if else else construct [closed] - php

Question

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
I'm not 100% comfortable with a PHP class defined here: mysqli
I stripped out the guts to shorten it somewhat and get a parse error at runtime.
<?php
function query($x)
{
if ($x > 8) {
return 'greater than eight!';
} else {
return true;
}
} else {
exit();
}
}
print query(7);
It's the same construct (I think) as the original, isn't it? Apart from the signature and the body of the method of course. I haven't come across an if else else clause before and it somehow doesn't 'feel right' for me at least logically wise. Moreover my code won't compile. Maybe you can set me straight?
Do you have any examples of how it may be used?
Secondly, from the original class - where or how does the $resource variable come into it? In what context would the object get passed a $resource variable?
My client code may be:
$db = new MySQLi;
$db->query("SELECT * FROM my_table");
but I don't see how $resource comes into play?

Answer 1

I assume you're trying to do something different but I hope this helps to explains how you can tie three conditions together.
function query($x) {
if ($x > 8) { // If $x is greater than 8
return 'greater than eight!';
} else if ($x < 8) { // If $x is lower than 8
return true;
} else {
return "The number is 8!";
}
}
print query(7);

Answer 2

You have a second else construct, it should look like:
if($x > 8) {
// your if(true) code
} else {
// your if(false) code
}

Answer 3

there is a missing if else block which is highlighted with ** here that's y you are getting the parser error as same is the problem with your code
<?php
final class MySQLi {
private $mysqli;
public function __construct($hostname, $username, $password, $database) {
$this->mysqli = new mysqli($hostname, $username, $password, $database);
if ($this->mysqli->connect_error) {
trigger_error('Error: Could not make a database link (' . $this->mysqli->connect_errno . ') ' . $this->mysqli->connect_error);
}
$this->mysqli->query("SET NAMES 'utf8'");
$this->mysqli->query("SET CHARACTER SET utf8");
$this->mysqli->query("SET CHARACTER_SET_CONNECTION=utf8");
$this->mysqli->query("SET SQL_MODE = ''");
}
public function query($sql) {
$result = $this->mysqli->query($sql);
if ($this->mysqli->errno) {
//$mysqli->errno
}
if (is_resource($resource)) {
$i = 0;
$data = array();
while ($row = $result->fetch_object()) {
$data[$i] = $row;
$i++;
}
$result->close();
$query = new stdClass();
$query->row = isset($data[0]) ? $data[0] : array();
$query->rows = $data;
$query->num_rows = $result->num_rows;
unset($data);
return $query;
} else {
return true;
}
***} else {
trigger_error('Error: ' . mysql_error($this->link) . '<br />Error No: ' . mysql_errno($this->link) . '<br />' . $sql);
exit();
}***
}
public function escape($value) {
return $this->mysqli->real_escape_string($value);
}
public function countAffected() {
return $this->mysqli->affected_rows;
}
public function getLastId() {
return $this->mysqli->insert_id;
}
public function __destruct() {
$this->mysqli->close();
}
}
?>

Answer 4

There is something missing in your code. If you someone runs your code.
Parse error: syntax error, unexpected T_ELSE on line 8
So your function should look like below
function query($x)
{
if ($x > 8)
{
//runs when $x value is greater than 8
return 'greater than eight!';
}
else
{
// if the condition didnt meet, according to my knowledge you should return false here
return true;
}
exit();
}
print query(7);
If you want to have a else if,
if (condition)
{
code to be executed if condition is true;
}
else if (condition)
{
code to be executed if condition is true;
}
else
{
code to be executed if condition is false;
}