytable t1
WHERE t1.value = 6554
I did a workaround based on Dems solution, and it works in Mysql:
I've created a "copy" of the sensors table like this:
drop table if exists sensors_new;
create table if not exists sensors_new like sensors;
insert into sensors_new select * from sensors;
Then I do what Dems recommended me doing, but using this new aux table in the select (to avoid the error that Mysql launches when Updating a table while doing a select in the same table).
UPDATE
sensors
SET
raw_data = (SELECT raw_data FROM sensors_new AS NextValue WHERE sensor_id = sensors.sensor_id AND timestampMS > sensors.timestampMS ORDER BY timestampMS ASC LIMIT 1)
WHERE
value = 6554
Then, just drop this auxiliar table.
I hope this helps Mysql users.

How do I fetch the last record in a MySQL database table using PHP?

I want to fetch the last result in MySQL database table using PHP. How would I go about doing this?
I have 2 Columns in the Table, MessageID(auto) & Message.
I already know how to connect to the database.
Use mysql_query:
<?php
$result = mysql_query('SELECT t.messageid, t.message
FROM TABLE t
ORDER BY t.messageid DESC
LIMIT 1') or die('Invalid query: ' . mysql_error());
//print values to screen
while ($row = mysql_fetch_assoc($result)) {
echo $row['messageid'];
echo $row['message'];
}
// Free the resources associated with the result set
// This is done automatically at the end of the script
mysql_free_result($result);
?>
The SQL query:
SELECT t.messageid, t.message
FROM TABLE t
ORDER BY t.messageid DESC
LIMIT 1
...uses the ORDER BY to set the values so the highest value is the first row in the resultset. The LIMIT says that of all those rows, only the first is actually returned in the resultset. Because messageid is auto-increment, the highest value is the most recent one...
Records in a relational database do not have an intrinsic "order" so you cannot fetch the "last" record without some kind of ORDER BY clause.
Therefore, in order to fetch the "last" record, simply reverse the ORDER BY clause (change ASC to DESC or vice versa) then select the first result.
If you have an auto-increment field and you just want to find the last value that was inserted, you can use the fact that the auto-increment fields are ever-increasing (therefore the "last" one will be the one with the highest value) and do something like this:
SELECT *
FROM my_table
ORDER BY id_field DESC
LIMIT 1
Of course you can select the last row by sorting DESC in your query. But what if you want to select the first row and then the last. You can run a new query, but you can also use the function mysql_data_seek. check code below:
$result = mysql_query('YOUR QUERY') or die('Invalid query: ' . mysql_error());
$row_first = mysql_fetch_array($result);
mysql_data_seek($result , (mysql_num_rows($result)-1));
$row_last = mysql_fetch_array($result);
Hope this helps
The MySql query would look like this:
select MessageID, Message
from Table
order by MessageID desc
limit 1;
I am too rusty with PHP to give you the right syntax for executing this.
This query works because you have an auto-incrementing identifying field (MessageID). By ordering the results by that field in descending (largest to smallest) order we are effectively returning the records in the table in reverse order. The limit 1 clause simply limits the result set to one record - the last one in the table.
What do you mean by "the last result"? You need to precise a bit more.
Do you mean "the last entry I registered"?
In this case you should use the appropriate method (depending on the extension you are using) mysqli->insert_id OR mysql_insert_id.
If you mean "the latest entry in the table", an SQL query such as Andrew Hare's is just what you need.
Do you mean the last record or do you need the id of the most recently inserted record? For that you would use the PHP mysql_insert_id() function. Or if you are using the myusqli extension use $mysqli->insert_id.
for some reason (which I don't know why), my boss force me to get the data in this way:
$message_arr = array();
while ($row = mysql_fetch_assoc($result)) {
$message_arr['messageid']= $row['messageid'];
$message_arr['message']= $row['message'];
}
return $message_arr;
Of course, you need everything from OMG Ponies's answer I'm just telling you another way to do it =)
I hope this help.
You should use SELECT query. How SELECT works.
SELECT * FROM table - selects everything in a table (id, row 1, row 2,...)
SELECT id FROM table - selects only particular row from table.
If you now know, how to select, you can use additional logic.
SELECT * FROM table ORDER by id DESC LIMIT 1;
selects everything from table table, orders it by id - orders it DESCENDING and limits the query to only one result.
If you would do it like this:
SELECT * FROM table ORDER by id ASC limit 1; - you would get 1 entry into database.
You can order it by any row you want.
Hope it helps.
One thing to remember is that data does not get saved in the insertion order in any MYSQL database. So in order to get the last entered record u will have to have an auto increment field. Since there is an auto increment field in this table we are good to go.
The below script will help to get the last entered record
<?php
$sql = "SELECT * FROM table_name ORDER BY MessageID DESC LIMIT 2";
$result_set = mysql_query($sql);
if($result_set){
while($row = mysql_fetch_array($result_set)) {
echo "Message Id: ".$row['MessageID']."<br>";
echo "Message: ".$row['Message']."<br>";
}
//creating alert
echo "<script type=\"text/javascript\">alert('Data was Retrieved
successfully');</script>";
}
else{
//creating alert
echo "<script type=\"text/javascript\">alert('ERROR! Could Not Retrieve
Data');</script>";
}
?>
The query selects all the records in the table and orders them according to the descending order of the MessageID (as it is the auto increment field) and limits the returned result to only one record. So since the table is ordered according to the descending order of the MessageID only the last entered record will be returned.
NOTE: if you are using a newer version you will have to use mysqli_query($connection_variable,$sql); instead of mysql_query($sql); and mysqli_fetch_array($result_set) instead of mysql_fetch_array($result_set)
$result = mysql_query('select max(id) from your_table ') or die('Invalid query: ' . mysql_error());
while ($row = mysql_fetch_assoc($result)) {
echo $row['id'];
echo $row['message'];
}
//
//
mysql_free_result($result);
simple like that
this code of php works fine
SELECT t.messageid, t.message
FROM TABLE t
ORDER BY t.messageid DESC
LIMIT 1
if you don't have concurrent entries going into some table.b'cause concurrent entries may not go in accordance of their insertion order.
$statement = $PDO->prepare("
SELECT MessageID,
Message
FROM myTable
ORDER BY MessageID DESC
LIMIT 1;
");
$statement->execute();
$result = $statement->fetch(\PDO::FETCH_ASSOC);
echo $result['MessageID']." and ".$result['Message'];

A logical problem with two tables

Hey guys, I created a list for fixtures.
$result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date");
$i = 1;
$d = "Start";
while ($row = mysql_fetch_assoc($result))
{
$odate = $row['date'];
$date=date("F j Y", $row['date']);
echo "<p>Fixture $i - $d to $date</p>";
}
As you can see from the query, the date is displayed from the fixtures table.
The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table.
Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table?
"SELECT * FROM ".TBL_CONF_RESULTS."
WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date"
That would be the second query!
EDIT FROM HERE ONWARDS...
Is there anyway I can select the date from two tables and then only use one if there are matches. Then use the rows of dates (GROUPED BY) to populate my query? Is that possible?
It sounds like you want to UNION the two result sets, akin to the following:
SELECT f.date FROM tbl_fixtures f
WHERE f.compname = '$comp_name'
UNION SELECT r.date FROM tbl_conf_results r
WHERE r.compid = '$_GET[id]' AND r.type2 = '2'
GROUP BY date
This should select f.date and add rows from r.date that aren't already in the result set (at least this is the behaviour with T-SQL). Apparently it may not scale well, but there are many blogs on that (search: UNION T-SQL).
From the notes on this page:
//performs the query
$result = mysql_query(...);
$num_rows = mysql_num_rows($result);
//if query result is empty, returns NULL, otherwise,
//returns an array containing the selected fields and their values
if($num_rows == NULL)
{
// Do the other query
}
else
{
// Do your stuff as now
}
WHERE compid = '$_GET[id]' presents an oportunity for SQL Injection.
Are TBL_FIXTURES and TBL_CONF_RESULTS supposed to read $TBL_FIXTURES and $TBL_CONF_RESULTS?
ChrisF has the solution!
One other thing you might think about is whether it is necessary to do a delete and move to another table. A common way to solve this type of challenge is to include a status field for each record, then rather than just querying for "all" you query for all where status = "x". For example, 1 might be "staging", 2 might be "in use", 3 might be "used" or "archived" In your example, rather than deleting the field and "moving" the record to another table (which would also have to happen in the foreach loop, one would assume) you could simply update the status field to the next status.
So, you'd eliminate the need for an additional table, remove one additional database hit per record, and theoretically improve the performance of your application.
Seems like what you want is a UNION query.
$q1 = "SELECT DISTINCT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name'";
$q2 = "SELECT DISTINCT date FROM ".TBL_CONF_RESULTS.
"WHERE compid = '$_GET[id]' && type2 = '2'";
$q = "($q1) UNION DISTINCT ($q2) ORDER BY date";

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