Last day of each month within a date range in php - php

How to get last day of each month within a date range in PHP?
Input:
$startdate = '2013-01-15'
$enddate = '2013-03-15'
The output that I want is:
2013-01-31 End date of January
2013-02-28 End date of February
2013-03-15 *End date of March is '2013-03-31' but the end date is '2013-03-15' .
So I want 2013-03-15.
How can I do that?

In the future, try to write the code yourself. If you are stuck with a specific part you can request help. Exception for this one time:
<?php
$startdate = new DateTime('2013-01-15');
$enddate = new DateTime('2013-04-15');
$year = $startdate->format('Y');
$start_month = (int)$startdate->format('m');
$end_month = (int)$enddate->format('m');
for ( $i=$start_month; $i<$end_month; $i++) {
$date = new DateTime($year.'-'.$i);
echo $date->format('Y-m-t').' End date of '.$date->format('F');
}
echo $enddate->format('Y-m-d');
Will output:
2013-01-31 End date of January
2013-02-28 End date of February
2013-03-31 End date of March
2013-04-15
Note that this does not work if the start and end dates have a different year. I have left this as an exercise.

function get_months($date1, $date2) {
$time1 = strtotime($date1);
$time2 = strtotime($date2);
$my = date('mY', $time2);
$months = array(date('Y-m-t', $time1));
$f = '';
while($time1 < $time2) {
$time1 = strtotime((date('Y-m-d', $time1).' +15days'));
if(date('F', $time1) != $f) {
$f = date('F', $time1);
if(date('mY', $time1) != $my && ($time1 < $time2))
$months[] = date('Y-m-t', $time1);
}
}
$months[] = date('Y-m-d', $time2);
return $months;
}
$myDates = get_months('2005-01-20', '2005-11-25');
$myDates will have the output you want. It will work even if years are different. Logic is from this URL

I'm little changed the function:
function get_months($date1, $date2) {
$time1 = strtotime($date1);
$time2 = strtotime($date2);
$my = date('mY', $time2);
$f = '';
while($time1 < $time2) {
$time1 = strtotime((date('Y-m-d', $time1).' +15days'));
if(date('F', $time1) != $f) {
$f = date('F', $time1);
if(date('mY', $time1) != $my && ($time1 < $time2))
$months[] = array(date('Y-m-01', $time1),date('Y-m-t', $time1));
}
}
$months[] = array(date('Y-m-01', $time2),date('Y-m-d', $time2));
return $months;
}

Related

Get whole week date starting from sunday to saturday from given date

Hello guys i am working in php and my requirement is to get complete week dates from given date as i need to calculate weekly working hour. And week must be started from sunday to saturday not monday to sunday. I have code which works properly for other days of week except sunday. it means if give any dates from monday to saturday it works properly but if i give sunday's date it give last week's dates. please check my code and advise me for better solution.
$days = array();
$ddate = "2018-01-07";
$date = new DateTime($ddate);
$week = $date->format("W");
$y = date("Y", strtotime($ddate));
echo "Weeknummer: $week"."<br>";
echo "Year: $y"."<br>";
for($day=0; $day<=6; $day++)
{
$days[$day] = date('Y-m-d', strtotime($y."W".$week.$day))."<br>";
}
print_r($days);
Using the DateTime, DateInterval and DatePeriod classes you could do it like this perhaps
function getperiod( $start ){
return new DatePeriod(
new DateTime( $start ),
new DateInterval('P1D'),
new DateTime( date( DATE_COOKIE, strtotime( $start . '+ 7days' ) ) )
);
}
$start='2018-01-07';
$period=getperiod( $start );
foreach( $period as $date ){
echo $date->format('l -> Y-m-d') . '<br />';
}
Which returns
Sunday -> 2018-01-07
Monday -> 2018-01-08
Tuesday -> 2018-01-09
Wednesday -> 2018-01-10
Thursday -> 2018-01-11
Friday -> 2018-01-12
Saturday -> 2018-01-13
Or, by modifying the parameters of the getperiod function you can make that function far more flexible.
function getperiod( $start, $interval='P1D', $days=7 ){
return new DatePeriod(
new DateTime( $start ),
new DateInterval( $interval ),
new DateTime( date( DATE_COOKIE, strtotime( $start . '+ '.$days.' days' ) ) )
);
}
$start='2018-01-07';
$days=array();
$period=getperiod( $start );
foreach( $period as $date ){
$days[]=$date->format('Y-m-d');
}
echo '<pre>',print_r($days,true),'</pre>';
For instance: To find every Sunday for the next year
$period=getperiod( $start,'P7D', 365 );
foreach( $period as $date ){
$days[]=$date->format('Y-m-d');
}
echo '<pre>',print_r($days,true),'</pre>';
To ensure that the calculations begin on a Sunday which has a numeric value of 7
function getperiod( $start, $interval='P1D', $days=7 ){
return new DatePeriod(
new DateTime( $start ),
new DateInterval( $interval ),
new DateTime( date( DATE_COOKIE, strtotime( $start . '+ '.$days.' days' ) ) )
);
}
/* A date from which to begin calculations */
$start='2018-01-01';
/* Array to store output */
$days=array();
/* integer to represent which day of the week to operate upon */
$startday = 7;
/* Output format for resultant dates */
$output='Y-m-d';
/* Calculate initial startdate given above variables */
$start=date( DATE_COOKIE, strtotime( $start . ' + ' . ( $startday - date( 'N', strtotime( $start ) ) ) . ' days' ) );
/* Get the period range */
$period=getperiod( $start );
foreach( $period as $date ){
/* store output in desired format */
$days[]=$date->format( $output );
}
/* do something with data */
echo '<pre>',print_r($days,true),'</pre>';
From source,
Here is the snippet you are looking for,
// set current date
$date = '01/03/2018';
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// calculate the number of days since Monday
$dow = date('w', $ts);
$offset = $dow - 1;
if ($offset < 0) {
$offset = 6;
}
// calculate timestamp for the Monday
$ts = $ts - $offset*86400;
// loop from Monday till Sunday
for ($i = 0; $i < 7; $i++, $ts += 86400){
print date("m/d/Y l", $ts) . "\n";
}
Here is working demo.
If you need normal standard format code,
Here is your snippet,
// set current date
$date = '2018-01-03';
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// calculate the number of days since Monday
$dow = date('w', $ts);
$offset = $dow - 1;
if ($offset < 0) {
$offset = 6;
}
// calculate timestamp for the Monday
$ts = $ts - $offset * 86400;
// loop from Monday till Sunday
for ($i = 0; $i < 7; $i++, $ts += 86400) {
print date("Y-m-d l", $ts) . "\n";
}
Here is working demo.
EDIT
As per your requirement, now week will start from sunday to saturday
<?php
// set current date
$date = '2018-01-03';
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// calculate the number of days since Sunday
$dow = date('w', $ts);
$offset = $dow;
if ($offset < 0) {
$offset = 6;
}
// calculate timestamp for the Sunday
$ts = $ts - $offset * 86400;
// loop from Sunday till Saturday
for ($i = 0; $i < 7; $i++, $ts += 86400) {
print date("Y-m-d l", $ts) . "\n";
}
<?php
$days = array();
$ddate = "2018-01-07";
$y = date("Y", strtotime($ddate));
if(date("l", strtotime($ddate))=='Sunday'){
$ddate = date("Y-m-d ", strtotime($ddate. "+1 day"));
}
$date = new DateTime($ddate);
$week = $date->format("W");
echo "<br/>";
echo "Weeknummer: $week"."<br>";
echo "Year: $y"."<br>";
for($day=0; $day<=6; $day++)
{
$days[$day] = date('Y-m-d', strtotime($y."W".$week.$day))."<br>";
}
print_r($days);
?>
try this:
$days = array();
$ddate = "2018-01-07";
$date = new DateTime($ddate);
$week = $date->format("N")==7?$date->modify("+1 week")->format("W"):$date->format("W");
$y = date("Y", strtotime($ddate));
echo "Weeknummer: $week"."<br>";
echo "Year: $y"."<br>";
for($day=0; $day<=6; $day++)
{
$days[$day] = date('Y-m-d', strtotime($y."W".$week.$day))."<br>";
}
print_r($days);
$dto = new DateTime();
$year = date_create($this->week_date)->format('o');
$week_no = date('W', strtotime($this->week_date));
$dto->setISODate($year, $week_no);
$dto->modify('-1 days');
$ret['sunday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['monday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['tuesday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['wednesday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['thursday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['friday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['saturday'] = $dto->format('Y-m-d');
$dto->modify('+1 days');
$ret['next_sunday'] = $dto->format('Y-m-d');

Calculate days in months between two dates with PHP

I have a period with startdate of 2016-12-26 and end date 2017-03-04.
Now I would like to find out how many days in each months there is, from a given period. Expected output from the above period dates (array):
2016-12: 5
2017-01: 31
2017-02: 28
2017-03: 4
How can I accomplish this cleanest way? I have tried to:
first looking at the period_start, get the days = 26 and
find out the start/end dates of the months between 2016-12 and 2017-03, to then calculate the days here (31 respectively 28 in february)
then finally calculating the 4 days in 2017-03.
But is there any cleaner/better way?
This can be achieved easily using the DateTime class. Create the objects, and use DateTime::diff() on them, then use the days property.
$start = new DateTime("2016-12-26");
$end = new DateTime("2017-03-04");
echo $start->diff($end)->days; // Output: 68
Live demo
http://php.net/datetime.construct
#Karem hope this logic will help you, this is working case for all your conditions please try this below one:
<?php
$startDate = '2016-12-26';
$endDate = '2017-03-04';
$varDate = $startDate;
while($varDate < $endDate){
$d = date('d', strtotime($varDate));
$Y = date('Y', strtotime($varDate));
$m = date('m', strtotime($varDate));
$days = cal_days_in_month(CAL_GREGORIAN,$m,$Y);
$time = strtotime($varDate);
if($varDate == $startDate){
$time = strtotime(date('Y-m-01', $time));
$days = $days - $d;
}
else if(date("Y-m", strtotime($varDate)) == date("Y-m", strtotime($endDate))){
$days = date("j", strtotime($endDate));
}
echo date('Y-m', strtotime($varDate)). ": ".$days."<br>";
$varDate = date('Y-m-d', strtotime("+1 month", $time));
}
This is long but easy to understand that how to achieve you your goal
<?php
function getMonthDays($start,$end){
if($start < $end){
$start_time = strtotime($start);
$last_day_of_start = strtotime(date("Y-m-t",$start_time));
$start_month_days = ($last_day_of_start - $start_time)/(60*60*24);
echo date("Y-m",$start_time).": ".$start_month_days."\n";
$days = "";
$start = date("Y-m-d", strtotime("+1 month", $start_time));
$start_time = strtotime($start);
while($start < $end){
$month = date("m",$start_time);
$year = date("Y",$start_time);
$days = date('t', mktime(0, 0, 0, $month, 1, $year));
echo date("Y-m",$start_time).": ".$days."\n";
$start = date("Y-m-d", strtotime("+1 month", $start_time));
$start_time = strtotime($start);
}
echo date("Y-m",strtotime($end)).": ".date("d",strtotime($end))."\n";
}else{
echo "Wrong Input";
}
}
getMonthDays('2016-12-26','2017-03-04');
?>
live demo : https://eval.in/781724
Function returns array : https://eval.in/781741
<?php
$d1 = strtotime('2016-12-26');
$d2 = strtotime('2017-03-04');
echo floor(($d2 - $d1)/(60*60*24));
?>
i used Carbon (https://carbon.nesbot.com/docs/) but you can do it with any other time lib.
$startDate = Carbon::createFromFormat('!Y-m-d', '2017-01-11');;
$endDate = Carbon::createFromFormat('!Y-m-d', '2018-11-13');;
$diffInMonths = $endDate->diffInMonths($startDate);
for ($i = 0; $i <= $diffInMonths; $i++) {
$start = $i == 0 ? $startDate->copy()->addMonth($i) : $startDate->copy()->addMonth($i)->firstOfMonth();
$end = $diffInMonths == $i ? $endDate->copy() : $start->copy()->endOfMonth();
echo $end->format('Y-m') . ' ' . ($end->diffInDays($start) + 1) . PHP_EOL;
}

How can I calculate date weekend in php

I have a date like this
$start = strtotime('2010-01-01'); $end = strtotime('2010-01-25');
My question:
How can I calculate or count weekend from $start & $end date range..??
A more modern approach is using php's DateTime class. Below, you get an array with week numbers as keys. I added the counts of weeks and weekend days.
<?php
$begin = new DateTime('2010-01-01');
$end = new DateTime('2010-01-25');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval, $end);
$weekends = [];
foreach($daterange as $date) {
if (in_array($date->format('N'), [6,7])) {
$weekends[$date->format('W')][] = $date->format('Y-m-d');
}
}
print_r($weekends);
echo 'Number of weeks: ' . count($weekends);
echo 'Number of weekend days: ' . (count($weekends, COUNT_RECURSIVE) - count($weekends));
Note: if you're using PHP 5.3, use array() instead of block arrays [].
May be this code snippet will help:
<?php
//get current month for example
$beginday = date("Y-m-01");
$lastday = date("Y-m-t");
$nr_work_days = getWorkingDays($beginday, $lastday);
echo $nr_work_days;
function getWorkingDays($startDate, $endDate)
{
$begin = strtotime($startDate);
$end = strtotime($endDate);
if ($begin > $end) {
echo "startdate is in the future! <br />";
return 0;
} else {
$no_days = 0;
$weekends = 0;
while ($begin <= $end) {
$no_days++; // no of days in the given interval
$what_day = date("N", $begin);
if ($what_day > 5) { // 6 and 7 are weekend days
$weekends++;
};
$begin += 86400; // +1 day
};
$working_days = $no_days - $weekends;
return $working_days;
}
}
Another solution can be: (Get date range between two dates excluding weekends)
This might help maybe:
$start = strtotime('2010-01-01');
$end = strtotime('2010-01-25');
$differ = $end-$start;
$min = $differ/60;
$hrs = $min/60;
$days = $hrs/24;
$weeks = $days/7;
if(is_int($weeks))
$weeks++;
echo '<pre>';
print_r(ceil($weeks));
echo '</pre>';

Get month name using start date and end date?

$startDate = "2014-03-01";
$endDate= "2014-05-25";
Result required: March, April, May;
for that PHP delivers the DatePeriod object. Just have a look at the following example.
$period = new DatePeriod(
new DateTime('2014-03-01'),
DateInterval::createFromDateString('1 month'),
new DateTime('2014-05-25')
);
foreach ($period as $month) {
echo strftime('%B', $month->format('U'));
}
A quick solution is to parse each day and check it month:
$startDate = "2014-03-01";
$endDate = "2014-05-25";
$start = strtotime($startDate);
$end = strtotime($endDate);
$result = array();
while ( $start <= $end )
{
$month = date("M", $start);
if( !in_array($month, $result) )
$result[] = $month;
$start += 86400;
}
print_r($result);
I believe it can be done much efficient by new OOP (DateTime object) approach, but this is fast and no-brain if you need to make it work.
<?php
$startDate = "2014-03-01";
echo date('F',strtotime($startDate));
?
$date = date('F',strtotime($startDate));
For full month representation (ie Januaray, February, etc)
$date = date('M',strtotime($startDate));
For abbreviated...(ie Jan, Feb, Mar)
REFERENCE
If you wanna echo out those months in between based on two dates....
$d = "2014-03-01";
$startDate = new DateTime($d);
$endDate = new DateTime("2014-05-01");
function diffInMonths(DateTime $date1, DateTime $date2)
{
$diff = $date1->diff($date2);
$months = $diff->y * 12 + $diff->m + $diff->d / 30;
return (int) round($months);
}
$t = diffInMonths($startDate, $endDate);
for($i=0;$i<$t+1;$i++){
echo date('F',strtotime($d. '+'.$i.' Months'));
}
PHP SANDBOX EXAMPLE

how to get list of date and name of day between two dates using php [duplicate]

This question already has answers here:
PHP: Return all dates between two dates in an array [duplicate]
(26 answers)
Closed 4 years ago.
<?php
$start=date('2013-05-02');
$end=date('2013-05-06');
?>
I got out put like following,I don't know how to get this please help me
Thursday 2013-05-02
Friday 2013-05-03
Saturday 2013-05-04
Sunday 2013-05-05
Monday 2013-05-06
$start = new DateTime('2013-5-02');
$end = new DateTime('2013-6-02');
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt)
{
echo $dt->format("l Y-m-d");
echo "<br>";
}
Note[it's support only Above 5.3.0 php version]
Adapting the answer found here you can quite easily do this.
function createDateRangeArray($strDateFrom,$strDateTo)
{
// takes two dates formatted as YYYY-MM-DD and creates an
// inclusive array of the dates between the from and to dates.
// could test validity of dates here but I'm already doing
// that in the main script
$aryRange=array();
$iDateFrom=mktime(1,0,0,substr($strDateFrom,5,2), substr($strDateFrom,8,2),substr($strDateFrom,0,4));
$iDateTo=mktime(1,0,0,substr($strDateTo,5,2), substr($strDateTo,8,2),substr($strDateTo,0,4));
if ($iDateTo>=$iDateFrom)
{
array_push($aryRange,date('Y-m-d',$iDateFrom)); // first entry
while ($iDateFrom<$iDateTo)
{
$iDateFrom+=86400; // add 24 hours
array_push($aryRange,date('l Y-m-d',$iDateFrom));
}
}
return $aryRange;
}
$start=date('2013-05-02');
$end=date('2013-05-06');
echo '<pre>'.print_r(createDateRangeArray($start, $end), 1).'</pre>';
This will work for you
<?php
function dateRange($start, $end) {
date_default_timezone_set('UTC');
$diff = strtotime($end) - strtotime($start);
$daysBetween = floor($diff/(60*60*24));
$formattedDates = array();
for ($i = 0; $i <= $daysBetween; $i++) {
$tmpDate = date('Y-m-d', strtotime($start . " + $i days"));
$formattedDates[] = date('l Y-m-d', strtotime($tmpDate));
}
return $formattedDates;
}
$start='2013-05-02';
$end='2013-05-06';
$formattedDates = dateRange($start, $end);
echo join(', ', $formattedDates);
// => Thursday 2013-05-02, Friday 2013-05-03, Saturday 2013-05-04, Sunday 2013-05-05, Monday 2013-05-06
Check this out,
<?php
$from_date = strtotime("2013-05-02");
$to_date = strtotime("2013-08-02");
for ($current_date = $from_date; $current_date <= $to_date; $current_date += (60 * 60 * 24)) { // looping for avvailable dates
// use date() and $currentDateTS to format the dates in between
$date = date("Y-m-d",$current_date);
$day_name = getdate($current_date) ;
$day_name = $day_name['weekday'];
echo $date." ".$day_name."<br>";
}
?>

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