Mysqli Procedural Insert Into Table not working - php

Question

I am trying to insert into a table with Procedural Mysqli. It is not posting any errors nor is it posting the information to the database. Here is my code:
$query = "INSERT INTO Accounts (FirstName, LastName, Username, Password, Access) VALUES ({$_POST['FirstNameTbx']}, {$_POST['LastNameTbx']}, {$_POST['UsernameTbx']}, {$_POST['PasswordTbx']}, {$_POST['AccessDDL']})";
mysqli_query($link, $query);
mysqli_close($link);
$Error .= "$query";
Update:
I changed to prepared statement, now I am getting:
Warning: mysqli_stmt::bind_param() [mysqli-stmt.bind-param]: Number of elements in type definition string doesn't match number of bind variables in /home/bryantrx/public_html/ec/add_user.php on line 19
There are only 5 variables that need to be bound, and the UserID auto increments, so it doesn't need to be bound or referenced in the statement..
if ($stmt = $link->prepare("INSERT INTO Accounts (FirstName, LastName, Username, Password, Access) VALUES (?, ?, ?, ?, ?)")){
$stmt->bind_param($_POST['FirstNameTbx'], $_POST['LastNameTbx'], $_POST['UsernameTbx'], $_POST['PasswordTbx'], $_POST['AccessDDL']);
$stmt->execute();
$Error .= "success";
$stmt->close();
} else {
echo $link->error;
}

Answer 1

To get an error message you need to call mysqli_error:
$error = mysqli_error($link);
You would also make life easier (and more secure) for yourself if you built your queries using prepare and parameters:
$query = "INSERT INTO Accounts (FirstName, LastName, Username, Password, Access)
VALUES ( ?, ?, ?, ?, ?)";
if ($stmt = mysqli_stmt_prepare($link, $query)) {
mysqli_stmt_bind_param($stmt, "sssss",
$_POST['FirstNameTbx'],
$_POST['LastNameTbx'],
$_POST['UsernameTbx'],
$_POST['PasswordTbx'],
$_POST['AccessDDL']);
if (!mysqli_stmt_execute($stmt)) {
$error = mysqli_stmt_error($stmt);
}
mysqli_stmt_close($stmt);
} else {
$error = mysqli_error($link);
}
mysqli_close($link);
UPDATE - ok, you've swapped to OO which is fine. When using bind_param the first parameter describes the data you are binding. In this case if it is five strings, you would put 5 "s" like so:
$stmt->bind_param("sssss",
$_POST['FirstNameTbx'],
$_POST['LastNameTbx'],
$_POST['UsernameTbx'],
$_POST['PasswordTbx'],
$_POST['AccessDDL']);