In PHP, how can I add an object element to an array? - php

Question

I'm using PHP. I have an array of objects, and would like to add an object to the end of it.
$myArray[] = null; //adds an element
$myArray[count($myArray) - 1]->name = "my name"; //modifies the element I just added
The above is functional, but is there a cleaner and more-readable way to write that? Maybe one line?

Answer 1

Just do:
$object = new stdClass();
$object->name = "My name";
$myArray[] = $object;
You need to create the object first (the new line) and then push it onto the end of the array (the [] line).
You can also do this:
$myArray[] = (object) ['name' => 'My name'];
However I would argue that's not as readable, even if it is more succinct.

Answer 2

Here is a clean method I've discovered:
$myArray = [];
array_push($myArray, (object)[
'key1' => 'someValue',
'key2' => 'someValue2',
'key3' => 'someValue3',
]);
return $myArray;

Answer 3

Do you really need an object? What about:
$myArray[] = array("name" => "my name");
Just use a two-dimensional array.
Output (var_dump):
array(1) {
[0]=>
array(1) {
["name"]=>
string(7) "my name"
}
}
You could access your last entry like this:
echo $myArray[count($myArray) - 1]["name"];

Answer 4

Something like:
class TestClass {
private $var1;
private $var2;
private function TestClass($var1, $var2){
$this->var1 = $var1;
$this->var2 = $var2;
}
public static function create($var1, $var2){
if (is_numeric($var1)){
return new TestClass($var1, $var2);
}
else return NULL;
}
}
$myArray = array();
$myArray[] = TestClass::create(15, "asdf");
$myArray[] = TestClass::create(20, "asdfa");
$myArray[] = TestClass::create("a", "abcd");
print_r($myArray);
$myArray = array_filter($myArray, function($e){ return !is_null($e);});
print_r($myArray);
I think that there are situations where this constructions are preferable to arrays. You can move all the checking logic to the class.
Here, before the call to array_filter $myArray has 3 elements. Two correct objects and a NULL. After the call, only the 2 correct elements persist.