Calculate date/time PHP [closed] - php

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Closed 10 years ago.
I need to compare a date to today. Basically I put in 2/17/13 and it will output "yesterday". I've tried echo date('l jS F', strtotime('2/15/13')); but it will only display that date not compare it to today.

Answer 1

From http://www.highlystructured.com/comparing_dates_php.html
$exp_date = "2006-01-16";
$todays_date = date("Y-m-d");
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) {
$valid = "yes";
} else {
$valid = "no";
}

Answer 2

Here's an example, to get you started:
$when = '2/17/13';
$now = new DateTime();
// I append $now's time to $then, to make sure we compare
// the two dates using the same time of the day
// if you want to compare to $then at 00:00:00, leave it out
$then = new DateTime( $when . ' ' . $now->format( 'H:i:s' ) );
$diff = $now->diff( $then );
switch( $diff->days )
{
case 0:
echo 'today';
break;
case 1:
echo $diff->invert ? 'yesterday' : 'tomorrow';
break;
default:
echo $diff->invert ? $diff->days . ' days ago' : $diff->days . ' days from now';
break;
}

Answer 3

Drupal ships with a very nice format_interval($interval, $granularity = 2, $langcode = NULL) function.
<?php
function format_interval($interval, $granularity = 2, $langcode = NULL) {
$units = array(
'1 year|#count years' => 31536000,
'1 month|#count months' => 2592000,
'1 week|#count weeks' => 604800,
'1 day|#count days' => 86400,
'1 hour|#count hours' => 3600,
'1 min|#count min' => 60,
'1 sec|#count sec' => 1,
);
$output = '';
foreach ($units as $key => $value) {
$key = explode('|', $key);
if ($interval >= $value) {
$output .= ($output ? ' ' : '') . format_plural(floor($interval / $value), $key[0], $key[1], array(), array('langcode' => $langcode));
$interval %= $value;
$granularity--;
}
if ($granularity == 0) {
break;
}
}
return $output ? $output : t('0 sec', array(), array('langcode' => $langcode));
}
?>
You don't need to be running Drupal to use it. Just include the above function somewhere. However, the above function also calls format_plural() - which calls t() (both custom Drupal functions), so you'll need to modify the above function or include all of them.
Your use case:
<?php
$today = date();
$compare = strtotime('2/15/13');
$interval = ($today - $compare);
print format_interval($interval, 1);
// Outputs '1 day'
?>

Answer 4

function checkDate($todaysDate,$expirationDate){
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) {
$valid = "yes";
} else {
$valid = "no";
}
return $valid
}
$expirationDate = "2006-01-16";
$todaysDate = date("Y-m-d");
$valid=checkDate($todaysDate,$expirationDate)
Do it in a function then you can use it with any combination of dates. You can then expand upon the function with some conditionals to figure out if its "yesterday".

Answer 5

function relativeTime($time) {
$d[0] = array(1,"second");
$d[1] = array(60,"minute");
$d[2] = array(3600,"hour");
$d[3] = array(86400,"day");
$d[4] = array(604800,"week");
$d[5] = array(2592000,"month");
$d[6] = array(31104000,"year");
$w = array();
$return = "";
$now = time();
$diff = ($now-$time);
$secondsLeft = $diff;
for($i=6;$i>-1;$i--)
{
$w[$i] = intval($secondsLeft/$d[$i][0]);
$secondsLeft -= ($w[$i]*$d[$i][0]);
if($w[$i]!=0)
{
$return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." ";
}
}
$return .= ($diff>0)?"ago":"left";
return $return;
}