How to insert an actual NULL value into a nullable column? - php

function save($gmt, $name, $address, $phone, $remark)
{
$query= "INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES ('$gmt', '$name', '$address', '$phone', '$remark')";
mysql_query($query);
}
Here, address, phone, and remark can be NULL. I need it to save NULL whenever the variable is set to NULL and the column is nullable, instead of inserting an empty string.
How can I insert NULL value into the database using PHP?

This is PHP solution, but you have to use mysqli because mysql deprecated, please read more about mysqli.
Also, you must consider SQL injection
function save($gmt, $name, $address, $phone, $remark)
{
if(empty($phone)){
$phone = 'NULL';
}else{
$phone = "'".$phone."'";
}
if(empty($remark)){
$remark = 'NULL';
}else{
$remark = "'".$remark."'";
}
$query= "INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES ('$gmt', '$name', '$address', $phone, $remark)";
mysql_query($query);
}
//tests
save("a", "b", "c", "", "")."<br>";
save("a", "b", "c", "d", "")."<br>";
save("a", "b", "c", "d", "e")."<br>";
/*
INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES ('a', 'b', 'c', NULL, NULL)
INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES ('a', 'b', 'c', 'd', NULL)
INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES ('a', 'b', 'c', 'd', 'e')
*/
?>
DEMO

Try switching to prepared statements (which as a bonus is less prone to SQL injections).
function save($gmt, $name, $address, $phone, $remark)
{
if(!isset($phone) || empty($phone)) { $phone = null; }
if(!isset($remark) || empty($remark) { $remark = null; }
$db = new PDO(...);
$stmt = $db->prepare("INSERT INTO `user` (`gmt`, `name`, `address`, `phone`, `remark`) VALUES (:gmt, :name, :address, :phone, :remark)");
$stmt->bindValue("gmt", $gmt, PDO::PARAM_STR);
$stmt->bindValue("name", $name, PDO::PARAM_STR);
$stmt->bindValue("address", $address, PDO::PARAM_STR);
$stmt->bindValue("phone", $phone, PDO::PARAM_STR);
$stmt->bindValue("remark", $remark, PDO::PARAM_STR);
$stmt->execute();
}
This will handle the null values correctly in MySQL

PHP doesn't print NULL - it is just an empty string. So in your example you will try to insert '', which in SQL again is an empty string.
You have to use NULL (without quotes).
And the best practice to achieve that is to use an ORM or a PHP framework with a database abstraction layer which does this for you.

Using ternary operator, you can also use this
$add = ($address == '' ? NULL : $address);
$phn = ($phone == '' ? NULL : $phone);
$rmk = ($remark == '' ? NULL : $remark);

fields can be NULL
-> qtd_aulas_previstas
-> qtd_aulas_dadas
$qtd_aulas_previstas = ( empty($qtd_aulas_previstas) ? 'NULL' : "'".$qtd_aulas_previstas."'");
$qtd_aulas_dadas = ( empty($qtd_aulas_dadas) ? 'NULL' : "'".$qtd_aulas_dadas."'");
//insere os dados na tabela
$inserir_tb = mysqli_query($conexao, "INSERT INTO tb_turma_bimestre VALUES('', '$cod_turma', '$cod_bimestre', $qtd_aulas_previstas, $qtd_aulas_dadas, '$data_abertura', '$data_encerramento', '$date_time', '$nome_login')")or die("Error2: " .mysqli_error($conexao));

Related

INSERT into mysql DATABASE Prepared Statments

Can anybody see why this is not inputting into my database..
I did have it working, but now i got the error on mysql A form on this field has more than 1000 fields, but none of them do....
here is the prep statment
$db = new PDO("mysql:host=localhost;dbname=class2", 'root', '');
$query="INSERT INTO `testdata` (`1st name`, `2nd name`, `title`, `info`, `location`, `phone`, `postcode`, `image`, `image2`, `image3`, `image4`, `image5`, `price`, `catagory`, `cond`, `delivery`, `email`, `username`, `youtubevideo`, `paypal`, `facebook`, `twitter`, `feedbackscore`)
VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)";
$stat=$db->prepare($query);
$stat->execute(array("$firstname","$lastname","$sellingtitle","$sellinginfo","$town","$phone1","$postcode","$i0url","$i1url","$i2url","$i3url","$i4url","$price","$catagory","$cond","$delivery","","$sellername","$youtubeurl","$paypal","$facebook","$twitter","feedbackscore"));
Your PDO is not prepared correctly.
$database = new PDO("mysql:host=localhost;dbname=class2", 'root', '');
$query = "UPDATE users SET first_name = :first_name, last_name = :last_name
WHERE user_id = :user_id";
$update = $database->prepare($query);
$update->execute([
':first_name' => $_POST['firstname'],
':last_name' => $_POST['lastname'],
':user_id' => $_SESSION['user_id']
]);
$update->fetch();
With PDO you define the keys of the values in the prepare string like :first_name.
So then in the execute function's array, you define the values of these keys.
Hope it helps.

sql error when submitting with php

My php files that submits an entry to a database table isn't working and I can't figure out why. It takes in an Ajax submit and I know that the problem isn't with the data, or the Ajax request as it processes as a success. The only issue is that no data is ever submitted to my database. I had this working before I changed to code to concatenate the address string where it was one variable before. Any advice would be great!
Here is the php files
UPDATE:::THIS IS THE UPDATED PHP FILE
<?php
require("dbinfo.php");
// Create connection
$conn = new mysqli('localhost', $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$name = $_POST['user_name'];
$street = $_POST['user_street'];
$city = $_POST['user_city'];
$state = $_POST['user_state'];
$country = $_POST['user_country'];
$zip = $_POST['user_zip'];
$address = $street.', '.$city.', '.$state.', '.$country.', '.$zip;
$shortAdd = $city.', '.$state.', '.$country;
$type = $_POST['user_color'];
$desc = $_POST['user_message'];
$request_url = "http://maps.googleapis.com/maps/api/geocode/xml?address=".$address."&sensor=true";
$xml = simplexml_load_file($request_url) or die("url not loading");
$status = $xml->status;
if ($status=="OK") {
$lat = $xml->result->geometry->location->lat;
$lon = $xml->result->geometry->location->lng;
}
$sql = "INSERT INTO `markers` (`name`, `address`, `lat`, `lng`, `type`, `desc`)
VALUES (?, ?, ?, ?, ?, ?);";
$stmt = $conn->prepare($sql);
$stmt->bind_param('ssssss', $name, $shortAdd, $lat, $lon, $type, $desc);
$stmt->execute();
$conn->close();
?>
While docliving's answer is correct, please take the extra step and use prepared statements. Your code is vulnerable to SQL injection attacks without it. It just takes a very minor change to convert it to use prepared statements. Here is how to do it with mysqli:
$sql = "INSERT INTO `markers` (`name`, `address`, `lat`, `lng`, `type`, `desc`)
VALUES (?, ?, ?, ?, ?, ?);";
$stmt = $conn->prepare($sql);
$stmt->bind_param('ssssss', $name, $shortAdd, $lat, $lon, $type, $desc);
$stmt->execute();
When #MySelfBoy wrote:
After the assignment, you have to execute SQL statements
He means that you have to execute your query
$sql = "INSERT INTO `markers` (`name`, `address`, `lat`, `lng`, `type`, `desc`)
VALUES ('$name', '$shortAdd', '$lat', '$lon', '$type', '$desc');";
with the following instruction:
$conn->query($sql);
NOTE: I Still canĀ“t make comments, so I'm posting it here.

Inserting into MySQL database, query not running

I'm making a simple sign up/in form for a school assignment.
for some reason I can't get it to create a new column in my current table.
All of the information for the $_Get is coming up properly. I imagine its a syntax error i'm not seeing. Any help would be great. Thank you.
if ( $_GET['action'] == "create" )
{
print('test');
// -----------------------
// PERFORM DATABASE UPDATE
$fn = $_GET['fn'];
$ln = $_GET['ln'];
$id = $_GET['id'];
$user = $_GET['user'];
$tel = $_GET['tel_num'];
$email = $_GET['email'];
$bday = $_GET['birthday'];
$password = $_GET['password'];
$address = $_GET['address'];
print('test1');
mysql_select_db("advweb2");
$sql="INSERT INTO `account` (`user`, `password` , `email` , `first_name` , `last_name` , `address` , `tel_num` , `birthday`)
VALUES ('$user', '$password', '$email', '$fn', '$ln', '$address', '$tel', '$bday')";
print_r($sql);
print("<div style='color:green'>update successful</div>");
// -----------------------
$action = "signin";
}
You need to execute the query.
You should be using MySQLi or PDO as detailed here as mysql_query is deprecated.
Example with mysqli:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$stmt = $mysqli->prepare(
"INSERT INTO `account` (`user`, `password` , `email` , `first_name` , `last_name` , `address` , `tel_num` , `birthday`)
VALUES (?, ?, ?, ?, ?, ?, ?, ?)"
);
$stmt->bind_param('ssssssss', $user, $password, $email, $fn, $ln, $address, $tel, $bday);
$stmt->execute();
/* ... */
$stmt->close()
?>
You need to make sure you clean your $_GET variables before inserting into the database to prevent SQL injection. A good read: how to prevent SQL injection.
Please don't use mysql_query, switch to mysqli or PDO instead.
$dbh = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);
$stmt = $dbh->prepare("INSERT INTO REGISTRY (name, value) VALUES (:name, :value)");
$stmt->bindParam(':name', $name);
$stmt->bindParam(':value', $value);
$name = 'one';
$value = 1;
$stmt->execute();
$dbh = null;
Use Mysqli or PDO as explained by others but if you insist execute your query like this:
$sql=mysql_query("INSERT INTO `account` (`user`, `password` , `email` , `first_name` , `last_name` , `address` , `tel_num` , `birthday`)
VALUES ('$user', '$password', '$email', '$fn', '$ln', '$address', '$tel', '$bday')");
Because You prepared query and assigned it to the variable but for missed to execute it.

Is it possible to combine mysqli prepared statement with multiple inserts?

I am well-versed in the old php mysql extension.
I am working on my first script that uses the mysqli extension.
I am going to be inserting a large number of rows into a table that are being generated dynamically.
Is it possible to use a prepared statement to insert multiple rows into a table without previously knowing the number of new rows that will be inserted each time?
$stmt = $mysqli->prepare("INSERT INTO `activity` (`id`, `name`, `type`) VALUES ?, ?, ?;");
If that isn't possible, which would be more efficient:
prepared statement, one row at a time
non-prepared statement, ~50 rows at a time
// prepared statement
$stmt = $mysqli->prepare("INSERT INTO `activity` (`id`, `name`, `type`) VALUES (?, ?, ?)");
for($i=0;$i<$limit;$i++)
{
$stmt->bind_param('iss', $id[$i], $name[$i], $type[$i]);
$stmt->execute();
}
// non-prepared statement
$query = "INSERT INTO `activity` (`id`, `name`, `type`) VALUES ";
for($i=0;$i<$limit;$i++)
{
$query .= "\n(".$mysqli->real_escape_string($id[$i]), $mysqli->real_escape_string($name[$i]), $mysqli->real_escape_string($type[$i])."),";
}
$query = substr($query, 0, -1).';';
PHP v.5.3.8
MySQL v. 5.1.60
$stmt = $mysqli->stmt_init();
if($stmt->prepare("INSERT INTO `activity` (`id`, `name`, `type`) VALUES (?, ?, ?)"))
{
$stmt->bind_param('iss', $_id, $_name, $_type);
for($i=0;$i<$limit;$i++)
{
$_id = $id[$i];
$_name = $name[$i];
$_type = $type[$i];
$stmt->execute();
}
}
should do it for you!

php prepared statement fails.

I'm guessing I'm missing something, but I can't seem to get this statement to work. When I load it into the page I get the white screen of death.
Here is what I'm trying to get to run
$statement = $db-> prepare("INSERT INTO `simplyaccomplished`.`blog_comment` (`ID`, `comment`, `date`, `ip_address`, `valid`, `name`, `blogcomment_ID`) VALUES (NULL, ?, NOW(), ?, 0, ?, ? );");
$statement -> bind_param("sssi",$comment, $ipaddress, $name , $comment_id);
$statement -> execute($statement);
$statement -> close();
The weird thing is this runs perfectly
$query = ("INSERT INTO `simplyaccomplished`.`blog_comment` (`ID`, `comment`, `date`, `ip_address`, `valid`, `name`, `blogcomment_ID`) VALUES (NULL,'$comment' , NOW(), '$ipaddress', '0', '$name', '$comment_id');");
$result =$db->query($query);
If someone could tell me where I'm going wrong I would greatly appreciate it!
The PDO method you're looking for is named bindParam, not bind_param :)
Try mysqli method,
$statement = $db-> prepare("INSERT INTO `simplyaccomplished`.`blog_comment` (`ID`,
`comment`, `date`, `ip_address`, `valid`, `name`, `blogcomment_ID`)
VALUES (?, ?, ?, ?,?, ?, ?)");
$statement -> bind_param("ssssisi",
null,$comment,NOW(),$ipaddress, 0,$name , $comment_id);
Take a look at PDO and MySqlI.

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