Submitting forms thru in PHP on jQuery - php

I have a registration form that is currently in a popup modal window coded in jQuery. I have a PHP submit button on the bottom and I have added jQuery code that stops the button from submitting. This is because it will stop my modal window from closing when I submit the page. My issue now is that submitting the form would be impossible. Is there a way to submit my form over all this crowded pop-ups and jQuery? Say is it possible to use AJAX or jQuery to submit the form and allow my PHP to handle it.
Since I am writing in PHP, there is quite a bit of server side validation going on, so the point of this is to allow my viewers to fix their validation mistakes before the modal window closes.
Here is my jQuery, I didnt bother to mess with that anymore as it does what I need.
$(document).ready(function() {
$('a.modal-window').click(function() {
//Getting the variable's value from a link
var loginBox = $(this).attr('href');
$(loginBox).fadeIn(300);
var popMargTop = ($(loginBox).height() + 24) / 2;
var popMargLeft = ($(loginBox).width() + 24) / 2;
$(loginBox).css({
'margin-top' : -popMargTop,
'margin-left' : -popMargLeft
});
// Add the mask to body
$('body').append('<div id="mask"></div>');
$('#mask').fadeIn(300);
return false;
});
// When clicking on the button close or the mask layer the popup closed
$('a.close, #mask').live('click', function() {
$('#mask , .login-popup').fadeOut(300 , function() {
$('#mask').remove();
});
return false;
});
});
Here is the code I used to stop the form from submitting:
$(function () {
$(':submit').click(function (event) {
event.preventDefault();
// submit the form dynamically
});
});
and below is my form, it might not matter although its there for the viewing.
<form method="post" id="loginform" action="<?php echo $_SERVER['PHP_SELF']?>">
<table style="color: white;">
<tr><th style="float:left;">Register a new account with us.</th></tr>
<tr><td>Username</td><td><input type="text" name="txtUser"/></td></tr>
<tr><td>Password</td><td><input type="text" name="txtPass"/></td></tr>
<tr><td>Email</td><td><input type="text" name="txtEmail"/></td></tr>
<tr><td>Confirm Email</td><td><input type="text" name="txtEmail2"/></td></tr>
<tr><td>First Name</td><td><input type="text" name="txtFname"/></td></tr>
<tr><td>Last Name</td><td><input type="text" name="txtLname"/></td></tr>
<tr><td>Address</td><td><input type="text" name="txtAddress"/></td></tr>
<tr><td>City</td><td><input type="text" name="txtCity"/></td></tr>
<tr><td>Postal Code</td><td><input type="text" name="txtPostal"/></td></tr>
<tr><td>Birth Year</td><td><input type="text" name="txtBirth"/></td></tr>
<tr><td>Gender</td><td><input type="radio" id="radio-1-1" name="radicalSex" class="regular-radio" value="m" selected="true" /><label for="radio-1-1"></label> Male</td></tr>
<tr><td></td><td><input type="radio" id="radio-1-2" name="radicalSex" class="regular-radio" value="f"/><label for="radio-1-2"></label> Female</td></tr>
<tr><td colspan='2' style="color: #FF6600;float:left;font-size:70%;"><?php echo $Error;?></td></tr>
<tr><td colspan="2"><input type="submit" name="btnRegister" ID="btnBlueTemp" value="Submit Registration" /></td></tr>
<tr><td colspan='2' style="float:left; font-size:70%;">Address information is optional</td></tr>
</table>
</form>

Let me give you an example of how you can do that .
<html>
<head>
<title></title>
<script src="js/jquery-1.7.2.min.js" type="text/javascript"></script>
<script>
$(document).ready(function(){
function validate(name, addr){
if(name=="") {
alert('Name is Blank');
return false;
} else if(addr=="") {
alert('Address is Blank');
return false;
} else {
return true;
}
}
$("#save").click(function(event){
event.preventDefault();
var name = $("#name").val();
var addr = $("#addr").val();
if(validate(name,addr)){
$.ajax({
type:'POST',
data:'name='+name+'&addr='+addr,
url:'test2.php',
success:function(data) {
alert(data);
}
})
}
});
});
</script>
</head>
<body>
<form name="frm" method="POST" action="">
<input type="text" name="name" id="name" value=""/><br>
<input type="text" name="addr" id="addr" value="" /><br>
<input type="submit" name="save" id="save" value="Save"/>
</form>
</body>
</html>
Now in test2.php You can do your php codes
<?php
if(isset($_POST['name'])) {
echo $_POST['name'];
}
?>
Hope this gives you an Idea.

You need to serialize the form data before posting it to PHP.
<script type="text/javascript">
var frm = $('#loginform');
frm.submit(function () {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert('submitted');
}
});
return false;//stop actual form submit
});
</script>

Then, submit your form via ajax
Jquery AJAX
On AJAX URL on which the request is sent, you can write necessary codes for validation and return accordingly. For eg. if some one the form element doesn't meet the validation, you can throw the flag accordingly as json value.
Its possible, why not.

Once you have done all the input validation at client side, just submit the form...
$("#loginform").submit();
Then you will have your server do the rest of the validation.
If you want to stay in the page and show the validation output from server, the. You should submit using Ajax.
It will send your form data to server, then you can do server validation, and output any errors. You will get this in your Ajax complete handler, which you can use to show error messages to user.

To stop the form from reloading the page you needn't call any prevent methods as a simple script request would do the trick.
For instance,
$('#loginForm').submit(function() {
// Do the relevant tasks needed here, form is already prevented from being submitted
});
Check out this demo for more information on what I am referring to

Related

Problems about keep in the page with ajax

I have a form. My objective is send and insert the values of the form to my database. Then
Clear the input of the form
Show the successful message.
Like this:
My problems:When I press the "save" button, I am redirected to another page.
This is the operating error:
and change the page
¿What is the problem on my code?
html
<html>
<head><title>Insert Data Into MySQL: jQuery + AJAX + PHP</title></head>
<body>
<form id="myForm" action="userInfo.php" method="post">
Name: <input type="text" name="name" /><br />
Age : <input type="text" name="age" /><br />
<button type="submit" id="sub">Save</button>
</form>
<span id="result"></span>
<script src="script/jquery-1.8.1.min.js" type="text/javascript"></script>
<script src="script/elscript.js" type="text/javascript"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js">
</script>
</body>
</html
This is my script
$("#myForm").submit( function(e) {
// Prevent the normal form submission event
e.preventDefault();
// Create an object of the form
var form = $(this);
// Make an AJAX request
$.post(this.action, form.serializeArray(), function(info) {
// Clear the form
form[0].reset();
// Display message
$("#result").html(info);
});
});
Finally, my code to insert
<?php
$conn = mysql_connect('localhost', 'root', '');
$db = mysql_select_db('practicas');
$name = $_POST['name'];
$age = $_POST['age'];
if(mysql_query("INSERT INTO ajaxtabla VALUES('$name', '$age')"))
echo "Successfully Inserted";
else
echo "Insertion Failed";
?>
Thanks for help me
You can simplify the code by having just one event handler for when you submit the form. Additionally, you need to include e.preventDefault() which prevents the normal function of the submit button.
$("#myForm").submit( function(e) {
// Prevent the normal form submission event
e.preventDefault();
// Create an object of the form
var form = $(this);
// Make an AJAX request
$.post(this.action, form.serializeArray(), function(info) {
// Clear the form
form[0].reset();
// Display message
$("#result").html(info);
});
});
Give your button a type attribute as well to ensure your form submits upon clicking.
<button type="submit" id="sub">Save</button>
Demo
$(function() {
$("#myForm").submit(function(e) {
// Prevent the normal form submission event
e.preventDefault();
console.log('onsubmit event handler triggered');
// Create an object of the form
var form = $(this);
// Make an AJAX request
/*$.post(this.action, form.serializeArray(), function(info) {
// Clear the form
form[0].reset();
// Display message
$("#result").html(info);
});*/
// fake AJAX request
setTimeout(function(){
// Clear the form
form[0].reset();
// Display message
$("#result").html('Successfully Inserted');
}, 3000);
});
});
<form id="myForm" action="userInfo.php" method="post">
Name: <input type="text" name="name" /><br /> Age : <input type="text" name="age" /><br />
<button type="submit" id="sub">Save</button>
</form>
<span id="result"></span>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js"></script>
In ajax you are posting the form with its action so it will be redirected confirm
If you don't want to redirect then send ajax request like this
$.ajax({
method:post,
url:"File name you want to send request"
}).done(function(response){
});

keeping PHP form values after Submitting with false inputs [duplicate]

I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form...
So anybody who wants can send a tip of the ad to some friends email-adress.
I am guessing the form must be submitted to a php page right?
<form name="tip" method="post" action="tip.php">
Tip somebody:
<input
name="tip_email"
type="text"
size="30"
onfocus="tip_div(1);"
onblur="tip_div(2);"
/>
<input type="submit" value="Skicka Tips" />
<input type="hidden" name="ad_id" />
</form>
When submitting the form, the page gets reloaded... I don't want that...
Is there any way to make it not reload and still send the mail?
Preferrably without ajax or jquery...
I've found what I think is an easier way.
If you put an Iframe in the page, you can redirect the exit of the action there and make it show up.
You can do nothing, of course. In that case, you can set the iframe display to none.
<iframe name="votar" style="display:none;"></iframe>
<form action="tip.php" method="post" target="votar">
<input type="submit" value="Skicka Tips">
<input type="hidden" name="ad_id" value="2">
</form>
You'll need to submit an ajax request to send the email without reloading the page. Take a look at http://api.jquery.com/jQuery.ajax/
Your code should be something along the lines of:
$('#submit').click(function() {
$.ajax({
url: 'send_email.php',
type: 'POST',
data: {
email: 'email#example.com',
message: 'hello world!'
},
success: function(msg) {
alert('Email Sent');
}
});
});
The form will submit in the background to the send_email.php page which will need to handle the request and send the email.
You either use AJAX or you
create and append an iframe to the document
set the iframes name to 'foo'
set the forms target to 'foo'
submit
have the forms action render javascript with 'parent.notify(...)' to give feedback
optionally you can remove the iframe
Fastest and easiest way is to use an iframe.
Put a frame at the bottom of your page.
<iframe name="frame"></iframe>
And in your form do this.
<form target="frame">
</form>
and to make the frame invisible in your css.
iframe{
display: none;
}
SUBMITTING THE FORM WITHOUT RELOADING THE PAGE AND GET THE RESULT OF SUBMITTED DATA ON THE SAME PAGE.
Here's some of the code I found on the internet that solves this problem :
1.) IFRAME
When the form is submitted, The action will be executed and target the specific iframe to reload.
index.php
<iframe name="content" style="">
</iframe>
<form action="iframe_content.php" method="post" target="content">
<input type="text" name="Name" value="">
<input type="submit" name="Submit" value="Submit">
</form>
iframe_content.php
<?php
$Submit = isset($_POST['Submit']) ? $_POST['Submit'] : false;
$Name = isset($_POST['Name']) ? $_POST['Name'] : '';
if($Submit){
echo $Name;
}
?>
2.) AJAX
Index.php:
<form >
<input type="" name="name" id="name">
<input type="" name="descr" id="descr">
<input type="submit" name="" value="submit" onclick="return clickButton();">
</form>
<p id="msg"></p>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
function clickButton(){
var name=document.getElementById('name').value;
var descr=document.getElementById('descr').value;
$.ajax({
type:"post",
url:"server_action.php",
data:
{
'name' :name,
'descr' :descr
},
cache:false,
success: function (html)
{
alert('Data Send');
$('#msg').html(html);
}
});
return false;
}
</script>
server_action.php
<?php
$name = isset($_POST['name']) ? $_POST['name'] : '';
$descr = isset($_POST['descr']) ? $_POST['descr'] : '';
echo $name;
echo $descr;
?>
Tags: phpajaxjqueryserversidehtml
A further possibility is to make a direct javascript link to your function:
<form action="javascript:your_function();" method="post">
...
It's a must to take help of jquery-ajax in this case. Without ajax, there is currently no solution.
First, call a JavaScript function when the form is submitted. Just set onsubmit="func()". Even if the function is called, the default action of the submission would be performed. If it is performed there would be no way of stoping the page from refreshing or redirecting. So, next task is to prevent the default action. Insert the following line at the start of func().
event.preventDefault()
Now, there will be no redirecting or refreshing. So, you simply make an ajax call from func() and do whatever you want to do when call ends.
Example:
Form:
<form id="form-id" onsubmit="func()">
<input id="input-id" type="text">
</form>
Javascript:
function func(){
event.preventDefault();
var newValue = $('#input-field-id').val();
$.ajax({
type: 'POST',
url: '...',
data: {...},
datatype: 'JSON',
success: function(data){...},
error: function(){...},
});
}
this is exactly how it CAN work without jQuery and AJAX and it's working very well using a simple iFrame. I LOVE IT, works in Opera10, FF3 and IE6. Thanks to some of the above posters pointing me the right direction, that's the only reason I am posting here:
<select name="aAddToPage[65654]"
onchange="
if (bCanAddMore) {
addToPage(65654,this);
}
else {
alert('Could not add another, wait until previous is added.');
this.options[0].selected = true;
};
" />
<option value="">Add to page..</option>
[more options with values here]</select>
<script type="text/javascript">
function addToPage(iProduct, oSelect){
iPage = oSelect.options[oSelect.selectedIndex].value;
if (iPage != "") {
bCanAddMore = false;
window.hiddenFrame.document.formFrame.iProduct.value = iProduct;
window.hiddenFrame.document.formFrame.iAddToPage.value = iPage;
window.hiddenFrame.document.formFrame.submit();
}
}
var bCanAddMore = true;</script>
<iframe name="hiddenFrame" style="display:none;" src="frame.php?p=addProductToPage" onload="bCanAddMore = true;"></iframe>
the php code generating the page that is being called above:
if( $_GET['p'] == 'addProductToPage' ){ // hidden form processing
if(!empty($_POST['iAddToPage'])) {
//.. do something with it..
}
print('
<html>
<body>
<form name="formFrame" id="formFrameId" style="display:none;" method="POST" action="frame.php?p=addProductToPage" >
<input type="hidden" name="iProduct" value="" />
<input type="hidden" name="iAddToPage" value="" />
</form>
</body>
</html>
');
}
This should solve your problem.In this code after submit button click we call jquery ajax and we pass url to posttype POST/GET
data: data information you can select input fields or any other.
sucess: callback if everything is ok from server
function parameter text, html or json, response from server
in sucess you can write write warnings if data you got is in some kind of state and so on. or execute your code what to do next.
<form id='tip'>
Tip somebody: <input name="tip_email" id="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/>
<input type="submit" id="submit" value="Skicka Tips"/>
<input type="hidden" id="ad_id" name="ad_id" />
</form>
<script>
$( "#tip" ).submit(function( e ) {
e.preventDefault();
$.ajax({
url: tip.php,
type:'POST',
data:
{
tip_email: $('#tip_email').val(),
ad_id: $('#ad_id').val()
},
success: function(msg)
{
alert('Email Sent');
}
});
});
</script>
You can try setting the target attribute of your form to a hidden iframe, so the page containing the form won't get reloaded.
I tried it with file uploads (which we know can't be done via AJAX), and it worked beautifully.
Have you tried using an iFrame? No ajax, and the original page will not load.
You can display the submit form as a separate page inside the iframe, and when it gets submitted the outer/container page will not reload. This solution will not make use of any kind of ajax.
function Foo(){
event.preventDefault();
$.ajax( {
url:"<?php echo base_url();?>Controllername/ctlr_function",
type:"POST",
data:'email='+$("#email").val(),
success:function(msg) {
alert('You are subscribed');
}
} );
}
I tried many times for a good solution and answer by #taufique helped me to arrive at this answer.
NB : Don't forget to put event.preventDefault(); at the beginning of the body of the function .
I did something similar to the jquery above, but I needed to reset my form data and graphic attachment canvases.
So here is what I came up with:
<script>
$(document).ready(function(){
$("#text_only_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
});
$("#pic_radio_button_id").click(function(){
$("#single_pic_div").show();
$("#multi_pic_div").hide();
});
$("#gallery_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").show();
});
$("#my_Submit_button_ID").click(function() {
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
var canvas=document.getElementById("canvas");
var canvasA=document.getElementById("canvasA");
var canvasB=document.getElementById("canvasB");
var canvasC=document.getElementById("canvasC");
var canvasD=document.getElementById("canvasD");
var ctx=canvas.getContext("2d");
var ctxA=canvasA.getContext("2d");
var ctxB=canvasB.getContext("2d");
var ctxC=canvasC.getContext("2d");
var ctxD=canvasD.getContext("2d");
ctx.clearRect(0, 0,480,480);
ctxA.clearRect(0, 0,480,480);
ctxB.clearRect(0, 0,480,480);
ctxC.clearRect(0, 0,480,480);
ctxD.clearRect(0, 0,480,480);
} });
return false;
}); });
</script>
That works well for me, for your application of just an html form, we can simplify this jquery code like this:
<script>
$(document).ready(function(){
$("#my_Submit_button_ID").click(function() {
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
} });
return false;
}); });
</script>
I don't know JavaScript and I just started to learn PHP, so what helped for me from all those responses was:
Create inedx.php and insert:
<iframe name="email" style=""></iframe>
<form action="email.php" method="post" target="email">
<input type="email" name="email" >
<input type="submit" name="Submit" value="Submit">
</form>
Create email.php and insert this code to check if you are getting the data (you should see it on index.php in the iframe):
<?php
if (isset($_POST['Submit'])){
$email = $_POST['email'];
echo $email;
}
?>
If everything is ok, change the code on email.php to:
<?php
if (isset($_POST['Submit'])){
$to = $_POST['email'];
$subject = "Test email";
$message = "Test message";
$headers = "From: test#test.com \r\n";
$headers .= "Reply-To: test#test.com \r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
mail($to, $subject, $message, $headers);
}
?>
Hope this helps for all other rookies like me :)
Modern Answer without XHR or jQuery
It's 2022, we don't need to use old tools like XHR or jQuery when we have the Fetch API and the FormData API!
The first thing we need to do is prevent the default form submission behavior from occurring with event.preventDefault():
form.addEventListener("submit", function(event){
event.preventDefault();
// ...
});
Now we need to replace the submission behavior with our own AJAX request. The Fetch API makes it pretty simple to post form data - just create a new FormData object, populating it with the form's values, and use it as the body of a fetch request:
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Note that this submits an HTTP request using the multipart/form-data format. If you need to post the data using application/x-www-form-urlencoded, create a new URLSearchParams object from the FormData object and use that as the fetch's body.
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Here's a full code example:
let form = document.querySelector("form");
form.addEventListener("submit", function(event){
event.preventDefault();
fetch(form.action, {
method: "post",
body: //new FormData(form) // for multipart/form-data
new URLSearchParams(new FormData(form)) //for application/x-www-form-urlencoded
});
});
<form method="POST">
<input name="name" placeholder="Name" />
<input name="phone" type="tel" placeholder="Phone" />
<input name="email" type="email" placeholder="Email" />
<input name="submit" type="submit" />
</form>
The page will get reloaded if you don't want to use javascript
You will need to use JavaScript without resulting to an iframe (ugly approach).
You can do it in JavaScript; using jQuery will make it painless.
I suggest you check out AJAX and Posting.
if you're submitting to the same page where the form is you could write the form tags with out an action and it will submit, like this
<form method='post'> <!-- you can see there is no action here-->
Here is some jQuery for posting to a php page and getting html back:
$('form').submit(function() {
$.post('tip.php', function(html) {
// do what you need in your success callback
}
return false;
});

Insert values database without change the page [duplicate]

I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form...
So anybody who wants can send a tip of the ad to some friends email-adress.
I am guessing the form must be submitted to a php page right?
<form name="tip" method="post" action="tip.php">
Tip somebody:
<input
name="tip_email"
type="text"
size="30"
onfocus="tip_div(1);"
onblur="tip_div(2);"
/>
<input type="submit" value="Skicka Tips" />
<input type="hidden" name="ad_id" />
</form>
When submitting the form, the page gets reloaded... I don't want that...
Is there any way to make it not reload and still send the mail?
Preferrably without ajax or jquery...
I've found what I think is an easier way.
If you put an Iframe in the page, you can redirect the exit of the action there and make it show up.
You can do nothing, of course. In that case, you can set the iframe display to none.
<iframe name="votar" style="display:none;"></iframe>
<form action="tip.php" method="post" target="votar">
<input type="submit" value="Skicka Tips">
<input type="hidden" name="ad_id" value="2">
</form>
You'll need to submit an ajax request to send the email without reloading the page. Take a look at http://api.jquery.com/jQuery.ajax/
Your code should be something along the lines of:
$('#submit').click(function() {
$.ajax({
url: 'send_email.php',
type: 'POST',
data: {
email: 'email#example.com',
message: 'hello world!'
},
success: function(msg) {
alert('Email Sent');
}
});
});
The form will submit in the background to the send_email.php page which will need to handle the request and send the email.
You either use AJAX or you
create and append an iframe to the document
set the iframes name to 'foo'
set the forms target to 'foo'
submit
have the forms action render javascript with 'parent.notify(...)' to give feedback
optionally you can remove the iframe
Fastest and easiest way is to use an iframe.
Put a frame at the bottom of your page.
<iframe name="frame"></iframe>
And in your form do this.
<form target="frame">
</form>
and to make the frame invisible in your css.
iframe{
display: none;
}
SUBMITTING THE FORM WITHOUT RELOADING THE PAGE AND GET THE RESULT OF SUBMITTED DATA ON THE SAME PAGE.
Here's some of the code I found on the internet that solves this problem :
1.) IFRAME
When the form is submitted, The action will be executed and target the specific iframe to reload.
index.php
<iframe name="content" style="">
</iframe>
<form action="iframe_content.php" method="post" target="content">
<input type="text" name="Name" value="">
<input type="submit" name="Submit" value="Submit">
</form>
iframe_content.php
<?php
$Submit = isset($_POST['Submit']) ? $_POST['Submit'] : false;
$Name = isset($_POST['Name']) ? $_POST['Name'] : '';
if($Submit){
echo $Name;
}
?>
2.) AJAX
Index.php:
<form >
<input type="" name="name" id="name">
<input type="" name="descr" id="descr">
<input type="submit" name="" value="submit" onclick="return clickButton();">
</form>
<p id="msg"></p>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
function clickButton(){
var name=document.getElementById('name').value;
var descr=document.getElementById('descr').value;
$.ajax({
type:"post",
url:"server_action.php",
data:
{
'name' :name,
'descr' :descr
},
cache:false,
success: function (html)
{
alert('Data Send');
$('#msg').html(html);
}
});
return false;
}
</script>
server_action.php
<?php
$name = isset($_POST['name']) ? $_POST['name'] : '';
$descr = isset($_POST['descr']) ? $_POST['descr'] : '';
echo $name;
echo $descr;
?>
Tags: phpajaxjqueryserversidehtml
A further possibility is to make a direct javascript link to your function:
<form action="javascript:your_function();" method="post">
...
It's a must to take help of jquery-ajax in this case. Without ajax, there is currently no solution.
First, call a JavaScript function when the form is submitted. Just set onsubmit="func()". Even if the function is called, the default action of the submission would be performed. If it is performed there would be no way of stoping the page from refreshing or redirecting. So, next task is to prevent the default action. Insert the following line at the start of func().
event.preventDefault()
Now, there will be no redirecting or refreshing. So, you simply make an ajax call from func() and do whatever you want to do when call ends.
Example:
Form:
<form id="form-id" onsubmit="func()">
<input id="input-id" type="text">
</form>
Javascript:
function func(){
event.preventDefault();
var newValue = $('#input-field-id').val();
$.ajax({
type: 'POST',
url: '...',
data: {...},
datatype: 'JSON',
success: function(data){...},
error: function(){...},
});
}
this is exactly how it CAN work without jQuery and AJAX and it's working very well using a simple iFrame. I LOVE IT, works in Opera10, FF3 and IE6. Thanks to some of the above posters pointing me the right direction, that's the only reason I am posting here:
<select name="aAddToPage[65654]"
onchange="
if (bCanAddMore) {
addToPage(65654,this);
}
else {
alert('Could not add another, wait until previous is added.');
this.options[0].selected = true;
};
" />
<option value="">Add to page..</option>
[more options with values here]</select>
<script type="text/javascript">
function addToPage(iProduct, oSelect){
iPage = oSelect.options[oSelect.selectedIndex].value;
if (iPage != "") {
bCanAddMore = false;
window.hiddenFrame.document.formFrame.iProduct.value = iProduct;
window.hiddenFrame.document.formFrame.iAddToPage.value = iPage;
window.hiddenFrame.document.formFrame.submit();
}
}
var bCanAddMore = true;</script>
<iframe name="hiddenFrame" style="display:none;" src="frame.php?p=addProductToPage" onload="bCanAddMore = true;"></iframe>
the php code generating the page that is being called above:
if( $_GET['p'] == 'addProductToPage' ){ // hidden form processing
if(!empty($_POST['iAddToPage'])) {
//.. do something with it..
}
print('
<html>
<body>
<form name="formFrame" id="formFrameId" style="display:none;" method="POST" action="frame.php?p=addProductToPage" >
<input type="hidden" name="iProduct" value="" />
<input type="hidden" name="iAddToPage" value="" />
</form>
</body>
</html>
');
}
This should solve your problem.In this code after submit button click we call jquery ajax and we pass url to posttype POST/GET
data: data information you can select input fields or any other.
sucess: callback if everything is ok from server
function parameter text, html or json, response from server
in sucess you can write write warnings if data you got is in some kind of state and so on. or execute your code what to do next.
<form id='tip'>
Tip somebody: <input name="tip_email" id="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/>
<input type="submit" id="submit" value="Skicka Tips"/>
<input type="hidden" id="ad_id" name="ad_id" />
</form>
<script>
$( "#tip" ).submit(function( e ) {
e.preventDefault();
$.ajax({
url: tip.php,
type:'POST',
data:
{
tip_email: $('#tip_email').val(),
ad_id: $('#ad_id').val()
},
success: function(msg)
{
alert('Email Sent');
}
});
});
</script>
You can try setting the target attribute of your form to a hidden iframe, so the page containing the form won't get reloaded.
I tried it with file uploads (which we know can't be done via AJAX), and it worked beautifully.
Have you tried using an iFrame? No ajax, and the original page will not load.
You can display the submit form as a separate page inside the iframe, and when it gets submitted the outer/container page will not reload. This solution will not make use of any kind of ajax.
function Foo(){
event.preventDefault();
$.ajax( {
url:"<?php echo base_url();?>Controllername/ctlr_function",
type:"POST",
data:'email='+$("#email").val(),
success:function(msg) {
alert('You are subscribed');
}
} );
}
I tried many times for a good solution and answer by #taufique helped me to arrive at this answer.
NB : Don't forget to put event.preventDefault(); at the beginning of the body of the function .
I did something similar to the jquery above, but I needed to reset my form data and graphic attachment canvases.
So here is what I came up with:
<script>
$(document).ready(function(){
$("#text_only_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
});
$("#pic_radio_button_id").click(function(){
$("#single_pic_div").show();
$("#multi_pic_div").hide();
});
$("#gallery_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").show();
});
$("#my_Submit_button_ID").click(function() {
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
var canvas=document.getElementById("canvas");
var canvasA=document.getElementById("canvasA");
var canvasB=document.getElementById("canvasB");
var canvasC=document.getElementById("canvasC");
var canvasD=document.getElementById("canvasD");
var ctx=canvas.getContext("2d");
var ctxA=canvasA.getContext("2d");
var ctxB=canvasB.getContext("2d");
var ctxC=canvasC.getContext("2d");
var ctxD=canvasD.getContext("2d");
ctx.clearRect(0, 0,480,480);
ctxA.clearRect(0, 0,480,480);
ctxB.clearRect(0, 0,480,480);
ctxC.clearRect(0, 0,480,480);
ctxD.clearRect(0, 0,480,480);
} });
return false;
}); });
</script>
That works well for me, for your application of just an html form, we can simplify this jquery code like this:
<script>
$(document).ready(function(){
$("#my_Submit_button_ID").click(function() {
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
} });
return false;
}); });
</script>
I don't know JavaScript and I just started to learn PHP, so what helped for me from all those responses was:
Create inedx.php and insert:
<iframe name="email" style=""></iframe>
<form action="email.php" method="post" target="email">
<input type="email" name="email" >
<input type="submit" name="Submit" value="Submit">
</form>
Create email.php and insert this code to check if you are getting the data (you should see it on index.php in the iframe):
<?php
if (isset($_POST['Submit'])){
$email = $_POST['email'];
echo $email;
}
?>
If everything is ok, change the code on email.php to:
<?php
if (isset($_POST['Submit'])){
$to = $_POST['email'];
$subject = "Test email";
$message = "Test message";
$headers = "From: test#test.com \r\n";
$headers .= "Reply-To: test#test.com \r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
mail($to, $subject, $message, $headers);
}
?>
Hope this helps for all other rookies like me :)
Modern Answer without XHR or jQuery
It's 2022, we don't need to use old tools like XHR or jQuery when we have the Fetch API and the FormData API!
The first thing we need to do is prevent the default form submission behavior from occurring with event.preventDefault():
form.addEventListener("submit", function(event){
event.preventDefault();
// ...
});
Now we need to replace the submission behavior with our own AJAX request. The Fetch API makes it pretty simple to post form data - just create a new FormData object, populating it with the form's values, and use it as the body of a fetch request:
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Note that this submits an HTTP request using the multipart/form-data format. If you need to post the data using application/x-www-form-urlencoded, create a new URLSearchParams object from the FormData object and use that as the fetch's body.
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Here's a full code example:
let form = document.querySelector("form");
form.addEventListener("submit", function(event){
event.preventDefault();
fetch(form.action, {
method: "post",
body: //new FormData(form) // for multipart/form-data
new URLSearchParams(new FormData(form)) //for application/x-www-form-urlencoded
});
});
<form method="POST">
<input name="name" placeholder="Name" />
<input name="phone" type="tel" placeholder="Phone" />
<input name="email" type="email" placeholder="Email" />
<input name="submit" type="submit" />
</form>
The page will get reloaded if you don't want to use javascript
You will need to use JavaScript without resulting to an iframe (ugly approach).
You can do it in JavaScript; using jQuery will make it painless.
I suggest you check out AJAX and Posting.
if you're submitting to the same page where the form is you could write the form tags with out an action and it will submit, like this
<form method='post'> <!-- you can see there is no action here-->
Here is some jQuery for posting to a php page and getting html back:
$('form').submit(function() {
$.post('tip.php', function(html) {
// do what you need in your success callback
}
return false;
});

jQuery form plugin , how to submit only visible fields

Using the jQuery form plugin, I just want to submit the visible fields (not the hidden ones ) of the form.
HTML:
<div class="result"></div>
<form id="myForm" action="comment.php" method="post">
Name: <input type="text" name="name" />
Comment: <textarea name="comment"></textarea>
<div style="display:none;">
<input type="text" value="" name="name_1" />
</div>
<input type="submit" value="Submit Comment" />
</form>
I cannot find a way to submit only the visible fields using any of the methods below:
ajaxForm:
// wait for the DOM to be loaded
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$('#myForm').ajaxForm(function() {
alert("Thank you for your comment!");
});
});
ajaxSubmit:
$('#myForm').ajaxSubmit({
target: '.result',
success: function(response) {
alert("Thank you for your comment!");
}
});
There is another method formSerialize but found no way to use it with the 2 methods mentioned above (usable with $.ajax however).
How to submit only the visible fields using any of the two methods ?
$("#myForm").on("submit", function() {
var visibleData = $('#myForm input:visible,textarea:visible,select:visible').fieldSerialize();
$.post(this.action, visibleData, function(result) {
alert('Thank you for your comment!');
});
// this is needed to prevent a non-ajax submit
return false;
});

jQuery simple form submission without reload

Could someone provide me with the most simple code for form submission with jquery. On the web is with all sorts of gizmo coding.
$('#your_form_id').submit(function(){
var dataString = $("#your_form_id").serialize();
$.ajax({
type: "POST",
url: "submit.php",
data: dataString,
success: function() {
alert('Sent!');
}
});
return false;
});
here is a another solution, not as simple as the Jquery Form Plugin, but it can be useful if you want to handle errors codes and messages by yourself
look at this HTML + Javascript sample :
<div>
<form method="post" id="fm-form" action ="">
<label>Name:</label>
<input type="text" id="fm-name" name="fm-name" value="" />
<label>Email:</label>
<input type="text" id="fm-email" name="fm-email" value="" />
<label>Birthdate:</label>
<input type="text" id="fm-birthdate" name="fm-birthdate" value="" />
<input type="submit" id="fm-submit" value="Save it">
</form>
</div>
<script type="text/javascript">
$(function() {
// disable the form submission
$("#fm-form").submit(function () { return false; });
// post the datas to "submit_form.php"
$("#fm-submit").click(function() {
$.post("/ajax/submit_form.php",
{ 'fm-name':$("#fm-name").val(),
'fm-email':$("#fm-email").val(),
'fm-birthdate':$("#fm-birthdate").val()
}
,function(xml) {
// submit_form.php will return an XML or JSON document
// check it for potential errors
});
});
});
</script>
What you want is jquery form plugin. It allows you to simply send normal 'form' using ajax - you can make a non-visible form and use this plugin to subnmit it. The option in Joel's answer is possible as well, it depends on the complexity of the thing you want to submit.
Take a look at the Form plugin:
$(function() {
$('#myForm').ajaxForm(function() {
alert("Thank you for your comment!");
});
});

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