mysqli_connect not selecting database [duplicate] - php

Question

$link = mysql_connect('localhost', $username, $password);
if (!$link)
{
die('Could not connect: ' . mysql_error());
}
I get this error:
Could not connect: Access denied for user 'www-data'#'localhost' (using password: NO)
Why?
Edit:
$username="root";
$password="root";
$database="test";
function Save($name)
{
$link = mysql_connect('localhost', $username, $password);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
#mysql_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO test (name)" .
"VALUES ('" . $name . "')";
mysql_query($query);
mysql_close();
}

Answer 1

Did you give $username and $password values? Something like this?
$username="root";
$password="";

Answer 2

Your $password variable is empty ((using password: NO)) then you trying log into www-data user without password, and server result is access denied. Propably this user have setted password.

Answer 3

From your edit, the issue appears to be a scoping one.
You're attempting to make a connection inside a function where the $username, $password and $database variables are defined outside that function.
I suggest you read the Variable Scope section of the manual and turn up your error reporting as #netcoder suggests in the question comments.

Answer 4

I think the problem is that, you are trying to connect to the database twice.
Somewhere in your code, you are already trying to connect to the database with username as "www-data"...... and again you are connecting to the database with username "root".
Also the password you are providing with the username "www-data" is wrong, thats y you getting the error message.

Answer 5

$username="root";
$password="root";
$database="test";
function Save($name)
{
global $username;
global $password;
global $database;
$link = mysql_connect('localhost', $username, $password);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
#mysql_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO test (name)" .
"VALUES ('" . $name . "')";
mysql_query($query);
mysql_close();
}