Hi everybody) I have table and few rows. How I can print all results for a specific date? Specific date like this - 30.01.2013 . Date previously saved in $date (in variable).
Google helped me), but it for last month..:
select id from tab where date_format(real_time, '%Y%m') = date_format(date_add(now(), interval -1 month), '%Y%m');
The date save in row TIMESTAMP.
select ...
from ...
where real_time = '2013-01-30'
Related
I have a table with different columns. Two of them are user and data. I want to find which users have no records in the last week.
How far have I arrived:
This gives me well the records ordered first by user and then by date:
SELECT *
FROM table1
ORDER BY user, date
I also could find a way to store one week in a var:
$oneWeek = strtotime("-1 week");
$oneWeek = date("Y-m-d H:i:s", $oneWeek);
echo $oneWeek . "<br>";
Is there a way I can select the users that do not have any records in the last seven days?
Use GROUP BY and HAVING:
SELECT t1.user
FROM table1 t1
GROUP BY t1.user
HAVING MAX(t1.date) < DATE_ADD(CURDATE(), INTERVAL -7 DAY);
This returns users whose maximum date is more than a week in the past. That is another way of saying that there are no records in the past week.
I want to get count of previous day records from database.
I am using following method
$date = date('Y-m-d H:i:s', strtotime('-1 day'));
$users = 'SELECT Count(*) FROM users where date="'.$date.'"';
This is show count 0 as date format in database is (Y-m-d H:i:s).
Thanks.
Could just do
select count(*) from users where to_days(date) = (to_days(now()) - 1);
This is useful if your date column is a datetime - we're just converting to a day number and checking how many records have yesterdays day number.
Hope it will help you
SELECT COUNT(*) FROM users WHERE date = (CURDATE() - INTERVAL 1 DAY)
You might want to consider asking MYSQL itself about it, so that PHP doesn't have to compute it (and it is likely to be faster) :
SELECT Count(*) FROM users WHERE date = DATE_SUB(NOW(), INTERVAL 1 DAY)
Say I've got a simple mysql table with columns id, title, date. Each day can have several rows, but not every day has a row. For example there might be 5 rows with June 15th as the date, but zero rows with June 14th as the date. How can I get all results from the past 7 days, excluding June 14th because it has no rows. So I'm not just subtracting 7 days from the current date. I want to get only the past 7 days which have any rows at all.
Then I want to return each day as a single result, like a group by date, but by the year/month/day part of the timestamp, so that what I get back is only 7 results, and each result is like an array of individual rows.
I hope that makes sense. Any ideas?
Edit:
I realized I can do it something like this:
WHERE Date BETWEEN DATE_SUB( NOW(), INTERVAL DATEDIFF( NOW(), (SELECT Date FROM test GROUP BY Date LIMIT 7,1 ) ) DAY ) and NOW()
But this gives an SQL syntax error. What I'm trying to do is a subquery and group by date to get one result for each day, and return one result starting at offset 7, then do a DATEDIFF on that to get the number of days that DATE_SUB should put in the INTERVAL x DAYS
You won't be able to get the same day results back as an array, but you can group it by date, with the titles comma separated:
SELECT GROUP_CONCAT(title) AS titles, date
FROM test
WHERE date > DATE_SUB(CURDATE(), INTERVAL 7 DAY)
GROUP BY date;
Then in PHP, do something like this:
foreach ($results as $row)
{
echo $row['date'];
foreach ($row['titles'] as $title)
{
echo $title;
}
}
Figured it out: It works!
WHERE Date BETWEEN DATE_SUB(NOW(), INTERVAL (DATEDIFF( NOW(), (SELECT Date FROM test GROUP BY Date ORDER BY Date DESC LIMIT 8,1 ) ) ) DAY) and NOW()
I was missing a parentheses, and I had to add ORDER BY and DESC to the subquery.
I want to be able to fetch results from mysql with a statement like this:
SELECT *
FROM table
WHERE amount > 1000
But I want to fetch the result constrained to a certain a month and year (based on input from user)... I was trying like this:
SELECT *
FROM table
WHERE amount > 1000
AND dateStart = MONTH('$m')
...$m being a month but it gave error.
In that table, it actually have two dates: startDate and endDate but I am focusing on startDate. The input values would be month and year. How do I phrase the SQL statement that gets the results based on that month of that year?
You were close - got the comparison backwards (assuming startDate is a DATETIME or TIMESTAMP data type):
SELECT *
FROM table
WHERE amount > 1000
AND MONTH(dateStart) = {$m}
Caveats:
Mind that you are using mysql_escape_string or you risk SQL injection attacks.
Function calls on columns means that an index, if one exists, can not be used
Alternatives:
Because using functions on columns can't use indexes, a better approach would be to use BETWEEN and the STR_TO_DATE functions:
WHERE startdate BETWEEN STR_TO_DATE([start_date], [format])
AND STR_TO_DATE([end_date], [format])
See the documentation for formatting syntax.
Reference:
MONTH
YEAR
BETWEEN
STR_TO_DATE
Use the month() function.
select month(now());
Try this:
SELECT *
FROM table
WHERE amount > 1000 AND MONTH(dateStart) = MONTH('$m') AND YEAR(dateStart) = YEAR('$m')
E.g.
$date = sprintf("'%04d-%02d-01'", $year, $month);
$query = "
SELECT
x,y,dateStart
FROM
tablename
WHERE
AND amount > 1000
AND dateStart >= $date
AND dateStart < $date+Interval 1 month
";
mysql_query($query, ...
This will create a query like e.g.
WHERE
AND amount > 1000
AND dateStart >= '2010-01-01'
AND dateStart < '2010-01-01'+Interval 1 month
+ Interval 1 month is an alternative to date_add().
SELECT Date('2010-01-01'+Interval 1 month)-> 2010-02-01
SELECT Date('2010-12-01'+Interval 1 month)-> 2011-01-01
This way you always get the first day of the following month. The records you want must have a dateStart before that date but after/equal to the first day of the month (and year) you've passed to sprintf().
'2010-01-01'+Interval 1 month doesn't change between rows. MySQL will calculate the term only once and can utilize indices for the search.
Try this
SELECT *
FROM table
WHERE amount > 1000
AND MONTH(datestart)
GROUP BY EXTRACT(YEAR_MONTH FROM datestart)
Try this if(date field is text then convert this string to date):
SELECT * FROM `table_name` WHERE MONTH(STR_TO_DATE(date,'%d/%m/%Y'))='11'
//This will give month number MONTH(STR_TO_DATE(date,'%d/%m/%Y'))
//If its return 11 then its November
// Change date format with your date string format %d/%m/%Y
Works in: MySQL 5.7, MySQL 5.6, MySQL 5.5, MySQL 5.1, MySQL 5.0, MySQL 4.1, MySQL 4.0, MySQL 3.23
Day:
SELECT EXTRACT(DAY FROM "2017-06-15");
Month:
SELECT EXTRACT(MONTH FROM "2017-06-15");
Year:
SELECT EXTRACT(YEAR FROM "2017-06-15");
I'm looking for a best practice advice how to speed up queries and at the same time to minimize the overhead needed to invoke date/mktime functions. To trivialize the problem I'm dealing with the following table layout:
CREATE TABLE my_table(
id INTEGER PRIMARY KEY NOT NULL AUTO_INCREMENT,
important_data INTEGER,
date INTEGER);
The user can choose to show 1) all entries between two dates:
SELECT * FROM my_table
WHERE date >= ? AND date <= ?
ORDER BY date DESC;
Output:
10-21-2009 12:12:12, 10002
10-21-2009 14:12:12, 15002
10-22-2009 14:05:01, 20030
10-23-2009 15:23:35, 300
....
I don't think there is much to improve in this case.
2) Summarize/group the output by day, week, month, year:
SELECT COUNT(*) AS count, SUM(important_data) AS important_data
FROM my_table
WHERE date >= ? AND date <= ?
ORDER BY date DESC;
Example output by month:
10-2009, 100002
11-2009, 200030
12-2009, 3000
01-2010, 0 /* <- very important to show empty dates, with no entries in the table! */
....
To accomplish option 2) I'm currently running a very costly for-loop with mktime/date like the following:
for(...){ /* example for group by day */
$span_from = (int)mktime(0, 0, 0, date("m", $time_min), date("d", $time_min)+$i, date("Y", $time_min));
$span_to = (int)mktime(0, 0, 0, date("m", $time_min), date("d", $time_min)+$i+1, date("Y", $time_min));
$query = "..";
$output = date("m-d-y", ..);
}
What are my ideas so far? Add additional/ redundant columns (INTEGER) for day (20091212), month (200912), week (200942) and year (2009). This way I can get rid of all the unnecessary queries in the for loop. However I'm still facing the problem to very fastly calculate all dates that doesn't have any equivalent in database. One way to simply move the problem could be to let MySQL do the job and simply use one big query (calculate all the dates/use MySQL date functions) with a left join (the data). Would it be wise to let MySQL take the extra load? Anyway I'm reluctant to use all these mktime/date in the for loop. Since I have complete control over the table layout and code even suggestions with major changes are welcome!
Update
Thanks to Greg I came up with the following SQL query. However it still bugs me to use 50 lines of sql statements - build up with php - that maybe could be done faster and more elegantly otherwise:
SELECT * FROM (
SELECT DATE_ADD('2009-01-30', INTERVAL 0 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 1 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 2 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 3 DAY) AS day UNION ALL
......
SELECT DATE_ADD('2009-01-30', INTERVAL 50 DAY) AS day ) AS dates
LEFT JOIN (
SELECT DATE_FORMAT(date, '%Y-%m-%d') AS date, SUM(data) AS data
FROM test
GROUP BY date
) AS results
ON DATE_FORMAT(dates.day, '%Y-%m-%d') = results.date;
You definitely shouldn't be doing a query inside a loop.
You can group like this:
SELECT COUNT(*) AS count, SUM(important_data) AS important_data, DATE_FORMAT('%Y-%m', date) AS month
FROM my_table
WHERE date BETWEEN ? AND ? -- This should be the min and max of the whole range
GROUP BY DATE_FORMAT('%Y-%m', date)
ORDER BY date DESC;
Then pull these into an array keyed by date and loop over your data range as you are doing (that loop should be pretty light on CPU).
Another idea is not to use string inside the query. Transform the string parameter to datetime, on mysql.
STR_TO_DATE(str,format)
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html