the where ___ in ____ sql command in my query using php - php

Question

I am trying to take a user's input of #,#, or just normal statements and then pull those results from a SQL database if the search results exist in the "query" column of a table called "job" in my database. Here is the error I am getting:
Unknown column 'Array' in 'where clause'
Here's my code:
$result_all = $_POST['result_name'];
$result_all_array= explode(',',$result_all);
$query = "select last_count, query, job_id from twitterinblack46.job where
query in (".$result_all_array.") order by last_count desc;";
$result= mysql_query($query);
if($result === FALSE) {
die(mysql_error());
}
else{
//Sets up table
echo "<table border='1'
<tr>
<th>Job ID</th>
<th>Last Count</th>
<th>Result</th>
</tr>";
//Populates table
while($row = mysql_fetch_array($result)){
echo"<tr>";
echo "<td>" . $row["job_id"] . "</td>";
echo "<td>" . ltrim($row["last_count"],'0') . "</td>";
echo "<td>" . str_replace(array('%23', '%40', '%20', 'q='), array('#','#',' ',''),
$row['query']) . "</td>";
echo "<tr>";
}
echo "</table>";
Anyone know what I am doing wrong?
Update:
Here was the confusion, I did not forget to copy the $ for query. "query" is the name of the column I want to get the information from in my query. So what I am saying is, what is the difference between these two sets of code and why doesn't it work for the first query?
Code that doesn't work:
$result_all= $_POST['result_name'];
$query = "select last_count, query, job_id from twitterinblack46.job where
query in (".$result_all.") order by last_count desc;";
$result= mysql_query($query);
Code that does work:
$job_id_all= $_POST['job_id'];
$query = 'select last_count, query, job_id from twitterinblack46.job where job_id in
('.$job_id_all.') order by last_count desc;';
$result= mysql_query($query);

Answer 1

It is obviously a problem of the form input, being multiple checkboxes checked for example.
Try this in both queries:
$result_all= implode(',', mysql_escape_string($_POST['result_name']));
$query = "select last_count, query, job_id from twitterinblack46.job where query in (".$result_all.") order by last_count desc;";
$result= mysql_query($query);