I'm trying to write a simple function which takes two arguments, adds them together and returns the result of the calculation.
Before performing the calculation the function checks whether either of the two arguments are undefined and if so, sets the argument to 0.
Here's my function:
Function - PHP
function returnZeroAdd ($arg, $arg2)
{
if(!isset($arg))
{
$arg = 0;
}
if(!isset($arg2))
{
$arg2 = 0;
}
echo $arg + $arg2;
}
I've tried to execute it like so :
returnZeroAdd($bawtryReturnCount, $bawtryFReturnCount);
But this throws up an undefined variable $bawtryFReturnCount error.
I do not know why the function isn't setting $bawtryFReturnCount) to 0 before performing the calculation thereby negating the 'undefined variable' error.
Can anybody provide a solution?
You cannot do this the way you want. As soon as you use an undefined variable, you will get this error. So the error doesn't occur inside your function, but already occurs in the call to your function.
1. Optional parameters
You might make a parameter optional, like so:
function returnZeroAdd ($arg = 0, $arg2 = 0)
{
return $arg + $arg2;
}
This way, the parameter is optional, and you can call the function like this:
echo returnZeroAdd(); // 0
echo returnZeroAdd(1); // 1
echo returnZeroAdd(1, 1); // 2
2. By reference
But I'm not sure if that is what you want. This call will still fail:
echo returnZeroAdd($undefinedVariable);
That can be solved by passing the variables by reference. You can then check if the values are set and if so, use them in the addition.
<?php
function returnZeroAdd (&$arg, &$arg2)
{
$result = 0;
if(isset($arg))
{
$result += $arg;
}
if(isset($arg2))
{
$result += $arg2;
}
return $result;
}
echo returnZeroAdd($x, $y);
Note that you will actually change the original value of a by reference parameter, if you change it in the function. That's why I changed the code in such a way that the parameters themselves are not modified. Look at this simplified example to see what I mean:
<?php
function example(&$arg)
{
if(!isset($arg))
{
$arg = 0;
}
return $arg;
}
echo example($x); // 0
echo $x // also 0
Of course that might be your intention. If so, you can safely set $arg and $arg2 to 0 inside the function.
The error is not thrown by the function itself, as the function is not aware of the global scope. The error is thrown before even the function is executed, while the PHP interperter is trying to pass $bawtryFReturnCount to the function, one does not find it, and throws error, however, it's not a fatal one and the execution is not stopped. THerefore, the function is executed with a non-set variable with default value of null, where I guess, isset will not work, as the arguments are mandatory, but not optional. A better check here will be empty($arg), however the error will still be present.
Because the functions are not and SHOULD NOT be aware of the global state of your application, you should do these checks from outside the functions and then call it.
if (!isset($bawtryReturnCount)) {
$bawtryReturnCount = 0
}
returnZeroAdd($bawtryReturnCount);
Or assign default values to the arguments in the function, making them optional instead of mandatory.
Your function could be rewritten as:
function returnZeroAdd ($arg = 0, $arg2 = 0)
{
echo $arg + $arg2;
}
You missunderstand how variables work. Since $bawtryFReturnCount isn't defined when you call the function; you get a warning. Your isset-checks performs the checks too late. Example:
$bawtryReturnCount = 4;
$bawtryFReturnCount = 0;
returnZeroAdd($bawtryReturnCount, $bawtryFReturnCount);
Will not result in an error.
If you really want to make the check inside the function you could pass the arguments by reference:
function returnZeroAdd (&$arg, &$arg2)
{
if(!isset($arg))
{
$arg = 0;
}
if(!isset($arg2))
{
$arg2 = 0;
}
echo $arg + $arg2;
}
However this will potentially modify your arguments outside the function, if it is not what you intend to do then you need this:
function returnZeroAdd (&$arg, &$arg2)
{
if(!isset($arg))
{
$localArg = 0;
}
else
{
$localArg = $arg;
}
if(!isset($arg2))
{
$localArg2 = 0;
}
else
{
$localArg2 = $arg2;
}
echo $localArg + $localArg2;
}
You can now pass undefined variables, it won't throw any error.
Alternatively you might want to give a default value to your arguments (in your case 0 seems appropriate):
function returnZeroAdd ($arg = 0, $arg2 = 0)
{
echo $arg + $arg2;
}
You have to define the variable before pass it to an function. for example
$bawtryReturnCount=10;
$bawtryFReturnCount=5;
define the two variable with some value and pass it to that function.
function returnZeroAdd ($arg=0, $arg2=0)
{
echo $arg + $arg2;
}
if you define a function like this means the function takes default value as 0 if the argument is not passed.
for example you can call the functio like this
returnZeroadd();// print 0
returnZeroadd(4);// print 4
returnZeroadd(4,5);// print 9
or you can define two variables and pass it as an argument and call like this.
$bawtryReturnCount=10;
$bawtryFReturnCount=5;
returnZeroadd($bawtryReturnCount, $bawtryFReturnCount);
I have been looking through wordpress's core files and stumbled across this piece of code, I noticed it had an ampersand before a variable name and after an =.
I have tried searching this and came across this from the PHP manual and it doesn't explain it well, or I'm looking at the wrong one! I also saw that it is used to modify a variable outside of the method where it is being used, but, thats what a variable is there for, to be modified so if this is correct how would one use it?
function _make_cat_compat( &$category ) {
if ( is_object( $category ) ) {
$category->cat_ID = &$category->term_id;
$category->category_count = &$category->count;
$category->category_description = &$category->description;
$category->cat_name = &$category->name;
$category->category_nicename = &$category->slug;
$category->category_parent = &$category->parent;
} elseif ( is_array( $category ) && isset( $category['term_id'] ) ) {
$category['cat_ID'] = &$category['term_id'];
$category['category_count'] = &$category['count'];
$category['category_description'] = &$category['description'];
$category['cat_name'] = &$category['name'];
$category['category_nicename'] = &$category['slug'];
$category['category_parent'] = &$category['parent'];
}
}
This means the function will modify the argument (by reference) instead working on a copy of it. Remove all the ampersands inside the body of the function, only the one in the argument is necessary.
function foo(&$foo) { $foo++; }
function bar($foo) { $foo++; }
$foo = 10;
foo($foo);
foo($foo);
// prints 12, function foo() has incremented var $foo twice
echo "$foo\n";
bar($foo);
// still 12, as bar() is working on a copy of $foo
echo "$foo\n";
// However, since PHP 5.0, all objects are passed by reference [(or to be more specific, by identifier)][1]
class Foo {
public $bar = 10;
}
$obj = new Foo;
echo "$obj->bar\n"; // 10, as expected
function objectIncrement($obj) { $obj->bar++; }
function objectRefIncrement(&$obj) { $obj->bar++; }
objectIncrement($obj);
echo "$obj->bar\n"; // 11, as expected, since objects are ALWAYS passed by reference (actually by identifier)
objectRefIncrement($obj);
echo "$obj->bar\n"; // 12
It's still a good idea, if you intend to modify the passed argument in a function/method, to explicitly pass it by reference. Aside from other advantages, your code also becomes more explicit and understandable.
BTW, you can do this:
function _make_cat_compat( &$category ) {
if (is_array( $category)) {
$category = (object)$category;
}
$category->cat_ID = $category->term_id;
$category->category_count = $category->count;
$category->category_description = $category->description;
$category->cat_name = $category->name;
$category->category_nicename = $category->slug;
$category->category_parent = $category->parent;
}
Looks cleaner to me, but I don't know your specific case. And I don't know how you would have either array or object - it implies some bad practices used.
When talking about method parameters, &$variable refers to a call by reference. So any change you make to this variable remains even if the method is done.
function a($arg) // call by value ($arg is a copy of the original)
{
$arg += 1;
}
function b(&$arg) // call by reference ($arg IS the original)
{
$arg += 1;
}
$myArg = 1;
a($myArg);
echo $myArg;
echo "\r\n";
b($myArg);
echo $myArg;
// Displays:
// 1
// 2
Here is the section of the PHP manual about references.
The & after the = basically means the same, but they are useless in this context because you already have a call by reference anyway. You can safely remove them.
Here's the correct PHP manual entry on references: http://php.net/manual/en/language.references.php
In most cases you don't need to pass a reference using the ampersand & as PHP will always pass a reference first and only create a copy of the variable on the first write access.
It is passing the variable as a reference. Without the ampersand the following code wouldnt work:
$var = "content";
function test(&$v)
{
$v = "this is new content";
}
test($var);
NOTE: this is untested code, but the theory is close enough. It allows to modify the variable from within a different scope, so rather than passing the value of a variable, in this example - "content", you are passing a reference to the variable itself, so you are directly editing the variable you passed in.
Its because this function doesnt return anything, just modify, and all.
Say i have this PHP code:
$FooBar = "a string";
i then need a function like this:
print_var_name($FooBar);
which prints:
FooBar
Any Ideas how to achieve this? Is this even possible in PHP?
I couldn't think of a way to do this efficiently either but I came up with this. It works, for the limited uses below.
shrug
<?php
function varName( $v ) {
$trace = debug_backtrace();
$vLine = file( __FILE__ );
$fLine = $vLine[ $trace[0]['line'] - 1 ];
preg_match( "#\\$(\w+)#", $fLine, $match );
print_r( $match );
}
$foo = "knight";
$bar = array( 1, 2, 3 );
$baz = 12345;
varName( $foo );
varName( $bar );
varName( $baz );
?>
// Returns
Array
(
[0] => $foo
[1] => foo
)
Array
(
[0] => $bar
[1] => bar
)
Array
(
[0] => $baz
[1] => baz
)
It works based on the line that called the function, where it finds the argument you passed in. I suppose it could be expanded to work with multiple arguments but, like others have said, if you could explain the situation better, another solution would probably work better.
You could use get_defined_vars() to find the name of a variable that has the same value as the one you're trying to find the name of. Obviously this will not always work, since different variables often have the same values, but it's the only way I can think of to do this.
Edit: get_defined_vars() doesn't seem to be working correctly, it returns 'var' because $var is used in the function itself. $GLOBALS seems to work so I've changed it to that.
function print_var_name($var) {
foreach($GLOBALS as $var_name => $value) {
if ($value === $var) {
return $var_name;
}
}
return false;
}
Edit: to be clear, there is no good way to do this in PHP, which is probably because you shouldn't have to do it. There are probably better ways of doing what you're trying to do.
You might consider changing your approach and using a variable variable name?
$var_name = "FooBar";
$$var_name = "a string";
then you could just
print($var_name);
to get
FooBar
Here's the link to the PHP manual on Variable variables
No-one seems to have mentioned the fundamental reasons why this is a) hard and b) unwise:
A "variable" is just a symbol pointing at something else. In PHP, it internally points to something called a "zval", which can actually be used for multiple variables simultaneously, either because they have the same value (PHP implements something called "copy-on-write" so that $foo = $bar doesn't need to allocate extra memory straight away) or because they have been assigned (or passed to a function) by reference (e.g. $foo =& $bar). So a zval has no name.
When you pass a parameter to a function you are creating a new variable (even if it's a reference). You could pass something anonymous, like "hello", but once inside your function, it's whatever variable you name it as. This is fairly fundamental to code separation: if a function relied on what a variable used to be called, it would be more like a goto than a properly separate function.
Global variables are generally considered a bad idea. A lot of the examples here assume that the variable you want to "reflect" can be found in $GLOBALS, but this will only be true if you've structured your code badly and variables aren't scoped to some function or object.
Variable names are there to help programmers read their code. Renaming variables to better suit their purpose is a very common refactoring practice, and the whole point is that it doesn't make any difference.
Now, I understand the desire for this for debugging (although some of the proposed usages go far beyond that), but as a generalised solution it's not actually as helpful as you might think: if your debug function says your variable is called "$file", that could still be any one of dozens of "$file" variables in your code, or a variable which you have called "$filename" but are passing to a function whose parameter is called "$file".
A far more useful piece of information is where in your code the debug function was called from. Since you can quickly find this in your editor, you can see which variable you were outputting for yourself, and can even pass whole expressions into it in one go (e.g. debug('$foo + $bar = ' . ($foo + $bar))).
For that, you can use this snippet at the top of your debug function:
$backtrace = debug_backtrace();
echo '# Debug function called from ' . $backtrace[0]['file'] . ' at line ' . $backtrace[0]['line'];
This is exactly what you want - its a ready to use "copy and drop in" function that echo the name of a given var:
function print_var_name(){
// read backtrace
$bt = debug_backtrace();
// read file
$file = file($bt[0]['file']);
// select exact print_var_name($varname) line
$src = $file[$bt[0]['line']-1];
// search pattern
$pat = '#(.*)'.__FUNCTION__.' *?\( *?(.*) *?\)(.*)#i';
// extract $varname from match no 2
$var = preg_replace($pat, '$2', $src);
// print to browser
echo '<pre>' . trim($var) . ' = ' . print_r(current(func_get_args()), true) . '</pre>';
}
USAGE: print_var_name($FooBar)
PRINT: FooBar
HINT
Now you can rename the function and it will still work and also use the function several times in one line! Thanks to #Cliffordlife
And I add a nicer output! Thanks to #Blue-Water
Lucas on PHP.net provided a reliable way to check if a variable exists. In his example, he iterates through a copy of the global variable array (or a scoped array) of variables, changes the value to a randomly generated value, and checks for the generated value in the copied array.
function variable_name( &$var, $scope=false, $prefix='UNIQUE', $suffix='VARIABLE' ){
if($scope) {
$vals = $scope;
} else {
$vals = $GLOBALS;
}
$old = $var;
$var = $new = $prefix.rand().$suffix;
$vname = FALSE;
foreach($vals as $key => $val) {
if($val === $new) $vname = $key;
}
$var = $old;
return $vname;
}
Then try:
$a = 'asdf';
$b = 'asdf';
$c = FALSE;
$d = FALSE;
echo variable_name($a); // a
echo variable_name($b); // b
echo variable_name($c); // c
echo variable_name($d); // d
Be sure to check his post on PHP.net: http://php.net/manual/en/language.variables.php
I made an inspection function for debugging reasons. It's like print_r() on steroids, much like Krumo but a little more effective on objects. I wanted to add the var name detection and came out with this, inspired by Nick Presta's post on this page. It detects any expression passed as an argument, not only variable names.
This is only the wrapper function that detects the passed expression.
Works on most of the cases.
It will not work if you call the function more than once in the same line of code.
This works fine:
die(inspect($this->getUser()->hasCredential("delete")));
inspect() is the function that will detect the passed expression.
We get: $this->getUser()->hasCredential("delete")
function inspect($label, $value = "__undefin_e_d__")
{
if($value == "__undefin_e_d__") {
/* The first argument is not the label but the
variable to inspect itself, so we need a label.
Let's try to find out it's name by peeking at
the source code.
*/
/* The reason for using an exotic string like
"__undefin_e_d__" instead of NULL here is that
inspected variables can also be NULL and I want
to inspect them anyway.
*/
$value = $label;
$bt = debug_backtrace();
$src = file($bt[0]["file"]);
$line = $src[ $bt[0]['line'] - 1 ];
// let's match the function call and the last closing bracket
preg_match( "#inspect\((.+)\)#", $line, $match );
/* let's count brackets to see how many of them actually belongs
to the var name
Eg: die(inspect($this->getUser()->hasCredential("delete")));
We want: $this->getUser()->hasCredential("delete")
*/
$max = strlen($match[1]);
$varname = "";
$c = 0;
for($i = 0; $i < $max; $i++){
if( $match[1]{$i} == "(" ) $c++;
elseif( $match[1]{$i} == ")" ) $c--;
if($c < 0) break;
$varname .= $match[1]{$i};
}
$label = $varname;
}
// $label now holds the name of the passed variable ($ included)
// Eg: inspect($hello)
// => $label = "$hello"
// or the whole expression evaluated
// Eg: inspect($this->getUser()->hasCredential("delete"))
// => $label = "$this->getUser()->hasCredential(\"delete\")"
// now the actual function call to the inspector method,
// passing the var name as the label:
// return dInspect::dump($label, $val);
// UPDATE: I commented this line because people got confused about
// the dInspect class, wich has nothing to do with the issue here.
echo("The label is: ".$label);
echo("The value is: ".$value);
}
Here's an example of the inspector function (and my dInspect class) in action:
http://inspect.ip1.cc
Texts are in spanish in that page, but code is concise and really easy to understand.
From php.net
#Alexandre - short solution
<?php
function vname(&$var, $scope=0)
{
$old = $var;
if (($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && $var = $old) return $key;
}
?>
#Lucas - usage
<?php
//1. Use of a variable contained in the global scope (default):
$my_global_variable = "My global string.";
echo vname($my_global_variable); // Outputs: my_global_variable
//2. Use of a local variable:
function my_local_func()
{
$my_local_variable = "My local string.";
return vname($my_local_variable, get_defined_vars());
}
echo my_local_func(); // Outputs: my_local_variable
//3. Use of an object property:
class myclass
{
public function __constructor()
{
$this->my_object_property = "My object property string.";
}
}
$obj = new myclass;
echo vname($obj->my_object_property, $obj); // Outputs: my_object_property
?>
Many replies question the usefulness of this. However, getting a reference for a variable can be very useful. Especially in cases with objects and $this. My solution works with objects, and as property defined objects as well:
function getReference(&$var)
{
if(is_object($var))
$var->___uniqid = uniqid();
else
$var = serialize($var);
$name = getReference_traverse($var,$GLOBALS);
if(is_object($var))
unset($var->___uniqid);
else
$var = unserialize($var);
return "\${$name}";
}
function getReference_traverse(&$var,$arr)
{
if($name = array_search($var,$arr,true))
return "{$name}";
foreach($arr as $key=>$value)
if(is_object($value))
if($name = getReference_traverse($var,get_object_vars($value)))
return "{$key}->{$name}";
}
Example for the above:
class A
{
public function whatIs()
{
echo getReference($this);
}
}
$B = 12;
$C = 12;
$D = new A;
echo getReference($B)."<br/>"; //$B
echo getReference($C)."<br/>"; //$C
$D->whatIs(); //$D
Adapted from answers above for many variables, with good performance, just one $GLOBALS scan for many
function compact_assoc(&$v1='__undefined__', &$v2='__undefined__',&$v3='__undefined__',&$v4='__undefined__',&$v5='__undefined__',&$v6='__undefined__',&$v7='__undefined__',&$v8='__undefined__',&$v9='__undefined__',&$v10='__undefined__',&$v11='__undefined__',&$v12='__undefined__',&$v13='__undefined__',&$v14='__undefined__',&$v15='__undefined__',&$v16='__undefined__',&$v17='__undefined__',&$v18='__undefined__',&$v19='__undefined__'
) {
$defined_vars=get_defined_vars();
$result=Array();
$reverse_key=Array();
$original_value=Array();
foreach( $defined_vars as $source_key => $source_value){
if($source_value==='__undefined__') break;
$original_value[$source_key]=$$source_key;
$new_test_value="PREFIX".rand()."SUFIX";
$reverse_key[$new_test_value]=$source_key;
$$source_key=$new_test_value;
}
foreach($GLOBALS as $key => &$value){
if( is_string($value) && isset($reverse_key[$value]) ) {
$result[$key]=&$value;
}
}
foreach( $original_value as $source_key => $original_value){
$$source_key=$original_value;
}
return $result;
}
$a = 'A';
$b = 'B';
$c = '999';
$myArray=Array ('id'=>'id123','name'=>'Foo');
print_r(compact_assoc($a,$b,$c,$myArray) );
//print
Array
(
[a] => A
[b] => B
[c] => 999
[myArray] => Array
(
[id] => id123
[name] => Foo
)
)
If the variable is interchangable, you must have logic somewhere that's determining which variable gets used. All you need to do is put the variable name in $variable within that logic while you're doing everything else.
I think we're all having a hard time understanding what you're needing this for. Sample code or an explanation of what you're actually trying to do might help, but I suspect you're way, way overthinking this.
I actually have a valid use case for this.
I have a function cacheVariable($var) (ok, I have a function cache($key, $value), but I'd like to have a function as mentioned).
The purpose is to do:
$colour = 'blue';
cacheVariable($colour);
...
// another session
...
$myColour = getCachedVariable('colour');
I have tried with
function cacheVariable($variable) {
$key = ${$variable}; // This doesn't help! It only gives 'variable'.
// do some caching using suitable backend such as apc, memcache or ramdisk
}
I have also tried with
function varName(&$var) {
$definedVariables = get_defined_vars();
$copyOfDefinedVariables = array();
foreach ($definedVariables as $variable=>$value) {
$copyOfDefinedVariables[$variable] = $value;
}
$oldVar = $var;
$var = !$var;
$difference = array_diff_assoc($definedVariables, $copyOfDefinedVariables);
$var = $oldVar;
return key(array_slice($difference, 0, 1, true));
}
But this fails as well... :(
Sure, I could continue to do cache('colour', $colour), but I'm lazy, you know... ;)
So, what I want is a function that gets the ORIGINAL name of a variable, as it was passed to a function. Inside the function there is no way I'm able to know that, as it seems. Passing get_defined_vars() by reference in the second example above helped me (Thanks to Jean-Jacques Guegan for that idea) somewhat. The latter function started working, but it still only kept returning the local variable ('variable', not 'colour').
I haven't tried yet to use get_func_args() and get_func_arg(), ${}-constructs and key() combined, but I presume it will fail as well.
I have this:
debug_echo(array('$query'=>$query, '$nrUsers'=>$nrUsers, '$hdr'=>$hdr));
I would prefer this:
debug_echo($query, $nrUsers, $hdr);
The existing function displays a yellow box with a red outline and shows each variable by name and value. The array solution works but is a little convoluted to type when it is needed.
That's my use case and yes, it does have to do with debugging. I agree with those who question its use otherwise.
Here's my solution based on Jeremy Ruten
class DebugHelper {
function printVarNames($systemDefinedVars, $varNames) {
foreach ($systemDefinedVars as $var=>$value) {
if (in_array($var, $varNames )) {
var_dump($var);
var_dump($value);
}
}
}
}
using it
DebugHelper::printVarNames(
$systemDefinedVars = get_defined_vars(),
$varNames=array('yourVar00', 'yourVar01')
);
You could use compact() to achieve this.
$FooBar = "a string";
$newArray = compact('FooBar');
This would create an associative array with the variable name as the key. You could then loop through the array using the key name where you needed it.
foreach($newarray as $key => $value) {
echo $key;
}
I think you want to know variable name with it's value. You can use an associative array to achieve this.
use variable names for array keys:
$vars = array('FooBar' => 'a string');
When you want to get variable names, use array_keys($vars), it will return an array of those variable names that used in your $vars array as it's keys.
This is the way I did it
function getVar(&$var) {
$tmp = $var; // store the variable value
$var = '_$_%&33xc$%^*7_r4'; // give the variable a new unique value
$name = array_search($var, $GLOBALS); // search $GLOBALS for that unique value and return the key(variable)
$var = $tmp; // restore the variable old value
return $name;
}
Usage
$city = "San Francisco";
echo getVar($city); // city
Note: some PHP 7 versions will not work properly due to a bug in array_search with $GLOBALS, however all other versions will work.
See this https://3v4l.org/UMW7V
There is no predefined function in PHP that can output the name of a variable. However, you can use the result of get_defined_vars(), which returns all the variables defined in the scope, including name and value. Here is an example:
<?php
// Function for determining the name of a variable
function getVarName(&$var, $definedVars=null) {
$definedVars = (!is_array($definedVars) ? $GLOBALS : $definedVars);
$val = $var;
$rand = 1;
while (in_array($rand, $definedVars, true)) {
$rand = md5(mt_rand(10000, 1000000));
}
$var = $rand;
foreach ($definedVars as $dvName=>$dvVal) {
if ($dvVal === $rand) {
$var = $val;
return $dvName;
}
}
return null;
}
// the name of $a is to be determined.
$a = 1;
// Determine the name of $a
echo getVarName($a);
?>
Read more in How to get a variable name as a string in PHP?
Why don't you just build a simple function and TELL it?
/**
* Prints out $obj for debug
*
* #param any_type $obj
* #param (string) $title
*/
function print_all( $obj, $title = false )
{
print "\n<div style=\"font-family:Arial;\">\n";
if( $title ) print "<div style=\"background-color:red; color:white; font-size:16px; font-weight:bold; margin:0; padding:10px; text-align:center;\">$title</div>\n";
print "<pre style=\"background-color:yellow; border:2px solid red; color:black; margin:0; padding:10px;\">\n\n";
var_export( $obj );
print "\n\n</pre>\n</div>\n";
}
print_all( $aUser, '$aUser' );
I was looking for this but just decided to pass the name in, I usually have the name in the clipboard anyway.
function VarTest($my_var,$my_var_name){
echo '$'.$my_var_name.': '.$my_var.'<br />';
}
$fruit='apple';
VarTest($fruit,'fruit');
I know this is old and already answered but I was actually looking for this. I am posting this answer to save people a little time refining some of the answers.
Option 1:
$data = array('$FooBar');
$vars = [];
$vars = preg_replace('/^\\$/', '', $data);
$varname = key(compact($vars));
echo $varname;
Prints:
FooBar
For whatever reason you would find yourself in a situation like this, it does actually work.
.
Option 2:
$FooBar = "a string";
$varname = trim(array_search($FooBar, $GLOBALS), " \t.");
echo $varname;
If $FooBar holds a unique value, it will print 'FooBar'. If $FooBar is empty or null it will print the name of the first empty or null string it finds.
It could be used as such:
if (isset($FooBar) && !is_null($FooBar) && !empty($FooBar)) {
$FooBar = "a string";
$varname = trim(array_search($FooBar, $GLOBALS), " \t.");
}
other use:
shrug
function varsToArrayAssoc(...$arguments){
$bt = debug_backtrace();
$file = file($bt[0]['file']);
$src = $file[$bt[0]['line']-1];
$pat = '#(.*)'.__FUNCTION__.' *?\( *?(.*) *?\)(.*)#i';
$vars =explode(',',substr_replace(trim(preg_replace($pat, '$2', $src)) ,"", -1));
$result=[];
foreach(func_get_args() as $key=>$v){
$index=trim(explode('$',$vars[$key])[1]);
$result[$index]=$v;
}
return $result;
}
$a=12;
$b=13;
$c=123;
$d='aa';
var_dump(varsToArrayAssoc($a,$b,$c,$d));
Use this to detach user variables from global to check variable at the moment.
function get_user_var_defined ()
{
return array_slice($GLOBALS,8,count($GLOBALS)-8);
}
function get_var_name ($var)
{
$vuser = get_user_var_defined();
foreach($vuser as $key=>$value)
{
if($var===$value) return $key ;
}
}
It may be considered quick and dirty, but my own personal preference is to use a function/method like this:
public function getVarName($var) {
$tmp = array($var => '');
$keys = array_keys($tmp);
return trim($keys[0]);
}
basically it just creates an associative array containing one null/empty element, using as a key the variable for which you want the name.
we then get the value of that key using array_keys and return it.
obviously this gets messy quick and wouldn't be desirable in a production environment, but it works for the problem presented.
why we have to use globals to get variable name... we can use simply like below.
$variableName = "ajaxmint";
echo getVarName('$variableName');
function getVarName($name) {
return str_replace('$','',$name);
}
I really fail to see the use case... If you will type print_var_name($foobar) what's so hard (and different) about typing print("foobar") instead?
Because even if you were to use this in a function, you'd get the local name of the variable...
In any case, here's the reflection manual in case there's something you need in there.