MongoDB search $in _id php - php

Question

Usually when I search for one related ID I do it like this:
$thisSearch = $collection->find(array(
'relatedMongoID' => new MongoId($mongoIDfromSomewhereElse)
));
How would I do it if I wanted to do something like this:
$mongoIdArray = array($mongoIDfromSomewhereElseOne, $mongoIDfromSomewhereElseTwo, $mongoIDfromSomewhereElseThree);
$thisSearch = $collection->find(array(
'relatedMongoID' => array( '$in' => new MongoId(mongoIdArray)
)));
I've tried it with and without the new MongoId(), i've even tried this with no luck.
foreach($mongoIdArray as $seprateIds){
$newMongoString .= new MongoId($seprateIds).', ';
}
$mongoIdArray = explode(',', $newMongoString).'0';
how do I search '$in' "_id" when you need to have the new MongoID() ran on each _id?

Answer 1

Hmm your rtying to do it the SQL way:
foreach($mongoIdArray as $seprateIds){
$newMongoString .= new MongoId($seprateIds).', ';
}
$mongoIdArray = explode(',', $newMongoString).'0';
Instead try:
$_ids = array();
foreach($mongoIdArray as $seprateIds){
$_ids[] = $serprateIds instanceof MongoId ? $seprateIds : new MongoId($seprateIds);
}
$thisSearch = $collection->find(array(
'relatedMongoID' => array( '$in' => $_ids)
));
That should produce a list of ObjectIds that can be used to search that field - relatedMongoID.
This is what I am doing
Basically, as shown in the documentation ( https://docs.mongodb.org/v3.0/reference/operator/query/in/ ) the $in operator for MongoDB in fact takes an array so you need to replicate this structure in PHP since the PHP driver is a 1-1 with the documentation on most fronts (except in some areas where you need to use an additional object, for example: MongoRegex)
Now, all _ids in MongoDB are in fact ObjectIds (unless you changed your structure) so what you need to do to complete this query is make an array of ObjectIds. The ObjectId in PHP is MongoId ( http://php.net/manual/en/class.mongoid.php )
So you need to make an array of MongoIds.
First, I walk through the array (could be done with array_walk) changing the values of each array element to a MongoId with the old value encapsulated in that object:
foreach($mongoIdArray as $seprateIds){
$_ids[] = $serprateIds instanceof MongoId ? $seprateIds : new MongoId($seprateIds);
}
I use a ternary operator here to see if the value is already a MongoId encapsulated value, and if not encapsulate it.
Then I add this new array to the query object to form the $in query array as shown in the main MongoDB documentation:
$thisSearch = $collection->find(array(
'relatedMongoID' => array( '$in' => $_ids)
));
So now when the query is sent to the server it forms a structure similar to:
{relatedMongoId: {$in: [ObjectId(''), ObjectId('')]}}
Which will return results.

Answer 2

Well... I came across the same issue and the solution might not be relevant anymore since the API might have changed. I solved this one with:
$ids = [
new \MongoDB\BSON\ObjectId('5ae0cc7bf3dd2b8bad1f71e2'),
new \MongoDB\BSON\ObjectId('5ae0cc7cf3dd2b8bae5aaf33'),
];
$collection->find([
'_id' => ['$in' => $_ids],
]);